Determine odds for a series of rolls of dice [duplicate]












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This question is an exact duplicate of:




  • question on probability of roll of one dice



If you have one die, lets say in 6 continuous rolls you roll the following:



3....3....6......2.....1....4



What is the possibility that after you roll the next 3....



That the following rolls would be.....



3......6......2......1......4. In that exact order for the following 5 rolls?



I don't think thus is too difficult a question but I don't have the knowledge to answer it.






probability dice







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marked as duplicate by GNUSupporter 8964民主女神 地下教會, N. F. Taussig, Masacroso, NCh, Lord_Farin Dec 19 '18 at 18:22


This question was marked as an exact duplicate of an existing question.


















  • $begingroup$
    What is the probability that the next roll is $3?$ That the next two rolls are $3,6$ in that order? And so on.
    $endgroup$
    – saulspatz
    Dec 17 '18 at 15:25
















0












$begingroup$



This question is an exact duplicate of:




  • question on probability of roll of one dice



If you have one die, lets say in 6 continuous rolls you roll the following:



3....3....6......2.....1....4



What is the possibility that after you roll the next 3....



That the following rolls would be.....



3......6......2......1......4. In that exact order for the following 5 rolls?



I don't think thus is too difficult a question but I don't have the knowledge to answer it.






probability dice







share|cite|improve this question











$endgroup$



marked as duplicate by GNUSupporter 8964民主女神 地下教會, N. F. Taussig, Masacroso, NCh, Lord_Farin Dec 19 '18 at 18:22


This question was marked as an exact duplicate of an existing question.


















  • $begingroup$
    What is the probability that the next roll is $3?$ That the next two rolls are $3,6$ in that order? And so on.
    $endgroup$
    – saulspatz
    Dec 17 '18 at 15:25














0












0








0





$begingroup$



This question is an exact duplicate of:




  • question on probability of roll of one dice



If you have one die, lets say in 6 continuous rolls you roll the following:



3....3....6......2.....1....4



What is the possibility that after you roll the next 3....



That the following rolls would be.....



3......6......2......1......4. In that exact order for the following 5 rolls?



I don't think thus is too difficult a question but I don't have the knowledge to answer it.






probability dice







share|cite|improve this question











$endgroup$





This question is an exact duplicate of:




  • question on probability of roll of one dice



If you have one die, lets say in 6 continuous rolls you roll the following:



3....3....6......2.....1....4



What is the possibility that after you roll the next 3....



That the following rolls would be.....



3......6......2......1......4. In that exact order for the following 5 rolls?



I don't think thus is too difficult a question but I don't have the knowledge to answer it.





This question is an exact duplicate of:




  • question on probability of roll of one dice






probability dice




probability dice






share|cite|improve this question















share|cite|improve this question













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share|cite|improve this question








edited Dec 17 '18 at 14:06









David G. Stork

11k41432




11k41432










asked Dec 17 '18 at 13:55









Steven SpeckSteven Speck

61




61




marked as duplicate by GNUSupporter 8964民主女神 地下教會, N. F. Taussig, Masacroso, NCh, Lord_Farin Dec 19 '18 at 18:22


This question was marked as an exact duplicate of an existing question.









marked as duplicate by GNUSupporter 8964民主女神 地下教會, N. F. Taussig, Masacroso, NCh, Lord_Farin Dec 19 '18 at 18:22


This question was marked as an exact duplicate of an existing question.














  • $begingroup$
    What is the probability that the next roll is $3?$ That the next two rolls are $3,6$ in that order? And so on.
    $endgroup$
    – saulspatz
    Dec 17 '18 at 15:25


















  • $begingroup$
    What is the probability that the next roll is $3?$ That the next two rolls are $3,6$ in that order? And so on.
    $endgroup$
    – saulspatz
    Dec 17 '18 at 15:25
















$begingroup$
What is the probability that the next roll is $3?$ That the next two rolls are $3,6$ in that order? And so on.
$endgroup$
– saulspatz
Dec 17 '18 at 15:25




$begingroup$
What is the probability that the next roll is $3?$ That the next two rolls are $3,6$ in that order? And so on.
$endgroup$
– saulspatz
Dec 17 '18 at 15:25










1 Answer
1






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0












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Each roll takes a value from the set ${1,2,;...,6}$, independent of past or future rolls. So the probability of seeing any sequence of 5 rolls is $left( frac{1}{6} right)^5$, regardless of what the sequence might be.






share|cite|improve this answer









$endgroup$




















    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0












    $begingroup$

    Each roll takes a value from the set ${1,2,;...,6}$, independent of past or future rolls. So the probability of seeing any sequence of 5 rolls is $left( frac{1}{6} right)^5$, regardless of what the sequence might be.






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      Each roll takes a value from the set ${1,2,;...,6}$, independent of past or future rolls. So the probability of seeing any sequence of 5 rolls is $left( frac{1}{6} right)^5$, regardless of what the sequence might be.






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        Each roll takes a value from the set ${1,2,;...,6}$, independent of past or future rolls. So the probability of seeing any sequence of 5 rolls is $left( frac{1}{6} right)^5$, regardless of what the sequence might be.






        share|cite|improve this answer









        $endgroup$



        Each roll takes a value from the set ${1,2,;...,6}$, independent of past or future rolls. So the probability of seeing any sequence of 5 rolls is $left( frac{1}{6} right)^5$, regardless of what the sequence might be.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 17 '18 at 21:56









        Aditya DuaAditya Dua

        1,18418




        1,18418















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