What is uniqueness quantification?












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Can someone explain the concept of Uniqueness quantification ∃! in an easily understandable way since I can't understand the definition of it, what's special about it with other logical operators like and, or, not?




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  • 3




    $begingroup$
    I do not know what the uniqueness operator is... I don't think it's a standard term. (Do you mean the unique existential quantifier as in $exists ! xphi(x)$?) Maybe write down the definition and give a little more context?
    $endgroup$
    – spaceisdarkgreen
    Dec 9 '18 at 5:24












  • $begingroup$
    thank you I corrected the typo mistake
    $endgroup$
    – CCola
    Dec 9 '18 at 6:18
















1












$begingroup$


Can someone explain the concept of Uniqueness quantification ∃! in an easily understandable way since I can't understand the definition of it, what's special about it with other logical operators like and, or, not?




    *









share|cite|improve this question











$endgroup$








  • 3




    $begingroup$
    I do not know what the uniqueness operator is... I don't think it's a standard term. (Do you mean the unique existential quantifier as in $exists ! xphi(x)$?) Maybe write down the definition and give a little more context?
    $endgroup$
    – spaceisdarkgreen
    Dec 9 '18 at 5:24












  • $begingroup$
    thank you I corrected the typo mistake
    $endgroup$
    – CCola
    Dec 9 '18 at 6:18














1












1








1





$begingroup$


Can someone explain the concept of Uniqueness quantification ∃! in an easily understandable way since I can't understand the definition of it, what's special about it with other logical operators like and, or, not?




    *









share|cite|improve this question











$endgroup$




Can someone explain the concept of Uniqueness quantification ∃! in an easily understandable way since I can't understand the definition of it, what's special about it with other logical operators like and, or, not?




    *






discrete-mathematics logic definition






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 9 '18 at 6:17







CCola

















asked Dec 9 '18 at 5:20









CColaCCola

346




346








  • 3




    $begingroup$
    I do not know what the uniqueness operator is... I don't think it's a standard term. (Do you mean the unique existential quantifier as in $exists ! xphi(x)$?) Maybe write down the definition and give a little more context?
    $endgroup$
    – spaceisdarkgreen
    Dec 9 '18 at 5:24












  • $begingroup$
    thank you I corrected the typo mistake
    $endgroup$
    – CCola
    Dec 9 '18 at 6:18














  • 3




    $begingroup$
    I do not know what the uniqueness operator is... I don't think it's a standard term. (Do you mean the unique existential quantifier as in $exists ! xphi(x)$?) Maybe write down the definition and give a little more context?
    $endgroup$
    – spaceisdarkgreen
    Dec 9 '18 at 5:24












  • $begingroup$
    thank you I corrected the typo mistake
    $endgroup$
    – CCola
    Dec 9 '18 at 6:18








3




3




$begingroup$
I do not know what the uniqueness operator is... I don't think it's a standard term. (Do you mean the unique existential quantifier as in $exists ! xphi(x)$?) Maybe write down the definition and give a little more context?
$endgroup$
– spaceisdarkgreen
Dec 9 '18 at 5:24






$begingroup$
I do not know what the uniqueness operator is... I don't think it's a standard term. (Do you mean the unique existential quantifier as in $exists ! xphi(x)$?) Maybe write down the definition and give a little more context?
$endgroup$
– spaceisdarkgreen
Dec 9 '18 at 5:24














$begingroup$
thank you I corrected the typo mistake
$endgroup$
– CCola
Dec 9 '18 at 6:18




$begingroup$
thank you I corrected the typo mistake
$endgroup$
– CCola
Dec 9 '18 at 6:18










1 Answer
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$begingroup$

I think the "Uniqueness quantification" Wikipedia article does a fair job of answering this question, but try this: how many integers are there which, when added to $3$ give you $7$? Only one, namely $4$. But how many integers are there which, when squared give you $25$? Two! ($5$ and $-5$.)



The uniqueness operator is a mathematical convention which allows us to describe the phenomenon which occurs when there is one and only one mathematical object which satisfies the given conditions.



In practice, you will usually see it paired with the existence operator "$exists$". This might look like the following: $forall x in mathbb{Z}$, $exists ! y in mathbb{Z}$ such that $x+y=0$. Translation: "For every integer $x$, there exists a unique integer $y$ such that $x+y=0$ (This is the additive inverse property).






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  • $begingroup$
    Please edit this answer to include a link to the Wikipedia article you mentioned.
    $endgroup$
    – Shaun
    Dec 9 '18 at 6:06











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1 Answer
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active

oldest

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active

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3












$begingroup$

I think the "Uniqueness quantification" Wikipedia article does a fair job of answering this question, but try this: how many integers are there which, when added to $3$ give you $7$? Only one, namely $4$. But how many integers are there which, when squared give you $25$? Two! ($5$ and $-5$.)



The uniqueness operator is a mathematical convention which allows us to describe the phenomenon which occurs when there is one and only one mathematical object which satisfies the given conditions.



In practice, you will usually see it paired with the existence operator "$exists$". This might look like the following: $forall x in mathbb{Z}$, $exists ! y in mathbb{Z}$ such that $x+y=0$. Translation: "For every integer $x$, there exists a unique integer $y$ such that $x+y=0$ (This is the additive inverse property).






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Please edit this answer to include a link to the Wikipedia article you mentioned.
    $endgroup$
    – Shaun
    Dec 9 '18 at 6:06
















3












$begingroup$

I think the "Uniqueness quantification" Wikipedia article does a fair job of answering this question, but try this: how many integers are there which, when added to $3$ give you $7$? Only one, namely $4$. But how many integers are there which, when squared give you $25$? Two! ($5$ and $-5$.)



The uniqueness operator is a mathematical convention which allows us to describe the phenomenon which occurs when there is one and only one mathematical object which satisfies the given conditions.



In practice, you will usually see it paired with the existence operator "$exists$". This might look like the following: $forall x in mathbb{Z}$, $exists ! y in mathbb{Z}$ such that $x+y=0$. Translation: "For every integer $x$, there exists a unique integer $y$ such that $x+y=0$ (This is the additive inverse property).






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Please edit this answer to include a link to the Wikipedia article you mentioned.
    $endgroup$
    – Shaun
    Dec 9 '18 at 6:06














3












3








3





$begingroup$

I think the "Uniqueness quantification" Wikipedia article does a fair job of answering this question, but try this: how many integers are there which, when added to $3$ give you $7$? Only one, namely $4$. But how many integers are there which, when squared give you $25$? Two! ($5$ and $-5$.)



The uniqueness operator is a mathematical convention which allows us to describe the phenomenon which occurs when there is one and only one mathematical object which satisfies the given conditions.



In practice, you will usually see it paired with the existence operator "$exists$". This might look like the following: $forall x in mathbb{Z}$, $exists ! y in mathbb{Z}$ such that $x+y=0$. Translation: "For every integer $x$, there exists a unique integer $y$ such that $x+y=0$ (This is the additive inverse property).






share|cite|improve this answer











$endgroup$



I think the "Uniqueness quantification" Wikipedia article does a fair job of answering this question, but try this: how many integers are there which, when added to $3$ give you $7$? Only one, namely $4$. But how many integers are there which, when squared give you $25$? Two! ($5$ and $-5$.)



The uniqueness operator is a mathematical convention which allows us to describe the phenomenon which occurs when there is one and only one mathematical object which satisfies the given conditions.



In practice, you will usually see it paired with the existence operator "$exists$". This might look like the following: $forall x in mathbb{Z}$, $exists ! y in mathbb{Z}$ such that $x+y=0$. Translation: "For every integer $x$, there exists a unique integer $y$ such that $x+y=0$ (This is the additive inverse property).







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Dec 9 '18 at 8:01









Raymond Hettinger

46119




46119










answered Dec 9 '18 at 5:33









Adam CartisanoAdam Cartisano

1764




1764












  • $begingroup$
    Please edit this answer to include a link to the Wikipedia article you mentioned.
    $endgroup$
    – Shaun
    Dec 9 '18 at 6:06


















  • $begingroup$
    Please edit this answer to include a link to the Wikipedia article you mentioned.
    $endgroup$
    – Shaun
    Dec 9 '18 at 6:06
















$begingroup$
Please edit this answer to include a link to the Wikipedia article you mentioned.
$endgroup$
– Shaun
Dec 9 '18 at 6:06




$begingroup$
Please edit this answer to include a link to the Wikipedia article you mentioned.
$endgroup$
– Shaun
Dec 9 '18 at 6:06


















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