Selecting elements from lists based on string pattern
$begingroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
asked Feb 2 at 4:46
Suite401Suite401
998312
$endgroup$
add a comment |
$begingroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
asked Feb 2 at 4:46
Suite401Suite401
998312
$endgroup$
add a comment |
$begingroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
asked Feb 2 at 4:46
Suite401Suite401
998312
$endgroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
list-manipulation string-manipulation
asked Feb 2 at 4:46
Suite401Suite401
998312
asked Feb 2 at 4:46
Suite401Suite401
998312
asked Feb 2 at 4:46
Suite401Suite401
998312
asked Feb 2 at 4:46
Suite401Suite401
998312
asked Feb 2 at 4:46
Suite401Suite401
998312
998312
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered Feb 2 at 7:26
kglrkglr
186k10203422
$endgroup$
add a comment |
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered Feb 2 at 5:54
Bob HanlonBob Hanlon
60.6k33597
$endgroup$
add a comment |
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.
answered Feb 2 at 5:33
BillBill
5,75069
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add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered Feb 2 at 7:26
kglrkglr
186k10203422
$endgroup$
add a comment |
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered Feb 2 at 7:26
kglrkglr
186k10203422
$endgroup$
add a comment |
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered Feb 2 at 7:26
kglrkglr
186k10203422
$endgroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered Feb 2 at 7:26
kglrkglr
186k10203422
answered Feb 2 at 7:26
kglrkglr
186k10203422
answered Feb 2 at 7:26
kglrkglr
186k10203422
answered Feb 2 at 7:26
kglrkglr
186k10203422
186k10203422
add a comment |
add a comment |
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered Feb 2 at 5:54
Bob HanlonBob Hanlon
60.6k33597
$endgroup$
add a comment |
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered Feb 2 at 5:54
Bob HanlonBob Hanlon
60.6k33597
$endgroup$
add a comment |
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered Feb 2 at 5:54
Bob HanlonBob Hanlon
60.6k33597
$endgroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered Feb 2 at 5:54
Bob HanlonBob Hanlon
60.6k33597
answered Feb 2 at 5:54
Bob HanlonBob Hanlon
60.6k33597
answered Feb 2 at 5:54
Bob HanlonBob Hanlon
60.6k33597
answered Feb 2 at 5:54
Bob HanlonBob Hanlon
60.6k33597
60.6k33597
add a comment |
add a comment |
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.
answered Feb 2 at 5:33
BillBill
5,75069
$endgroup$
add a comment |
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.
answered Feb 2 at 5:33
BillBill
5,75069
$endgroup$
add a comment |
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.
answered Feb 2 at 5:33
BillBill
5,75069
$endgroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.
answered Feb 2 at 5:33
BillBill
5,75069
answered Feb 2 at 5:33
BillBill
5,75069
answered Feb 2 at 5:33
BillBill
5,75069
answered Feb 2 at 5:33
BillBill
5,75069
5,75069
add a comment |
add a comment |
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