Is this Bayesian Network probability correct?
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I just extended a bayesian network that was on a ppt into this form. I'm trying to get P(A,B,C,D,E) and I think it's p(A)P(B)P(C|A,B)P(D|C)P(E|C) but as I'm not sure, just wanted to check if it is correct.
probability bayesian bayesian-network
asked Dec 9 '18 at 13:54
PuffedRiceCrackersPuffedRiceCrackers
32
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add a comment |
$begingroup$
I just extended a bayesian network that was on a ppt into this form. I'm trying to get P(A,B,C,D,E) and I think it's p(A)P(B)P(C|A,B)P(D|C)P(E|C) but as I'm not sure, just wanted to check if it is correct.
probability bayesian bayesian-network
asked Dec 9 '18 at 13:54
PuffedRiceCrackersPuffedRiceCrackers
32
$endgroup$
add a comment |
$begingroup$
I just extended a bayesian network that was on a ppt into this form. I'm trying to get P(A,B,C,D,E) and I think it's p(A)P(B)P(C|A,B)P(D|C)P(E|C) but as I'm not sure, just wanted to check if it is correct.
probability bayesian bayesian-network
asked Dec 9 '18 at 13:54
PuffedRiceCrackersPuffedRiceCrackers
32
$endgroup$
I just extended a bayesian network that was on a ppt into this form. I'm trying to get P(A,B,C,D,E) and I think it's p(A)P(B)P(C|A,B)P(D|C)P(E|C) but as I'm not sure, just wanted to check if it is correct.
probability bayesian bayesian-network
probability bayesian bayesian-network
asked Dec 9 '18 at 13:54
PuffedRiceCrackersPuffedRiceCrackers
32
asked Dec 9 '18 at 13:54
PuffedRiceCrackersPuffedRiceCrackers
32
asked Dec 9 '18 at 13:54
PuffedRiceCrackersPuffedRiceCrackers
32
asked Dec 9 '18 at 13:54
PuffedRiceCrackersPuffedRiceCrackers
32
asked Dec 9 '18 at 13:54
PuffedRiceCrackersPuffedRiceCrackers
32
32
add a comment |
add a comment |
1 Answer
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Welcome to MSE! The general form is
$p_{X_1,ldots,X_n} = prod_i p_{X_imid pi(X_i)}$
where $pi(X_i)$ are the parents of $X_i$.
Your form is correct.
answered Dec 9 '18 at 13:58
WuestenfuxWuestenfux
4,2871413
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
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$begingroup$
Welcome to MSE! The general form is
$p_{X_1,ldots,X_n} = prod_i p_{X_imid pi(X_i)}$
where $pi(X_i)$ are the parents of $X_i$.
Your form is correct.
answered Dec 9 '18 at 13:58
WuestenfuxWuestenfux
4,2871413
$endgroup$
add a comment |
$begingroup$
Welcome to MSE! The general form is
$p_{X_1,ldots,X_n} = prod_i p_{X_imid pi(X_i)}$
where $pi(X_i)$ are the parents of $X_i$.
Your form is correct.
answered Dec 9 '18 at 13:58
WuestenfuxWuestenfux
4,2871413
$endgroup$
add a comment |
$begingroup$
Welcome to MSE! The general form is
$p_{X_1,ldots,X_n} = prod_i p_{X_imid pi(X_i)}$
where $pi(X_i)$ are the parents of $X_i$.
Your form is correct.
answered Dec 9 '18 at 13:58
WuestenfuxWuestenfux
4,2871413
$endgroup$
Welcome to MSE! The general form is
$p_{X_1,ldots,X_n} = prod_i p_{X_imid pi(X_i)}$
where $pi(X_i)$ are the parents of $X_i$.
Your form is correct.
answered Dec 9 '18 at 13:58
WuestenfuxWuestenfux
4,2871413
answered Dec 9 '18 at 13:58
WuestenfuxWuestenfux
4,2871413
answered Dec 9 '18 at 13:58
WuestenfuxWuestenfux
4,2871413
answered Dec 9 '18 at 13:58
WuestenfuxWuestenfux
4,2871413
4,2871413
add a comment |
add a comment |
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