$M bigotimes_R (Pi_{iin I} B_i) ncong Pi_{i in I} (M bigotimes B_i)$ [closed]
let M and Bi be R-MODULE for all i in I
Show that $M bigotimes_R (Pi_{iin I} B_i) ncong Pi_{i in I} (M bigotimes B_i)$
Take $R=mathbb{Z}$, $M=mathbb{Q}$ and $B_n =frac{mathbb{Z}}{P^n mathbb{Z}}$
, n > 0
commutative-algebra
closed as off-topic by Scientifica, user26857, Saad, Brahadeesh, Lord Shark the Unknown Nov 28 '18 at 5:54
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Scientifica, user26857, Saad, Brahadeesh, Lord Shark the Unknown
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
let M and Bi be R-MODULE for all i in I
Show that $M bigotimes_R (Pi_{iin I} B_i) ncong Pi_{i in I} (M bigotimes B_i)$
Take $R=mathbb{Z}$, $M=mathbb{Q}$ and $B_n =frac{mathbb{Z}}{P^n mathbb{Z}}$
, n > 0
commutative-algebra
closed as off-topic by Scientifica, user26857, Saad, Brahadeesh, Lord Shark the Unknown Nov 28 '18 at 5:54
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Scientifica, user26857, Saad, Brahadeesh, Lord Shark the Unknown
If this question can be reworded to fit the rules in the help center, please edit the question.
3
Nice exercise! Where does it come from? I can see one side is zero, and the other isn't.
– Lord Shark the Unknown
Nov 27 '18 at 19:01
add a comment |
let M and Bi be R-MODULE for all i in I
Show that $M bigotimes_R (Pi_{iin I} B_i) ncong Pi_{i in I} (M bigotimes B_i)$
Take $R=mathbb{Z}$, $M=mathbb{Q}$ and $B_n =frac{mathbb{Z}}{P^n mathbb{Z}}$
, n > 0
commutative-algebra
let M and Bi be R-MODULE for all i in I
Show that $M bigotimes_R (Pi_{iin I} B_i) ncong Pi_{i in I} (M bigotimes B_i)$
Take $R=mathbb{Z}$, $M=mathbb{Q}$ and $B_n =frac{mathbb{Z}}{P^n mathbb{Z}}$
, n > 0
commutative-algebra
commutative-algebra
edited Nov 28 '18 at 14:44
asked Nov 27 '18 at 19:00
Aaaaaa
253
253
closed as off-topic by Scientifica, user26857, Saad, Brahadeesh, Lord Shark the Unknown Nov 28 '18 at 5:54
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Scientifica, user26857, Saad, Brahadeesh, Lord Shark the Unknown
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Scientifica, user26857, Saad, Brahadeesh, Lord Shark the Unknown Nov 28 '18 at 5:54
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Scientifica, user26857, Saad, Brahadeesh, Lord Shark the Unknown
If this question can be reworded to fit the rules in the help center, please edit the question.
3
Nice exercise! Where does it come from? I can see one side is zero, and the other isn't.
– Lord Shark the Unknown
Nov 27 '18 at 19:01
add a comment |
3
Nice exercise! Where does it come from? I can see one side is zero, and the other isn't.
– Lord Shark the Unknown
Nov 27 '18 at 19:01
3
3
Nice exercise! Where does it come from? I can see one side is zero, and the other isn't.
– Lord Shark the Unknown
Nov 27 '18 at 19:01
Nice exercise! Where does it come from? I can see one side is zero, and the other isn't.
– Lord Shark the Unknown
Nov 27 '18 at 19:01
add a comment |
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3
Nice exercise! Where does it come from? I can see one side is zero, and the other isn't.
– Lord Shark the Unknown
Nov 27 '18 at 19:01