Expected value of lottery drawing by using the Indicator Random Variable?












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The question states:
In a lottery 5 number are chosen from the set {1,..,90} without replacement. We order the 5 numbers in increasing order and we denote by X the number of times the difference between two neighboring numbers is 1.



I included a picture of my attempt and I think I might've messed up since the numbers are ordered.



enter image description here










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    $begingroup$


    The question states:
    In a lottery 5 number are chosen from the set {1,..,90} without replacement. We order the 5 numbers in increasing order and we denote by X the number of times the difference between two neighboring numbers is 1.



    I included a picture of my attempt and I think I might've messed up since the numbers are ordered.



    enter image description here










    share|cite|improve this question









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      0





      $begingroup$


      The question states:
      In a lottery 5 number are chosen from the set {1,..,90} without replacement. We order the 5 numbers in increasing order and we denote by X the number of times the difference between two neighboring numbers is 1.



      I included a picture of my attempt and I think I might've messed up since the numbers are ordered.



      enter image description here










      share|cite|improve this question









      $endgroup$




      The question states:
      In a lottery 5 number are chosen from the set {1,..,90} without replacement. We order the 5 numbers in increasing order and we denote by X the number of times the difference between two neighboring numbers is 1.



      I included a picture of my attempt and I think I might've messed up since the numbers are ordered.



      enter image description here







      probability statistics expected-value






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      asked Dec 9 '18 at 21:57









      Matt WilburMatt Wilbur

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          Order cannot matter: it affects the numerator and denominator by the same factor of $5!$



          So an expectation of $(5 times 4)times dfrac{89}{90times 89} = dfrac29$, which is what you found, looks correct






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            $begingroup$

            Order cannot matter: it affects the numerator and denominator by the same factor of $5!$



            So an expectation of $(5 times 4)times dfrac{89}{90times 89} = dfrac29$, which is what you found, looks correct






            share|cite|improve this answer









            $endgroup$


















              0












              $begingroup$

              Order cannot matter: it affects the numerator and denominator by the same factor of $5!$



              So an expectation of $(5 times 4)times dfrac{89}{90times 89} = dfrac29$, which is what you found, looks correct






              share|cite|improve this answer









              $endgroup$
















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                0





                $begingroup$

                Order cannot matter: it affects the numerator and denominator by the same factor of $5!$



                So an expectation of $(5 times 4)times dfrac{89}{90times 89} = dfrac29$, which is what you found, looks correct






                share|cite|improve this answer









                $endgroup$



                Order cannot matter: it affects the numerator and denominator by the same factor of $5!$



                So an expectation of $(5 times 4)times dfrac{89}{90times 89} = dfrac29$, which is what you found, looks correct







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 19 '18 at 18:27









                HenryHenry

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                99.9k480165






























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