Summation with power












0












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Please help me with the below Summation



$sum_{r=0}^{infty}2^r times n^{frac{1}{2^r}}$



While solving problem based on finding time complexity, I came upto this expression. I am unable to move further. Please help.










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$endgroup$

















    0












    $begingroup$


    Please help me with the below Summation



    $sum_{r=0}^{infty}2^r times n^{frac{1}{2^r}}$



    While solving problem based on finding time complexity, I came upto this expression. I am unable to move further. Please help.










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      Please help me with the below Summation



      $sum_{r=0}^{infty}2^r times n^{frac{1}{2^r}}$



      While solving problem based on finding time complexity, I came upto this expression. I am unable to move further. Please help.










      share|cite|improve this question









      $endgroup$




      Please help me with the below Summation



      $sum_{r=0}^{infty}2^r times n^{frac{1}{2^r}}$



      While solving problem based on finding time complexity, I came upto this expression. I am unable to move further. Please help.







      summation






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      share|cite|improve this question










      asked Jan 1 at 8:53









      user3767495user3767495

      4028




      4028






















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          $begingroup$

          The infinite sum doesn’t converge:



          $$lim_{r to infty} 2^rn^{frac{1}{2r}} = lim_{r to infty} 2^r(1) = +infty$$






          share|cite|improve this answer









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            1 Answer
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            active

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            active

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            active

            oldest

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            1












            $begingroup$

            The infinite sum doesn’t converge:



            $$lim_{r to infty} 2^rn^{frac{1}{2r}} = lim_{r to infty} 2^r(1) = +infty$$






            share|cite|improve this answer









            $endgroup$


















              1












              $begingroup$

              The infinite sum doesn’t converge:



              $$lim_{r to infty} 2^rn^{frac{1}{2r}} = lim_{r to infty} 2^r(1) = +infty$$






              share|cite|improve this answer









              $endgroup$
















                1












                1








                1





                $begingroup$

                The infinite sum doesn’t converge:



                $$lim_{r to infty} 2^rn^{frac{1}{2r}} = lim_{r to infty} 2^r(1) = +infty$$






                share|cite|improve this answer









                $endgroup$



                The infinite sum doesn’t converge:



                $$lim_{r to infty} 2^rn^{frac{1}{2r}} = lim_{r to infty} 2^r(1) = +infty$$







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Jan 1 at 9:06









                KM101KM101

                6,0801525




                6,0801525






























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