Derivative of $ y = arctg sqrt{x} $ [closed]












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My solution is $ frac{1}{1+x} ast frac{1}{2}ast x^{-frac{1}{2}} $. Is it correct? Thanks






derivatives







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closed as off-topic by Did, Brahadeesh, Cesareo, KM101, DRF Dec 4 at 14:39


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, Brahadeesh, Cesareo, KM101, DRF

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  • Edited a mistype in my solution.
    – Johny547
    Nov 25 at 14:54










  • Yes, it is correct.
    – José Carlos Santos
    Nov 25 at 14:56
















0














My solution is $ frac{1}{1+x} ast frac{1}{2}ast x^{-frac{1}{2}} $. Is it correct? Thanks






derivatives







share|cite|improve this question













closed as off-topic by Did, Brahadeesh, Cesareo, KM101, DRF Dec 4 at 14:39


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, Brahadeesh, Cesareo, KM101, DRF

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Edited a mistype in my solution.
    – Johny547
    Nov 25 at 14:54










  • Yes, it is correct.
    – José Carlos Santos
    Nov 25 at 14:56














0












0








0







My solution is $ frac{1}{1+x} ast frac{1}{2}ast x^{-frac{1}{2}} $. Is it correct? Thanks






derivatives







share|cite|improve this question













My solution is $ frac{1}{1+x} ast frac{1}{2}ast x^{-frac{1}{2}} $. Is it correct? Thanks






derivatives




derivatives






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Nov 25 at 14:53









Johny547

1154




1154




closed as off-topic by Did, Brahadeesh, Cesareo, KM101, DRF Dec 4 at 14:39


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, Brahadeesh, Cesareo, KM101, DRF

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Did, Brahadeesh, Cesareo, KM101, DRF Dec 4 at 14:39


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, Brahadeesh, Cesareo, KM101, DRF

If this question can be reworded to fit the rules in the help center, please edit the question.












  • Edited a mistype in my solution.
    – Johny547
    Nov 25 at 14:54










  • Yes, it is correct.
    – José Carlos Santos
    Nov 25 at 14:56


















  • Edited a mistype in my solution.
    – Johny547
    Nov 25 at 14:54










  • Yes, it is correct.
    – José Carlos Santos
    Nov 25 at 14:56
















Edited a mistype in my solution.
– Johny547
Nov 25 at 14:54




Edited a mistype in my solution.
– Johny547
Nov 25 at 14:54












Yes, it is correct.
– José Carlos Santos
Nov 25 at 14:56




Yes, it is correct.
– José Carlos Santos
Nov 25 at 14:56










1 Answer
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0














That is correct. $y' = frac{1}{2sqrt{x}(x+1)}$






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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    That is correct. $y' = frac{1}{2sqrt{x}(x+1)}$






    share|cite|improve this answer


























      0














      That is correct. $y' = frac{1}{2sqrt{x}(x+1)}$






      share|cite|improve this answer
























        0












        0








        0






        That is correct. $y' = frac{1}{2sqrt{x}(x+1)}$






        share|cite|improve this answer












        That is correct. $y' = frac{1}{2sqrt{x}(x+1)}$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 25 at 15:04









        TeamoBeamo

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