Trouble calculating line integral using Green's theorem, complicated integral.












1












$begingroup$


"Calculate line integral of scalar function [$y(e^x) -1]dx + [e^x]dy$ over curve $C$, where $C$ is the semicircle through $(0, 10), (10, 0)$, and $(0, 10)$"



I plan on using Green's theorem, and since curve C does not include the bottom line on x axis, subtract line integral over this line on x axis from result of area integral from Green's theorem. However, I am having trouble calculating the line integral over this bottom curve, I've tried using cartesian and polar coordinates, but it gets very complex. Am I doing something wrong?










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  • $begingroup$
    is it y(e^x) (y a function of e^x) or ye^x?
    $endgroup$
    – Picaud Vincent
    Dec 2 '18 at 13:16










  • $begingroup$
    the latter, y * e^x
    $endgroup$
    – MinYoung Kim
    Dec 3 '18 at 8:23
















1












$begingroup$


"Calculate line integral of scalar function [$y(e^x) -1]dx + [e^x]dy$ over curve $C$, where $C$ is the semicircle through $(0, 10), (10, 0)$, and $(0, 10)$"



I plan on using Green's theorem, and since curve C does not include the bottom line on x axis, subtract line integral over this line on x axis from result of area integral from Green's theorem. However, I am having trouble calculating the line integral over this bottom curve, I've tried using cartesian and polar coordinates, but it gets very complex. Am I doing something wrong?










share|cite|improve this question











$endgroup$












  • $begingroup$
    is it y(e^x) (y a function of e^x) or ye^x?
    $endgroup$
    – Picaud Vincent
    Dec 2 '18 at 13:16










  • $begingroup$
    the latter, y * e^x
    $endgroup$
    – MinYoung Kim
    Dec 3 '18 at 8:23














1












1








1





$begingroup$


"Calculate line integral of scalar function [$y(e^x) -1]dx + [e^x]dy$ over curve $C$, where $C$ is the semicircle through $(0, 10), (10, 0)$, and $(0, 10)$"



I plan on using Green's theorem, and since curve C does not include the bottom line on x axis, subtract line integral over this line on x axis from result of area integral from Green's theorem. However, I am having trouble calculating the line integral over this bottom curve, I've tried using cartesian and polar coordinates, but it gets very complex. Am I doing something wrong?










share|cite|improve this question











$endgroup$




"Calculate line integral of scalar function [$y(e^x) -1]dx + [e^x]dy$ over curve $C$, where $C$ is the semicircle through $(0, 10), (10, 0)$, and $(0, 10)$"



I plan on using Green's theorem, and since curve C does not include the bottom line on x axis, subtract line integral over this line on x axis from result of area integral from Green's theorem. However, I am having trouble calculating the line integral over this bottom curve, I've tried using cartesian and polar coordinates, but it gets very complex. Am I doing something wrong?







greens-theorem






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share|cite|improve this question













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share|cite|improve this question








edited Dec 2 '18 at 12:32









amWhy

192k28225439




192k28225439










asked Dec 2 '18 at 12:26









MinYoung KimMinYoung Kim

82




82












  • $begingroup$
    is it y(e^x) (y a function of e^x) or ye^x?
    $endgroup$
    – Picaud Vincent
    Dec 2 '18 at 13:16










  • $begingroup$
    the latter, y * e^x
    $endgroup$
    – MinYoung Kim
    Dec 3 '18 at 8:23


















  • $begingroup$
    is it y(e^x) (y a function of e^x) or ye^x?
    $endgroup$
    – Picaud Vincent
    Dec 2 '18 at 13:16










  • $begingroup$
    the latter, y * e^x
    $endgroup$
    – MinYoung Kim
    Dec 3 '18 at 8:23
















$begingroup$
is it y(e^x) (y a function of e^x) or ye^x?
$endgroup$
– Picaud Vincent
Dec 2 '18 at 13:16




$begingroup$
is it y(e^x) (y a function of e^x) or ye^x?
$endgroup$
– Picaud Vincent
Dec 2 '18 at 13:16












$begingroup$
the latter, y * e^x
$endgroup$
– MinYoung Kim
Dec 3 '18 at 8:23




$begingroup$
the latter, y * e^x
$endgroup$
– MinYoung Kim
Dec 3 '18 at 8:23










1 Answer
1






active

oldest

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0












$begingroup$

Green's theorem states that: wiki



"for a curve C positively oriented, piecewise smooth, simple closed in a plane, and D be the region bounded by C. If L and M are functions of (x, y) defined on an open region containing D and have continuous partial derivatives", then:
$$
oint_C Ldx+Mdy=intint_D frac{partial M}{partial x}-frac{partial L}{partial y}dxdy
$$

Your example: $L=ye^x-1$, $M=e^x$
Thus:
$$
oint_C Ldx+Mdy=intint_D e^x-e^xdxdy=0
$$






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I got that part, I was asking how to calculate line integral over bottom to subtract from zero because its calculation was complicated, but I figured it out.
    $endgroup$
    – MinYoung Kim
    Dec 3 '18 at 20:57










  • $begingroup$
    @MinYoungKim Ok, I understand, thanks
    $endgroup$
    – Picaud Vincent
    Dec 3 '18 at 21:23











Your Answer





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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0












$begingroup$

Green's theorem states that: wiki



"for a curve C positively oriented, piecewise smooth, simple closed in a plane, and D be the region bounded by C. If L and M are functions of (x, y) defined on an open region containing D and have continuous partial derivatives", then:
$$
oint_C Ldx+Mdy=intint_D frac{partial M}{partial x}-frac{partial L}{partial y}dxdy
$$

Your example: $L=ye^x-1$, $M=e^x$
Thus:
$$
oint_C Ldx+Mdy=intint_D e^x-e^xdxdy=0
$$






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I got that part, I was asking how to calculate line integral over bottom to subtract from zero because its calculation was complicated, but I figured it out.
    $endgroup$
    – MinYoung Kim
    Dec 3 '18 at 20:57










  • $begingroup$
    @MinYoungKim Ok, I understand, thanks
    $endgroup$
    – Picaud Vincent
    Dec 3 '18 at 21:23
















0












$begingroup$

Green's theorem states that: wiki



"for a curve C positively oriented, piecewise smooth, simple closed in a plane, and D be the region bounded by C. If L and M are functions of (x, y) defined on an open region containing D and have continuous partial derivatives", then:
$$
oint_C Ldx+Mdy=intint_D frac{partial M}{partial x}-frac{partial L}{partial y}dxdy
$$

Your example: $L=ye^x-1$, $M=e^x$
Thus:
$$
oint_C Ldx+Mdy=intint_D e^x-e^xdxdy=0
$$






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I got that part, I was asking how to calculate line integral over bottom to subtract from zero because its calculation was complicated, but I figured it out.
    $endgroup$
    – MinYoung Kim
    Dec 3 '18 at 20:57










  • $begingroup$
    @MinYoungKim Ok, I understand, thanks
    $endgroup$
    – Picaud Vincent
    Dec 3 '18 at 21:23














0












0








0





$begingroup$

Green's theorem states that: wiki



"for a curve C positively oriented, piecewise smooth, simple closed in a plane, and D be the region bounded by C. If L and M are functions of (x, y) defined on an open region containing D and have continuous partial derivatives", then:
$$
oint_C Ldx+Mdy=intint_D frac{partial M}{partial x}-frac{partial L}{partial y}dxdy
$$

Your example: $L=ye^x-1$, $M=e^x$
Thus:
$$
oint_C Ldx+Mdy=intint_D e^x-e^xdxdy=0
$$






share|cite|improve this answer









$endgroup$



Green's theorem states that: wiki



"for a curve C positively oriented, piecewise smooth, simple closed in a plane, and D be the region bounded by C. If L and M are functions of (x, y) defined on an open region containing D and have continuous partial derivatives", then:
$$
oint_C Ldx+Mdy=intint_D frac{partial M}{partial x}-frac{partial L}{partial y}dxdy
$$

Your example: $L=ye^x-1$, $M=e^x$
Thus:
$$
oint_C Ldx+Mdy=intint_D e^x-e^xdxdy=0
$$







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Dec 3 '18 at 9:22









Picaud VincentPicaud Vincent

1,33439




1,33439












  • $begingroup$
    I got that part, I was asking how to calculate line integral over bottom to subtract from zero because its calculation was complicated, but I figured it out.
    $endgroup$
    – MinYoung Kim
    Dec 3 '18 at 20:57










  • $begingroup$
    @MinYoungKim Ok, I understand, thanks
    $endgroup$
    – Picaud Vincent
    Dec 3 '18 at 21:23


















  • $begingroup$
    I got that part, I was asking how to calculate line integral over bottom to subtract from zero because its calculation was complicated, but I figured it out.
    $endgroup$
    – MinYoung Kim
    Dec 3 '18 at 20:57










  • $begingroup$
    @MinYoungKim Ok, I understand, thanks
    $endgroup$
    – Picaud Vincent
    Dec 3 '18 at 21:23
















$begingroup$
I got that part, I was asking how to calculate line integral over bottom to subtract from zero because its calculation was complicated, but I figured it out.
$endgroup$
– MinYoung Kim
Dec 3 '18 at 20:57




$begingroup$
I got that part, I was asking how to calculate line integral over bottom to subtract from zero because its calculation was complicated, but I figured it out.
$endgroup$
– MinYoung Kim
Dec 3 '18 at 20:57












$begingroup$
@MinYoungKim Ok, I understand, thanks
$endgroup$
– Picaud Vincent
Dec 3 '18 at 21:23




$begingroup$
@MinYoungKim Ok, I understand, thanks
$endgroup$
– Picaud Vincent
Dec 3 '18 at 21:23


















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