(a) Calculate the correlation between X and Y, Corr(X,Y).












0












$begingroup$


Suppose X and Y are random variables, such that



$$E(X)=5, E(Y)=3, E(X^2)=26, E(Y^2)=13, E(XY)=10$$



We used the equation enter image description here



and got



$$r=frac{10n -(5*3)}{sqrt{[26n-26][13n-13]}}$$



we not sure what n is. any help?










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$endgroup$








  • 1




    $begingroup$
    You are using the formula for sample correlation coefficient, which is a different (though somewhat related) idea.
    $endgroup$
    – André Nicolas
    May 1 '16 at 15:04
















0












$begingroup$


Suppose X and Y are random variables, such that



$$E(X)=5, E(Y)=3, E(X^2)=26, E(Y^2)=13, E(XY)=10$$



We used the equation enter image description here



and got



$$r=frac{10n -(5*3)}{sqrt{[26n-26][13n-13]}}$$



we not sure what n is. any help?










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    You are using the formula for sample correlation coefficient, which is a different (though somewhat related) idea.
    $endgroup$
    – André Nicolas
    May 1 '16 at 15:04














0












0








0





$begingroup$


Suppose X and Y are random variables, such that



$$E(X)=5, E(Y)=3, E(X^2)=26, E(Y^2)=13, E(XY)=10$$



We used the equation enter image description here



and got



$$r=frac{10n -(5*3)}{sqrt{[26n-26][13n-13]}}$$



we not sure what n is. any help?










share|cite|improve this question











$endgroup$




Suppose X and Y are random variables, such that



$$E(X)=5, E(Y)=3, E(X^2)=26, E(Y^2)=13, E(XY)=10$$



We used the equation enter image description here



and got



$$r=frac{10n -(5*3)}{sqrt{[26n-26][13n-13]}}$$



we not sure what n is. any help?







probability correlation






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share|cite|improve this question













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edited May 1 '16 at 15:39







user198044

















asked May 1 '16 at 14:58









k_jana16k_jana16

64




64








  • 1




    $begingroup$
    You are using the formula for sample correlation coefficient, which is a different (though somewhat related) idea.
    $endgroup$
    – André Nicolas
    May 1 '16 at 15:04














  • 1




    $begingroup$
    You are using the formula for sample correlation coefficient, which is a different (though somewhat related) idea.
    $endgroup$
    – André Nicolas
    May 1 '16 at 15:04








1




1




$begingroup$
You are using the formula for sample correlation coefficient, which is a different (though somewhat related) idea.
$endgroup$
– André Nicolas
May 1 '16 at 15:04




$begingroup$
You are using the formula for sample correlation coefficient, which is a different (though somewhat related) idea.
$endgroup$
– André Nicolas
May 1 '16 at 15:04










1 Answer
1






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0












$begingroup$

$Cor(X,Y)=dfrac{E(XY)-E(X)E(Y)}{sqrt{(E(X^2)-(E(X))^2)(E(Y^2)-(E(Y))^2)}}$



Now plug in the values.






share|cite|improve this answer









$endgroup$









  • 1




    $begingroup$
    thank you. i used the wrong equation
    $endgroup$
    – k_jana16
    May 1 '16 at 15:03













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1 Answer
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1 Answer
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0












$begingroup$

$Cor(X,Y)=dfrac{E(XY)-E(X)E(Y)}{sqrt{(E(X^2)-(E(X))^2)(E(Y^2)-(E(Y))^2)}}$



Now plug in the values.






share|cite|improve this answer









$endgroup$









  • 1




    $begingroup$
    thank you. i used the wrong equation
    $endgroup$
    – k_jana16
    May 1 '16 at 15:03


















0












$begingroup$

$Cor(X,Y)=dfrac{E(XY)-E(X)E(Y)}{sqrt{(E(X^2)-(E(X))^2)(E(Y^2)-(E(Y))^2)}}$



Now plug in the values.






share|cite|improve this answer









$endgroup$









  • 1




    $begingroup$
    thank you. i used the wrong equation
    $endgroup$
    – k_jana16
    May 1 '16 at 15:03
















0












0








0





$begingroup$

$Cor(X,Y)=dfrac{E(XY)-E(X)E(Y)}{sqrt{(E(X^2)-(E(X))^2)(E(Y^2)-(E(Y))^2)}}$



Now plug in the values.






share|cite|improve this answer









$endgroup$



$Cor(X,Y)=dfrac{E(XY)-E(X)E(Y)}{sqrt{(E(X^2)-(E(X))^2)(E(Y^2)-(E(Y))^2)}}$



Now plug in the values.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered May 1 '16 at 15:01









Landon CarterLandon Carter

7,45311644




7,45311644








  • 1




    $begingroup$
    thank you. i used the wrong equation
    $endgroup$
    – k_jana16
    May 1 '16 at 15:03
















  • 1




    $begingroup$
    thank you. i used the wrong equation
    $endgroup$
    – k_jana16
    May 1 '16 at 15:03










1




1




$begingroup$
thank you. i used the wrong equation
$endgroup$
– k_jana16
May 1 '16 at 15:03






$begingroup$
thank you. i used the wrong equation
$endgroup$
– k_jana16
May 1 '16 at 15:03




















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