In R-Mod Category, example for $Bcong A oplus C nRightarrow 0 to A to B to C to0$ splits.












1












$begingroup$


https://en.wikipedia.org/wiki/Splitting_lemma



In $R$-Mod Category, short exact sequence
$0 to A stackrel{f}{rightarrow} B stackrel{g}{rightarrow} C to0$ splits
if it satisfies one of the following equivalent conditions:



$(1) exists f_1intext{Hom}(B,A)text{ s.t. } f_1circ f=text{Id}_A$.



$(2) exists g_1intext{Hom}(C,B)text{ s.t. } gcirc g_1=text{Id}_C$.



$(3) text{Im }f=text{Ker }g$ is direct summand of $B$.



$(4) exists text{ isomorphism } h:Bto A oplus C text{ s.t. } $



$h circ f text{ is natural injection and }g circ h^{-1} text{ is natural projection.}$



And
$0 to A stackrel{f}{rightarrow} B stackrel{g}{rightarrow} C to0$ splits $implies Bcong A oplus C$.



So what if we remove the condition:



$ text{isomorphism } h:Bto A oplus C text{ satisfying } $



$h circ f text{ is natural injection and }g circ h^{-1} text{ is natural projection?}$



Is there any counter example? Thanks in advance.



Related questions:



$(1)$ Example of a non-splitting exact sequence $0rightarrow Mrightarrow Moplus Nrightarrow Nrightarrow 0$, question



$(2)$ A nonsplit short exact sequence of abelian groups with $B cong A oplus C$










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$endgroup$












  • $begingroup$
    You mean, there exists an isomorphism, but it just doesn't satisfy the injection/projection conditions?
    $endgroup$
    – rschwieb
    Dec 13 '18 at 14:40












  • $begingroup$
    Possible duplicate of A nonsplit short exact sequence of abelian groups with $B cong A oplus C$
    $endgroup$
    – yamete kudasai
    Dec 13 '18 at 14:42










  • $begingroup$
    What do you mean by "drop the condition"?
    $endgroup$
    – positrón0802
    Dec 13 '18 at 14:57
















1












$begingroup$


https://en.wikipedia.org/wiki/Splitting_lemma



In $R$-Mod Category, short exact sequence
$0 to A stackrel{f}{rightarrow} B stackrel{g}{rightarrow} C to0$ splits
if it satisfies one of the following equivalent conditions:



$(1) exists f_1intext{Hom}(B,A)text{ s.t. } f_1circ f=text{Id}_A$.



$(2) exists g_1intext{Hom}(C,B)text{ s.t. } gcirc g_1=text{Id}_C$.



$(3) text{Im }f=text{Ker }g$ is direct summand of $B$.



$(4) exists text{ isomorphism } h:Bto A oplus C text{ s.t. } $



$h circ f text{ is natural injection and }g circ h^{-1} text{ is natural projection.}$



And
$0 to A stackrel{f}{rightarrow} B stackrel{g}{rightarrow} C to0$ splits $implies Bcong A oplus C$.



So what if we remove the condition:



$ text{isomorphism } h:Bto A oplus C text{ satisfying } $



$h circ f text{ is natural injection and }g circ h^{-1} text{ is natural projection?}$



Is there any counter example? Thanks in advance.



Related questions:



$(1)$ Example of a non-splitting exact sequence $0rightarrow Mrightarrow Moplus Nrightarrow Nrightarrow 0$, question



$(2)$ A nonsplit short exact sequence of abelian groups with $B cong A oplus C$










share|cite|improve this question











$endgroup$












  • $begingroup$
    You mean, there exists an isomorphism, but it just doesn't satisfy the injection/projection conditions?
    $endgroup$
    – rschwieb
    Dec 13 '18 at 14:40












  • $begingroup$
    Possible duplicate of A nonsplit short exact sequence of abelian groups with $B cong A oplus C$
    $endgroup$
    – yamete kudasai
    Dec 13 '18 at 14:42










  • $begingroup$
    What do you mean by "drop the condition"?
    $endgroup$
    – positrón0802
    Dec 13 '18 at 14:57














1












1








1





$begingroup$


https://en.wikipedia.org/wiki/Splitting_lemma



In $R$-Mod Category, short exact sequence
$0 to A stackrel{f}{rightarrow} B stackrel{g}{rightarrow} C to0$ splits
if it satisfies one of the following equivalent conditions:



$(1) exists f_1intext{Hom}(B,A)text{ s.t. } f_1circ f=text{Id}_A$.



$(2) exists g_1intext{Hom}(C,B)text{ s.t. } gcirc g_1=text{Id}_C$.



$(3) text{Im }f=text{Ker }g$ is direct summand of $B$.



$(4) exists text{ isomorphism } h:Bto A oplus C text{ s.t. } $



$h circ f text{ is natural injection and }g circ h^{-1} text{ is natural projection.}$



And
$0 to A stackrel{f}{rightarrow} B stackrel{g}{rightarrow} C to0$ splits $implies Bcong A oplus C$.



So what if we remove the condition:



$ text{isomorphism } h:Bto A oplus C text{ satisfying } $



$h circ f text{ is natural injection and }g circ h^{-1} text{ is natural projection?}$



Is there any counter example? Thanks in advance.



Related questions:



$(1)$ Example of a non-splitting exact sequence $0rightarrow Mrightarrow Moplus Nrightarrow Nrightarrow 0$, question



$(2)$ A nonsplit short exact sequence of abelian groups with $B cong A oplus C$










share|cite|improve this question











$endgroup$




https://en.wikipedia.org/wiki/Splitting_lemma



In $R$-Mod Category, short exact sequence
$0 to A stackrel{f}{rightarrow} B stackrel{g}{rightarrow} C to0$ splits
if it satisfies one of the following equivalent conditions:



$(1) exists f_1intext{Hom}(B,A)text{ s.t. } f_1circ f=text{Id}_A$.



$(2) exists g_1intext{Hom}(C,B)text{ s.t. } gcirc g_1=text{Id}_C$.



$(3) text{Im }f=text{Ker }g$ is direct summand of $B$.



$(4) exists text{ isomorphism } h:Bto A oplus C text{ s.t. } $



$h circ f text{ is natural injection and }g circ h^{-1} text{ is natural projection.}$



And
$0 to A stackrel{f}{rightarrow} B stackrel{g}{rightarrow} C to0$ splits $implies Bcong A oplus C$.



So what if we remove the condition:



$ text{isomorphism } h:Bto A oplus C text{ satisfying } $



$h circ f text{ is natural injection and }g circ h^{-1} text{ is natural projection?}$



Is there any counter example? Thanks in advance.



Related questions:



$(1)$ Example of a non-splitting exact sequence $0rightarrow Mrightarrow Moplus Nrightarrow Nrightarrow 0$, question



$(2)$ A nonsplit short exact sequence of abelian groups with $B cong A oplus C$







abstract-algebra modules






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edited Dec 26 '18 at 21:28









user26857

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asked Dec 13 '18 at 14:30









AndrewsAndrews

4081317




4081317












  • $begingroup$
    You mean, there exists an isomorphism, but it just doesn't satisfy the injection/projection conditions?
    $endgroup$
    – rschwieb
    Dec 13 '18 at 14:40












  • $begingroup$
    Possible duplicate of A nonsplit short exact sequence of abelian groups with $B cong A oplus C$
    $endgroup$
    – yamete kudasai
    Dec 13 '18 at 14:42










  • $begingroup$
    What do you mean by "drop the condition"?
    $endgroup$
    – positrón0802
    Dec 13 '18 at 14:57


















  • $begingroup$
    You mean, there exists an isomorphism, but it just doesn't satisfy the injection/projection conditions?
    $endgroup$
    – rschwieb
    Dec 13 '18 at 14:40












  • $begingroup$
    Possible duplicate of A nonsplit short exact sequence of abelian groups with $B cong A oplus C$
    $endgroup$
    – yamete kudasai
    Dec 13 '18 at 14:42










  • $begingroup$
    What do you mean by "drop the condition"?
    $endgroup$
    – positrón0802
    Dec 13 '18 at 14:57
















$begingroup$
You mean, there exists an isomorphism, but it just doesn't satisfy the injection/projection conditions?
$endgroup$
– rschwieb
Dec 13 '18 at 14:40






$begingroup$
You mean, there exists an isomorphism, but it just doesn't satisfy the injection/projection conditions?
$endgroup$
– rschwieb
Dec 13 '18 at 14:40














$begingroup$
Possible duplicate of A nonsplit short exact sequence of abelian groups with $B cong A oplus C$
$endgroup$
– yamete kudasai
Dec 13 '18 at 14:42




$begingroup$
Possible duplicate of A nonsplit short exact sequence of abelian groups with $B cong A oplus C$
$endgroup$
– yamete kudasai
Dec 13 '18 at 14:42












$begingroup$
What do you mean by "drop the condition"?
$endgroup$
– positrón0802
Dec 13 '18 at 14:57




$begingroup$
What do you mean by "drop the condition"?
$endgroup$
– positrón0802
Dec 13 '18 at 14:57










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Here ring $R$ is communtative to make Hom$_R(C, - )$ a $R$-module.






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    $begingroup$

    enter image description here



    Here ring $R$ is communtative to make Hom$_R(C, - )$ a $R$-module.






    share|cite|improve this answer









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      $begingroup$

      enter image description here



      Here ring $R$ is communtative to make Hom$_R(C, - )$ a $R$-module.






      share|cite|improve this answer









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        $begingroup$

        enter image description here



        Here ring $R$ is communtative to make Hom$_R(C, - )$ a $R$-module.






        share|cite|improve this answer









        $endgroup$



        enter image description here



        Here ring $R$ is communtative to make Hom$_R(C, - )$ a $R$-module.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 13 '18 at 23:50









        AndrewsAndrews

        4081317




        4081317






























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