A Pair of Odd (but Still Balanced) Dice
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I have a pair of odd six-sided dice at my house... I don't quite remember where I got them.
Each die has only one number on each side, and each of these numbers is a positive number.
Each pair of opposite faces sums to the same number on each individual die (but not necessarily the same across both dice)
Furthermore, the two dice, when rolled together, have the same probability of coming up a certain number as two six sided dice coming up with the same number.
Here are my drawings of three faces from each die:
(the 6 on the top drawing is actually a 6)
To solve the puzzle, all you have to do is:
Draw a complete cube net of each die.
Good luck and happy puzzling!
logical-deduction visual dice
edited Jan 22 at 22:33
Acccumulation
504111
asked Jan 22 at 13:49
Excited RaichuExcited Raichu
6,51521166
$endgroup$
add a comment |
$begingroup$
I have a pair of odd six-sided dice at my house... I don't quite remember where I got them.
Each die has only one number on each side, and each of these numbers is a positive number.
Each pair of opposite faces sums to the same number on each individual die (but not necessarily the same across both dice)
Furthermore, the two dice, when rolled together, have the same probability of coming up a certain number as two six sided dice coming up with the same number.
Here are my drawings of three faces from each die:
(the 6 on the top drawing is actually a 6)
To solve the puzzle, all you have to do is:
Draw a complete cube net of each die.
Good luck and happy puzzling!
logical-deduction visual dice
edited Jan 22 at 22:33
Acccumulation
504111
asked Jan 22 at 13:49
Excited RaichuExcited Raichu
6,51521166
$endgroup$
$begingroup$
is that a 6 or a 9? or can it be both? thanks!
$endgroup$
– Omega Krypton
Jan 22 at 13:53
$begingroup$
@OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
$endgroup$
– Excited Raichu
Jan 22 at 13:57
1
$begingroup$
Now that an answer has been accepted, I'll add that they are called Sicherman dice.
$endgroup$
– Jaap Scherphuis
Jan 22 at 15:51
add a comment |
$begingroup$
I have a pair of odd six-sided dice at my house... I don't quite remember where I got them.
Each die has only one number on each side, and each of these numbers is a positive number.
Each pair of opposite faces sums to the same number on each individual die (but not necessarily the same across both dice)
Furthermore, the two dice, when rolled together, have the same probability of coming up a certain number as two six sided dice coming up with the same number.
Here are my drawings of three faces from each die:
(the 6 on the top drawing is actually a 6)
To solve the puzzle, all you have to do is:
Draw a complete cube net of each die.
Good luck and happy puzzling!
logical-deduction visual dice
edited Jan 22 at 22:33
Acccumulation
504111
asked Jan 22 at 13:49
Excited RaichuExcited Raichu
6,51521166
$endgroup$
I have a pair of odd six-sided dice at my house... I don't quite remember where I got them.
Each die has only one number on each side, and each of these numbers is a positive number.
Each pair of opposite faces sums to the same number on each individual die (but not necessarily the same across both dice)
Furthermore, the two dice, when rolled together, have the same probability of coming up a certain number as two six sided dice coming up with the same number.
Here are my drawings of three faces from each die:
(the 6 on the top drawing is actually a 6)
To solve the puzzle, all you have to do is:
Draw a complete cube net of each die.
Good luck and happy puzzling!
logical-deduction visual dice
logical-deduction visual dice
edited Jan 22 at 22:33
Acccumulation
504111
asked Jan 22 at 13:49
Excited RaichuExcited Raichu
6,51521166
edited Jan 22 at 22:33
Acccumulation
504111
asked Jan 22 at 13:49
Excited RaichuExcited Raichu
6,51521166
edited Jan 22 at 22:33
Acccumulation
504111
edited Jan 22 at 22:33
Acccumulation
504111
edited Jan 22 at 22:33
Acccumulation
504111
504111
asked Jan 22 at 13:49
Excited RaichuExcited Raichu
6,51521166
asked Jan 22 at 13:49
Excited RaichuExcited Raichu
6,51521166
asked Jan 22 at 13:49
Excited RaichuExcited Raichu
6,51521166
6,51521166
$begingroup$
is that a 6 or a 9? or can it be both? thanks!
$endgroup$
– Omega Krypton
Jan 22 at 13:53
$begingroup$
@OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
$endgroup$
– Excited Raichu
Jan 22 at 13:57
1
$begingroup$
Now that an answer has been accepted, I'll add that they are called Sicherman dice.
$endgroup$
– Jaap Scherphuis
Jan 22 at 15:51
add a comment |
$begingroup$
is that a 6 or a 9? or can it be both? thanks!
$endgroup$
– Omega Krypton
Jan 22 at 13:53
$begingroup$
@OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
$endgroup$
– Excited Raichu
Jan 22 at 13:57
1
$begingroup$
Now that an answer has been accepted, I'll add that they are called Sicherman dice.
$endgroup$
– Jaap Scherphuis
Jan 22 at 15:51
$begingroup$
is that a 6 or a 9? or can it be both? thanks!
$endgroup$
– Omega Krypton
Jan 22 at 13:53
$begingroup$
is that a 6 or a 9? or can it be both? thanks!
$endgroup$
– Omega Krypton
Jan 22 at 13:53
$begingroup$
@OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
$endgroup$
– Excited Raichu
Jan 22 at 13:57
$begingroup$
@OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
$endgroup$
– Excited Raichu
Jan 22 at 13:57
1
1
$begingroup$
Now that an answer has been accepted, I'll add that they are called Sicherman dice.
$endgroup$
– Jaap Scherphuis
Jan 22 at 15:51
$begingroup$
Now that an answer has been accepted, I'll add that they are called Sicherman dice.
$endgroup$
– Jaap Scherphuis
Jan 22 at 15:51
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Easy:
To get a 2 we need a 1 on the 224 die, and this must be opposite the 4, so 1,2,2,3,3,4, and we also need a 12, which must be 4+8, so the other die is 1,3,4,5,6,8.
answered Jan 22 at 13:59
JonMark PerryJonMark Perry
19.2k63991
$endgroup$
1
$begingroup$
In the absence of the requirement that opposite faces on a given die sum to equal values, would there be any other solutions (beyond the obvious permutations)?
$endgroup$
– supercat
Jan 22 at 16:48
$begingroup$
not according to en.wikipedia.org/wiki/Sicherman_dice#Mathematical_justification; @supercat
$endgroup$
– JonMark Perry
Jan 22 at 17:00
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
Easy:
To get a 2 we need a 1 on the 224 die, and this must be opposite the 4, so 1,2,2,3,3,4, and we also need a 12, which must be 4+8, so the other die is 1,3,4,5,6,8.
answered Jan 22 at 13:59
JonMark PerryJonMark Perry
19.2k63991
$endgroup$
1
$begingroup$
In the absence of the requirement that opposite faces on a given die sum to equal values, would there be any other solutions (beyond the obvious permutations)?
$endgroup$
– supercat
Jan 22 at 16:48
$begingroup$
not according to en.wikipedia.org/wiki/Sicherman_dice#Mathematical_justification; @supercat
$endgroup$
– JonMark Perry
Jan 22 at 17:00
add a comment |
$begingroup$
Easy:
To get a 2 we need a 1 on the 224 die, and this must be opposite the 4, so 1,2,2,3,3,4, and we also need a 12, which must be 4+8, so the other die is 1,3,4,5,6,8.
answered Jan 22 at 13:59
JonMark PerryJonMark Perry
19.2k63991
$endgroup$
1
$begingroup$
In the absence of the requirement that opposite faces on a given die sum to equal values, would there be any other solutions (beyond the obvious permutations)?
$endgroup$
– supercat
Jan 22 at 16:48
$begingroup$
not according to en.wikipedia.org/wiki/Sicherman_dice#Mathematical_justification; @supercat
$endgroup$
– JonMark Perry
Jan 22 at 17:00
add a comment |
$begingroup$
Easy:
To get a 2 we need a 1 on the 224 die, and this must be opposite the 4, so 1,2,2,3,3,4, and we also need a 12, which must be 4+8, so the other die is 1,3,4,5,6,8.
answered Jan 22 at 13:59
JonMark PerryJonMark Perry
19.2k63991
$endgroup$
Easy:
To get a 2 we need a 1 on the 224 die, and this must be opposite the 4, so 1,2,2,3,3,4, and we also need a 12, which must be 4+8, so the other die is 1,3,4,5,6,8.
answered Jan 22 at 13:59
JonMark PerryJonMark Perry
19.2k63991
answered Jan 22 at 13:59
JonMark PerryJonMark Perry
19.2k63991
answered Jan 22 at 13:59
JonMark PerryJonMark Perry
19.2k63991
answered Jan 22 at 13:59
JonMark PerryJonMark Perry
19.2k63991
19.2k63991
1
$begingroup$
In the absence of the requirement that opposite faces on a given die sum to equal values, would there be any other solutions (beyond the obvious permutations)?
$endgroup$
– supercat
Jan 22 at 16:48
$begingroup$
not according to en.wikipedia.org/wiki/Sicherman_dice#Mathematical_justification; @supercat
$endgroup$
– JonMark Perry
Jan 22 at 17:00
add a comment |
1
$begingroup$
In the absence of the requirement that opposite faces on a given die sum to equal values, would there be any other solutions (beyond the obvious permutations)?
$endgroup$
– supercat
Jan 22 at 16:48
$begingroup$
not according to en.wikipedia.org/wiki/Sicherman_dice#Mathematical_justification; @supercat
$endgroup$
– JonMark Perry
Jan 22 at 17:00
1
1
$begingroup$
In the absence of the requirement that opposite faces on a given die sum to equal values, would there be any other solutions (beyond the obvious permutations)?
$endgroup$
– supercat
Jan 22 at 16:48
$begingroup$
In the absence of the requirement that opposite faces on a given die sum to equal values, would there be any other solutions (beyond the obvious permutations)?
$endgroup$
– supercat
Jan 22 at 16:48
$begingroup$
not according to en.wikipedia.org/wiki/Sicherman_dice#Mathematical_justification; @supercat
$endgroup$
– JonMark Perry
Jan 22 at 17:00
$begingroup$
not according to en.wikipedia.org/wiki/Sicherman_dice#Mathematical_justification; @supercat
$endgroup$
– JonMark Perry
Jan 22 at 17:00
add a comment |
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$begingroup$
is that a 6 or a 9? or can it be both? thanks!
$endgroup$
– Omega Krypton
Jan 22 at 13:53
$begingroup$
@OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
$endgroup$
– Excited Raichu
Jan 22 at 13:57
1
$begingroup$
Now that an answer has been accepted, I'll add that they are called Sicherman dice.
$endgroup$
– Jaap Scherphuis
Jan 22 at 15:51