Partial derivative with respect to three variables

I just started learning LaTeX and I am facing problem in writing the following equation, can anyone please help me out?

enter image description here

edited Feb 22 at 14:03

Bernard

174k776207

asked Feb 22 at 13:41

shadow kh

1284

add a comment |

I just started learning LaTeX and I am facing problem in writing the following equation, can anyone please help me out?

enter image description here

edited Feb 22 at 14:03

Bernard

174k776207

asked Feb 22 at 13:41

shadow kh

1284

add a comment |

I just started learning LaTeX and I am facing problem in writing the following equation, can anyone please help me out?

enter image description here

edited Feb 22 at 14:03

Bernard

174k776207

asked Feb 22 at 13:41

shadow kh

1284

I just started learning LaTeX and I am facing problem in writing the following equation, can anyone please help me out?

enter image description here

symbols

edited Feb 22 at 14:03

Bernard

174k776207

asked Feb 22 at 13:41

shadow kh

1284

edited Feb 22 at 14:03

Bernard

174k776207

asked Feb 22 at 13:41

shadow kh

1284

edited Feb 22 at 14:03

Bernard

174k776207

edited Feb 22 at 14:03

Bernard

174k776207

edited Feb 22 at 14:03

Bernard

174k776207

asked Feb 22 at 13:41

shadow kh

1284

asked Feb 22 at 13:41

shadow kh

1284

asked Feb 22 at 13:41

shadow kh

1284

add a comment |

5 Answers
5

active

oldest

votes

A simpler code with the diffcoeff package. The order of differentiation is automatically computed — I suppose k+l is k_1+k_2+l:

documentclass{article}

usepackage{mathtools, diffcoeff}

DeclarePairedDelimiterabs{lvert}{rvert}



begin{document}



[

abs*{diffp[k_1,k_2,l]{u_0}

           {x_1, x_2, t}} leq C

]



end{document}

enter image description here

answered Feb 22 at 14:06

Bernard

174k776207

I didn't know about diffcoeff. Nice. Off topic: k_1+k_2+l just to be compatible with order of powers in denominator? :-)

– Sigur
Feb 22 at 14:09

@Sigur: it is a comparatively recent package. For the question: yes it is so. Of course, I understand that probably, $k$ denotes $k_1+k_2$, but there doesn't seem to be tools to use k in the numerator and k_1, k_2 in the denominator.

– Bernard
Feb 22 at 14:15

Is there any way to eliminate the parentheses around the variables in the denominator? IMHO, adding parentheses like this creates ambiguity and is wrong. See i.stack.imgur.com/Jc3v8.png The powers k_1, k_2 and l should be applied to the whole partial <variable> thing.

– Ruixi Zhang
Feb 23 at 13:05

It seems to be hard-coded in the package for so-called long variables (it goes into the category, I suspect, because of the indices). As it's written in latex 3, which I don't master, I have no idea how to patch it, unfortunately. Maybe, ask a new question about this feature?

– Bernard
Feb 23 at 13:54

add a comment |

You could write

[leftlvertfrac{partial^{k+l}u_0}

{{partial x_1}^{k_1}{partial x_2}^{k_2}partial t^l}rightrvert

leq C]

enter image description here

edited Feb 22 at 13:52

Sigur

26.1k457142

answered Feb 22 at 13:45

José Carlos Santos

8571217

add a comment |

one more variation ...

documentclass{article}

usepackage{mathtools}

DeclarePairedDelimiterabs{lvert}{rvert}



begin{document}

[

abs*{frac{partial^{k+l}u_0}

           {partial x_1^{k_1}partial x_2^{k_2}partial t^l}} leq C

]

end{document}

enter image description here

answered Feb 22 at 13:49

Zarko

128k868167

How did you produce the frame around the image?

– Sigur
Feb 22 at 13:55

@Sigur, it is not part of latex code, but drawn by Snipping Tool, which i use for copping image from pdf previewer to site. in it i select option Show Ink selection ...

– Zarko
Feb 22 at 14:01

Ah, OK. I use Shutter. Maybe there is such frame option there.

– Sigur
Feb 22 at 14:02

Thanks to you I've just created a plugin for Shutter to add 1px solid blue frame around the image. Now I need to know how to run it automatically when screen shot is created.

– Sigur
Feb 22 at 15:03

For the frame around formula in LaTeX, simply use boxed{...} inside the math context. Of course, to get the wide white horizontal margin you would have to manually add some space with hspace or qquad

– Jhor
Feb 22 at 20:55

add a comment |

Like this?

enter image description here

documentclass{report}

usepackage{amsmath}



begin{document}

[ Bigglvert 

   frac{partial^{k+l}u_0}

        {partial^{k_1}{x_1}, 

         partial^{k_2}{x_2}, 

         partial^{l}{t}} 

   Biggrvert leq C, 

]

end{document}

edited Feb 22 at 13:53

answered Feb 22 at 13:46

Sigur

26.1k457142

1

The notation here is wrong I’m afraid. The k_1, k_2 and l should follow the variables, not the partial signs. See i.stack.imgur.com/Jc3v8.png

– Ruixi Zhang
Feb 23 at 13:04

add a comment |

documentclass{article}



begin{document}

$ left | frac{partial^{k+1}u_0}{{partial x_1}^{k_1} {partial x_2}^{k_2} partial t^l} right | leq C $

end{document}

enter image description here

edited Feb 22 at 13:48

answered Feb 22 at 13:46

Sina Ahmadi

77338

add a comment |

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5 Answers
5

active

oldest

votes

5 Answers
5

active

oldest

votes

A simpler code with the diffcoeff package. The order of differentiation is automatically computed — I suppose k+l is k_1+k_2+l:

documentclass{article}

usepackage{mathtools, diffcoeff}

DeclarePairedDelimiterabs{lvert}{rvert}



begin{document}



[

abs*{diffp[k_1,k_2,l]{u_0}

           {x_1, x_2, t}} leq C

]



end{document}

enter image description here

answered Feb 22 at 14:06

Bernard

174k776207

I didn't know about diffcoeff. Nice. Off topic: k_1+k_2+l just to be compatible with order of powers in denominator? :-)

– Sigur
Feb 22 at 14:09

@Sigur: it is a comparatively recent package. For the question: yes it is so. Of course, I understand that probably, $k$ denotes $k_1+k_2$, but there doesn't seem to be tools to use k in the numerator and k_1, k_2 in the denominator.

– Bernard
Feb 22 at 14:15

Is there any way to eliminate the parentheses around the variables in the denominator? IMHO, adding parentheses like this creates ambiguity and is wrong. See i.stack.imgur.com/Jc3v8.png The powers k_1, k_2 and l should be applied to the whole partial <variable> thing.

– Ruixi Zhang
Feb 23 at 13:05

It seems to be hard-coded in the package for so-called long variables (it goes into the category, I suspect, because of the indices). As it's written in latex 3, which I don't master, I have no idea how to patch it, unfortunately. Maybe, ask a new question about this feature?

– Bernard
Feb 23 at 13:54

add a comment |

A simpler code with the diffcoeff package. The order of differentiation is automatically computed — I suppose k+l is k_1+k_2+l:

documentclass{article}

usepackage{mathtools, diffcoeff}

DeclarePairedDelimiterabs{lvert}{rvert}



begin{document}



[

abs*{diffp[k_1,k_2,l]{u_0}

           {x_1, x_2, t}} leq C

]



end{document}

enter image description here

answered Feb 22 at 14:06

Bernard

174k776207

I didn't know about diffcoeff. Nice. Off topic: k_1+k_2+l just to be compatible with order of powers in denominator? :-)

– Sigur
Feb 22 at 14:09

@Sigur: it is a comparatively recent package. For the question: yes it is so. Of course, I understand that probably, $k$ denotes $k_1+k_2$, but there doesn't seem to be tools to use k in the numerator and k_1, k_2 in the denominator.

– Bernard
Feb 22 at 14:15

Is there any way to eliminate the parentheses around the variables in the denominator? IMHO, adding parentheses like this creates ambiguity and is wrong. See i.stack.imgur.com/Jc3v8.png The powers k_1, k_2 and l should be applied to the whole partial <variable> thing.

– Ruixi Zhang
Feb 23 at 13:05

It seems to be hard-coded in the package for so-called long variables (it goes into the category, I suspect, because of the indices). As it's written in latex 3, which I don't master, I have no idea how to patch it, unfortunately. Maybe, ask a new question about this feature?

– Bernard
Feb 23 at 13:54

add a comment |

A simpler code with the diffcoeff package. The order of differentiation is automatically computed — I suppose k+l is k_1+k_2+l:

documentclass{article}

usepackage{mathtools, diffcoeff}

DeclarePairedDelimiterabs{lvert}{rvert}



begin{document}



[

abs*{diffp[k_1,k_2,l]{u_0}

           {x_1, x_2, t}} leq C

]



end{document}

enter image description here

answered Feb 22 at 14:06

Bernard

174k776207

A simpler code with the diffcoeff package. The order of differentiation is automatically computed — I suppose k+l is k_1+k_2+l:

documentclass{article}

usepackage{mathtools, diffcoeff}

DeclarePairedDelimiterabs{lvert}{rvert}



begin{document}



[

abs*{diffp[k_1,k_2,l]{u_0}

           {x_1, x_2, t}} leq C

]



end{document}

enter image description here

answered Feb 22 at 14:06

Bernard

174k776207

answered Feb 22 at 14:06

Bernard

174k776207

answered Feb 22 at 14:06

Bernard

174k776207

answered Feb 22 at 14:06

Bernard

174k776207

I didn't know about diffcoeff. Nice. Off topic: k_1+k_2+l just to be compatible with order of powers in denominator? :-)

– Sigur
Feb 22 at 14:09

@Sigur: it is a comparatively recent package. For the question: yes it is so. Of course, I understand that probably, $k$ denotes $k_1+k_2$, but there doesn't seem to be tools to use k in the numerator and k_1, k_2 in the denominator.

– Bernard
Feb 22 at 14:15

Is there any way to eliminate the parentheses around the variables in the denominator? IMHO, adding parentheses like this creates ambiguity and is wrong. See i.stack.imgur.com/Jc3v8.png The powers k_1, k_2 and l should be applied to the whole partial <variable> thing.

– Ruixi Zhang
Feb 23 at 13:05

It seems to be hard-coded in the package for so-called long variables (it goes into the category, I suspect, because of the indices). As it's written in latex 3, which I don't master, I have no idea how to patch it, unfortunately. Maybe, ask a new question about this feature?

– Bernard
Feb 23 at 13:54

add a comment |

I didn't know about diffcoeff. Nice. Off topic: k_1+k_2+l just to be compatible with order of powers in denominator? :-)

– Sigur
Feb 22 at 14:09

@Sigur: it is a comparatively recent package. For the question: yes it is so. Of course, I understand that probably, $k$ denotes $k_1+k_2$, but there doesn't seem to be tools to use k in the numerator and k_1, k_2 in the denominator.

– Bernard
Feb 22 at 14:15

Is there any way to eliminate the parentheses around the variables in the denominator? IMHO, adding parentheses like this creates ambiguity and is wrong. See i.stack.imgur.com/Jc3v8.png The powers k_1, k_2 and l should be applied to the whole partial <variable> thing.

– Ruixi Zhang
Feb 23 at 13:05

It seems to be hard-coded in the package for so-called long variables (it goes into the category, I suspect, because of the indices). As it's written in latex 3, which I don't master, I have no idea how to patch it, unfortunately. Maybe, ask a new question about this feature?

– Bernard
Feb 23 at 13:54

I didn't know about diffcoeff. Nice. Off topic: k_1+k_2+l just to be compatible with order of powers in denominator? :-)

– Sigur
Feb 22 at 14:09

@Sigur: it is a comparatively recent package. For the question: yes it is so. Of course, I understand that probably, $k$ denotes $k_1+k_2$, but there doesn't seem to be tools to use k in the numerator and k_1, k_2 in the denominator.

– Bernard
Feb 22 at 14:15

Is there any way to eliminate the parentheses around the variables in the denominator? IMHO, adding parentheses like this creates ambiguity and is wrong. See i.stack.imgur.com/Jc3v8.png The powers k_1, k_2 and l should be applied to the whole partial <variable> thing.

– Ruixi Zhang
Feb 23 at 13:05

It seems to be hard-coded in the package for so-called long variables (it goes into the category, I suspect, because of the indices). As it's written in latex 3, which I don't master, I have no idea how to patch it, unfortunately. Maybe, ask a new question about this feature?

– Bernard
Feb 23 at 13:54

add a comment |

You could write

[leftlvertfrac{partial^{k+l}u_0}

{{partial x_1}^{k_1}{partial x_2}^{k_2}partial t^l}rightrvert

leq C]

enter image description here

edited Feb 22 at 13:52

Sigur

26.1k457142

answered Feb 22 at 13:45

José Carlos Santos

8571217

add a comment |

You could write

[leftlvertfrac{partial^{k+l}u_0}

{{partial x_1}^{k_1}{partial x_2}^{k_2}partial t^l}rightrvert

leq C]

enter image description here

edited Feb 22 at 13:52

Sigur

26.1k457142

answered Feb 22 at 13:45

José Carlos Santos

8571217

add a comment |

You could write

[leftlvertfrac{partial^{k+l}u_0}

{{partial x_1}^{k_1}{partial x_2}^{k_2}partial t^l}rightrvert

leq C]

enter image description here

edited Feb 22 at 13:52

Sigur

26.1k457142

answered Feb 22 at 13:45

José Carlos Santos

8571217

You could write

[leftlvertfrac{partial^{k+l}u_0}

{{partial x_1}^{k_1}{partial x_2}^{k_2}partial t^l}rightrvert

leq C]

enter image description here

edited Feb 22 at 13:52

Sigur

26.1k457142

answered Feb 22 at 13:45

José Carlos Santos

8571217

edited Feb 22 at 13:52

Sigur

26.1k457142

edited Feb 22 at 13:52

Sigur

26.1k457142

edited Feb 22 at 13:52

Sigur

26.1k457142

answered Feb 22 at 13:45

José Carlos Santos

8571217

answered Feb 22 at 13:45

José Carlos Santos

8571217

answered Feb 22 at 13:45

José Carlos Santos

8571217

add a comment |

one more variation ...

documentclass{article}

usepackage{mathtools}

DeclarePairedDelimiterabs{lvert}{rvert}



begin{document}

[

abs*{frac{partial^{k+l}u_0}

           {partial x_1^{k_1}partial x_2^{k_2}partial t^l}} leq C

]

end{document}

enter image description here

answered Feb 22 at 13:49

Zarko

128k868167

How did you produce the frame around the image?

– Sigur
Feb 22 at 13:55

@Sigur, it is not part of latex code, but drawn by Snipping Tool, which i use for copping image from pdf previewer to site. in it i select option Show Ink selection ...

– Zarko
Feb 22 at 14:01

Ah, OK. I use Shutter. Maybe there is such frame option there.

– Sigur
Feb 22 at 14:02

Thanks to you I've just created a plugin for Shutter to add 1px solid blue frame around the image. Now I need to know how to run it automatically when screen shot is created.

– Sigur
Feb 22 at 15:03

For the frame around formula in LaTeX, simply use boxed{...} inside the math context. Of course, to get the wide white horizontal margin you would have to manually add some space with hspace or qquad

– Jhor
Feb 22 at 20:55

add a comment |

one more variation ...

documentclass{article}

usepackage{mathtools}

DeclarePairedDelimiterabs{lvert}{rvert}



begin{document}

[

abs*{frac{partial^{k+l}u_0}

           {partial x_1^{k_1}partial x_2^{k_2}partial t^l}} leq C

]

end{document}

enter image description here

answered Feb 22 at 13:49

Zarko

128k868167

How did you produce the frame around the image?

– Sigur
Feb 22 at 13:55

@Sigur, it is not part of latex code, but drawn by Snipping Tool, which i use for copping image from pdf previewer to site. in it i select option Show Ink selection ...

– Zarko
Feb 22 at 14:01

Ah, OK. I use Shutter. Maybe there is such frame option there.

– Sigur
Feb 22 at 14:02

Thanks to you I've just created a plugin for Shutter to add 1px solid blue frame around the image. Now I need to know how to run it automatically when screen shot is created.

– Sigur
Feb 22 at 15:03

For the frame around formula in LaTeX, simply use boxed{...} inside the math context. Of course, to get the wide white horizontal margin you would have to manually add some space with hspace or qquad

– Jhor
Feb 22 at 20:55

add a comment |

one more variation ...

documentclass{article}

usepackage{mathtools}

DeclarePairedDelimiterabs{lvert}{rvert}



begin{document}

[

abs*{frac{partial^{k+l}u_0}

           {partial x_1^{k_1}partial x_2^{k_2}partial t^l}} leq C

]

end{document}

enter image description here

answered Feb 22 at 13:49

Zarko

128k868167

one more variation ...

documentclass{article}

usepackage{mathtools}

DeclarePairedDelimiterabs{lvert}{rvert}



begin{document}

[

abs*{frac{partial^{k+l}u_0}

           {partial x_1^{k_1}partial x_2^{k_2}partial t^l}} leq C

]

end{document}

enter image description here

answered Feb 22 at 13:49

Zarko

128k868167

answered Feb 22 at 13:49

Zarko

128k868167

answered Feb 22 at 13:49

Zarko

128k868167

answered Feb 22 at 13:49

Zarko

128k868167

How did you produce the frame around the image?

– Sigur
Feb 22 at 13:55

@Sigur, it is not part of latex code, but drawn by Snipping Tool, which i use for copping image from pdf previewer to site. in it i select option Show Ink selection ...

– Zarko
Feb 22 at 14:01

Ah, OK. I use Shutter. Maybe there is such frame option there.

– Sigur
Feb 22 at 14:02

Thanks to you I've just created a plugin for Shutter to add 1px solid blue frame around the image. Now I need to know how to run it automatically when screen shot is created.

– Sigur
Feb 22 at 15:03

For the frame around formula in LaTeX, simply use boxed{...} inside the math context. Of course, to get the wide white horizontal margin you would have to manually add some space with hspace or qquad

– Jhor
Feb 22 at 20:55

add a comment |

How did you produce the frame around the image?

– Sigur
Feb 22 at 13:55

@Sigur, it is not part of latex code, but drawn by Snipping Tool, which i use for copping image from pdf previewer to site. in it i select option Show Ink selection ...

– Zarko
Feb 22 at 14:01

Ah, OK. I use Shutter. Maybe there is such frame option there.

– Sigur
Feb 22 at 14:02

Thanks to you I've just created a plugin for Shutter to add 1px solid blue frame around the image. Now I need to know how to run it automatically when screen shot is created.

– Sigur
Feb 22 at 15:03

For the frame around formula in LaTeX, simply use boxed{...} inside the math context. Of course, to get the wide white horizontal margin you would have to manually add some space with hspace or qquad

– Jhor
Feb 22 at 20:55

How did you produce the frame around the image?

– Sigur
Feb 22 at 13:55

@Sigur, it is not part of latex code, but drawn by Snipping Tool, which i use for copping image from pdf previewer to site. in it i select option Show Ink selection ...

– Zarko
Feb 22 at 14:01

Ah, OK. I use Shutter. Maybe there is such frame option there.

– Sigur
Feb 22 at 14:02

Thanks to you I've just created a plugin for Shutter to add 1px solid blue frame around the image. Now I need to know how to run it automatically when screen shot is created.

– Sigur
Feb 22 at 15:03

For the frame around formula in LaTeX, simply use boxed{...} inside the math context. Of course, to get the wide white horizontal margin you would have to manually add some space with hspace or qquad

– Jhor
Feb 22 at 20:55

add a comment |

Like this?

enter image description here

documentclass{report}

usepackage{amsmath}



begin{document}

[ Bigglvert 

   frac{partial^{k+l}u_0}

        {partial^{k_1}{x_1}, 

         partial^{k_2}{x_2}, 

         partial^{l}{t}} 

   Biggrvert leq C, 

]

end{document}

edited Feb 22 at 13:53

answered Feb 22 at 13:46

Sigur

26.1k457142

1

The notation here is wrong I’m afraid. The k_1, k_2 and l should follow the variables, not the partial signs. See i.stack.imgur.com/Jc3v8.png

– Ruixi Zhang
Feb 23 at 13:04

add a comment |

Like this?

enter image description here

documentclass{report}

usepackage{amsmath}



begin{document}

[ Bigglvert 

   frac{partial^{k+l}u_0}

        {partial^{k_1}{x_1}, 

         partial^{k_2}{x_2}, 

         partial^{l}{t}} 

   Biggrvert leq C, 

]

end{document}

edited Feb 22 at 13:53

answered Feb 22 at 13:46

Sigur

26.1k457142

1

The notation here is wrong I’m afraid. The k_1, k_2 and l should follow the variables, not the partial signs. See i.stack.imgur.com/Jc3v8.png

– Ruixi Zhang
Feb 23 at 13:04

add a comment |

Like this?

enter image description here

documentclass{report}

usepackage{amsmath}



begin{document}

[ Bigglvert 

   frac{partial^{k+l}u_0}

        {partial^{k_1}{x_1}, 

         partial^{k_2}{x_2}, 

         partial^{l}{t}} 

   Biggrvert leq C, 

]

end{document}

edited Feb 22 at 13:53

answered Feb 22 at 13:46

Sigur

26.1k457142

Like this?

enter image description here

documentclass{report}

usepackage{amsmath}



begin{document}

[ Bigglvert 

   frac{partial^{k+l}u_0}

        {partial^{k_1}{x_1}, 

         partial^{k_2}{x_2}, 

         partial^{l}{t}} 

   Biggrvert leq C, 

]

end{document}

edited Feb 22 at 13:53

answered Feb 22 at 13:46

Sigur

26.1k457142

edited Feb 22 at 13:53

answered Feb 22 at 13:46

Sigur

26.1k457142

answered Feb 22 at 13:46

Sigur

26.1k457142

answered Feb 22 at 13:46

Sigur

26.1k457142

1

The notation here is wrong I’m afraid. The k_1, k_2 and l should follow the variables, not the partial signs. See i.stack.imgur.com/Jc3v8.png

– Ruixi Zhang
Feb 23 at 13:04

add a comment |

1

The notation here is wrong I’m afraid. The k_1, k_2 and l should follow the variables, not the partial signs. See i.stack.imgur.com/Jc3v8.png

– Ruixi Zhang
Feb 23 at 13:04

The notation here is wrong I’m afraid. The k_1, k_2 and l should follow the variables, not the partial signs. See i.stack.imgur.com/Jc3v8.png

– Ruixi Zhang
Feb 23 at 13:04

add a comment |

documentclass{article}



begin{document}

$ left | frac{partial^{k+1}u_0}{{partial x_1}^{k_1} {partial x_2}^{k_2} partial t^l} right | leq C $

end{document}

enter image description here

edited Feb 22 at 13:48

answered Feb 22 at 13:46

Sina Ahmadi

77338

add a comment |

documentclass{article}



begin{document}

$ left | frac{partial^{k+1}u_0}{{partial x_1}^{k_1} {partial x_2}^{k_2} partial t^l} right | leq C $

end{document}

enter image description here

edited Feb 22 at 13:48

answered Feb 22 at 13:46

Sina Ahmadi

77338

add a comment |

documentclass{article}



begin{document}

$ left | frac{partial^{k+1}u_0}{{partial x_1}^{k_1} {partial x_2}^{k_2} partial t^l} right | leq C $

end{document}

enter image description here

edited Feb 22 at 13:48

answered Feb 22 at 13:46

Sina Ahmadi

77338

documentclass{article}



begin{document}

$ left | frac{partial^{k+1}u_0}{{partial x_1}^{k_1} {partial x_2}^{k_2} partial t^l} right | leq C $

end{document}

enter image description here

edited Feb 22 at 13:48

answered Feb 22 at 13:46

Sina Ahmadi

77338

edited Feb 22 at 13:48

answered Feb 22 at 13:46

Sina Ahmadi

77338

answered Feb 22 at 13:46

Sina Ahmadi

77338

answered Feb 22 at 13:46

Sina Ahmadi

77338

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