Linear polynomial whose multiplication with a given quadratic polynomial vanishes in the Jacobi ring












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$begingroup$


Let $mathbb C[x_1,ldots,x_n]$ be the polynomial ring of $n$ varibles, and $mathbb C[x_1,ldots,x_n]_d$ be its homogeneous degree $d$ piece. Let $Fin mathbb C[x_1,ldots,x_n]_3$ be a homogeneous cubic polynomial which has smooth zero locus. Then
$$P=mathbb C{x_i partial_j F}$$
is a linear space of dimension $n^2$ (by smoothness). For any homogeneous quadratic polynomial $q in mathbb C[x_1,ldots,x_n]_2$, we define
$$n(q)=dim{fin mathbb C[x_1,ldots,x_n]_1: fcdot q in P }$$
which can be also formulated as the dimension of the set of linear polynomial $f$ whose multiplication with $q$ vanishes in the Jacobi ring.



For example, easy to see $n(q)=n$ if and only if $q=sum c_i partial_i F$.



I computed several examples, and it seems the following is always hold:




If $qneq sum c_i partial_i F$, then $n(q)leq2$.




But I don't know how to prove it. I can show it in some special case, but in general ${partial_iF}$ is quite mysterious to me. Also it seems the function $n(q)$ is hard to control.



Could someone help me? Thanks in advance!










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$endgroup$

















    4












    $begingroup$


    Let $mathbb C[x_1,ldots,x_n]$ be the polynomial ring of $n$ varibles, and $mathbb C[x_1,ldots,x_n]_d$ be its homogeneous degree $d$ piece. Let $Fin mathbb C[x_1,ldots,x_n]_3$ be a homogeneous cubic polynomial which has smooth zero locus. Then
    $$P=mathbb C{x_i partial_j F}$$
    is a linear space of dimension $n^2$ (by smoothness). For any homogeneous quadratic polynomial $q in mathbb C[x_1,ldots,x_n]_2$, we define
    $$n(q)=dim{fin mathbb C[x_1,ldots,x_n]_1: fcdot q in P }$$
    which can be also formulated as the dimension of the set of linear polynomial $f$ whose multiplication with $q$ vanishes in the Jacobi ring.



    For example, easy to see $n(q)=n$ if and only if $q=sum c_i partial_i F$.



    I computed several examples, and it seems the following is always hold:




    If $qneq sum c_i partial_i F$, then $n(q)leq2$.




    But I don't know how to prove it. I can show it in some special case, but in general ${partial_iF}$ is quite mysterious to me. Also it seems the function $n(q)$ is hard to control.



    Could someone help me? Thanks in advance!










    share|cite|improve this question









    $endgroup$















      4












      4








      4


      2



      $begingroup$


      Let $mathbb C[x_1,ldots,x_n]$ be the polynomial ring of $n$ varibles, and $mathbb C[x_1,ldots,x_n]_d$ be its homogeneous degree $d$ piece. Let $Fin mathbb C[x_1,ldots,x_n]_3$ be a homogeneous cubic polynomial which has smooth zero locus. Then
      $$P=mathbb C{x_i partial_j F}$$
      is a linear space of dimension $n^2$ (by smoothness). For any homogeneous quadratic polynomial $q in mathbb C[x_1,ldots,x_n]_2$, we define
      $$n(q)=dim{fin mathbb C[x_1,ldots,x_n]_1: fcdot q in P }$$
      which can be also formulated as the dimension of the set of linear polynomial $f$ whose multiplication with $q$ vanishes in the Jacobi ring.



      For example, easy to see $n(q)=n$ if and only if $q=sum c_i partial_i F$.



      I computed several examples, and it seems the following is always hold:




      If $qneq sum c_i partial_i F$, then $n(q)leq2$.




      But I don't know how to prove it. I can show it in some special case, but in general ${partial_iF}$ is quite mysterious to me. Also it seems the function $n(q)$ is hard to control.



      Could someone help me? Thanks in advance!










      share|cite|improve this question









      $endgroup$




      Let $mathbb C[x_1,ldots,x_n]$ be the polynomial ring of $n$ varibles, and $mathbb C[x_1,ldots,x_n]_d$ be its homogeneous degree $d$ piece. Let $Fin mathbb C[x_1,ldots,x_n]_3$ be a homogeneous cubic polynomial which has smooth zero locus. Then
      $$P=mathbb C{x_i partial_j F}$$
      is a linear space of dimension $n^2$ (by smoothness). For any homogeneous quadratic polynomial $q in mathbb C[x_1,ldots,x_n]_2$, we define
      $$n(q)=dim{fin mathbb C[x_1,ldots,x_n]_1: fcdot q in P }$$
      which can be also formulated as the dimension of the set of linear polynomial $f$ whose multiplication with $q$ vanishes in the Jacobi ring.



      For example, easy to see $n(q)=n$ if and only if $q=sum c_i partial_i F$.



      I computed several examples, and it seems the following is always hold:




      If $qneq sum c_i partial_i F$, then $n(q)leq2$.




      But I don't know how to prove it. I can show it in some special case, but in general ${partial_iF}$ is quite mysterious to me. Also it seems the function $n(q)$ is hard to control.



      Could someone help me? Thanks in advance!







      abstract-algebra algebraic-geometry polynomials homogeneous-equation






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      share|cite|improve this question











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      asked Dec 10 '18 at 21:03









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