Is it true that $Asubset f^{-1}(f(A))$ if and only if $f$ is injective?












1














I'm doing some homework and I have trouble with some problems.
Let $X,Y$ be sets, $f:Xmapsto Y$, $A subset X$, $Csubset Y$.
I need to prove that $Asubset f^{-1}(f(A))$ if and only if $f$ is injective; and that $f(f^{-1}(C))subset C$ if and only if $f$ is surjective.
I tried to apply the definitions but I just got confused because of $f^{-1}(f(A))$, so i could use some advice.










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  • It is not enough that $A subset f^{-1}(f(A))$ for some $A subset X$, because let $f: {1, 2, 3} rightarrow {1, 2}$ with $f(1) = 1$, $f(2) = f(3) = 2$ and $A = {1}$ then $A subset f^{-1}(f(A))$ but f is not injective.
    – BurningKarl
    Nov 26 at 22:24










  • These properties are not true as stated. Are you sure this is what your homework says?
    – Arnaud D.
    Nov 26 at 22:25










  • @ArnaudD I'm not sure. That's how I have the exercises in the copy my teacher gave me.
    – Armando Rosas
    Nov 27 at 0:26
















1














I'm doing some homework and I have trouble with some problems.
Let $X,Y$ be sets, $f:Xmapsto Y$, $A subset X$, $Csubset Y$.
I need to prove that $Asubset f^{-1}(f(A))$ if and only if $f$ is injective; and that $f(f^{-1}(C))subset C$ if and only if $f$ is surjective.
I tried to apply the definitions but I just got confused because of $f^{-1}(f(A))$, so i could use some advice.










share|cite|improve this question
























  • It is not enough that $A subset f^{-1}(f(A))$ for some $A subset X$, because let $f: {1, 2, 3} rightarrow {1, 2}$ with $f(1) = 1$, $f(2) = f(3) = 2$ and $A = {1}$ then $A subset f^{-1}(f(A))$ but f is not injective.
    – BurningKarl
    Nov 26 at 22:24










  • These properties are not true as stated. Are you sure this is what your homework says?
    – Arnaud D.
    Nov 26 at 22:25










  • @ArnaudD I'm not sure. That's how I have the exercises in the copy my teacher gave me.
    – Armando Rosas
    Nov 27 at 0:26














1












1








1







I'm doing some homework and I have trouble with some problems.
Let $X,Y$ be sets, $f:Xmapsto Y$, $A subset X$, $Csubset Y$.
I need to prove that $Asubset f^{-1}(f(A))$ if and only if $f$ is injective; and that $f(f^{-1}(C))subset C$ if and only if $f$ is surjective.
I tried to apply the definitions but I just got confused because of $f^{-1}(f(A))$, so i could use some advice.










share|cite|improve this question















I'm doing some homework and I have trouble with some problems.
Let $X,Y$ be sets, $f:Xmapsto Y$, $A subset X$, $Csubset Y$.
I need to prove that $Asubset f^{-1}(f(A))$ if and only if $f$ is injective; and that $f(f^{-1}(C))subset C$ if and only if $f$ is surjective.
I tried to apply the definitions but I just got confused because of $f^{-1}(f(A))$, so i could use some advice.







analysis elementary-set-theory






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edited Nov 27 at 0:20

























asked Nov 26 at 22:14









Armando Rosas

525




525












  • It is not enough that $A subset f^{-1}(f(A))$ for some $A subset X$, because let $f: {1, 2, 3} rightarrow {1, 2}$ with $f(1) = 1$, $f(2) = f(3) = 2$ and $A = {1}$ then $A subset f^{-1}(f(A))$ but f is not injective.
    – BurningKarl
    Nov 26 at 22:24










  • These properties are not true as stated. Are you sure this is what your homework says?
    – Arnaud D.
    Nov 26 at 22:25










  • @ArnaudD I'm not sure. That's how I have the exercises in the copy my teacher gave me.
    – Armando Rosas
    Nov 27 at 0:26


















  • It is not enough that $A subset f^{-1}(f(A))$ for some $A subset X$, because let $f: {1, 2, 3} rightarrow {1, 2}$ with $f(1) = 1$, $f(2) = f(3) = 2$ and $A = {1}$ then $A subset f^{-1}(f(A))$ but f is not injective.
    – BurningKarl
    Nov 26 at 22:24










  • These properties are not true as stated. Are you sure this is what your homework says?
    – Arnaud D.
    Nov 26 at 22:25










  • @ArnaudD I'm not sure. That's how I have the exercises in the copy my teacher gave me.
    – Armando Rosas
    Nov 27 at 0:26
















It is not enough that $A subset f^{-1}(f(A))$ for some $A subset X$, because let $f: {1, 2, 3} rightarrow {1, 2}$ with $f(1) = 1$, $f(2) = f(3) = 2$ and $A = {1}$ then $A subset f^{-1}(f(A))$ but f is not injective.
– BurningKarl
Nov 26 at 22:24




It is not enough that $A subset f^{-1}(f(A))$ for some $A subset X$, because let $f: {1, 2, 3} rightarrow {1, 2}$ with $f(1) = 1$, $f(2) = f(3) = 2$ and $A = {1}$ then $A subset f^{-1}(f(A))$ but f is not injective.
– BurningKarl
Nov 26 at 22:24












These properties are not true as stated. Are you sure this is what your homework says?
– Arnaud D.
Nov 26 at 22:25




These properties are not true as stated. Are you sure this is what your homework says?
– Arnaud D.
Nov 26 at 22:25












@ArnaudD I'm not sure. That's how I have the exercises in the copy my teacher gave me.
– Armando Rosas
Nov 27 at 0:26




@ArnaudD I'm not sure. That's how I have the exercises in the copy my teacher gave me.
– Armando Rosas
Nov 27 at 0:26










1 Answer
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Note that $f^{-1}(f(C))$ should be $f(f^{-1}(C))$.





The inclusion $Asubset f^{-1}(f(A))$ is true for every map and every subset of the map's domain.



Indeed, if $ain A$, then $f(a)in f(A)$ (by definition), which is to say that $ain f^{-1}(f(A))$.



Similarly, $f(f^{-1}(C))subset C$ holds for every map $f$ and every subset of the map's codomain. Indeed, if $yin f(f^{-1}(C))$, then $y=f(x)$, for some $xin f^{-1}(C)$. But then $f(x)in C$, which is to say $yin C$.



What you want to show is that




$fcolon Xto Y$ is injective if and only if, for every $Asubset X$, $A=f^{-1}(f(A))$




and similarly that




$fcolon Xto Y$ is surjective if and only if, for every $Csubset Y$, $C=f(f^{-1}(C))$




Hint for the $Rightarrow$ direction in the first statement: you have to prove that $f^{-1}(f(A))subset A$. Take $xin f^{-1}(f(A))$; then $f(x)in f(A)$. Apply injectivity.






share|cite|improve this answer





















  • I made the correction. The same hint holds for the surjectivity proposition?
    – Armando Rosas
    Nov 27 at 0:24










  • @ArmandoRosas Very similar. Don't forget to prove also the $Leftarrow$ directions.
    – egreg
    Nov 27 at 7:46










  • I have trouble with the $Leftarrow$ proof of surjectivity. I let c be in C , then c it's an element of $f(f^{-1}(C))$, can i directly say that f is surjective here? Because then $c=f(x)$ with $xin f^{-1}(C)subset X$, is it not?
    – Armando Rosas
    Nov 27 at 22:03










  • @ArmandoRosas For $C=Y$, $Y=f(f^{-1}(Y))=f(X)$.
    – egreg
    Nov 27 at 22:19











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1 Answer
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1 Answer
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4














Note that $f^{-1}(f(C))$ should be $f(f^{-1}(C))$.





The inclusion $Asubset f^{-1}(f(A))$ is true for every map and every subset of the map's domain.



Indeed, if $ain A$, then $f(a)in f(A)$ (by definition), which is to say that $ain f^{-1}(f(A))$.



Similarly, $f(f^{-1}(C))subset C$ holds for every map $f$ and every subset of the map's codomain. Indeed, if $yin f(f^{-1}(C))$, then $y=f(x)$, for some $xin f^{-1}(C)$. But then $f(x)in C$, which is to say $yin C$.



What you want to show is that




$fcolon Xto Y$ is injective if and only if, for every $Asubset X$, $A=f^{-1}(f(A))$




and similarly that




$fcolon Xto Y$ is surjective if and only if, for every $Csubset Y$, $C=f(f^{-1}(C))$




Hint for the $Rightarrow$ direction in the first statement: you have to prove that $f^{-1}(f(A))subset A$. Take $xin f^{-1}(f(A))$; then $f(x)in f(A)$. Apply injectivity.






share|cite|improve this answer





















  • I made the correction. The same hint holds for the surjectivity proposition?
    – Armando Rosas
    Nov 27 at 0:24










  • @ArmandoRosas Very similar. Don't forget to prove also the $Leftarrow$ directions.
    – egreg
    Nov 27 at 7:46










  • I have trouble with the $Leftarrow$ proof of surjectivity. I let c be in C , then c it's an element of $f(f^{-1}(C))$, can i directly say that f is surjective here? Because then $c=f(x)$ with $xin f^{-1}(C)subset X$, is it not?
    – Armando Rosas
    Nov 27 at 22:03










  • @ArmandoRosas For $C=Y$, $Y=f(f^{-1}(Y))=f(X)$.
    – egreg
    Nov 27 at 22:19
















4














Note that $f^{-1}(f(C))$ should be $f(f^{-1}(C))$.





The inclusion $Asubset f^{-1}(f(A))$ is true for every map and every subset of the map's domain.



Indeed, if $ain A$, then $f(a)in f(A)$ (by definition), which is to say that $ain f^{-1}(f(A))$.



Similarly, $f(f^{-1}(C))subset C$ holds for every map $f$ and every subset of the map's codomain. Indeed, if $yin f(f^{-1}(C))$, then $y=f(x)$, for some $xin f^{-1}(C)$. But then $f(x)in C$, which is to say $yin C$.



What you want to show is that




$fcolon Xto Y$ is injective if and only if, for every $Asubset X$, $A=f^{-1}(f(A))$




and similarly that




$fcolon Xto Y$ is surjective if and only if, for every $Csubset Y$, $C=f(f^{-1}(C))$




Hint for the $Rightarrow$ direction in the first statement: you have to prove that $f^{-1}(f(A))subset A$. Take $xin f^{-1}(f(A))$; then $f(x)in f(A)$. Apply injectivity.






share|cite|improve this answer





















  • I made the correction. The same hint holds for the surjectivity proposition?
    – Armando Rosas
    Nov 27 at 0:24










  • @ArmandoRosas Very similar. Don't forget to prove also the $Leftarrow$ directions.
    – egreg
    Nov 27 at 7:46










  • I have trouble with the $Leftarrow$ proof of surjectivity. I let c be in C , then c it's an element of $f(f^{-1}(C))$, can i directly say that f is surjective here? Because then $c=f(x)$ with $xin f^{-1}(C)subset X$, is it not?
    – Armando Rosas
    Nov 27 at 22:03










  • @ArmandoRosas For $C=Y$, $Y=f(f^{-1}(Y))=f(X)$.
    – egreg
    Nov 27 at 22:19














4












4








4






Note that $f^{-1}(f(C))$ should be $f(f^{-1}(C))$.





The inclusion $Asubset f^{-1}(f(A))$ is true for every map and every subset of the map's domain.



Indeed, if $ain A$, then $f(a)in f(A)$ (by definition), which is to say that $ain f^{-1}(f(A))$.



Similarly, $f(f^{-1}(C))subset C$ holds for every map $f$ and every subset of the map's codomain. Indeed, if $yin f(f^{-1}(C))$, then $y=f(x)$, for some $xin f^{-1}(C)$. But then $f(x)in C$, which is to say $yin C$.



What you want to show is that




$fcolon Xto Y$ is injective if and only if, for every $Asubset X$, $A=f^{-1}(f(A))$




and similarly that




$fcolon Xto Y$ is surjective if and only if, for every $Csubset Y$, $C=f(f^{-1}(C))$




Hint for the $Rightarrow$ direction in the first statement: you have to prove that $f^{-1}(f(A))subset A$. Take $xin f^{-1}(f(A))$; then $f(x)in f(A)$. Apply injectivity.






share|cite|improve this answer












Note that $f^{-1}(f(C))$ should be $f(f^{-1}(C))$.





The inclusion $Asubset f^{-1}(f(A))$ is true for every map and every subset of the map's domain.



Indeed, if $ain A$, then $f(a)in f(A)$ (by definition), which is to say that $ain f^{-1}(f(A))$.



Similarly, $f(f^{-1}(C))subset C$ holds for every map $f$ and every subset of the map's codomain. Indeed, if $yin f(f^{-1}(C))$, then $y=f(x)$, for some $xin f^{-1}(C)$. But then $f(x)in C$, which is to say $yin C$.



What you want to show is that




$fcolon Xto Y$ is injective if and only if, for every $Asubset X$, $A=f^{-1}(f(A))$




and similarly that




$fcolon Xto Y$ is surjective if and only if, for every $Csubset Y$, $C=f(f^{-1}(C))$




Hint for the $Rightarrow$ direction in the first statement: you have to prove that $f^{-1}(f(A))subset A$. Take $xin f^{-1}(f(A))$; then $f(x)in f(A)$. Apply injectivity.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Nov 26 at 22:24









egreg

178k1484200




178k1484200












  • I made the correction. The same hint holds for the surjectivity proposition?
    – Armando Rosas
    Nov 27 at 0:24










  • @ArmandoRosas Very similar. Don't forget to prove also the $Leftarrow$ directions.
    – egreg
    Nov 27 at 7:46










  • I have trouble with the $Leftarrow$ proof of surjectivity. I let c be in C , then c it's an element of $f(f^{-1}(C))$, can i directly say that f is surjective here? Because then $c=f(x)$ with $xin f^{-1}(C)subset X$, is it not?
    – Armando Rosas
    Nov 27 at 22:03










  • @ArmandoRosas For $C=Y$, $Y=f(f^{-1}(Y))=f(X)$.
    – egreg
    Nov 27 at 22:19


















  • I made the correction. The same hint holds for the surjectivity proposition?
    – Armando Rosas
    Nov 27 at 0:24










  • @ArmandoRosas Very similar. Don't forget to prove also the $Leftarrow$ directions.
    – egreg
    Nov 27 at 7:46










  • I have trouble with the $Leftarrow$ proof of surjectivity. I let c be in C , then c it's an element of $f(f^{-1}(C))$, can i directly say that f is surjective here? Because then $c=f(x)$ with $xin f^{-1}(C)subset X$, is it not?
    – Armando Rosas
    Nov 27 at 22:03










  • @ArmandoRosas For $C=Y$, $Y=f(f^{-1}(Y))=f(X)$.
    – egreg
    Nov 27 at 22:19
















I made the correction. The same hint holds for the surjectivity proposition?
– Armando Rosas
Nov 27 at 0:24




I made the correction. The same hint holds for the surjectivity proposition?
– Armando Rosas
Nov 27 at 0:24












@ArmandoRosas Very similar. Don't forget to prove also the $Leftarrow$ directions.
– egreg
Nov 27 at 7:46




@ArmandoRosas Very similar. Don't forget to prove also the $Leftarrow$ directions.
– egreg
Nov 27 at 7:46












I have trouble with the $Leftarrow$ proof of surjectivity. I let c be in C , then c it's an element of $f(f^{-1}(C))$, can i directly say that f is surjective here? Because then $c=f(x)$ with $xin f^{-1}(C)subset X$, is it not?
– Armando Rosas
Nov 27 at 22:03




I have trouble with the $Leftarrow$ proof of surjectivity. I let c be in C , then c it's an element of $f(f^{-1}(C))$, can i directly say that f is surjective here? Because then $c=f(x)$ with $xin f^{-1}(C)subset X$, is it not?
– Armando Rosas
Nov 27 at 22:03












@ArmandoRosas For $C=Y$, $Y=f(f^{-1}(Y))=f(X)$.
– egreg
Nov 27 at 22:19




@ArmandoRosas For $C=Y$, $Y=f(f^{-1}(Y))=f(X)$.
– egreg
Nov 27 at 22:19


















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