Find the eigenvalue and eigenvector
$begingroup$
Can someone give me some guidance on how to obtain the eigenvalue and eigenvector for the following equation? Don't I need another equation?
$EIu_{yy}+pu=0$ where $lambda=frac{p}{EI}$
ordinary-differential-equations eigenvalues-eigenvectors
asked Dec 14 '18 at 9:37
carlosremovecarlosremove
253
$endgroup$
add a comment |
$begingroup$
Can someone give me some guidance on how to obtain the eigenvalue and eigenvector for the following equation? Don't I need another equation?
$EIu_{yy}+pu=0$ where $lambda=frac{p}{EI}$
ordinary-differential-equations eigenvalues-eigenvectors
asked Dec 14 '18 at 9:37
carlosremovecarlosremove
253
$endgroup$
$begingroup$
$lambda$ does not appear in the equation? Also, you would need some boundary conditions.
$endgroup$
– Roberto Rastapopoulos
Dec 14 '18 at 9:38
add a comment |
$begingroup$
Can someone give me some guidance on how to obtain the eigenvalue and eigenvector for the following equation? Don't I need another equation?
$EIu_{yy}+pu=0$ where $lambda=frac{p}{EI}$
ordinary-differential-equations eigenvalues-eigenvectors
asked Dec 14 '18 at 9:37
carlosremovecarlosremove
253
$endgroup$
Can someone give me some guidance on how to obtain the eigenvalue and eigenvector for the following equation? Don't I need another equation?
$EIu_{yy}+pu=0$ where $lambda=frac{p}{EI}$
ordinary-differential-equations eigenvalues-eigenvectors
ordinary-differential-equations eigenvalues-eigenvectors
asked Dec 14 '18 at 9:37
carlosremovecarlosremove
253
asked Dec 14 '18 at 9:37
carlosremovecarlosremove
253
asked Dec 14 '18 at 9:37
carlosremovecarlosremove
253
asked Dec 14 '18 at 9:37
carlosremovecarlosremove
253
asked Dec 14 '18 at 9:37
carlosremovecarlosremove
253
253
$begingroup$
$lambda$ does not appear in the equation? Also, you would need some boundary conditions.
$endgroup$
– Roberto Rastapopoulos
Dec 14 '18 at 9:38
add a comment |
$begingroup$
$lambda$ does not appear in the equation? Also, you would need some boundary conditions.
$endgroup$
– Roberto Rastapopoulos
Dec 14 '18 at 9:38
$begingroup$
$lambda$ does not appear in the equation? Also, you would need some boundary conditions.
$endgroup$
– Roberto Rastapopoulos
Dec 14 '18 at 9:38
$begingroup$
$lambda$ does not appear in the equation? Also, you would need some boundary conditions.
$endgroup$
– Roberto Rastapopoulos
Dec 14 '18 at 9:38
add a comment |
1 Answer
1
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oldest
votes
$begingroup$
Write it as
$$
frac{{rm d}^2u}{{rm d}y^2} = - lambda u
$$
And try solutions of the form
$$
u(y) = A e^{pm isqrt{lambda}y}
$$
Eigenvectors are $u$ and eigenvalues are $lambda$
answered Dec 14 '18 at 9:39
caveraccaverac
14.6k31130
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add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Write it as
$$
frac{{rm d}^2u}{{rm d}y^2} = - lambda u
$$
And try solutions of the form
$$
u(y) = A e^{pm isqrt{lambda}y}
$$
Eigenvectors are $u$ and eigenvalues are $lambda$
answered Dec 14 '18 at 9:39
caveraccaverac
14.6k31130
$endgroup$
add a comment |
$begingroup$
Write it as
$$
frac{{rm d}^2u}{{rm d}y^2} = - lambda u
$$
And try solutions of the form
$$
u(y) = A e^{pm isqrt{lambda}y}
$$
Eigenvectors are $u$ and eigenvalues are $lambda$
answered Dec 14 '18 at 9:39
caveraccaverac
14.6k31130
$endgroup$
add a comment |
$begingroup$
Write it as
$$
frac{{rm d}^2u}{{rm d}y^2} = - lambda u
$$
And try solutions of the form
$$
u(y) = A e^{pm isqrt{lambda}y}
$$
Eigenvectors are $u$ and eigenvalues are $lambda$
answered Dec 14 '18 at 9:39
caveraccaverac
14.6k31130
$endgroup$
Write it as
$$
frac{{rm d}^2u}{{rm d}y^2} = - lambda u
$$
And try solutions of the form
$$
u(y) = A e^{pm isqrt{lambda}y}
$$
Eigenvectors are $u$ and eigenvalues are $lambda$
answered Dec 14 '18 at 9:39
caveraccaverac
14.6k31130
answered Dec 14 '18 at 9:39
caveraccaverac
14.6k31130
answered Dec 14 '18 at 9:39
caveraccaverac
14.6k31130
answered Dec 14 '18 at 9:39
caveraccaverac
14.6k31130
14.6k31130
add a comment |
add a comment |
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$begingroup$
$lambda$ does not appear in the equation? Also, you would need some boundary conditions.
$endgroup$
– Roberto Rastapopoulos
Dec 14 '18 at 9:38