How to reduce columns in dataframe pandas












7















Here how the datalooks like in df dataframe:



        A   B   C   D
0.js 2 1 1 -1
1.js 3 -5 1 -4
total 5 -4 2 -5


And I would get new dataframe df1:



        A     C
0.js 2 1
1.js 3 1
total 5 2


So basically it should look like this:
df1 = df[df["total"] > 0]
but it should filter on row instead of column and I can't figure it out..










share|improve this question




















  • 2





    Do you want to only keep the columns where the condition is met ALWAYS, even if the condition is not met once in another column.

    – Edeki Okoh
    Feb 5 at 20:26






  • 2





    Can't you transpose and do the filter?

    – Andrew Naguib
    Feb 5 at 20:27











  • Your DataFrame is just a single row?

    – ALollz
    Feb 5 at 20:30











  • not a single row

    – J Oderberg
    Feb 5 at 20:32











  • Please, add a reproducible dataframe :)

    – Andrew Naguib
    Feb 5 at 20:39
















7















Here how the datalooks like in df dataframe:



        A   B   C   D
0.js 2 1 1 -1
1.js 3 -5 1 -4
total 5 -4 2 -5


And I would get new dataframe df1:



        A     C
0.js 2 1
1.js 3 1
total 5 2


So basically it should look like this:
df1 = df[df["total"] > 0]
but it should filter on row instead of column and I can't figure it out..










share|improve this question




















  • 2





    Do you want to only keep the columns where the condition is met ALWAYS, even if the condition is not met once in another column.

    – Edeki Okoh
    Feb 5 at 20:26






  • 2





    Can't you transpose and do the filter?

    – Andrew Naguib
    Feb 5 at 20:27











  • Your DataFrame is just a single row?

    – ALollz
    Feb 5 at 20:30











  • not a single row

    – J Oderberg
    Feb 5 at 20:32











  • Please, add a reproducible dataframe :)

    – Andrew Naguib
    Feb 5 at 20:39














7












7








7


1






Here how the datalooks like in df dataframe:



        A   B   C   D
0.js 2 1 1 -1
1.js 3 -5 1 -4
total 5 -4 2 -5


And I would get new dataframe df1:



        A     C
0.js 2 1
1.js 3 1
total 5 2


So basically it should look like this:
df1 = df[df["total"] > 0]
but it should filter on row instead of column and I can't figure it out..










share|improve this question
















Here how the datalooks like in df dataframe:



        A   B   C   D
0.js 2 1 1 -1
1.js 3 -5 1 -4
total 5 -4 2 -5


And I would get new dataframe df1:



        A     C
0.js 2 1
1.js 3 1
total 5 2


So basically it should look like this:
df1 = df[df["total"] > 0]
but it should filter on row instead of column and I can't figure it out..







python pandas dataframe






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Feb 5 at 20:50









Scott Boston

56.1k73157




56.1k73157










asked Feb 5 at 20:24









J OderbergJ Oderberg

404




404








  • 2





    Do you want to only keep the columns where the condition is met ALWAYS, even if the condition is not met once in another column.

    – Edeki Okoh
    Feb 5 at 20:26






  • 2





    Can't you transpose and do the filter?

    – Andrew Naguib
    Feb 5 at 20:27











  • Your DataFrame is just a single row?

    – ALollz
    Feb 5 at 20:30











  • not a single row

    – J Oderberg
    Feb 5 at 20:32











  • Please, add a reproducible dataframe :)

    – Andrew Naguib
    Feb 5 at 20:39














  • 2





    Do you want to only keep the columns where the condition is met ALWAYS, even if the condition is not met once in another column.

    – Edeki Okoh
    Feb 5 at 20:26






  • 2





    Can't you transpose and do the filter?

    – Andrew Naguib
    Feb 5 at 20:27











  • Your DataFrame is just a single row?

    – ALollz
    Feb 5 at 20:30











  • not a single row

    – J Oderberg
    Feb 5 at 20:32











  • Please, add a reproducible dataframe :)

    – Andrew Naguib
    Feb 5 at 20:39








2




2





Do you want to only keep the columns where the condition is met ALWAYS, even if the condition is not met once in another column.

– Edeki Okoh
Feb 5 at 20:26





Do you want to only keep the columns where the condition is met ALWAYS, even if the condition is not met once in another column.

– Edeki Okoh
Feb 5 at 20:26




2




2





Can't you transpose and do the filter?

– Andrew Naguib
Feb 5 at 20:27





Can't you transpose and do the filter?

– Andrew Naguib
Feb 5 at 20:27













Your DataFrame is just a single row?

– ALollz
Feb 5 at 20:30





Your DataFrame is just a single row?

– ALollz
Feb 5 at 20:30













not a single row

– J Oderberg
Feb 5 at 20:32





not a single row

– J Oderberg
Feb 5 at 20:32













Please, add a reproducible dataframe :)

– Andrew Naguib
Feb 5 at 20:39





Please, add a reproducible dataframe :)

– Andrew Naguib
Feb 5 at 20:39












3 Answers
3






active

oldest

votes


















2














You can use, loc with boolean indexing or reindex:



df.loc[:, df.columns[(df.loc['total'] > 0)]]


OR



df.reindex(df.columns[(df.loc['total'] > 0)], axis=1)


Output:



       A  C
0.js 2 1
1.js 3 1
total 5 2





share|improve this answer































    4














    You want to use .loc[:, column_mask] i.e.



    In [11]: df.loc[:, df.sum() > 0]
    Out[11]:
    A C
    total 5 2

    # or

    In [12]: df.loc[:, df.iloc[0] > 0]
    Out[12]:
    A C
    total 5 2





    share|improve this answer































      4














      Use .where to set negative values to NaN and then dropna setting axis = 1:



      df.where(df.gt(0)).dropna(axis=1)

      A C
      total 5 2





      share|improve this answer

























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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2














        You can use, loc with boolean indexing or reindex:



        df.loc[:, df.columns[(df.loc['total'] > 0)]]


        OR



        df.reindex(df.columns[(df.loc['total'] > 0)], axis=1)


        Output:



               A  C
        0.js 2 1
        1.js 3 1
        total 5 2





        share|improve this answer




























          2














          You can use, loc with boolean indexing or reindex:



          df.loc[:, df.columns[(df.loc['total'] > 0)]]


          OR



          df.reindex(df.columns[(df.loc['total'] > 0)], axis=1)


          Output:



                 A  C
          0.js 2 1
          1.js 3 1
          total 5 2





          share|improve this answer


























            2












            2








            2







            You can use, loc with boolean indexing or reindex:



            df.loc[:, df.columns[(df.loc['total'] > 0)]]


            OR



            df.reindex(df.columns[(df.loc['total'] > 0)], axis=1)


            Output:



                   A  C
            0.js 2 1
            1.js 3 1
            total 5 2





            share|improve this answer













            You can use, loc with boolean indexing or reindex:



            df.loc[:, df.columns[(df.loc['total'] > 0)]]


            OR



            df.reindex(df.columns[(df.loc['total'] > 0)], axis=1)


            Output:



                   A  C
            0.js 2 1
            1.js 3 1
            total 5 2






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Feb 5 at 20:48









            Scott BostonScott Boston

            56.1k73157




            56.1k73157

























                4














                You want to use .loc[:, column_mask] i.e.



                In [11]: df.loc[:, df.sum() > 0]
                Out[11]:
                A C
                total 5 2

                # or

                In [12]: df.loc[:, df.iloc[0] > 0]
                Out[12]:
                A C
                total 5 2





                share|improve this answer




























                  4














                  You want to use .loc[:, column_mask] i.e.



                  In [11]: df.loc[:, df.sum() > 0]
                  Out[11]:
                  A C
                  total 5 2

                  # or

                  In [12]: df.loc[:, df.iloc[0] > 0]
                  Out[12]:
                  A C
                  total 5 2





                  share|improve this answer


























                    4












                    4








                    4







                    You want to use .loc[:, column_mask] i.e.



                    In [11]: df.loc[:, df.sum() > 0]
                    Out[11]:
                    A C
                    total 5 2

                    # or

                    In [12]: df.loc[:, df.iloc[0] > 0]
                    Out[12]:
                    A C
                    total 5 2





                    share|improve this answer













                    You want to use .loc[:, column_mask] i.e.



                    In [11]: df.loc[:, df.sum() > 0]
                    Out[11]:
                    A C
                    total 5 2

                    # or

                    In [12]: df.loc[:, df.iloc[0] > 0]
                    Out[12]:
                    A C
                    total 5 2






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Feb 5 at 20:27









                    Andy HaydenAndy Hayden

                    186k52434422




                    186k52434422























                        4














                        Use .where to set negative values to NaN and then dropna setting axis = 1:



                        df.where(df.gt(0)).dropna(axis=1)

                        A C
                        total 5 2





                        share|improve this answer






























                          4














                          Use .where to set negative values to NaN and then dropna setting axis = 1:



                          df.where(df.gt(0)).dropna(axis=1)

                          A C
                          total 5 2





                          share|improve this answer




























                            4












                            4








                            4







                            Use .where to set negative values to NaN and then dropna setting axis = 1:



                            df.where(df.gt(0)).dropna(axis=1)

                            A C
                            total 5 2





                            share|improve this answer















                            Use .where to set negative values to NaN and then dropna setting axis = 1:



                            df.where(df.gt(0)).dropna(axis=1)

                            A C
                            total 5 2






                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited Feb 5 at 20:32

























                            answered Feb 5 at 20:27









                            yatuyatu

                            12k31339




                            12k31339






























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