Show that any finite simple non-abelian group is not solvable. [closed]











up vote
-1
down vote

favorite












Aluffi's Algebra claims (implicitly) that any finite simple non-abelian group is not solvable.
On the other hand, it defines a group to be not solvable if its derived series doesn't terminate with the identity.
How to show that a finite simple non-abelian group is not solvable based on the original definition it gives?



PS The derived series of $G$ is the sequence of subgroups $G ⊇ G' ⊇ G'' ⊇ G''' ⊇ dots$ . $G' = [G,G]$.










share|cite|improve this question













closed as off-topic by Did, amWhy, Shailesh, Cesareo, user10354138 Nov 19 at 2:17


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, amWhy, Shailesh, Cesareo, user10354138

If this question can be reworded to fit the rules in the help center, please edit the question.

















    up vote
    -1
    down vote

    favorite












    Aluffi's Algebra claims (implicitly) that any finite simple non-abelian group is not solvable.
    On the other hand, it defines a group to be not solvable if its derived series doesn't terminate with the identity.
    How to show that a finite simple non-abelian group is not solvable based on the original definition it gives?



    PS The derived series of $G$ is the sequence of subgroups $G ⊇ G' ⊇ G'' ⊇ G''' ⊇ dots$ . $G' = [G,G]$.










    share|cite|improve this question













    closed as off-topic by Did, amWhy, Shailesh, Cesareo, user10354138 Nov 19 at 2:17


    This question appears to be off-topic. The users who voted to close gave this specific reason:


    • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, amWhy, Shailesh, Cesareo, user10354138

    If this question can be reworded to fit the rules in the help center, please edit the question.















      up vote
      -1
      down vote

      favorite









      up vote
      -1
      down vote

      favorite











      Aluffi's Algebra claims (implicitly) that any finite simple non-abelian group is not solvable.
      On the other hand, it defines a group to be not solvable if its derived series doesn't terminate with the identity.
      How to show that a finite simple non-abelian group is not solvable based on the original definition it gives?



      PS The derived series of $G$ is the sequence of subgroups $G ⊇ G' ⊇ G'' ⊇ G''' ⊇ dots$ . $G' = [G,G]$.










      share|cite|improve this question













      Aluffi's Algebra claims (implicitly) that any finite simple non-abelian group is not solvable.
      On the other hand, it defines a group to be not solvable if its derived series doesn't terminate with the identity.
      How to show that a finite simple non-abelian group is not solvable based on the original definition it gives?



      PS The derived series of $G$ is the sequence of subgroups $G ⊇ G' ⊇ G'' ⊇ G''' ⊇ dots$ . $G' = [G,G]$.







      abstract-algebra solvable-groups






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Nov 18 at 17:03









      72D

      48716




      48716




      closed as off-topic by Did, amWhy, Shailesh, Cesareo, user10354138 Nov 19 at 2:17


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, amWhy, Shailesh, Cesareo, user10354138

      If this question can be reworded to fit the rules in the help center, please edit the question.




      closed as off-topic by Did, amWhy, Shailesh, Cesareo, user10354138 Nov 19 at 2:17


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, amWhy, Shailesh, Cesareo, user10354138

      If this question can be reworded to fit the rules in the help center, please edit the question.






















          1 Answer
          1






          active

          oldest

          votes

















          up vote
          0
          down vote



          accepted










          Well, we know that always $;G'lhd G;$ , so if the group $;G;$ is non-abelian simple...what is then $;G';$ ?






          share|cite|improve this answer




























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            0
            down vote



            accepted










            Well, we know that always $;G'lhd G;$ , so if the group $;G;$ is non-abelian simple...what is then $;G';$ ?






            share|cite|improve this answer

























              up vote
              0
              down vote



              accepted










              Well, we know that always $;G'lhd G;$ , so if the group $;G;$ is non-abelian simple...what is then $;G';$ ?






              share|cite|improve this answer























                up vote
                0
                down vote



                accepted







                up vote
                0
                down vote



                accepted






                Well, we know that always $;G'lhd G;$ , so if the group $;G;$ is non-abelian simple...what is then $;G';$ ?






                share|cite|improve this answer












                Well, we know that always $;G'lhd G;$ , so if the group $;G;$ is non-abelian simple...what is then $;G';$ ?







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Nov 18 at 17:05









                DonAntonio

                176k1491224




                176k1491224















                    Popular posts from this blog

                    Probability when a professor distributes a quiz and homework assignment to a class of n students.

                    Aardman Animations

                    Are they similar matrix