Bash script to detect empty message string. Getting: too many arguments












1















I have a bash script where I can pipe in output from another application into the below script. But I think I have an incorrect logic for testing if the message is empty or not. If its empty I want it to do nothing, but if it detects the word "error" in the string, it should run another function.



What am I doing wrong in my logic?



I'm getting too many arguments on the 3rd to the last line, most likely due to the message being empty.



message=$( cat )

if [ -n "${message// /}" ]; then
#execute if the the variable is not empty and contains non space characters
message="``` ${message} ```"
else
#execute if the variable is empty or contains only spaces
message=""
fi

sendX() {
.....
}

if [ -z "$message" ]; then
echo "Please pipe a message to me!"
else
sendX
fi

sendAlert() {
......
}

checkword="error"

echo $message

if [ $message =~ $checkword ]; then <---- Error: too many arguments
sendY
fi









share|improve this question



























    1















    I have a bash script where I can pipe in output from another application into the below script. But I think I have an incorrect logic for testing if the message is empty or not. If its empty I want it to do nothing, but if it detects the word "error" in the string, it should run another function.



    What am I doing wrong in my logic?



    I'm getting too many arguments on the 3rd to the last line, most likely due to the message being empty.



    message=$( cat )

    if [ -n "${message// /}" ]; then
    #execute if the the variable is not empty and contains non space characters
    message="``` ${message} ```"
    else
    #execute if the variable is empty or contains only spaces
    message=""
    fi

    sendX() {
    .....
    }

    if [ -z "$message" ]; then
    echo "Please pipe a message to me!"
    else
    sendX
    fi

    sendAlert() {
    ......
    }

    checkword="error"

    echo $message

    if [ $message =~ $checkword ]; then <---- Error: too many arguments
    sendY
    fi









    share|improve this question

























      1












      1








      1








      I have a bash script where I can pipe in output from another application into the below script. But I think I have an incorrect logic for testing if the message is empty or not. If its empty I want it to do nothing, but if it detects the word "error" in the string, it should run another function.



      What am I doing wrong in my logic?



      I'm getting too many arguments on the 3rd to the last line, most likely due to the message being empty.



      message=$( cat )

      if [ -n "${message// /}" ]; then
      #execute if the the variable is not empty and contains non space characters
      message="``` ${message} ```"
      else
      #execute if the variable is empty or contains only spaces
      message=""
      fi

      sendX() {
      .....
      }

      if [ -z "$message" ]; then
      echo "Please pipe a message to me!"
      else
      sendX
      fi

      sendAlert() {
      ......
      }

      checkword="error"

      echo $message

      if [ $message =~ $checkword ]; then <---- Error: too many arguments
      sendY
      fi









      share|improve this question














      I have a bash script where I can pipe in output from another application into the below script. But I think I have an incorrect logic for testing if the message is empty or not. If its empty I want it to do nothing, but if it detects the word "error" in the string, it should run another function.



      What am I doing wrong in my logic?



      I'm getting too many arguments on the 3rd to the last line, most likely due to the message being empty.



      message=$( cat )

      if [ -n "${message// /}" ]; then
      #execute if the the variable is not empty and contains non space characters
      message="``` ${message} ```"
      else
      #execute if the variable is empty or contains only spaces
      message=""
      fi

      sendX() {
      .....
      }

      if [ -z "$message" ]; then
      echo "Please pipe a message to me!"
      else
      sendX
      fi

      sendAlert() {
      ......
      }

      checkword="error"

      echo $message

      if [ $message =~ $checkword ]; then <---- Error: too many arguments
      sendY
      fi






      bash shell-script






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Feb 13 at 22:36









      Patoshi パトシPatoshi パトシ

      56341322




      56341322






















          1 Answer
          1






          active

          oldest

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          4














          You're getting a "too many arguments" error since [ ... ] does not understand the =~ operator (used in bash for regular expression matching). Since [ ... ] does not understand the operator, it is treated as a string. You then have [ ... ] with three strings inside it, and they don't fulfil the semantic requirements for a proper test, which is why bash errors out at this point.



          In bash, you would use =~ inside of [[ ... ]].



          However, what I assume you'd like to do in that test is to see whether $message contains $checkword as a substring. This could also be done with



          [[ "$message" == *"$checkword"* ]] && sendY


          or with case ... esac:



          case $message in
          *"$checkword"*) sendY
          esac


          This way you don't have to worry about $checkword containing characters that may be special in regular expressions.



          You also need to double quote $message in echo $message, or you may get unexpected output if $message contains filename globbing characters like *.



          Related:




          • Bash - If Syntax confusion

          • What is the difference between the Bash operators [[ vs [ vs ( vs ((?

          • When is double-quoting necessary?


          • Why is printf better than echo? (because it would be better to use printf '%sn' "$message" than echo "$message" for user-supplied data)


          • https://www.shellcheck.net/ (which would have picked up these issues and possibly others, like missing a proper #!-line)




          You could also use this instead of the first operation in the script:



          case $message in
          *[! ]*) # contains non-space
          message='``` '"$message"' ```' ;;
          *) # contains nothing or only spaces
          message=
          esac


          Using case ... esac in both places would make your script (at least the bits that you have shown) portable to any sh-like shell.






          share|improve this answer

























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4














            You're getting a "too many arguments" error since [ ... ] does not understand the =~ operator (used in bash for regular expression matching). Since [ ... ] does not understand the operator, it is treated as a string. You then have [ ... ] with three strings inside it, and they don't fulfil the semantic requirements for a proper test, which is why bash errors out at this point.



            In bash, you would use =~ inside of [[ ... ]].



            However, what I assume you'd like to do in that test is to see whether $message contains $checkword as a substring. This could also be done with



            [[ "$message" == *"$checkword"* ]] && sendY


            or with case ... esac:



            case $message in
            *"$checkword"*) sendY
            esac


            This way you don't have to worry about $checkword containing characters that may be special in regular expressions.



            You also need to double quote $message in echo $message, or you may get unexpected output if $message contains filename globbing characters like *.



            Related:




            • Bash - If Syntax confusion

            • What is the difference between the Bash operators [[ vs [ vs ( vs ((?

            • When is double-quoting necessary?


            • Why is printf better than echo? (because it would be better to use printf '%sn' "$message" than echo "$message" for user-supplied data)


            • https://www.shellcheck.net/ (which would have picked up these issues and possibly others, like missing a proper #!-line)




            You could also use this instead of the first operation in the script:



            case $message in
            *[! ]*) # contains non-space
            message='``` '"$message"' ```' ;;
            *) # contains nothing or only spaces
            message=
            esac


            Using case ... esac in both places would make your script (at least the bits that you have shown) portable to any sh-like shell.






            share|improve this answer






























              4














              You're getting a "too many arguments" error since [ ... ] does not understand the =~ operator (used in bash for regular expression matching). Since [ ... ] does not understand the operator, it is treated as a string. You then have [ ... ] with three strings inside it, and they don't fulfil the semantic requirements for a proper test, which is why bash errors out at this point.



              In bash, you would use =~ inside of [[ ... ]].



              However, what I assume you'd like to do in that test is to see whether $message contains $checkword as a substring. This could also be done with



              [[ "$message" == *"$checkword"* ]] && sendY


              or with case ... esac:



              case $message in
              *"$checkword"*) sendY
              esac


              This way you don't have to worry about $checkword containing characters that may be special in regular expressions.



              You also need to double quote $message in echo $message, or you may get unexpected output if $message contains filename globbing characters like *.



              Related:




              • Bash - If Syntax confusion

              • What is the difference between the Bash operators [[ vs [ vs ( vs ((?

              • When is double-quoting necessary?


              • Why is printf better than echo? (because it would be better to use printf '%sn' "$message" than echo "$message" for user-supplied data)


              • https://www.shellcheck.net/ (which would have picked up these issues and possibly others, like missing a proper #!-line)




              You could also use this instead of the first operation in the script:



              case $message in
              *[! ]*) # contains non-space
              message='``` '"$message"' ```' ;;
              *) # contains nothing or only spaces
              message=
              esac


              Using case ... esac in both places would make your script (at least the bits that you have shown) portable to any sh-like shell.






              share|improve this answer




























                4












                4








                4







                You're getting a "too many arguments" error since [ ... ] does not understand the =~ operator (used in bash for regular expression matching). Since [ ... ] does not understand the operator, it is treated as a string. You then have [ ... ] with three strings inside it, and they don't fulfil the semantic requirements for a proper test, which is why bash errors out at this point.



                In bash, you would use =~ inside of [[ ... ]].



                However, what I assume you'd like to do in that test is to see whether $message contains $checkword as a substring. This could also be done with



                [[ "$message" == *"$checkword"* ]] && sendY


                or with case ... esac:



                case $message in
                *"$checkword"*) sendY
                esac


                This way you don't have to worry about $checkword containing characters that may be special in regular expressions.



                You also need to double quote $message in echo $message, or you may get unexpected output if $message contains filename globbing characters like *.



                Related:




                • Bash - If Syntax confusion

                • What is the difference between the Bash operators [[ vs [ vs ( vs ((?

                • When is double-quoting necessary?


                • Why is printf better than echo? (because it would be better to use printf '%sn' "$message" than echo "$message" for user-supplied data)


                • https://www.shellcheck.net/ (which would have picked up these issues and possibly others, like missing a proper #!-line)




                You could also use this instead of the first operation in the script:



                case $message in
                *[! ]*) # contains non-space
                message='``` '"$message"' ```' ;;
                *) # contains nothing or only spaces
                message=
                esac


                Using case ... esac in both places would make your script (at least the bits that you have shown) portable to any sh-like shell.






                share|improve this answer















                You're getting a "too many arguments" error since [ ... ] does not understand the =~ operator (used in bash for regular expression matching). Since [ ... ] does not understand the operator, it is treated as a string. You then have [ ... ] with three strings inside it, and they don't fulfil the semantic requirements for a proper test, which is why bash errors out at this point.



                In bash, you would use =~ inside of [[ ... ]].



                However, what I assume you'd like to do in that test is to see whether $message contains $checkword as a substring. This could also be done with



                [[ "$message" == *"$checkword"* ]] && sendY


                or with case ... esac:



                case $message in
                *"$checkword"*) sendY
                esac


                This way you don't have to worry about $checkword containing characters that may be special in regular expressions.



                You also need to double quote $message in echo $message, or you may get unexpected output if $message contains filename globbing characters like *.



                Related:




                • Bash - If Syntax confusion

                • What is the difference between the Bash operators [[ vs [ vs ( vs ((?

                • When is double-quoting necessary?


                • Why is printf better than echo? (because it would be better to use printf '%sn' "$message" than echo "$message" for user-supplied data)


                • https://www.shellcheck.net/ (which would have picked up these issues and possibly others, like missing a proper #!-line)




                You could also use this instead of the first operation in the script:



                case $message in
                *[! ]*) # contains non-space
                message='``` '"$message"' ```' ;;
                *) # contains nothing or only spaces
                message=
                esac


                Using case ... esac in both places would make your script (at least the bits that you have shown) portable to any sh-like shell.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Feb 14 at 10:20

























                answered Feb 13 at 23:13









                KusalanandaKusalananda

                135k17255423




                135k17255423






























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