What is an example of a groupoid which is not a semigroup?











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I know that groupoid refers to an algebraic structure with a binary operation. The only necessary condition is closure.



However, I couldn't find any easy-to-understand example of a groupoid which is not a semigroup. I did come across some examples of (certain type of) matrices but then matrix multiplication is always associative (thus making it a semi-group).



So, could someone please provide me an example of a groupoid which isn't a semigroup?










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  • 2




    You should be careful with the word "groupoid". In the 60s some people used this word to refer to "sets with a binary operation" (possibly non-associative), but these are now called magmas. Groupoids, on the other hand, are sets (or classes) with a partially defined binary operation satisfying group-like properties.
    – Luiz Cordeiro
    May 19 at 17:50










  • @LuizCordeiro Thanks. I didn't know that. However, I guess in the context of this question: "Give an example of a groupoid which is not a semigroup." I think they mean "magma" by "groupoid"?
    – user563280
    May 19 at 17:57










  • Yes, since you're looking for an example of a non-associative binary operation, you're looking for a magma which isn't a semigroup.
    – Luiz Cordeiro
    May 19 at 18:01















up vote
2
down vote

favorite












I know that groupoid refers to an algebraic structure with a binary operation. The only necessary condition is closure.



However, I couldn't find any easy-to-understand example of a groupoid which is not a semigroup. I did come across some examples of (certain type of) matrices but then matrix multiplication is always associative (thus making it a semi-group).



So, could someone please provide me an example of a groupoid which isn't a semigroup?










share|cite|improve this question




















  • 2




    You should be careful with the word "groupoid". In the 60s some people used this word to refer to "sets with a binary operation" (possibly non-associative), but these are now called magmas. Groupoids, on the other hand, are sets (or classes) with a partially defined binary operation satisfying group-like properties.
    – Luiz Cordeiro
    May 19 at 17:50










  • @LuizCordeiro Thanks. I didn't know that. However, I guess in the context of this question: "Give an example of a groupoid which is not a semigroup." I think they mean "magma" by "groupoid"?
    – user563280
    May 19 at 17:57










  • Yes, since you're looking for an example of a non-associative binary operation, you're looking for a magma which isn't a semigroup.
    – Luiz Cordeiro
    May 19 at 18:01













up vote
2
down vote

favorite









up vote
2
down vote

favorite











I know that groupoid refers to an algebraic structure with a binary operation. The only necessary condition is closure.



However, I couldn't find any easy-to-understand example of a groupoid which is not a semigroup. I did come across some examples of (certain type of) matrices but then matrix multiplication is always associative (thus making it a semi-group).



So, could someone please provide me an example of a groupoid which isn't a semigroup?










share|cite|improve this question















I know that groupoid refers to an algebraic structure with a binary operation. The only necessary condition is closure.



However, I couldn't find any easy-to-understand example of a groupoid which is not a semigroup. I did come across some examples of (certain type of) matrices but then matrix multiplication is always associative (thus making it a semi-group).



So, could someone please provide me an example of a groupoid which isn't a semigroup?







abstract-algebra semigroups magma






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edited Nov 21 at 14:37









Arnaud D.

15.5k52343




15.5k52343










asked May 19 at 17:42







user563280















  • 2




    You should be careful with the word "groupoid". In the 60s some people used this word to refer to "sets with a binary operation" (possibly non-associative), but these are now called magmas. Groupoids, on the other hand, are sets (or classes) with a partially defined binary operation satisfying group-like properties.
    – Luiz Cordeiro
    May 19 at 17:50










  • @LuizCordeiro Thanks. I didn't know that. However, I guess in the context of this question: "Give an example of a groupoid which is not a semigroup." I think they mean "magma" by "groupoid"?
    – user563280
    May 19 at 17:57










  • Yes, since you're looking for an example of a non-associative binary operation, you're looking for a magma which isn't a semigroup.
    – Luiz Cordeiro
    May 19 at 18:01














  • 2




    You should be careful with the word "groupoid". In the 60s some people used this word to refer to "sets with a binary operation" (possibly non-associative), but these are now called magmas. Groupoids, on the other hand, are sets (or classes) with a partially defined binary operation satisfying group-like properties.
    – Luiz Cordeiro
    May 19 at 17:50










  • @LuizCordeiro Thanks. I didn't know that. However, I guess in the context of this question: "Give an example of a groupoid which is not a semigroup." I think they mean "magma" by "groupoid"?
    – user563280
    May 19 at 17:57










  • Yes, since you're looking for an example of a non-associative binary operation, you're looking for a magma which isn't a semigroup.
    – Luiz Cordeiro
    May 19 at 18:01








2




2




You should be careful with the word "groupoid". In the 60s some people used this word to refer to "sets with a binary operation" (possibly non-associative), but these are now called magmas. Groupoids, on the other hand, are sets (or classes) with a partially defined binary operation satisfying group-like properties.
– Luiz Cordeiro
May 19 at 17:50




You should be careful with the word "groupoid". In the 60s some people used this word to refer to "sets with a binary operation" (possibly non-associative), but these are now called magmas. Groupoids, on the other hand, are sets (or classes) with a partially defined binary operation satisfying group-like properties.
– Luiz Cordeiro
May 19 at 17:50












@LuizCordeiro Thanks. I didn't know that. However, I guess in the context of this question: "Give an example of a groupoid which is not a semigroup." I think they mean "magma" by "groupoid"?
– user563280
May 19 at 17:57




@LuizCordeiro Thanks. I didn't know that. However, I guess in the context of this question: "Give an example of a groupoid which is not a semigroup." I think they mean "magma" by "groupoid"?
– user563280
May 19 at 17:57












Yes, since you're looking for an example of a non-associative binary operation, you're looking for a magma which isn't a semigroup.
– Luiz Cordeiro
May 19 at 18:01




Yes, since you're looking for an example of a non-associative binary operation, you're looking for a magma which isn't a semigroup.
– Luiz Cordeiro
May 19 at 18:01










5 Answers
5






active

oldest

votes

















up vote
4
down vote













These are called magmas, not groupoids.



The ``midpoint'' operation $sast t=frac{s+t}{2}$ on $mathbb{R}$ makes it a magma which is not a semigroup.






share|cite|improve this answer




























    up vote
    2
    down vote













    Here's three different examples.




    1. Take an abelian group $(A,+)$ and define a new binary operation $circ$ on $A$ by $xcirc y=x+(-y)$. This is an example of a quasigroup.


    2. Take a group $(G,cdot)$ and define a new binary operation $triangleleft$ on $G$ by $xtriangleleft y=xcdot y cdot x^{-1}$. This is an example of a quandle.


    3. Take a digraph $(V,A)$ with the property that for any two distinct vertices $v,win V$, exactly one of the arcs $vw$ or $wv$ is in $A$. Define a commutative binary operation $cdot$ on $V$ by $vcdot v=v$ and $vcdot w=w$ if and only if $vwin A$. This is an example of a tournament.



    A quasigroup is associative if and only if it is a group, a quandle is associative if and only if it is trivial, and a tournament is associative if and only if it is a commutative idempotent semigroup (aka a semilattice).






    share|cite|improve this answer




























      up vote
      0
      down vote













      Let $a,b,c$ be distinct members of a three element set and $ab=c=cc $, $bc=a=aa$ and define $ac, bb $ however you like (but in ${a,b,c}$.) You have a nonassociative binary operation.






      share|cite|improve this answer




























        up vote
        0
        down vote













        Let ${a,b}$ be a set with two distinct elements.



        Define a partial multiplication by $atimes a=a$ and $btimes b=b$ and nothing more (so $atimes b$ and $btimes a$ are not defined).



        Then ${a,b}$ equipped with this multiplication is a groupoid, but not a semigroup.



        I suspect you use another definition of groupoid. If it is what I would call a magma then see the other answers.






        share|cite|improve this answer




























          up vote
          0
          down vote













          First, the term 'groupoid' recently rather means primarily a category with invertible arrows, and the term 'magma' is arising for an algebraic structure with a binary operation.



          For a familiar example, consider $Bbb Z$ (or almost any Abelian group) with the subtraction.



          Or, define $a*b:=a+b+1$ (or whatever..)



          Other examples arise e.g. from finite quasigroups whose multiplication table is a latin square: having each element once in every row and in every column.






          share|cite|improve this answer





















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            5 Answers
            5






            active

            oldest

            votes








            5 Answers
            5






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            4
            down vote













            These are called magmas, not groupoids.



            The ``midpoint'' operation $sast t=frac{s+t}{2}$ on $mathbb{R}$ makes it a magma which is not a semigroup.






            share|cite|improve this answer

























              up vote
              4
              down vote













              These are called magmas, not groupoids.



              The ``midpoint'' operation $sast t=frac{s+t}{2}$ on $mathbb{R}$ makes it a magma which is not a semigroup.






              share|cite|improve this answer























                up vote
                4
                down vote










                up vote
                4
                down vote









                These are called magmas, not groupoids.



                The ``midpoint'' operation $sast t=frac{s+t}{2}$ on $mathbb{R}$ makes it a magma which is not a semigroup.






                share|cite|improve this answer












                These are called magmas, not groupoids.



                The ``midpoint'' operation $sast t=frac{s+t}{2}$ on $mathbb{R}$ makes it a magma which is not a semigroup.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered May 19 at 17:55









                Luiz Cordeiro

                12.5k1143




                12.5k1143






















                    up vote
                    2
                    down vote













                    Here's three different examples.




                    1. Take an abelian group $(A,+)$ and define a new binary operation $circ$ on $A$ by $xcirc y=x+(-y)$. This is an example of a quasigroup.


                    2. Take a group $(G,cdot)$ and define a new binary operation $triangleleft$ on $G$ by $xtriangleleft y=xcdot y cdot x^{-1}$. This is an example of a quandle.


                    3. Take a digraph $(V,A)$ with the property that for any two distinct vertices $v,win V$, exactly one of the arcs $vw$ or $wv$ is in $A$. Define a commutative binary operation $cdot$ on $V$ by $vcdot v=v$ and $vcdot w=w$ if and only if $vwin A$. This is an example of a tournament.



                    A quasigroup is associative if and only if it is a group, a quandle is associative if and only if it is trivial, and a tournament is associative if and only if it is a commutative idempotent semigroup (aka a semilattice).






                    share|cite|improve this answer

























                      up vote
                      2
                      down vote













                      Here's three different examples.




                      1. Take an abelian group $(A,+)$ and define a new binary operation $circ$ on $A$ by $xcirc y=x+(-y)$. This is an example of a quasigroup.


                      2. Take a group $(G,cdot)$ and define a new binary operation $triangleleft$ on $G$ by $xtriangleleft y=xcdot y cdot x^{-1}$. This is an example of a quandle.


                      3. Take a digraph $(V,A)$ with the property that for any two distinct vertices $v,win V$, exactly one of the arcs $vw$ or $wv$ is in $A$. Define a commutative binary operation $cdot$ on $V$ by $vcdot v=v$ and $vcdot w=w$ if and only if $vwin A$. This is an example of a tournament.



                      A quasigroup is associative if and only if it is a group, a quandle is associative if and only if it is trivial, and a tournament is associative if and only if it is a commutative idempotent semigroup (aka a semilattice).






                      share|cite|improve this answer























                        up vote
                        2
                        down vote










                        up vote
                        2
                        down vote









                        Here's three different examples.




                        1. Take an abelian group $(A,+)$ and define a new binary operation $circ$ on $A$ by $xcirc y=x+(-y)$. This is an example of a quasigroup.


                        2. Take a group $(G,cdot)$ and define a new binary operation $triangleleft$ on $G$ by $xtriangleleft y=xcdot y cdot x^{-1}$. This is an example of a quandle.


                        3. Take a digraph $(V,A)$ with the property that for any two distinct vertices $v,win V$, exactly one of the arcs $vw$ or $wv$ is in $A$. Define a commutative binary operation $cdot$ on $V$ by $vcdot v=v$ and $vcdot w=w$ if and only if $vwin A$. This is an example of a tournament.



                        A quasigroup is associative if and only if it is a group, a quandle is associative if and only if it is trivial, and a tournament is associative if and only if it is a commutative idempotent semigroup (aka a semilattice).






                        share|cite|improve this answer












                        Here's three different examples.




                        1. Take an abelian group $(A,+)$ and define a new binary operation $circ$ on $A$ by $xcirc y=x+(-y)$. This is an example of a quasigroup.


                        2. Take a group $(G,cdot)$ and define a new binary operation $triangleleft$ on $G$ by $xtriangleleft y=xcdot y cdot x^{-1}$. This is an example of a quandle.


                        3. Take a digraph $(V,A)$ with the property that for any two distinct vertices $v,win V$, exactly one of the arcs $vw$ or $wv$ is in $A$. Define a commutative binary operation $cdot$ on $V$ by $vcdot v=v$ and $vcdot w=w$ if and only if $vwin A$. This is an example of a tournament.



                        A quasigroup is associative if and only if it is a group, a quandle is associative if and only if it is trivial, and a tournament is associative if and only if it is a commutative idempotent semigroup (aka a semilattice).







                        share|cite|improve this answer












                        share|cite|improve this answer



                        share|cite|improve this answer










                        answered May 20 at 1:32









                        Eran

                        1,178818




                        1,178818






















                            up vote
                            0
                            down vote













                            Let $a,b,c$ be distinct members of a three element set and $ab=c=cc $, $bc=a=aa$ and define $ac, bb $ however you like (but in ${a,b,c}$.) You have a nonassociative binary operation.






                            share|cite|improve this answer

























                              up vote
                              0
                              down vote













                              Let $a,b,c$ be distinct members of a three element set and $ab=c=cc $, $bc=a=aa$ and define $ac, bb $ however you like (but in ${a,b,c}$.) You have a nonassociative binary operation.






                              share|cite|improve this answer























                                up vote
                                0
                                down vote










                                up vote
                                0
                                down vote









                                Let $a,b,c$ be distinct members of a three element set and $ab=c=cc $, $bc=a=aa$ and define $ac, bb $ however you like (but in ${a,b,c}$.) You have a nonassociative binary operation.






                                share|cite|improve this answer












                                Let $a,b,c$ be distinct members of a three element set and $ab=c=cc $, $bc=a=aa$ and define $ac, bb $ however you like (but in ${a,b,c}$.) You have a nonassociative binary operation.







                                share|cite|improve this answer












                                share|cite|improve this answer



                                share|cite|improve this answer










                                answered May 19 at 17:54









                                rschwieb

                                104k1299238




                                104k1299238






















                                    up vote
                                    0
                                    down vote













                                    Let ${a,b}$ be a set with two distinct elements.



                                    Define a partial multiplication by $atimes a=a$ and $btimes b=b$ and nothing more (so $atimes b$ and $btimes a$ are not defined).



                                    Then ${a,b}$ equipped with this multiplication is a groupoid, but not a semigroup.



                                    I suspect you use another definition of groupoid. If it is what I would call a magma then see the other answers.






                                    share|cite|improve this answer

























                                      up vote
                                      0
                                      down vote













                                      Let ${a,b}$ be a set with two distinct elements.



                                      Define a partial multiplication by $atimes a=a$ and $btimes b=b$ and nothing more (so $atimes b$ and $btimes a$ are not defined).



                                      Then ${a,b}$ equipped with this multiplication is a groupoid, but not a semigroup.



                                      I suspect you use another definition of groupoid. If it is what I would call a magma then see the other answers.






                                      share|cite|improve this answer























                                        up vote
                                        0
                                        down vote










                                        up vote
                                        0
                                        down vote









                                        Let ${a,b}$ be a set with two distinct elements.



                                        Define a partial multiplication by $atimes a=a$ and $btimes b=b$ and nothing more (so $atimes b$ and $btimes a$ are not defined).



                                        Then ${a,b}$ equipped with this multiplication is a groupoid, but not a semigroup.



                                        I suspect you use another definition of groupoid. If it is what I would call a magma then see the other answers.






                                        share|cite|improve this answer












                                        Let ${a,b}$ be a set with two distinct elements.



                                        Define a partial multiplication by $atimes a=a$ and $btimes b=b$ and nothing more (so $atimes b$ and $btimes a$ are not defined).



                                        Then ${a,b}$ equipped with this multiplication is a groupoid, but not a semigroup.



                                        I suspect you use another definition of groupoid. If it is what I would call a magma then see the other answers.







                                        share|cite|improve this answer












                                        share|cite|improve this answer



                                        share|cite|improve this answer










                                        answered May 19 at 17:56









                                        Vera

                                        2,467617




                                        2,467617






















                                            up vote
                                            0
                                            down vote













                                            First, the term 'groupoid' recently rather means primarily a category with invertible arrows, and the term 'magma' is arising for an algebraic structure with a binary operation.



                                            For a familiar example, consider $Bbb Z$ (or almost any Abelian group) with the subtraction.



                                            Or, define $a*b:=a+b+1$ (or whatever..)



                                            Other examples arise e.g. from finite quasigroups whose multiplication table is a latin square: having each element once in every row and in every column.






                                            share|cite|improve this answer

























                                              up vote
                                              0
                                              down vote













                                              First, the term 'groupoid' recently rather means primarily a category with invertible arrows, and the term 'magma' is arising for an algebraic structure with a binary operation.



                                              For a familiar example, consider $Bbb Z$ (or almost any Abelian group) with the subtraction.



                                              Or, define $a*b:=a+b+1$ (or whatever..)



                                              Other examples arise e.g. from finite quasigroups whose multiplication table is a latin square: having each element once in every row and in every column.






                                              share|cite|improve this answer























                                                up vote
                                                0
                                                down vote










                                                up vote
                                                0
                                                down vote









                                                First, the term 'groupoid' recently rather means primarily a category with invertible arrows, and the term 'magma' is arising for an algebraic structure with a binary operation.



                                                For a familiar example, consider $Bbb Z$ (or almost any Abelian group) with the subtraction.



                                                Or, define $a*b:=a+b+1$ (or whatever..)



                                                Other examples arise e.g. from finite quasigroups whose multiplication table is a latin square: having each element once in every row and in every column.






                                                share|cite|improve this answer












                                                First, the term 'groupoid' recently rather means primarily a category with invertible arrows, and the term 'magma' is arising for an algebraic structure with a binary operation.



                                                For a familiar example, consider $Bbb Z$ (or almost any Abelian group) with the subtraction.



                                                Or, define $a*b:=a+b+1$ (or whatever..)



                                                Other examples arise e.g. from finite quasigroups whose multiplication table is a latin square: having each element once in every row and in every column.







                                                share|cite|improve this answer












                                                share|cite|improve this answer



                                                share|cite|improve this answer










                                                answered May 19 at 17:58









                                                Berci

                                                59.2k23672




                                                59.2k23672






























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