Distance of a point (inside) circle with arbitrary direction












0












$begingroup$


For a circle with radius $r$ centered at point $A equiv (x_a, y_a)$,



How to calculate distance CM in, a given arbitrary direction



$d equiv (d_x, d_y) leftarrow |d|_2 = 1.0 $



for a point
$C equiv (C_x, C_y)$ inside the circle and a point on the Circle $M$
(see figure below)



Distance Problem










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  • $begingroup$
    Are you given point $C$ and some angle $theta$ and need to find $M$?
    $endgroup$
    – Daniel Mathias
    Dec 28 '18 at 13:41
















0












$begingroup$


For a circle with radius $r$ centered at point $A equiv (x_a, y_a)$,



How to calculate distance CM in, a given arbitrary direction



$d equiv (d_x, d_y) leftarrow |d|_2 = 1.0 $



for a point
$C equiv (C_x, C_y)$ inside the circle and a point on the Circle $M$
(see figure below)



Distance Problem










share|cite|improve this question









$endgroup$












  • $begingroup$
    Are you given point $C$ and some angle $theta$ and need to find $M$?
    $endgroup$
    – Daniel Mathias
    Dec 28 '18 at 13:41














0












0








0





$begingroup$


For a circle with radius $r$ centered at point $A equiv (x_a, y_a)$,



How to calculate distance CM in, a given arbitrary direction



$d equiv (d_x, d_y) leftarrow |d|_2 = 1.0 $



for a point
$C equiv (C_x, C_y)$ inside the circle and a point on the Circle $M$
(see figure below)



Distance Problem










share|cite|improve this question









$endgroup$




For a circle with radius $r$ centered at point $A equiv (x_a, y_a)$,



How to calculate distance CM in, a given arbitrary direction



$d equiv (d_x, d_y) leftarrow |d|_2 = 1.0 $



for a point
$C equiv (C_x, C_y)$ inside the circle and a point on the Circle $M$
(see figure below)



Distance Problem







geometry trigonometry euclidean-geometry






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asked Dec 28 '18 at 7:14









DOOMDOOM

1848




1848












  • $begingroup$
    Are you given point $C$ and some angle $theta$ and need to find $M$?
    $endgroup$
    – Daniel Mathias
    Dec 28 '18 at 13:41


















  • $begingroup$
    Are you given point $C$ and some angle $theta$ and need to find $M$?
    $endgroup$
    – Daniel Mathias
    Dec 28 '18 at 13:41
















$begingroup$
Are you given point $C$ and some angle $theta$ and need to find $M$?
$endgroup$
– Daniel Mathias
Dec 28 '18 at 13:41




$begingroup$
Are you given point $C$ and some angle $theta$ and need to find $M$?
$endgroup$
– Daniel Mathias
Dec 28 '18 at 13:41










1 Answer
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$begingroup$

The parametric equation of line $CM$ is
$$
(x,y)=(C_x+d_x,t,C_y+d_y,t).
$$

Substitute these coordinates into the equation of the circle
$$
(x-x_a)^2+(y-y_a)^2=r^2
$$

to get the values of $t$ giving the intersections. Of course you'll get two solutions for $t$: if you want only the intersection of the circle with the ray starting at $C$ with direction $d$, then you must keep only the positive solution.






share|cite|improve this answer









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    1 Answer
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    1 Answer
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    $begingroup$

    The parametric equation of line $CM$ is
    $$
    (x,y)=(C_x+d_x,t,C_y+d_y,t).
    $$

    Substitute these coordinates into the equation of the circle
    $$
    (x-x_a)^2+(y-y_a)^2=r^2
    $$

    to get the values of $t$ giving the intersections. Of course you'll get two solutions for $t$: if you want only the intersection of the circle with the ray starting at $C$ with direction $d$, then you must keep only the positive solution.






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      The parametric equation of line $CM$ is
      $$
      (x,y)=(C_x+d_x,t,C_y+d_y,t).
      $$

      Substitute these coordinates into the equation of the circle
      $$
      (x-x_a)^2+(y-y_a)^2=r^2
      $$

      to get the values of $t$ giving the intersections. Of course you'll get two solutions for $t$: if you want only the intersection of the circle with the ray starting at $C$ with direction $d$, then you must keep only the positive solution.






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        The parametric equation of line $CM$ is
        $$
        (x,y)=(C_x+d_x,t,C_y+d_y,t).
        $$

        Substitute these coordinates into the equation of the circle
        $$
        (x-x_a)^2+(y-y_a)^2=r^2
        $$

        to get the values of $t$ giving the intersections. Of course you'll get two solutions for $t$: if you want only the intersection of the circle with the ray starting at $C$ with direction $d$, then you must keep only the positive solution.






        share|cite|improve this answer









        $endgroup$



        The parametric equation of line $CM$ is
        $$
        (x,y)=(C_x+d_x,t,C_y+d_y,t).
        $$

        Substitute these coordinates into the equation of the circle
        $$
        (x-x_a)^2+(y-y_a)^2=r^2
        $$

        to get the values of $t$ giving the intersections. Of course you'll get two solutions for $t$: if you want only the intersection of the circle with the ray starting at $C$ with direction $d$, then you must keep only the positive solution.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 28 '18 at 16:40









        AretinoAretino

        25.3k21445




        25.3k21445






























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