How to find out which pole goes to which infinity zero in root locus
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Branches are colored in MATLAB's rlocus function. How can it be easily determined, without using a software, that which pole-zero are at the both ends of a branch? For example, in the following transfer function,
$G(s)H(s)=dfrac{K}{s(s+1)(s^2+4s+13)}$
the result with MATLAB would be
enter image description here
Why don't the branches that start at complex poles go towards the right hand infinity zeros, and branches that start at real poles go to the left hand ones?
linear-algebra control-theory
asked Dec 17 '18 at 12:28
Hossein AbbasiHossein Abbasi
11
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add a comment |
$begingroup$
Branches are colored in MATLAB's rlocus function. How can it be easily determined, without using a software, that which pole-zero are at the both ends of a branch? For example, in the following transfer function,
$G(s)H(s)=dfrac{K}{s(s+1)(s^2+4s+13)}$
the result with MATLAB would be
enter image description here
Why don't the branches that start at complex poles go towards the right hand infinity zeros, and branches that start at real poles go to the left hand ones?
linear-algebra control-theory
asked Dec 17 '18 at 12:28
Hossein AbbasiHossein Abbasi
11
$endgroup$
$begingroup$
What do you mean by right hand infinity zero?
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– Felix Crazzolara
Jan 10 at 23:03
add a comment |
$begingroup$
Branches are colored in MATLAB's rlocus function. How can it be easily determined, without using a software, that which pole-zero are at the both ends of a branch? For example, in the following transfer function,
$G(s)H(s)=dfrac{K}{s(s+1)(s^2+4s+13)}$
the result with MATLAB would be
enter image description here
Why don't the branches that start at complex poles go towards the right hand infinity zeros, and branches that start at real poles go to the left hand ones?
linear-algebra control-theory
asked Dec 17 '18 at 12:28
Hossein AbbasiHossein Abbasi
11
$endgroup$
Branches are colored in MATLAB's rlocus function. How can it be easily determined, without using a software, that which pole-zero are at the both ends of a branch? For example, in the following transfer function,
$G(s)H(s)=dfrac{K}{s(s+1)(s^2+4s+13)}$
the result with MATLAB would be
enter image description here
Why don't the branches that start at complex poles go towards the right hand infinity zeros, and branches that start at real poles go to the left hand ones?
linear-algebra control-theory
linear-algebra control-theory
asked Dec 17 '18 at 12:28
Hossein AbbasiHossein Abbasi
11
asked Dec 17 '18 at 12:28
Hossein AbbasiHossein Abbasi
11
asked Dec 17 '18 at 12:28
Hossein AbbasiHossein Abbasi
11
asked Dec 17 '18 at 12:28
Hossein AbbasiHossein Abbasi
11
asked Dec 17 '18 at 12:28
Hossein AbbasiHossein Abbasi
11
11
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What do you mean by right hand infinity zero?
$endgroup$
– Felix Crazzolara
Jan 10 at 23:03
add a comment |
$begingroup$
What do you mean by right hand infinity zero?
$endgroup$
– Felix Crazzolara
Jan 10 at 23:03
$begingroup$
What do you mean by right hand infinity zero?
$endgroup$
– Felix Crazzolara
Jan 10 at 23:03
$begingroup$
What do you mean by right hand infinity zero?
$endgroup$
– Felix Crazzolara
Jan 10 at 23:03
add a comment |
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$begingroup$
What do you mean by right hand infinity zero?
$endgroup$
– Felix Crazzolara
Jan 10 at 23:03