Regex find a comma between two strings
I'm trying to remove commas from a certain place within a text file. The input looks like this:
Y=6","~2807-1 Q12m. Plate(s), screw(s), rod(s) or pin(s) in any bone - NO"
I only want to remove the commas between the "Y=6","" and the ending double quote. If I use
(?<=Y=d",").*(?=")
I can isolate the part between those but can't for the life of me figure out how to just get the commas.
regex
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I'm trying to remove commas from a certain place within a text file. The input looks like this:
Y=6","~2807-1 Q12m. Plate(s), screw(s), rod(s) or pin(s) in any bone - NO"
I only want to remove the commas between the "Y=6","" and the ending double quote. If I use
(?<=Y=d",").*(?=")
I can isolate the part between those but can't for the life of me figure out how to just get the commas.
regex
add a comment |
I'm trying to remove commas from a certain place within a text file. The input looks like this:
Y=6","~2807-1 Q12m. Plate(s), screw(s), rod(s) or pin(s) in any bone - NO"
I only want to remove the commas between the "Y=6","" and the ending double quote. If I use
(?<=Y=d",").*(?=")
I can isolate the part between those but can't for the life of me figure out how to just get the commas.
regex
I'm trying to remove commas from a certain place within a text file. The input looks like this:
Y=6","~2807-1 Q12m. Plate(s), screw(s), rod(s) or pin(s) in any bone - NO"
I only want to remove the commas between the "Y=6","" and the ending double quote. If I use
(?<=Y=d",").*(?=")
I can isolate the part between those but can't for the life of me figure out how to just get the commas.
regex
regex
asked Jan 30 at 15:25
ScottPScottP
11
11
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1 Answer
1
active
oldest
votes
- Find:
(?:Y=d","|G)[^,"]*K,
- Replace:
NOTHING
Demo
Explanation:
(?: # start non capture group
Y=d # literally Y= followed by 1 digit. You may want to use d+ for 1 or more digits
"," # literally ","
| # OR
G # restart form last match position
) # end group
[^,"]* # 0 or more any character that is not comma or double quote
K # forget all we have seen until this position
, # a comma
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
- Find:
(?:Y=d","|G)[^,"]*K,
- Replace:
NOTHING
Demo
Explanation:
(?: # start non capture group
Y=d # literally Y= followed by 1 digit. You may want to use d+ for 1 or more digits
"," # literally ","
| # OR
G # restart form last match position
) # end group
[^,"]* # 0 or more any character that is not comma or double quote
K # forget all we have seen until this position
, # a comma
add a comment |
- Find:
(?:Y=d","|G)[^,"]*K,
- Replace:
NOTHING
Demo
Explanation:
(?: # start non capture group
Y=d # literally Y= followed by 1 digit. You may want to use d+ for 1 or more digits
"," # literally ","
| # OR
G # restart form last match position
) # end group
[^,"]* # 0 or more any character that is not comma or double quote
K # forget all we have seen until this position
, # a comma
add a comment |
- Find:
(?:Y=d","|G)[^,"]*K,
- Replace:
NOTHING
Demo
Explanation:
(?: # start non capture group
Y=d # literally Y= followed by 1 digit. You may want to use d+ for 1 or more digits
"," # literally ","
| # OR
G # restart form last match position
) # end group
[^,"]* # 0 or more any character that is not comma or double quote
K # forget all we have seen until this position
, # a comma
- Find:
(?:Y=d","|G)[^,"]*K,
- Replace:
NOTHING
Demo
Explanation:
(?: # start non capture group
Y=d # literally Y= followed by 1 digit. You may want to use d+ for 1 or more digits
"," # literally ","
| # OR
G # restart form last match position
) # end group
[^,"]* # 0 or more any character that is not comma or double quote
K # forget all we have seen until this position
, # a comma
answered Jan 30 at 16:23
TotoToto
3,822101226
3,822101226
add a comment |
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