About $ F(u) = int_{-pi/2}^{+pi/2} ln(g(x) + u) dx $












3














We know for $ u > 1 $
$$ int_{-pi/2}^{+pi/2} ln(sin(x) + u) dx
= pi left(lnleft(u + sqrt{u^2 -1}right) - ln(2)right) $$



Usually this is shown by using differentiation under the Integral sign or contour integration.



This made me wonder :



Consider the log-transform



For a given real continuous function $F(u)$ find a real continuous function $g(x) $ that only depends on $x$ ( not on $u$ ) such that



$$ F(u) = int_{-pi/2}^{+pi/2} ln(g(x) + u) dx $$



So



$$ mathcal{L}(F(u)) = g(u) $$



Where $mathcal{L}$ stands for “ log-transform “.



For instance
$$ mathcal{L}left[ pi left(lnleft(u + sqrt{u^2 -1}right) - ln(2)right) right] = sin(u). $$



Notice that in this case $sin(2u),sin(3u),sin(4u),... $ and $sin(-u),sin(-2u),sin(-3u),sin(-4u),... $ are also solutions !
Perhaps uniqueness comes from functions that are strictly increasing ? ( $mathcal{L} ... = exp(u) $? )



What is known about these (inverse) integral transforms ?



Is there an Integral representation for them ?










share|cite|improve this question
























  • Pardon my ignorance, when you say 'log-transform' do you mean to take the log of the function? (Just want to be 100% clear before I give this a go). Btw - Great question.
    – DavidG
    Nov 28 '18 at 23:25










  • No log is taken DavidG. Just a name. Thanks
    – mick
    Nov 29 '18 at 14:49






  • 1




    Thanks for the clarification. Wanted to be sure before I proceeded.
    – DavidG
    Nov 29 '18 at 23:12
















3














We know for $ u > 1 $
$$ int_{-pi/2}^{+pi/2} ln(sin(x) + u) dx
= pi left(lnleft(u + sqrt{u^2 -1}right) - ln(2)right) $$



Usually this is shown by using differentiation under the Integral sign or contour integration.



This made me wonder :



Consider the log-transform



For a given real continuous function $F(u)$ find a real continuous function $g(x) $ that only depends on $x$ ( not on $u$ ) such that



$$ F(u) = int_{-pi/2}^{+pi/2} ln(g(x) + u) dx $$



So



$$ mathcal{L}(F(u)) = g(u) $$



Where $mathcal{L}$ stands for “ log-transform “.



For instance
$$ mathcal{L}left[ pi left(lnleft(u + sqrt{u^2 -1}right) - ln(2)right) right] = sin(u). $$



Notice that in this case $sin(2u),sin(3u),sin(4u),... $ and $sin(-u),sin(-2u),sin(-3u),sin(-4u),... $ are also solutions !
Perhaps uniqueness comes from functions that are strictly increasing ? ( $mathcal{L} ... = exp(u) $? )



What is known about these (inverse) integral transforms ?



Is there an Integral representation for them ?










share|cite|improve this question
























  • Pardon my ignorance, when you say 'log-transform' do you mean to take the log of the function? (Just want to be 100% clear before I give this a go). Btw - Great question.
    – DavidG
    Nov 28 '18 at 23:25










  • No log is taken DavidG. Just a name. Thanks
    – mick
    Nov 29 '18 at 14:49






  • 1




    Thanks for the clarification. Wanted to be sure before I proceeded.
    – DavidG
    Nov 29 '18 at 23:12














3












3








3


3





We know for $ u > 1 $
$$ int_{-pi/2}^{+pi/2} ln(sin(x) + u) dx
= pi left(lnleft(u + sqrt{u^2 -1}right) - ln(2)right) $$



Usually this is shown by using differentiation under the Integral sign or contour integration.



This made me wonder :



Consider the log-transform



For a given real continuous function $F(u)$ find a real continuous function $g(x) $ that only depends on $x$ ( not on $u$ ) such that



$$ F(u) = int_{-pi/2}^{+pi/2} ln(g(x) + u) dx $$



So



$$ mathcal{L}(F(u)) = g(u) $$



Where $mathcal{L}$ stands for “ log-transform “.



For instance
$$ mathcal{L}left[ pi left(lnleft(u + sqrt{u^2 -1}right) - ln(2)right) right] = sin(u). $$



Notice that in this case $sin(2u),sin(3u),sin(4u),... $ and $sin(-u),sin(-2u),sin(-3u),sin(-4u),... $ are also solutions !
Perhaps uniqueness comes from functions that are strictly increasing ? ( $mathcal{L} ... = exp(u) $? )



What is known about these (inverse) integral transforms ?



Is there an Integral representation for them ?










share|cite|improve this question















We know for $ u > 1 $
$$ int_{-pi/2}^{+pi/2} ln(sin(x) + u) dx
= pi left(lnleft(u + sqrt{u^2 -1}right) - ln(2)right) $$



Usually this is shown by using differentiation under the Integral sign or contour integration.



This made me wonder :



Consider the log-transform



For a given real continuous function $F(u)$ find a real continuous function $g(x) $ that only depends on $x$ ( not on $u$ ) such that



$$ F(u) = int_{-pi/2}^{+pi/2} ln(g(x) + u) dx $$



So



$$ mathcal{L}(F(u)) = g(u) $$



Where $mathcal{L}$ stands for “ log-transform “.



For instance
$$ mathcal{L}left[ pi left(lnleft(u + sqrt{u^2 -1}right) - ln(2)right) right] = sin(u). $$



Notice that in this case $sin(2u),sin(3u),sin(4u),... $ and $sin(-u),sin(-2u),sin(-3u),sin(-4u),... $ are also solutions !
Perhaps uniqueness comes from functions that are strictly increasing ? ( $mathcal{L} ... = exp(u) $? )



What is known about these (inverse) integral transforms ?



Is there an Integral representation for them ?







calculus representation-theory closed-form integral-transforms inverse-problems






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 28 '18 at 12:42









DavidG

1,648619




1,648619










asked Nov 27 '18 at 18:52









mick

5,07922064




5,07922064












  • Pardon my ignorance, when you say 'log-transform' do you mean to take the log of the function? (Just want to be 100% clear before I give this a go). Btw - Great question.
    – DavidG
    Nov 28 '18 at 23:25










  • No log is taken DavidG. Just a name. Thanks
    – mick
    Nov 29 '18 at 14:49






  • 1




    Thanks for the clarification. Wanted to be sure before I proceeded.
    – DavidG
    Nov 29 '18 at 23:12


















  • Pardon my ignorance, when you say 'log-transform' do you mean to take the log of the function? (Just want to be 100% clear before I give this a go). Btw - Great question.
    – DavidG
    Nov 28 '18 at 23:25










  • No log is taken DavidG. Just a name. Thanks
    – mick
    Nov 29 '18 at 14:49






  • 1




    Thanks for the clarification. Wanted to be sure before I proceeded.
    – DavidG
    Nov 29 '18 at 23:12
















Pardon my ignorance, when you say 'log-transform' do you mean to take the log of the function? (Just want to be 100% clear before I give this a go). Btw - Great question.
– DavidG
Nov 28 '18 at 23:25




Pardon my ignorance, when you say 'log-transform' do you mean to take the log of the function? (Just want to be 100% clear before I give this a go). Btw - Great question.
– DavidG
Nov 28 '18 at 23:25












No log is taken DavidG. Just a name. Thanks
– mick
Nov 29 '18 at 14:49




No log is taken DavidG. Just a name. Thanks
– mick
Nov 29 '18 at 14:49




1




1




Thanks for the clarification. Wanted to be sure before I proceeded.
– DavidG
Nov 29 '18 at 23:12




Thanks for the clarification. Wanted to be sure before I proceeded.
– DavidG
Nov 29 '18 at 23:12















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