Trying to plot the norm of the solutions to NDsolve












3












$begingroup$



I have been tried to do two things with the solutions from NDSolveValue




  • plot the norm of the solutions of a differential equation system versus time.

  • plot one component of the solutions of a differential equation system versus time.


but I have been having difficulty it setting up the right syntax to do so.




The problem seems to be (for plotting the norms of the solutions), that Mathematica takes the norm of all the solutions, or tries to find the norm of a function rather than the value of the function at a certain time.



I have created a minimum working example from the original code. The major change is that in the original code set is a random set of $n$ points. The examples are my best guess for the correct syntax for the problems listed above. For context I have included a 3D parametric plot which works as intended.



If you have any questions please don't be afraid to ask.



Minimum Example



(*Simulation Parameters*)
Clear[i, P, B]
Clear[f]
f[P_, B_] := 1/2 P + 10 B/(1 + B);
tmax = 20;
A = {{1/20, 1/4, 1/50}, {1/4, 1/26, 1/40}};
set = {{1.1, 11.2, 0.2}, {5.6, 4.3, 7.8}, {2.3, 3.4, 3.4}};

(*ODE System*)
ODEsys = {i'[t] == f[P[t], B[t]] - i[t],
P'[t] ==
P[t] (1 - A[[1, 1]] P[t] - A[[1, 2]] B[t] - A[[1, 3]] i[t]),
B'[t] == B[t] (1 - A[[2, 2]] B[t] - A[[2, 3]] i[t])};

(* Simulation *)
With[{ttmax = tmax},
sol = ParametricNDSolveValue[{ODEsys, {P[0] == init1, B[0] == init2,
i[0] == init0}}, {P, B, i}, {t, 0, ttmax}, {init1, init2,
init0}]];

(* Plots I am having trouble with *)
(* Cannot plot the first component of multiple solutions. *)
ParametricPlot[{t,
Evaluate[Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)][[All,
1]]}, {t, 0, tmax}, PlotRange -> All]

(* Takes the norm of all solutions. Does not plot the norms of the
three different solutions. *)
ParametricPlot[{t,
Norm[Evaluate[
Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)]]}, {t, 0,
tmax}, PlotRange -> All]

(* This plot works as attended. *)
trajectoriesPlot =
ParametricPlot3D[
Evaluate[Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)], {t,
0, tmax}, PlotRange -> All]









share|improve this question









$endgroup$












  • $begingroup$
    I am looking for the default Euclidean norm e.g. $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ not $||(P_1,B_1,I_3)||=|P_1|+|B_1|+|I_3| or anything else. Abs does not give the magnitude of a vector.
    $endgroup$
    – AzJ
    Feb 5 at 22:20
















3












$begingroup$



I have been tried to do two things with the solutions from NDSolveValue




  • plot the norm of the solutions of a differential equation system versus time.

  • plot one component of the solutions of a differential equation system versus time.


but I have been having difficulty it setting up the right syntax to do so.




The problem seems to be (for plotting the norms of the solutions), that Mathematica takes the norm of all the solutions, or tries to find the norm of a function rather than the value of the function at a certain time.



I have created a minimum working example from the original code. The major change is that in the original code set is a random set of $n$ points. The examples are my best guess for the correct syntax for the problems listed above. For context I have included a 3D parametric plot which works as intended.



If you have any questions please don't be afraid to ask.



Minimum Example



(*Simulation Parameters*)
Clear[i, P, B]
Clear[f]
f[P_, B_] := 1/2 P + 10 B/(1 + B);
tmax = 20;
A = {{1/20, 1/4, 1/50}, {1/4, 1/26, 1/40}};
set = {{1.1, 11.2, 0.2}, {5.6, 4.3, 7.8}, {2.3, 3.4, 3.4}};

(*ODE System*)
ODEsys = {i'[t] == f[P[t], B[t]] - i[t],
P'[t] ==
P[t] (1 - A[[1, 1]] P[t] - A[[1, 2]] B[t] - A[[1, 3]] i[t]),
B'[t] == B[t] (1 - A[[2, 2]] B[t] - A[[2, 3]] i[t])};

(* Simulation *)
With[{ttmax = tmax},
sol = ParametricNDSolveValue[{ODEsys, {P[0] == init1, B[0] == init2,
i[0] == init0}}, {P, B, i}, {t, 0, ttmax}, {init1, init2,
init0}]];

(* Plots I am having trouble with *)
(* Cannot plot the first component of multiple solutions. *)
ParametricPlot[{t,
Evaluate[Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)][[All,
1]]}, {t, 0, tmax}, PlotRange -> All]

(* Takes the norm of all solutions. Does not plot the norms of the
three different solutions. *)
ParametricPlot[{t,
Norm[Evaluate[
Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)]]}, {t, 0,
tmax}, PlotRange -> All]

(* This plot works as attended. *)
trajectoriesPlot =
ParametricPlot3D[
Evaluate[Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)], {t,
0, tmax}, PlotRange -> All]









share|improve this question









$endgroup$












  • $begingroup$
    I am looking for the default Euclidean norm e.g. $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ not $||(P_1,B_1,I_3)||=|P_1|+|B_1|+|I_3| or anything else. Abs does not give the magnitude of a vector.
    $endgroup$
    – AzJ
    Feb 5 at 22:20














3












3








3





$begingroup$



I have been tried to do two things with the solutions from NDSolveValue




  • plot the norm of the solutions of a differential equation system versus time.

  • plot one component of the solutions of a differential equation system versus time.


but I have been having difficulty it setting up the right syntax to do so.




The problem seems to be (for plotting the norms of the solutions), that Mathematica takes the norm of all the solutions, or tries to find the norm of a function rather than the value of the function at a certain time.



I have created a minimum working example from the original code. The major change is that in the original code set is a random set of $n$ points. The examples are my best guess for the correct syntax for the problems listed above. For context I have included a 3D parametric plot which works as intended.



If you have any questions please don't be afraid to ask.



Minimum Example



(*Simulation Parameters*)
Clear[i, P, B]
Clear[f]
f[P_, B_] := 1/2 P + 10 B/(1 + B);
tmax = 20;
A = {{1/20, 1/4, 1/50}, {1/4, 1/26, 1/40}};
set = {{1.1, 11.2, 0.2}, {5.6, 4.3, 7.8}, {2.3, 3.4, 3.4}};

(*ODE System*)
ODEsys = {i'[t] == f[P[t], B[t]] - i[t],
P'[t] ==
P[t] (1 - A[[1, 1]] P[t] - A[[1, 2]] B[t] - A[[1, 3]] i[t]),
B'[t] == B[t] (1 - A[[2, 2]] B[t] - A[[2, 3]] i[t])};

(* Simulation *)
With[{ttmax = tmax},
sol = ParametricNDSolveValue[{ODEsys, {P[0] == init1, B[0] == init2,
i[0] == init0}}, {P, B, i}, {t, 0, ttmax}, {init1, init2,
init0}]];

(* Plots I am having trouble with *)
(* Cannot plot the first component of multiple solutions. *)
ParametricPlot[{t,
Evaluate[Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)][[All,
1]]}, {t, 0, tmax}, PlotRange -> All]

(* Takes the norm of all solutions. Does not plot the norms of the
three different solutions. *)
ParametricPlot[{t,
Norm[Evaluate[
Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)]]}, {t, 0,
tmax}, PlotRange -> All]

(* This plot works as attended. *)
trajectoriesPlot =
ParametricPlot3D[
Evaluate[Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)], {t,
0, tmax}, PlotRange -> All]









share|improve this question









$endgroup$





I have been tried to do two things with the solutions from NDSolveValue




  • plot the norm of the solutions of a differential equation system versus time.

  • plot one component of the solutions of a differential equation system versus time.


but I have been having difficulty it setting up the right syntax to do so.




The problem seems to be (for plotting the norms of the solutions), that Mathematica takes the norm of all the solutions, or tries to find the norm of a function rather than the value of the function at a certain time.



I have created a minimum working example from the original code. The major change is that in the original code set is a random set of $n$ points. The examples are my best guess for the correct syntax for the problems listed above. For context I have included a 3D parametric plot which works as intended.



If you have any questions please don't be afraid to ask.



Minimum Example



(*Simulation Parameters*)
Clear[i, P, B]
Clear[f]
f[P_, B_] := 1/2 P + 10 B/(1 + B);
tmax = 20;
A = {{1/20, 1/4, 1/50}, {1/4, 1/26, 1/40}};
set = {{1.1, 11.2, 0.2}, {5.6, 4.3, 7.8}, {2.3, 3.4, 3.4}};

(*ODE System*)
ODEsys = {i'[t] == f[P[t], B[t]] - i[t],
P'[t] ==
P[t] (1 - A[[1, 1]] P[t] - A[[1, 2]] B[t] - A[[1, 3]] i[t]),
B'[t] == B[t] (1 - A[[2, 2]] B[t] - A[[2, 3]] i[t])};

(* Simulation *)
With[{ttmax = tmax},
sol = ParametricNDSolveValue[{ODEsys, {P[0] == init1, B[0] == init2,
i[0] == init0}}, {P, B, i}, {t, 0, ttmax}, {init1, init2,
init0}]];

(* Plots I am having trouble with *)
(* Cannot plot the first component of multiple solutions. *)
ParametricPlot[{t,
Evaluate[Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)][[All,
1]]}, {t, 0, tmax}, PlotRange -> All]

(* Takes the norm of all solutions. Does not plot the norms of the
three different solutions. *)
ParametricPlot[{t,
Norm[Evaluate[
Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)]]}, {t, 0,
tmax}, PlotRange -> All]

(* This plot works as attended. *)
trajectoriesPlot =
ParametricPlot3D[
Evaluate[Through /@ (sol[#[[1]], #[[2]], #[[3]]][t] & /@ set)], {t,
0, tmax}, PlotRange -> All]






plotting differential-equations syntax






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Feb 5 at 19:55









AzJAzJ

41438




41438












  • $begingroup$
    I am looking for the default Euclidean norm e.g. $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ not $||(P_1,B_1,I_3)||=|P_1|+|B_1|+|I_3| or anything else. Abs does not give the magnitude of a vector.
    $endgroup$
    – AzJ
    Feb 5 at 22:20


















  • $begingroup$
    I am looking for the default Euclidean norm e.g. $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ not $||(P_1,B_1,I_3)||=|P_1|+|B_1|+|I_3| or anything else. Abs does not give the magnitude of a vector.
    $endgroup$
    – AzJ
    Feb 5 at 22:20
















$begingroup$
I am looking for the default Euclidean norm e.g. $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ not $||(P_1,B_1,I_3)||=|P_1|+|B_1|+|I_3| or anything else. Abs does not give the magnitude of a vector.
$endgroup$
– AzJ
Feb 5 at 22:20




$begingroup$
I am looking for the default Euclidean norm e.g. $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ not $||(P_1,B_1,I_3)||=|P_1|+|B_1|+|I_3| or anything else. Abs does not give the magnitude of a vector.
$endgroup$
– AzJ
Feb 5 at 22:20










2 Answers
2






active

oldest

votes


















4












$begingroup$



  • plot the norm of the solutions of a differential equation system versus time.




Plot[Evaluate@(Norm[Through[sol[## & @@ #][t]]] & /@ set), {t, 0, tmax}, 
PlotRange -> All, AspectRatio -> 1, ImageSize -> Large,
PlotLegends -> Placed[ToString /@ set, Top],
PlotLabel -> (Norm[{P[t], B[t], i[t]}])]


enter image description here





  • plot one component of the solutions of a differential equation system versus time.






Row[ParametricPlot[Evaluate@Thread[{t, (Through[sol[## & @@ #][t]] & /@ set)[[All, #]]}], 
{t, 0, tmax}, PlotRange -> All,
PlotLegends -> Placed[set[[All, #]], Top] , AspectRatio -> 1,
ImageSize -> 300, PlotLabel -> ({P[t], B[t], i[t]}[[#]])] & /@ {1,
2, 3}, Spacer[5]]


enter image description here



Alternatively, you can use Plot:



Row[Plot[Evaluate@(Through[sol[## & @@ #][t]] & /@ set)[[All, #]], {t, 0, tmax}, 
PlotRange -> All, AspectRatio -> 1, ImageSize -> 300,
PlotLegends -> Placed[set[[All, #]], Top] ,
PlotLabel -> ({P[t], B[t], i[t]}[[#]])] & /@ {1, 2, 3}, Spacer[5]]


enter image description here






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    I really like this solution exactly what I was looking for and more.
    $endgroup$
    – AzJ
    Feb 5 at 22:52



















2












$begingroup$

sol = ParametricNDSolveValue[{ODEsys, {P[0] == init1, B[0] == init2,i[0] == init0}}, {P[t], B[t], i[t]}, {t, 0, tmax}, {init1, init2,init0}]


plot of solutions:



Plot[Table[# &[ Apply[sol, set[[i]]]]  , {i, 1, Length[set]}] , {t, 0,tmax}, PlotRange -> {0, Automatic}]


plot of euclidean norm:



Plot[Table[Sqrt[ #.#] &[ Apply[sol, set[[i]]] ], {i, 1, Length[set]}] , {t, 0,tmax}, PlotRange -> {0, Automatic}]





share|improve this answer











$endgroup$













  • $begingroup$
    This does not answer my question for my reasons. First something like Plot[Table[Map[#[t] &, Apply[sol, set[[i]]]], {i, 2, 2}], {t, 0,tmax}] does not plot all of the second components of all the solutions. It plots all the components of the second solution. Next I meant Euclidean Norm, not some other norm (I thought it was self evident as that is the default used by Mathematica when given a vector). Playing around with your code snippet I haven't been able to get the desired result
    $endgroup$
    – AzJ
    Feb 5 at 22:00










  • $begingroup$
    My plot shows 3x3 solutions as you asked for!
    $endgroup$
    – Ulrich Neumann
    Feb 5 at 22:07










  • $begingroup$
    Sorry my terminology may have confused you. For the context of my problem as I am solving a system of ODEs one function (for example $P(t)$) is a component of the solution $(P(t),B(t),I(t))$.
    $endgroup$
    – AzJ
    Feb 5 at 22:12










  • $begingroup$
    If I have three solutions $(P_1,B_1,I_1)$,$(P_2,B_2,I_2)$,$(P_3,B_3,I_3)$ (with the difference being they start at different initial conditions), I am looking for plots of the following (as examples): $P_1,P_2,P_3$ versus time, and $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ versus time.
    $endgroup$
    – AzJ
    Feb 5 at 22:17












  • $begingroup$
    Thanks for your corrected answer
    $endgroup$
    – AzJ
    Feb 5 at 22:51











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









4












$begingroup$



  • plot the norm of the solutions of a differential equation system versus time.




Plot[Evaluate@(Norm[Through[sol[## & @@ #][t]]] & /@ set), {t, 0, tmax}, 
PlotRange -> All, AspectRatio -> 1, ImageSize -> Large,
PlotLegends -> Placed[ToString /@ set, Top],
PlotLabel -> (Norm[{P[t], B[t], i[t]}])]


enter image description here





  • plot one component of the solutions of a differential equation system versus time.






Row[ParametricPlot[Evaluate@Thread[{t, (Through[sol[## & @@ #][t]] & /@ set)[[All, #]]}], 
{t, 0, tmax}, PlotRange -> All,
PlotLegends -> Placed[set[[All, #]], Top] , AspectRatio -> 1,
ImageSize -> 300, PlotLabel -> ({P[t], B[t], i[t]}[[#]])] & /@ {1,
2, 3}, Spacer[5]]


enter image description here



Alternatively, you can use Plot:



Row[Plot[Evaluate@(Through[sol[## & @@ #][t]] & /@ set)[[All, #]], {t, 0, tmax}, 
PlotRange -> All, AspectRatio -> 1, ImageSize -> 300,
PlotLegends -> Placed[set[[All, #]], Top] ,
PlotLabel -> ({P[t], B[t], i[t]}[[#]])] & /@ {1, 2, 3}, Spacer[5]]


enter image description here






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    I really like this solution exactly what I was looking for and more.
    $endgroup$
    – AzJ
    Feb 5 at 22:52
















4












$begingroup$



  • plot the norm of the solutions of a differential equation system versus time.




Plot[Evaluate@(Norm[Through[sol[## & @@ #][t]]] & /@ set), {t, 0, tmax}, 
PlotRange -> All, AspectRatio -> 1, ImageSize -> Large,
PlotLegends -> Placed[ToString /@ set, Top],
PlotLabel -> (Norm[{P[t], B[t], i[t]}])]


enter image description here





  • plot one component of the solutions of a differential equation system versus time.






Row[ParametricPlot[Evaluate@Thread[{t, (Through[sol[## & @@ #][t]] & /@ set)[[All, #]]}], 
{t, 0, tmax}, PlotRange -> All,
PlotLegends -> Placed[set[[All, #]], Top] , AspectRatio -> 1,
ImageSize -> 300, PlotLabel -> ({P[t], B[t], i[t]}[[#]])] & /@ {1,
2, 3}, Spacer[5]]


enter image description here



Alternatively, you can use Plot:



Row[Plot[Evaluate@(Through[sol[## & @@ #][t]] & /@ set)[[All, #]], {t, 0, tmax}, 
PlotRange -> All, AspectRatio -> 1, ImageSize -> 300,
PlotLegends -> Placed[set[[All, #]], Top] ,
PlotLabel -> ({P[t], B[t], i[t]}[[#]])] & /@ {1, 2, 3}, Spacer[5]]


enter image description here






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    I really like this solution exactly what I was looking for and more.
    $endgroup$
    – AzJ
    Feb 5 at 22:52














4












4








4





$begingroup$



  • plot the norm of the solutions of a differential equation system versus time.




Plot[Evaluate@(Norm[Through[sol[## & @@ #][t]]] & /@ set), {t, 0, tmax}, 
PlotRange -> All, AspectRatio -> 1, ImageSize -> Large,
PlotLegends -> Placed[ToString /@ set, Top],
PlotLabel -> (Norm[{P[t], B[t], i[t]}])]


enter image description here





  • plot one component of the solutions of a differential equation system versus time.






Row[ParametricPlot[Evaluate@Thread[{t, (Through[sol[## & @@ #][t]] & /@ set)[[All, #]]}], 
{t, 0, tmax}, PlotRange -> All,
PlotLegends -> Placed[set[[All, #]], Top] , AspectRatio -> 1,
ImageSize -> 300, PlotLabel -> ({P[t], B[t], i[t]}[[#]])] & /@ {1,
2, 3}, Spacer[5]]


enter image description here



Alternatively, you can use Plot:



Row[Plot[Evaluate@(Through[sol[## & @@ #][t]] & /@ set)[[All, #]], {t, 0, tmax}, 
PlotRange -> All, AspectRatio -> 1, ImageSize -> 300,
PlotLegends -> Placed[set[[All, #]], Top] ,
PlotLabel -> ({P[t], B[t], i[t]}[[#]])] & /@ {1, 2, 3}, Spacer[5]]


enter image description here






share|improve this answer











$endgroup$





  • plot the norm of the solutions of a differential equation system versus time.




Plot[Evaluate@(Norm[Through[sol[## & @@ #][t]]] & /@ set), {t, 0, tmax}, 
PlotRange -> All, AspectRatio -> 1, ImageSize -> Large,
PlotLegends -> Placed[ToString /@ set, Top],
PlotLabel -> (Norm[{P[t], B[t], i[t]}])]


enter image description here





  • plot one component of the solutions of a differential equation system versus time.






Row[ParametricPlot[Evaluate@Thread[{t, (Through[sol[## & @@ #][t]] & /@ set)[[All, #]]}], 
{t, 0, tmax}, PlotRange -> All,
PlotLegends -> Placed[set[[All, #]], Top] , AspectRatio -> 1,
ImageSize -> 300, PlotLabel -> ({P[t], B[t], i[t]}[[#]])] & /@ {1,
2, 3}, Spacer[5]]


enter image description here



Alternatively, you can use Plot:



Row[Plot[Evaluate@(Through[sol[## & @@ #][t]] & /@ set)[[All, #]], {t, 0, tmax}, 
PlotRange -> All, AspectRatio -> 1, ImageSize -> 300,
PlotLegends -> Placed[set[[All, #]], Top] ,
PlotLabel -> ({P[t], B[t], i[t]}[[#]])] & /@ {1, 2, 3}, Spacer[5]]


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited Feb 5 at 23:41

























answered Feb 5 at 22:35









kglrkglr

187k10203422




187k10203422








  • 1




    $begingroup$
    I really like this solution exactly what I was looking for and more.
    $endgroup$
    – AzJ
    Feb 5 at 22:52














  • 1




    $begingroup$
    I really like this solution exactly what I was looking for and more.
    $endgroup$
    – AzJ
    Feb 5 at 22:52








1




1




$begingroup$
I really like this solution exactly what I was looking for and more.
$endgroup$
– AzJ
Feb 5 at 22:52




$begingroup$
I really like this solution exactly what I was looking for and more.
$endgroup$
– AzJ
Feb 5 at 22:52











2












$begingroup$

sol = ParametricNDSolveValue[{ODEsys, {P[0] == init1, B[0] == init2,i[0] == init0}}, {P[t], B[t], i[t]}, {t, 0, tmax}, {init1, init2,init0}]


plot of solutions:



Plot[Table[# &[ Apply[sol, set[[i]]]]  , {i, 1, Length[set]}] , {t, 0,tmax}, PlotRange -> {0, Automatic}]


plot of euclidean norm:



Plot[Table[Sqrt[ #.#] &[ Apply[sol, set[[i]]] ], {i, 1, Length[set]}] , {t, 0,tmax}, PlotRange -> {0, Automatic}]





share|improve this answer











$endgroup$













  • $begingroup$
    This does not answer my question for my reasons. First something like Plot[Table[Map[#[t] &, Apply[sol, set[[i]]]], {i, 2, 2}], {t, 0,tmax}] does not plot all of the second components of all the solutions. It plots all the components of the second solution. Next I meant Euclidean Norm, not some other norm (I thought it was self evident as that is the default used by Mathematica when given a vector). Playing around with your code snippet I haven't been able to get the desired result
    $endgroup$
    – AzJ
    Feb 5 at 22:00










  • $begingroup$
    My plot shows 3x3 solutions as you asked for!
    $endgroup$
    – Ulrich Neumann
    Feb 5 at 22:07










  • $begingroup$
    Sorry my terminology may have confused you. For the context of my problem as I am solving a system of ODEs one function (for example $P(t)$) is a component of the solution $(P(t),B(t),I(t))$.
    $endgroup$
    – AzJ
    Feb 5 at 22:12










  • $begingroup$
    If I have three solutions $(P_1,B_1,I_1)$,$(P_2,B_2,I_2)$,$(P_3,B_3,I_3)$ (with the difference being they start at different initial conditions), I am looking for plots of the following (as examples): $P_1,P_2,P_3$ versus time, and $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ versus time.
    $endgroup$
    – AzJ
    Feb 5 at 22:17












  • $begingroup$
    Thanks for your corrected answer
    $endgroup$
    – AzJ
    Feb 5 at 22:51
















2












$begingroup$

sol = ParametricNDSolveValue[{ODEsys, {P[0] == init1, B[0] == init2,i[0] == init0}}, {P[t], B[t], i[t]}, {t, 0, tmax}, {init1, init2,init0}]


plot of solutions:



Plot[Table[# &[ Apply[sol, set[[i]]]]  , {i, 1, Length[set]}] , {t, 0,tmax}, PlotRange -> {0, Automatic}]


plot of euclidean norm:



Plot[Table[Sqrt[ #.#] &[ Apply[sol, set[[i]]] ], {i, 1, Length[set]}] , {t, 0,tmax}, PlotRange -> {0, Automatic}]





share|improve this answer











$endgroup$













  • $begingroup$
    This does not answer my question for my reasons. First something like Plot[Table[Map[#[t] &, Apply[sol, set[[i]]]], {i, 2, 2}], {t, 0,tmax}] does not plot all of the second components of all the solutions. It plots all the components of the second solution. Next I meant Euclidean Norm, not some other norm (I thought it was self evident as that is the default used by Mathematica when given a vector). Playing around with your code snippet I haven't been able to get the desired result
    $endgroup$
    – AzJ
    Feb 5 at 22:00










  • $begingroup$
    My plot shows 3x3 solutions as you asked for!
    $endgroup$
    – Ulrich Neumann
    Feb 5 at 22:07










  • $begingroup$
    Sorry my terminology may have confused you. For the context of my problem as I am solving a system of ODEs one function (for example $P(t)$) is a component of the solution $(P(t),B(t),I(t))$.
    $endgroup$
    – AzJ
    Feb 5 at 22:12










  • $begingroup$
    If I have three solutions $(P_1,B_1,I_1)$,$(P_2,B_2,I_2)$,$(P_3,B_3,I_3)$ (with the difference being they start at different initial conditions), I am looking for plots of the following (as examples): $P_1,P_2,P_3$ versus time, and $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ versus time.
    $endgroup$
    – AzJ
    Feb 5 at 22:17












  • $begingroup$
    Thanks for your corrected answer
    $endgroup$
    – AzJ
    Feb 5 at 22:51














2












2








2





$begingroup$

sol = ParametricNDSolveValue[{ODEsys, {P[0] == init1, B[0] == init2,i[0] == init0}}, {P[t], B[t], i[t]}, {t, 0, tmax}, {init1, init2,init0}]


plot of solutions:



Plot[Table[# &[ Apply[sol, set[[i]]]]  , {i, 1, Length[set]}] , {t, 0,tmax}, PlotRange -> {0, Automatic}]


plot of euclidean norm:



Plot[Table[Sqrt[ #.#] &[ Apply[sol, set[[i]]] ], {i, 1, Length[set]}] , {t, 0,tmax}, PlotRange -> {0, Automatic}]





share|improve this answer











$endgroup$



sol = ParametricNDSolveValue[{ODEsys, {P[0] == init1, B[0] == init2,i[0] == init0}}, {P[t], B[t], i[t]}, {t, 0, tmax}, {init1, init2,init0}]


plot of solutions:



Plot[Table[# &[ Apply[sol, set[[i]]]]  , {i, 1, Length[set]}] , {t, 0,tmax}, PlotRange -> {0, Automatic}]


plot of euclidean norm:



Plot[Table[Sqrt[ #.#] &[ Apply[sol, set[[i]]] ], {i, 1, Length[set]}] , {t, 0,tmax}, PlotRange -> {0, Automatic}]






share|improve this answer














share|improve this answer



share|improve this answer








edited Feb 5 at 22:26

























answered Feb 5 at 20:09









Ulrich NeumannUlrich Neumann

9,406516




9,406516












  • $begingroup$
    This does not answer my question for my reasons. First something like Plot[Table[Map[#[t] &, Apply[sol, set[[i]]]], {i, 2, 2}], {t, 0,tmax}] does not plot all of the second components of all the solutions. It plots all the components of the second solution. Next I meant Euclidean Norm, not some other norm (I thought it was self evident as that is the default used by Mathematica when given a vector). Playing around with your code snippet I haven't been able to get the desired result
    $endgroup$
    – AzJ
    Feb 5 at 22:00










  • $begingroup$
    My plot shows 3x3 solutions as you asked for!
    $endgroup$
    – Ulrich Neumann
    Feb 5 at 22:07










  • $begingroup$
    Sorry my terminology may have confused you. For the context of my problem as I am solving a system of ODEs one function (for example $P(t)$) is a component of the solution $(P(t),B(t),I(t))$.
    $endgroup$
    – AzJ
    Feb 5 at 22:12










  • $begingroup$
    If I have three solutions $(P_1,B_1,I_1)$,$(P_2,B_2,I_2)$,$(P_3,B_3,I_3)$ (with the difference being they start at different initial conditions), I am looking for plots of the following (as examples): $P_1,P_2,P_3$ versus time, and $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ versus time.
    $endgroup$
    – AzJ
    Feb 5 at 22:17












  • $begingroup$
    Thanks for your corrected answer
    $endgroup$
    – AzJ
    Feb 5 at 22:51


















  • $begingroup$
    This does not answer my question for my reasons. First something like Plot[Table[Map[#[t] &, Apply[sol, set[[i]]]], {i, 2, 2}], {t, 0,tmax}] does not plot all of the second components of all the solutions. It plots all the components of the second solution. Next I meant Euclidean Norm, not some other norm (I thought it was self evident as that is the default used by Mathematica when given a vector). Playing around with your code snippet I haven't been able to get the desired result
    $endgroup$
    – AzJ
    Feb 5 at 22:00










  • $begingroup$
    My plot shows 3x3 solutions as you asked for!
    $endgroup$
    – Ulrich Neumann
    Feb 5 at 22:07










  • $begingroup$
    Sorry my terminology may have confused you. For the context of my problem as I am solving a system of ODEs one function (for example $P(t)$) is a component of the solution $(P(t),B(t),I(t))$.
    $endgroup$
    – AzJ
    Feb 5 at 22:12










  • $begingroup$
    If I have three solutions $(P_1,B_1,I_1)$,$(P_2,B_2,I_2)$,$(P_3,B_3,I_3)$ (with the difference being they start at different initial conditions), I am looking for plots of the following (as examples): $P_1,P_2,P_3$ versus time, and $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ versus time.
    $endgroup$
    – AzJ
    Feb 5 at 22:17












  • $begingroup$
    Thanks for your corrected answer
    $endgroup$
    – AzJ
    Feb 5 at 22:51
















$begingroup$
This does not answer my question for my reasons. First something like Plot[Table[Map[#[t] &, Apply[sol, set[[i]]]], {i, 2, 2}], {t, 0,tmax}] does not plot all of the second components of all the solutions. It plots all the components of the second solution. Next I meant Euclidean Norm, not some other norm (I thought it was self evident as that is the default used by Mathematica when given a vector). Playing around with your code snippet I haven't been able to get the desired result
$endgroup$
– AzJ
Feb 5 at 22:00




$begingroup$
This does not answer my question for my reasons. First something like Plot[Table[Map[#[t] &, Apply[sol, set[[i]]]], {i, 2, 2}], {t, 0,tmax}] does not plot all of the second components of all the solutions. It plots all the components of the second solution. Next I meant Euclidean Norm, not some other norm (I thought it was self evident as that is the default used by Mathematica when given a vector). Playing around with your code snippet I haven't been able to get the desired result
$endgroup$
– AzJ
Feb 5 at 22:00












$begingroup$
My plot shows 3x3 solutions as you asked for!
$endgroup$
– Ulrich Neumann
Feb 5 at 22:07




$begingroup$
My plot shows 3x3 solutions as you asked for!
$endgroup$
– Ulrich Neumann
Feb 5 at 22:07












$begingroup$
Sorry my terminology may have confused you. For the context of my problem as I am solving a system of ODEs one function (for example $P(t)$) is a component of the solution $(P(t),B(t),I(t))$.
$endgroup$
– AzJ
Feb 5 at 22:12




$begingroup$
Sorry my terminology may have confused you. For the context of my problem as I am solving a system of ODEs one function (for example $P(t)$) is a component of the solution $(P(t),B(t),I(t))$.
$endgroup$
– AzJ
Feb 5 at 22:12












$begingroup$
If I have three solutions $(P_1,B_1,I_1)$,$(P_2,B_2,I_2)$,$(P_3,B_3,I_3)$ (with the difference being they start at different initial conditions), I am looking for plots of the following (as examples): $P_1,P_2,P_3$ versus time, and $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ versus time.
$endgroup$
– AzJ
Feb 5 at 22:17






$begingroup$
If I have three solutions $(P_1,B_1,I_1)$,$(P_2,B_2,I_2)$,$(P_3,B_3,I_3)$ (with the difference being they start at different initial conditions), I am looking for plots of the following (as examples): $P_1,P_2,P_3$ versus time, and $||(P_1,B_1,I_3)||=sqrt{P_1^2+B_1^2+I_3^2}$ versus time.
$endgroup$
– AzJ
Feb 5 at 22:17














$begingroup$
Thanks for your corrected answer
$endgroup$
– AzJ
Feb 5 at 22:51




$begingroup$
Thanks for your corrected answer
$endgroup$
– AzJ
Feb 5 at 22:51


















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