Why $lim_{xto0^+}{frac bxleft[frac xaright]}=0$?, where $[x] = sup{n in N, n leq x}$
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I ask this question here, and I was told that using squezze theorem I could solve it, but using this idea in this limit I end with.
$frac{b}{a} leq lim_{xto0^+}{frac bxleft[frac xaright]} leq infty$
Why?
calculus limits fractions
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add a comment |
$begingroup$
I ask this question here, and I was told that using squezze theorem I could solve it, but using this idea in this limit I end with.
$frac{b}{a} leq lim_{xto0^+}{frac bxleft[frac xaright]} leq infty$
Why?
calculus limits fractions
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$begingroup$
Been attempting to fix your title, I see you've been helping. Seems better to me now.
$endgroup$
– Matt Samuel
Dec 14 '18 at 16:00
$begingroup$
Yeah, first edit don't work out, but I appreciate your help.
$endgroup$
– Maria Guthier
Dec 14 '18 at 16:01
add a comment |
$begingroup$
I ask this question here, and I was told that using squezze theorem I could solve it, but using this idea in this limit I end with.
$frac{b}{a} leq lim_{xto0^+}{frac bxleft[frac xaright]} leq infty$
Why?
calculus limits fractions
$endgroup$
I ask this question here, and I was told that using squezze theorem I could solve it, but using this idea in this limit I end with.
$frac{b}{a} leq lim_{xto0^+}{frac bxleft[frac xaright]} leq infty$
Why?
calculus limits fractions
calculus limits fractions
edited Dec 14 '18 at 16:00
Matt Samuel
38.5k63768
38.5k63768
asked Dec 14 '18 at 15:55
Maria GuthierMaria Guthier
887
887
$begingroup$
Been attempting to fix your title, I see you've been helping. Seems better to me now.
$endgroup$
– Matt Samuel
Dec 14 '18 at 16:00
$begingroup$
Yeah, first edit don't work out, but I appreciate your help.
$endgroup$
– Maria Guthier
Dec 14 '18 at 16:01
add a comment |
$begingroup$
Been attempting to fix your title, I see you've been helping. Seems better to me now.
$endgroup$
– Matt Samuel
Dec 14 '18 at 16:00
$begingroup$
Yeah, first edit don't work out, but I appreciate your help.
$endgroup$
– Maria Guthier
Dec 14 '18 at 16:01
$begingroup$
Been attempting to fix your title, I see you've been helping. Seems better to me now.
$endgroup$
– Matt Samuel
Dec 14 '18 at 16:00
$begingroup$
Been attempting to fix your title, I see you've been helping. Seems better to me now.
$endgroup$
– Matt Samuel
Dec 14 '18 at 16:00
$begingroup$
Yeah, first edit don't work out, but I appreciate your help.
$endgroup$
– Maria Guthier
Dec 14 '18 at 16:01
$begingroup$
Yeah, first edit don't work out, but I appreciate your help.
$endgroup$
– Maria Guthier
Dec 14 '18 at 16:01
add a comment |
1 Answer
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Hint: $x-1leq left [ x right ]leq x$
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1 Answer
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1 Answer
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Hint: $x-1leq left [ x right ]leq x$
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Hint: $x-1leq left [ x right ]leq x$
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Hint: $x-1leq left [ x right ]leq x$
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Hint: $x-1leq left [ x right ]leq x$
answered Dec 14 '18 at 15:58
John11John11
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$begingroup$
Been attempting to fix your title, I see you've been helping. Seems better to me now.
$endgroup$
– Matt Samuel
Dec 14 '18 at 16:00
$begingroup$
Yeah, first edit don't work out, but I appreciate your help.
$endgroup$
– Maria Guthier
Dec 14 '18 at 16:01