Add number in the string after each letter
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D to A3B1C7D1.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
edited Feb 22 at 11:28
markus
14.8k11336
asked Feb 22 at 11:08
WangWang
20119
add a comment |
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D to A3B1C7D1.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
edited Feb 22 at 11:28
markus
14.8k11336
asked Feb 22 at 11:08
WangWang
20119
add a comment |
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D to A3B1C7D1.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
edited Feb 22 at 11:28
markus
14.8k11336
asked Feb 22 at 11:08
WangWang
20119
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D to A3B1C7D1.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
r regex string
edited Feb 22 at 11:28
markus
14.8k11336
asked Feb 22 at 11:08
WangWang
20119
edited Feb 22 at 11:28
markus
14.8k11336
asked Feb 22 at 11:08
WangWang
20119
edited Feb 22 at 11:28
markus
14.8k11336
edited Feb 22 at 11:28
markus
14.8k11336
edited Feb 22 at 11:28
markus
14.8k11336
14.8k11336
asked Feb 22 at 11:08
WangWang
20119
asked Feb 22 at 11:08
WangWang
20119
asked Feb 22 at 11:08
WangWang
20119
20119
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1 in this case.
answered Feb 22 at 11:38
arg0nautarg0naut
6,0141421
add a comment |
Find all (uppercase) letters ([A-Z]) that is not followed by a number and replace it with that string + 1:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
answered Feb 22 at 13:18
sindri_baldursindri_baldur
8,3151033
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep all positions that do not end with a number, and paste a 1 to them.
answered Feb 22 at 11:18
boskiboski
661415
9
Almost. Check the second element it should be"A3B1C3"
– markus
Feb 22 at 11:19
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1 in this case.
answered Feb 22 at 11:38
arg0nautarg0naut
6,0141421
add a comment |
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1 in this case.
answered Feb 22 at 11:38
arg0nautarg0naut
6,0141421
add a comment |
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1 in this case.
answered Feb 22 at 11:38
arg0nautarg0naut
6,0141421
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1 in this case.
answered Feb 22 at 11:38
arg0nautarg0naut
6,0141421
edited Feb 22 at 11:46
answered Feb 22 at 11:38
arg0nautarg0naut
6,0141421
answered Feb 22 at 11:38
arg0nautarg0naut
6,0141421
answered Feb 22 at 11:38
arg0nautarg0naut
6,0141421
6,0141421
add a comment |
add a comment |
Find all (uppercase) letters ([A-Z]) that is not followed by a number and replace it with that string + 1:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
answered Feb 22 at 13:18
sindri_baldursindri_baldur
8,3151033
add a comment |
Find all (uppercase) letters ([A-Z]) that is not followed by a number and replace it with that string + 1:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
answered Feb 22 at 13:18
sindri_baldursindri_baldur
8,3151033
add a comment |
Find all (uppercase) letters ([A-Z]) that is not followed by a number and replace it with that string + 1:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
answered Feb 22 at 13:18
sindri_baldursindri_baldur
8,3151033
Find all (uppercase) letters ([A-Z]) that is not followed by a number and replace it with that string + 1:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
answered Feb 22 at 13:18
sindri_baldursindri_baldur
8,3151033
edited Feb 22 at 13:44
answered Feb 22 at 13:18
sindri_baldursindri_baldur
8,3151033
answered Feb 22 at 13:18
sindri_baldursindri_baldur
8,3151033
answered Feb 22 at 13:18
sindri_baldursindri_baldur
8,3151033
8,3151033
add a comment |
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep all positions that do not end with a number, and paste a 1 to them.
answered Feb 22 at 11:18
boskiboski
661415
9
Almost. Check the second element it should be"A3B1C3"
– markus
Feb 22 at 11:19
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep all positions that do not end with a number, and paste a 1 to them.
answered Feb 22 at 11:18
boskiboski
661415
9
Almost. Check the second element it should be"A3B1C3"
– markus
Feb 22 at 11:19
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep all positions that do not end with a number, and paste a 1 to them.
answered Feb 22 at 11:18
boskiboski
661415
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep all positions that do not end with a number, and paste a 1 to them.
answered Feb 22 at 11:18
boskiboski
661415
answered Feb 22 at 11:18
boskiboski
661415
answered Feb 22 at 11:18
boskiboski
661415
answered Feb 22 at 11:18
boskiboski
661415
661415
9
Almost. Check the second element it should be"A3B1C3"
– markus
Feb 22 at 11:19
add a comment |
9
Almost. Check the second element it should be"A3B1C3"
– markus
Feb 22 at 11:19
9
9
Almost. Check the second element it should be
"A3B1C3"– markus
Feb 22 at 11:19
Almost. Check the second element it should be
"A3B1C3"– markus
Feb 22 at 11:19
add a comment |
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