How many distinct 4 letter words can be created using the 26 alphabets.
up vote
2
down vote
favorite
How many distinct 4 letter words can be created using the 26 alphabets. I have a project in which I can enter the name of the branch ID which is a 4 letter word that can be of any combinations. I want to know, how many entries can be made.
permutations
asked Oct 7 '13 at 11:53
karthik reddy
113113
add a comment |
up vote
2
down vote
favorite
How many distinct 4 letter words can be created using the 26 alphabets. I have a project in which I can enter the name of the branch ID which is a 4 letter word that can be of any combinations. I want to know, how many entries can be made.
permutations
asked Oct 7 '13 at 11:53
karthik reddy
113113
2
$26.26.26.26$????
– user87543
Oct 7 '13 at 11:54
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
How many distinct 4 letter words can be created using the 26 alphabets. I have a project in which I can enter the name of the branch ID which is a 4 letter word that can be of any combinations. I want to know, how many entries can be made.
permutations
asked Oct 7 '13 at 11:53
karthik reddy
113113
How many distinct 4 letter words can be created using the 26 alphabets. I have a project in which I can enter the name of the branch ID which is a 4 letter word that can be of any combinations. I want to know, how many entries can be made.
permutations
permutations
asked Oct 7 '13 at 11:53
karthik reddy
113113
asked Oct 7 '13 at 11:53
karthik reddy
113113
asked Oct 7 '13 at 11:53
karthik reddy
113113
asked Oct 7 '13 at 11:53
karthik reddy
113113
asked Oct 7 '13 at 11:53
karthik reddy
113113
113113
2
$26.26.26.26$????
– user87543
Oct 7 '13 at 11:54
add a comment |
2
$26.26.26.26$????
– user87543
Oct 7 '13 at 11:54
2
2
$26.26.26.26$????
– user87543
Oct 7 '13 at 11:54
$26.26.26.26$????
– user87543
Oct 7 '13 at 11:54
add a comment |
3 Answers
3
active
oldest
votes
up vote
5
down vote
accepted
There are $26$ distinct options for each letter, hence there are $,26cdot 26cdot 26cdot 26 = 26^4 = 456976;$ distinct four-letter "word" combinations one can form using a $26$-letter alphabet.
answered Oct 7 '13 at 11:59
amWhy
191k27223439
add a comment |
up vote
2
down vote
One approach to this would be to assume each feasible word must contain one vowel or a "y". The remaining 3 letters can be either consonants or vowels. So there are 5*26*26*26=105,456 words where the first letter is a vowel or a "y". Take this number and multiply and you get all the words that are feasible. So, 105,446*4=421,824 total words. Sorry if the numbers are off, doing my calculations on my phone
answered Jul 12 '15 at 20:32
Adam Nowak
211
Good thinking about vowels.. but wouldn't any English word need a vowel within within the middle-two letters?
– ashleedawg
Nov 10 at 23:12
add a comment |
up vote
-1
down vote
let say there are 4 word ABCD. here
'A' can have 26 letter combination to its right.
'B' can have 26 letter combination to its right
'C' can have 26 letter combination to its right
'D' can have 26 letter combination to its right
so u dont need to have a look at left combination because its already done by previous right's. there fore 26^4 will be the answer 456976.
answered Nov 21 at 6:33
vicky
1
Nobody is talking about left or right here. You would need good arguments as to why that is relevant. The question is more than 5 years old an has an accepted answer (that has the same resultt as you), making it unlikely that anybody will benefit from this answer. Spend your time wiser.
– Henrik
Nov 21 at 6:56
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
accepted
There are $26$ distinct options for each letter, hence there are $,26cdot 26cdot 26cdot 26 = 26^4 = 456976;$ distinct four-letter "word" combinations one can form using a $26$-letter alphabet.
answered Oct 7 '13 at 11:59
amWhy
191k27223439
add a comment |
up vote
5
down vote
accepted
There are $26$ distinct options for each letter, hence there are $,26cdot 26cdot 26cdot 26 = 26^4 = 456976;$ distinct four-letter "word" combinations one can form using a $26$-letter alphabet.
answered Oct 7 '13 at 11:59
amWhy
191k27223439
add a comment |
up vote
5
down vote
accepted
up vote
5
down vote
accepted
There are $26$ distinct options for each letter, hence there are $,26cdot 26cdot 26cdot 26 = 26^4 = 456976;$ distinct four-letter "word" combinations one can form using a $26$-letter alphabet.
answered Oct 7 '13 at 11:59
amWhy
191k27223439
There are $26$ distinct options for each letter, hence there are $,26cdot 26cdot 26cdot 26 = 26^4 = 456976;$ distinct four-letter "word" combinations one can form using a $26$-letter alphabet.
answered Oct 7 '13 at 11:59
amWhy
191k27223439
answered Oct 7 '13 at 11:59
amWhy
191k27223439
answered Oct 7 '13 at 11:59
amWhy
191k27223439
answered Oct 7 '13 at 11:59
amWhy
191k27223439
191k27223439
add a comment |
add a comment |
up vote
2
down vote
One approach to this would be to assume each feasible word must contain one vowel or a "y". The remaining 3 letters can be either consonants or vowels. So there are 5*26*26*26=105,456 words where the first letter is a vowel or a "y". Take this number and multiply and you get all the words that are feasible. So, 105,446*4=421,824 total words. Sorry if the numbers are off, doing my calculations on my phone
answered Jul 12 '15 at 20:32
Adam Nowak
211
Good thinking about vowels.. but wouldn't any English word need a vowel within within the middle-two letters?
– ashleedawg
Nov 10 at 23:12
add a comment |
up vote
2
down vote
One approach to this would be to assume each feasible word must contain one vowel or a "y". The remaining 3 letters can be either consonants or vowels. So there are 5*26*26*26=105,456 words where the first letter is a vowel or a "y". Take this number and multiply and you get all the words that are feasible. So, 105,446*4=421,824 total words. Sorry if the numbers are off, doing my calculations on my phone
answered Jul 12 '15 at 20:32
Adam Nowak
211
Good thinking about vowels.. but wouldn't any English word need a vowel within within the middle-two letters?
– ashleedawg
Nov 10 at 23:12
add a comment |
up vote
2
down vote
up vote
2
down vote
One approach to this would be to assume each feasible word must contain one vowel or a "y". The remaining 3 letters can be either consonants or vowels. So there are 5*26*26*26=105,456 words where the first letter is a vowel or a "y". Take this number and multiply and you get all the words that are feasible. So, 105,446*4=421,824 total words. Sorry if the numbers are off, doing my calculations on my phone
answered Jul 12 '15 at 20:32
Adam Nowak
211
One approach to this would be to assume each feasible word must contain one vowel or a "y". The remaining 3 letters can be either consonants or vowels. So there are 5*26*26*26=105,456 words where the first letter is a vowel or a "y". Take this number and multiply and you get all the words that are feasible. So, 105,446*4=421,824 total words. Sorry if the numbers are off, doing my calculations on my phone
answered Jul 12 '15 at 20:32
Adam Nowak
211
answered Jul 12 '15 at 20:32
Adam Nowak
211
answered Jul 12 '15 at 20:32
Adam Nowak
211
answered Jul 12 '15 at 20:32
Adam Nowak
211
211
Good thinking about vowels.. but wouldn't any English word need a vowel within within the middle-two letters?
– ashleedawg
Nov 10 at 23:12
add a comment |
Good thinking about vowels.. but wouldn't any English word need a vowel within within the middle-two letters?
– ashleedawg
Nov 10 at 23:12
Good thinking about vowels.. but wouldn't any English word need a vowel within within the middle-two letters?
– ashleedawg
Nov 10 at 23:12
Good thinking about vowels.. but wouldn't any English word need a vowel within within the middle-two letters?
– ashleedawg
Nov 10 at 23:12
add a comment |
up vote
-1
down vote
let say there are 4 word ABCD. here
'A' can have 26 letter combination to its right.
'B' can have 26 letter combination to its right
'C' can have 26 letter combination to its right
'D' can have 26 letter combination to its right
so u dont need to have a look at left combination because its already done by previous right's. there fore 26^4 will be the answer 456976.
answered Nov 21 at 6:33
vicky
1
Nobody is talking about left or right here. You would need good arguments as to why that is relevant. The question is more than 5 years old an has an accepted answer (that has the same resultt as you), making it unlikely that anybody will benefit from this answer. Spend your time wiser.
– Henrik
Nov 21 at 6:56
add a comment |
up vote
-1
down vote
let say there are 4 word ABCD. here
'A' can have 26 letter combination to its right.
'B' can have 26 letter combination to its right
'C' can have 26 letter combination to its right
'D' can have 26 letter combination to its right
so u dont need to have a look at left combination because its already done by previous right's. there fore 26^4 will be the answer 456976.
answered Nov 21 at 6:33
vicky
1
Nobody is talking about left or right here. You would need good arguments as to why that is relevant. The question is more than 5 years old an has an accepted answer (that has the same resultt as you), making it unlikely that anybody will benefit from this answer. Spend your time wiser.
– Henrik
Nov 21 at 6:56
add a comment |
up vote
-1
down vote
up vote
-1
down vote
let say there are 4 word ABCD. here
'A' can have 26 letter combination to its right.
'B' can have 26 letter combination to its right
'C' can have 26 letter combination to its right
'D' can have 26 letter combination to its right
so u dont need to have a look at left combination because its already done by previous right's. there fore 26^4 will be the answer 456976.
answered Nov 21 at 6:33
vicky
1
let say there are 4 word ABCD. here
'A' can have 26 letter combination to its right.
'B' can have 26 letter combination to its right
'C' can have 26 letter combination to its right
'D' can have 26 letter combination to its right
so u dont need to have a look at left combination because its already done by previous right's. there fore 26^4 will be the answer 456976.
answered Nov 21 at 6:33
vicky
1
answered Nov 21 at 6:33
vicky
1
answered Nov 21 at 6:33
vicky
1
answered Nov 21 at 6:33
vicky
1
1
Nobody is talking about left or right here. You would need good arguments as to why that is relevant. The question is more than 5 years old an has an accepted answer (that has the same resultt as you), making it unlikely that anybody will benefit from this answer. Spend your time wiser.
– Henrik
Nov 21 at 6:56
add a comment |
Nobody is talking about left or right here. You would need good arguments as to why that is relevant. The question is more than 5 years old an has an accepted answer (that has the same resultt as you), making it unlikely that anybody will benefit from this answer. Spend your time wiser.
– Henrik
Nov 21 at 6:56
Nobody is talking about left or right here. You would need good arguments as to why that is relevant. The question is more than 5 years old an has an accepted answer (that has the same resultt as you), making it unlikely that anybody will benefit from this answer. Spend your time wiser.
– Henrik
Nov 21 at 6:56
Nobody is talking about left or right here. You would need good arguments as to why that is relevant. The question is more than 5 years old an has an accepted answer (that has the same resultt as you), making it unlikely that anybody will benefit from this answer. Spend your time wiser.
– Henrik
Nov 21 at 6:56
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f517599%2fhow-many-distinct-4-letter-words-can-be-created-using-the-26-alphabets%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
$26.26.26.26$????
– user87543
Oct 7 '13 at 11:54