Closure of an open cell in a CW complex
$begingroup$
Given a CW complex $X$ and any of its cells $e$, the closure $bar{e}$ in $X$ is covered by finitely many open cells by "C". Can we prove that $bar{e}$ is exactly a union of open cells, or, $(bar{e}-e)$ a union of open cells of strictly lower dimensions? If not, is there any counterexample?
general-topology algebraic-topology
$endgroup$
add a comment |
$begingroup$
Given a CW complex $X$ and any of its cells $e$, the closure $bar{e}$ in $X$ is covered by finitely many open cells by "C". Can we prove that $bar{e}$ is exactly a union of open cells, or, $(bar{e}-e)$ a union of open cells of strictly lower dimensions? If not, is there any counterexample?
general-topology algebraic-topology
$endgroup$
add a comment |
$begingroup$
Given a CW complex $X$ and any of its cells $e$, the closure $bar{e}$ in $X$ is covered by finitely many open cells by "C". Can we prove that $bar{e}$ is exactly a union of open cells, or, $(bar{e}-e)$ a union of open cells of strictly lower dimensions? If not, is there any counterexample?
general-topology algebraic-topology
$endgroup$
Given a CW complex $X$ and any of its cells $e$, the closure $bar{e}$ in $X$ is covered by finitely many open cells by "C". Can we prove that $bar{e}$ is exactly a union of open cells, or, $(bar{e}-e)$ a union of open cells of strictly lower dimensions? If not, is there any counterexample?
general-topology algebraic-topology
general-topology algebraic-topology
asked Dec 26 '18 at 8:25
Smart YaoSmart Yao
1369
1369
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
In general $overline e$ won't be a union of open cells.
Simple example. One $0$-cell $e_0$, one $1$-cell $e_1$
and one $2$-cell $e_2$. Attach $e_1$ to $e_0$ making an $S^1$. Now attach $e_2$
to this $S_1$ by mapping the boundary of the unit disc to a point $P$ on $S^1$ that
isn't $e_0$. Then $overline{e_2}=e_2cup{P}$ and that isn't a union of
open cells.
$endgroup$
$begingroup$
Does it imply the so-called $delta$-complex if the condition in the question is imposed?
$endgroup$
– Smart Yao
Jan 5 at 1:00
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3052741%2fclosure-of-an-open-cell-in-a-cw-complex%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
In general $overline e$ won't be a union of open cells.
Simple example. One $0$-cell $e_0$, one $1$-cell $e_1$
and one $2$-cell $e_2$. Attach $e_1$ to $e_0$ making an $S^1$. Now attach $e_2$
to this $S_1$ by mapping the boundary of the unit disc to a point $P$ on $S^1$ that
isn't $e_0$. Then $overline{e_2}=e_2cup{P}$ and that isn't a union of
open cells.
$endgroup$
$begingroup$
Does it imply the so-called $delta$-complex if the condition in the question is imposed?
$endgroup$
– Smart Yao
Jan 5 at 1:00
add a comment |
$begingroup$
In general $overline e$ won't be a union of open cells.
Simple example. One $0$-cell $e_0$, one $1$-cell $e_1$
and one $2$-cell $e_2$. Attach $e_1$ to $e_0$ making an $S^1$. Now attach $e_2$
to this $S_1$ by mapping the boundary of the unit disc to a point $P$ on $S^1$ that
isn't $e_0$. Then $overline{e_2}=e_2cup{P}$ and that isn't a union of
open cells.
$endgroup$
$begingroup$
Does it imply the so-called $delta$-complex if the condition in the question is imposed?
$endgroup$
– Smart Yao
Jan 5 at 1:00
add a comment |
$begingroup$
In general $overline e$ won't be a union of open cells.
Simple example. One $0$-cell $e_0$, one $1$-cell $e_1$
and one $2$-cell $e_2$. Attach $e_1$ to $e_0$ making an $S^1$. Now attach $e_2$
to this $S_1$ by mapping the boundary of the unit disc to a point $P$ on $S^1$ that
isn't $e_0$. Then $overline{e_2}=e_2cup{P}$ and that isn't a union of
open cells.
$endgroup$
In general $overline e$ won't be a union of open cells.
Simple example. One $0$-cell $e_0$, one $1$-cell $e_1$
and one $2$-cell $e_2$. Attach $e_1$ to $e_0$ making an $S^1$. Now attach $e_2$
to this $S_1$ by mapping the boundary of the unit disc to a point $P$ on $S^1$ that
isn't $e_0$. Then $overline{e_2}=e_2cup{P}$ and that isn't a union of
open cells.
edited Dec 26 '18 at 8:42
answered Dec 26 '18 at 8:30
Lord Shark the UnknownLord Shark the Unknown
106k1161133
106k1161133
$begingroup$
Does it imply the so-called $delta$-complex if the condition in the question is imposed?
$endgroup$
– Smart Yao
Jan 5 at 1:00
add a comment |
$begingroup$
Does it imply the so-called $delta$-complex if the condition in the question is imposed?
$endgroup$
– Smart Yao
Jan 5 at 1:00
$begingroup$
Does it imply the so-called $delta$-complex if the condition in the question is imposed?
$endgroup$
– Smart Yao
Jan 5 at 1:00
$begingroup$
Does it imply the so-called $delta$-complex if the condition in the question is imposed?
$endgroup$
– Smart Yao
Jan 5 at 1:00
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3052741%2fclosure-of-an-open-cell-in-a-cw-complex%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown