Is there any difference between a “derivative” and a “directional derivative”?
$begingroup$
See What is directional derivative?
It is just the usual derivative i.e. the ONE VARIABLE/ONE DIMENSIONAL
Derivative obtained from breaking down a VECTOR DERIVATIVE.
This example will make it clear. Consider a humming bird moving around
you. You are interested(assume!) in the change in the position of the
bird with respect to time(i.e. its velocity). But being a
mathematician(assume!), you realize that NOT 1, but actually 3 -
Variables: x, y and z are changing. So you call the Velocity in
X-direction as the DIRECTIONAL DERIVATIVE OF THE POSITION WITH RESPECT
TO TIME IN THE X DIRECTION…
I hope you understand. If not, ponder for a few days. Even if you
don’t understand then, just let me know.
See How different is directional derivative from the usual derivative f'?.
All derivatives are directional derivatives, sort of. The directional derivative indicates the rate of change of the function in
a specific direction. The usual derivative $f'$ of a function $f$ of
one variable indicates the rate of change of the function in the
positive coordinate direction. The only other direction that you can
define for a function of one variable is the negative coordinate
direction, and that turns out to be just $-f'$.
For a function of two
variables, you have a lot more choices. There is an infinite number of
directional derivatives, one for each direction in the plane.
Fortunately, you don’t have to calculate them all separately, it’s
enough to compute the directional derivatives in two coordinate
directions, the partial derivatives. It is particularly convenient if
these direction are chosen to be orthogonal. Then you can obtain the
directional derivative in any direction, given by a vector $d$, by
forming the dot product between the partial derivatives and the
components of the vector $d$ expressed in the same coordinate system.
What I understand is they are the same.
So, Is there any difference between a "derivative" and a "directional derivative"?
derivatives differential
$endgroup$
add a comment |
$begingroup$
See What is directional derivative?
It is just the usual derivative i.e. the ONE VARIABLE/ONE DIMENSIONAL
Derivative obtained from breaking down a VECTOR DERIVATIVE.
This example will make it clear. Consider a humming bird moving around
you. You are interested(assume!) in the change in the position of the
bird with respect to time(i.e. its velocity). But being a
mathematician(assume!), you realize that NOT 1, but actually 3 -
Variables: x, y and z are changing. So you call the Velocity in
X-direction as the DIRECTIONAL DERIVATIVE OF THE POSITION WITH RESPECT
TO TIME IN THE X DIRECTION…
I hope you understand. If not, ponder for a few days. Even if you
don’t understand then, just let me know.
See How different is directional derivative from the usual derivative f'?.
All derivatives are directional derivatives, sort of. The directional derivative indicates the rate of change of the function in
a specific direction. The usual derivative $f'$ of a function $f$ of
one variable indicates the rate of change of the function in the
positive coordinate direction. The only other direction that you can
define for a function of one variable is the negative coordinate
direction, and that turns out to be just $-f'$.
For a function of two
variables, you have a lot more choices. There is an infinite number of
directional derivatives, one for each direction in the plane.
Fortunately, you don’t have to calculate them all separately, it’s
enough to compute the directional derivatives in two coordinate
directions, the partial derivatives. It is particularly convenient if
these direction are chosen to be orthogonal. Then you can obtain the
directional derivative in any direction, given by a vector $d$, by
forming the dot product between the partial derivatives and the
components of the vector $d$ expressed in the same coordinate system.
What I understand is they are the same.
So, Is there any difference between a "derivative" and a "directional derivative"?
derivatives differential
$endgroup$
$begingroup$
See Directional derivative : "the directional derivative of a multivariate differentiable function along a given vector v at a given point x intuitively represents the instantaneous rate of change of the function, moving through x with a velocity specified by v. It therefore generalizes the notion of a partial derivative."
$endgroup$
– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
$begingroup$
So, the relation is that between a more general concept and a specific case.
$endgroup$
– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
add a comment |
$begingroup$
See What is directional derivative?
It is just the usual derivative i.e. the ONE VARIABLE/ONE DIMENSIONAL
Derivative obtained from breaking down a VECTOR DERIVATIVE.
This example will make it clear. Consider a humming bird moving around
you. You are interested(assume!) in the change in the position of the
bird with respect to time(i.e. its velocity). But being a
mathematician(assume!), you realize that NOT 1, but actually 3 -
Variables: x, y and z are changing. So you call the Velocity in
X-direction as the DIRECTIONAL DERIVATIVE OF THE POSITION WITH RESPECT
TO TIME IN THE X DIRECTION…
I hope you understand. If not, ponder for a few days. Even if you
don’t understand then, just let me know.
See How different is directional derivative from the usual derivative f'?.
All derivatives are directional derivatives, sort of. The directional derivative indicates the rate of change of the function in
a specific direction. The usual derivative $f'$ of a function $f$ of
one variable indicates the rate of change of the function in the
positive coordinate direction. The only other direction that you can
define for a function of one variable is the negative coordinate
direction, and that turns out to be just $-f'$.
For a function of two
variables, you have a lot more choices. There is an infinite number of
directional derivatives, one for each direction in the plane.
Fortunately, you don’t have to calculate them all separately, it’s
enough to compute the directional derivatives in two coordinate
directions, the partial derivatives. It is particularly convenient if
these direction are chosen to be orthogonal. Then you can obtain the
directional derivative in any direction, given by a vector $d$, by
forming the dot product between the partial derivatives and the
components of the vector $d$ expressed in the same coordinate system.
What I understand is they are the same.
So, Is there any difference between a "derivative" and a "directional derivative"?
derivatives differential
$endgroup$
See What is directional derivative?
It is just the usual derivative i.e. the ONE VARIABLE/ONE DIMENSIONAL
Derivative obtained from breaking down a VECTOR DERIVATIVE.
This example will make it clear. Consider a humming bird moving around
you. You are interested(assume!) in the change in the position of the
bird with respect to time(i.e. its velocity). But being a
mathematician(assume!), you realize that NOT 1, but actually 3 -
Variables: x, y and z are changing. So you call the Velocity in
X-direction as the DIRECTIONAL DERIVATIVE OF THE POSITION WITH RESPECT
TO TIME IN THE X DIRECTION…
I hope you understand. If not, ponder for a few days. Even if you
don’t understand then, just let me know.
See How different is directional derivative from the usual derivative f'?.
All derivatives are directional derivatives, sort of. The directional derivative indicates the rate of change of the function in
a specific direction. The usual derivative $f'$ of a function $f$ of
one variable indicates the rate of change of the function in the
positive coordinate direction. The only other direction that you can
define for a function of one variable is the negative coordinate
direction, and that turns out to be just $-f'$.
For a function of two
variables, you have a lot more choices. There is an infinite number of
directional derivatives, one for each direction in the plane.
Fortunately, you don’t have to calculate them all separately, it’s
enough to compute the directional derivatives in two coordinate
directions, the partial derivatives. It is particularly convenient if
these direction are chosen to be orthogonal. Then you can obtain the
directional derivative in any direction, given by a vector $d$, by
forming the dot product between the partial derivatives and the
components of the vector $d$ expressed in the same coordinate system.
What I understand is they are the same.
So, Is there any difference between a "derivative" and a "directional derivative"?
derivatives differential
derivatives differential
edited Dec 30 '18 at 14:19
José Carlos Santos
170k23132238
170k23132238
asked Dec 30 '18 at 12:42
user366312user366312
663418
663418
$begingroup$
See Directional derivative : "the directional derivative of a multivariate differentiable function along a given vector v at a given point x intuitively represents the instantaneous rate of change of the function, moving through x with a velocity specified by v. It therefore generalizes the notion of a partial derivative."
$endgroup$
– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
$begingroup$
So, the relation is that between a more general concept and a specific case.
$endgroup$
– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
add a comment |
$begingroup$
See Directional derivative : "the directional derivative of a multivariate differentiable function along a given vector v at a given point x intuitively represents the instantaneous rate of change of the function, moving through x with a velocity specified by v. It therefore generalizes the notion of a partial derivative."
$endgroup$
– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
$begingroup$
So, the relation is that between a more general concept and a specific case.
$endgroup$
– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
$begingroup$
See Directional derivative : "the directional derivative of a multivariate differentiable function along a given vector v at a given point x intuitively represents the instantaneous rate of change of the function, moving through x with a velocity specified by v. It therefore generalizes the notion of a partial derivative."
$endgroup$
– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
$begingroup$
See Directional derivative : "the directional derivative of a multivariate differentiable function along a given vector v at a given point x intuitively represents the instantaneous rate of change of the function, moving through x with a velocity specified by v. It therefore generalizes the notion of a partial derivative."
$endgroup$
– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
$begingroup$
So, the relation is that between a more general concept and a specific case.
$endgroup$
– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
$begingroup$
So, the relation is that between a more general concept and a specific case.
$endgroup$
– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Yes, there is a difference. And a big one. Let us assume that $f$ is a differentiable map from $mathbb{R}^n$ into $mathbb R$.
The directional derivative of $f$ at a point $p$ with repect to a vector $v$ is a number. That number tells us how fast $f$ grows near $p$ in the direction given by $v$.
The derivative $f'$ at a point $p$ is a linear map from $mathbb{R}^n$ into $mathbb R$. And, given a vector $v$, $f'(p)(v)$ is precisely the directional derivative of $f$ at $p$ with respect to the direction provided by $v$.
$endgroup$
$begingroup$
So, what is the difference between a partial derivative and a directional derivative then?
$endgroup$
– user366312
Dec 30 '18 at 12:53
$begingroup$
No big difference: partial derivatives are directional derivatives with respect to the vectors of the standard basis of $mathbb{R}^n$.
$endgroup$
– José Carlos Santos
Dec 30 '18 at 12:54
add a comment |
$begingroup$
If you have a function $f=f(x_1,...,x_n)$ which depends on $n$ variables the partial derivative $frac{partial f}{partial x_i}$ is a directional derivative in the direction of the vector $e_i=(0,...,0,1,0,...,0)$ wich has zeros in each entry but the i-th entry where it is $1$.
The directional derivative in a direction $hin Bbb R^n$ is defined like this: $$frac{partial f(x)}{partial h}=limlimits_{txrightarrow{}0}frac{f(x+ht)-f(x)}{t}$$ and is noted $D_hf(x)$. And this definition agrees with the partial derivative with respect to $x_i$ a.k.a. the directional derivative in the direction of $e_i$

$endgroup$
$begingroup$
text doesn't match with the plot.
$endgroup$
– user366312
Dec 30 '18 at 13:06
add a comment |
$begingroup$
From the way in which this paragraph is worded it makes most sense to think of a function in more than two dimensions, e.g.
$$z=f(x,y)$$
in this context we know that we can take derivatives in two different dimensions, to give:
$$frac{partial z}{partial x},frac{partial z}{partial y}$$
when the term derivative is used, we usually mean the of the function with respect to its single variable $frac{df(x)}{dx}$ or we state in which dimension we intend to find the derivative "the rate of change of $z$ with respect to $x$". From this it is clear to see that we presume the positive direction in any axis ($+x$ as supposed to $-x$). All this concept of "directional derivative" introduces is that we can define a derivative in any direction compared to the function
$endgroup$
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Yes, there is a difference. And a big one. Let us assume that $f$ is a differentiable map from $mathbb{R}^n$ into $mathbb R$.
The directional derivative of $f$ at a point $p$ with repect to a vector $v$ is a number. That number tells us how fast $f$ grows near $p$ in the direction given by $v$.
The derivative $f'$ at a point $p$ is a linear map from $mathbb{R}^n$ into $mathbb R$. And, given a vector $v$, $f'(p)(v)$ is precisely the directional derivative of $f$ at $p$ with respect to the direction provided by $v$.
$endgroup$
$begingroup$
So, what is the difference between a partial derivative and a directional derivative then?
$endgroup$
– user366312
Dec 30 '18 at 12:53
$begingroup$
No big difference: partial derivatives are directional derivatives with respect to the vectors of the standard basis of $mathbb{R}^n$.
$endgroup$
– José Carlos Santos
Dec 30 '18 at 12:54
add a comment |
$begingroup$
Yes, there is a difference. And a big one. Let us assume that $f$ is a differentiable map from $mathbb{R}^n$ into $mathbb R$.
The directional derivative of $f$ at a point $p$ with repect to a vector $v$ is a number. That number tells us how fast $f$ grows near $p$ in the direction given by $v$.
The derivative $f'$ at a point $p$ is a linear map from $mathbb{R}^n$ into $mathbb R$. And, given a vector $v$, $f'(p)(v)$ is precisely the directional derivative of $f$ at $p$ with respect to the direction provided by $v$.
$endgroup$
$begingroup$
So, what is the difference between a partial derivative and a directional derivative then?
$endgroup$
– user366312
Dec 30 '18 at 12:53
$begingroup$
No big difference: partial derivatives are directional derivatives with respect to the vectors of the standard basis of $mathbb{R}^n$.
$endgroup$
– José Carlos Santos
Dec 30 '18 at 12:54
add a comment |
$begingroup$
Yes, there is a difference. And a big one. Let us assume that $f$ is a differentiable map from $mathbb{R}^n$ into $mathbb R$.
The directional derivative of $f$ at a point $p$ with repect to a vector $v$ is a number. That number tells us how fast $f$ grows near $p$ in the direction given by $v$.
The derivative $f'$ at a point $p$ is a linear map from $mathbb{R}^n$ into $mathbb R$. And, given a vector $v$, $f'(p)(v)$ is precisely the directional derivative of $f$ at $p$ with respect to the direction provided by $v$.
$endgroup$
Yes, there is a difference. And a big one. Let us assume that $f$ is a differentiable map from $mathbb{R}^n$ into $mathbb R$.
The directional derivative of $f$ at a point $p$ with repect to a vector $v$ is a number. That number tells us how fast $f$ grows near $p$ in the direction given by $v$.
The derivative $f'$ at a point $p$ is a linear map from $mathbb{R}^n$ into $mathbb R$. And, given a vector $v$, $f'(p)(v)$ is precisely the directional derivative of $f$ at $p$ with respect to the direction provided by $v$.
answered Dec 30 '18 at 12:51
José Carlos SantosJosé Carlos Santos
170k23132238
170k23132238
$begingroup$
So, what is the difference between a partial derivative and a directional derivative then?
$endgroup$
– user366312
Dec 30 '18 at 12:53
$begingroup$
No big difference: partial derivatives are directional derivatives with respect to the vectors of the standard basis of $mathbb{R}^n$.
$endgroup$
– José Carlos Santos
Dec 30 '18 at 12:54
add a comment |
$begingroup$
So, what is the difference between a partial derivative and a directional derivative then?
$endgroup$
– user366312
Dec 30 '18 at 12:53
$begingroup$
No big difference: partial derivatives are directional derivatives with respect to the vectors of the standard basis of $mathbb{R}^n$.
$endgroup$
– José Carlos Santos
Dec 30 '18 at 12:54
$begingroup$
So, what is the difference between a partial derivative and a directional derivative then?
$endgroup$
– user366312
Dec 30 '18 at 12:53
$begingroup$
So, what is the difference between a partial derivative and a directional derivative then?
$endgroup$
– user366312
Dec 30 '18 at 12:53
$begingroup$
No big difference: partial derivatives are directional derivatives with respect to the vectors of the standard basis of $mathbb{R}^n$.
$endgroup$
– José Carlos Santos
Dec 30 '18 at 12:54
$begingroup$
No big difference: partial derivatives are directional derivatives with respect to the vectors of the standard basis of $mathbb{R}^n$.
$endgroup$
– José Carlos Santos
Dec 30 '18 at 12:54
add a comment |
$begingroup$
If you have a function $f=f(x_1,...,x_n)$ which depends on $n$ variables the partial derivative $frac{partial f}{partial x_i}$ is a directional derivative in the direction of the vector $e_i=(0,...,0,1,0,...,0)$ wich has zeros in each entry but the i-th entry where it is $1$.
The directional derivative in a direction $hin Bbb R^n$ is defined like this: $$frac{partial f(x)}{partial h}=limlimits_{txrightarrow{}0}frac{f(x+ht)-f(x)}{t}$$ and is noted $D_hf(x)$. And this definition agrees with the partial derivative with respect to $x_i$ a.k.a. the directional derivative in the direction of $e_i$

$endgroup$
$begingroup$
text doesn't match with the plot.
$endgroup$
– user366312
Dec 30 '18 at 13:06
add a comment |
$begingroup$
If you have a function $f=f(x_1,...,x_n)$ which depends on $n$ variables the partial derivative $frac{partial f}{partial x_i}$ is a directional derivative in the direction of the vector $e_i=(0,...,0,1,0,...,0)$ wich has zeros in each entry but the i-th entry where it is $1$.
The directional derivative in a direction $hin Bbb R^n$ is defined like this: $$frac{partial f(x)}{partial h}=limlimits_{txrightarrow{}0}frac{f(x+ht)-f(x)}{t}$$ and is noted $D_hf(x)$. And this definition agrees with the partial derivative with respect to $x_i$ a.k.a. the directional derivative in the direction of $e_i$

$endgroup$
$begingroup$
text doesn't match with the plot.
$endgroup$
– user366312
Dec 30 '18 at 13:06
add a comment |
$begingroup$
If you have a function $f=f(x_1,...,x_n)$ which depends on $n$ variables the partial derivative $frac{partial f}{partial x_i}$ is a directional derivative in the direction of the vector $e_i=(0,...,0,1,0,...,0)$ wich has zeros in each entry but the i-th entry where it is $1$.
The directional derivative in a direction $hin Bbb R^n$ is defined like this: $$frac{partial f(x)}{partial h}=limlimits_{txrightarrow{}0}frac{f(x+ht)-f(x)}{t}$$ and is noted $D_hf(x)$. And this definition agrees with the partial derivative with respect to $x_i$ a.k.a. the directional derivative in the direction of $e_i$

$endgroup$
If you have a function $f=f(x_1,...,x_n)$ which depends on $n$ variables the partial derivative $frac{partial f}{partial x_i}$ is a directional derivative in the direction of the vector $e_i=(0,...,0,1,0,...,0)$ wich has zeros in each entry but the i-th entry where it is $1$.
The directional derivative in a direction $hin Bbb R^n$ is defined like this: $$frac{partial f(x)}{partial h}=limlimits_{txrightarrow{}0}frac{f(x+ht)-f(x)}{t}$$ and is noted $D_hf(x)$. And this definition agrees with the partial derivative with respect to $x_i$ a.k.a. the directional derivative in the direction of $e_i$

edited Dec 30 '18 at 13:07
answered Dec 30 '18 at 13:02
John CataldoJohn Cataldo
1,1931316
1,1931316
$begingroup$
text doesn't match with the plot.
$endgroup$
– user366312
Dec 30 '18 at 13:06
add a comment |
$begingroup$
text doesn't match with the plot.
$endgroup$
– user366312
Dec 30 '18 at 13:06
$begingroup$
text doesn't match with the plot.
$endgroup$
– user366312
Dec 30 '18 at 13:06
$begingroup$
text doesn't match with the plot.
$endgroup$
– user366312
Dec 30 '18 at 13:06
add a comment |
$begingroup$
From the way in which this paragraph is worded it makes most sense to think of a function in more than two dimensions, e.g.
$$z=f(x,y)$$
in this context we know that we can take derivatives in two different dimensions, to give:
$$frac{partial z}{partial x},frac{partial z}{partial y}$$
when the term derivative is used, we usually mean the of the function with respect to its single variable $frac{df(x)}{dx}$ or we state in which dimension we intend to find the derivative "the rate of change of $z$ with respect to $x$". From this it is clear to see that we presume the positive direction in any axis ($+x$ as supposed to $-x$). All this concept of "directional derivative" introduces is that we can define a derivative in any direction compared to the function
$endgroup$
add a comment |
$begingroup$
From the way in which this paragraph is worded it makes most sense to think of a function in more than two dimensions, e.g.
$$z=f(x,y)$$
in this context we know that we can take derivatives in two different dimensions, to give:
$$frac{partial z}{partial x},frac{partial z}{partial y}$$
when the term derivative is used, we usually mean the of the function with respect to its single variable $frac{df(x)}{dx}$ or we state in which dimension we intend to find the derivative "the rate of change of $z$ with respect to $x$". From this it is clear to see that we presume the positive direction in any axis ($+x$ as supposed to $-x$). All this concept of "directional derivative" introduces is that we can define a derivative in any direction compared to the function
$endgroup$
add a comment |
$begingroup$
From the way in which this paragraph is worded it makes most sense to think of a function in more than two dimensions, e.g.
$$z=f(x,y)$$
in this context we know that we can take derivatives in two different dimensions, to give:
$$frac{partial z}{partial x},frac{partial z}{partial y}$$
when the term derivative is used, we usually mean the of the function with respect to its single variable $frac{df(x)}{dx}$ or we state in which dimension we intend to find the derivative "the rate of change of $z$ with respect to $x$". From this it is clear to see that we presume the positive direction in any axis ($+x$ as supposed to $-x$). All this concept of "directional derivative" introduces is that we can define a derivative in any direction compared to the function
$endgroup$
From the way in which this paragraph is worded it makes most sense to think of a function in more than two dimensions, e.g.
$$z=f(x,y)$$
in this context we know that we can take derivatives in two different dimensions, to give:
$$frac{partial z}{partial x},frac{partial z}{partial y}$$
when the term derivative is used, we usually mean the of the function with respect to its single variable $frac{df(x)}{dx}$ or we state in which dimension we intend to find the derivative "the rate of change of $z$ with respect to $x$". From this it is clear to see that we presume the positive direction in any axis ($+x$ as supposed to $-x$). All this concept of "directional derivative" introduces is that we can define a derivative in any direction compared to the function
answered Dec 30 '18 at 12:49
Henry LeeHenry Lee
2,221319
2,221319
add a comment |
add a comment |
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See Directional derivative : "the directional derivative of a multivariate differentiable function along a given vector v at a given point x intuitively represents the instantaneous rate of change of the function, moving through x with a velocity specified by v. It therefore generalizes the notion of a partial derivative."
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– Mauro ALLEGRANZA
Dec 30 '18 at 12:48
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So, the relation is that between a more general concept and a specific case.
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– Mauro ALLEGRANZA
Dec 30 '18 at 12:48