Derivative of $ y = arctg sqrt{x} $ [closed]
My solution is $ frac{1}{1+x} ast frac{1}{2}ast x^{-frac{1}{2}} $. Is it correct? Thanks
derivatives
asked Nov 25 at 14:53
Johny547
1154
closed as off-topic by Did, Brahadeesh, Cesareo, KM101, DRF Dec 4 at 14:39
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My solution is $ frac{1}{1+x} ast frac{1}{2}ast x^{-frac{1}{2}} $. Is it correct? Thanks
derivatives
asked Nov 25 at 14:53
Johny547
1154
closed as off-topic by Did, Brahadeesh, Cesareo, KM101, DRF Dec 4 at 14:39
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, Brahadeesh, Cesareo, KM101, DRF
If this question can be reworded to fit the rules in the help center, please edit the question.
Edited a mistype in my solution.
– Johny547
Nov 25 at 14:54
Yes, it is correct.
– José Carlos Santos
Nov 25 at 14:56
add a comment |
My solution is $ frac{1}{1+x} ast frac{1}{2}ast x^{-frac{1}{2}} $. Is it correct? Thanks
derivatives
asked Nov 25 at 14:53
Johny547
1154
My solution is $ frac{1}{1+x} ast frac{1}{2}ast x^{-frac{1}{2}} $. Is it correct? Thanks
derivatives
derivatives
asked Nov 25 at 14:53
Johny547
1154
asked Nov 25 at 14:53
Johny547
1154
asked Nov 25 at 14:53
Johny547
1154
asked Nov 25 at 14:53
Johny547
1154
asked Nov 25 at 14:53
Johny547
1154
1154
closed as off-topic by Did, Brahadeesh, Cesareo, KM101, DRF Dec 4 at 14:39
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, Brahadeesh, Cesareo, KM101, DRF
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Did, Brahadeesh, Cesareo, KM101, DRF Dec 4 at 14:39
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, Brahadeesh, Cesareo, KM101, DRF
If this question can be reworded to fit the rules in the help center, please edit the question.
Edited a mistype in my solution.
– Johny547
Nov 25 at 14:54
Yes, it is correct.
– José Carlos Santos
Nov 25 at 14:56
add a comment |
Edited a mistype in my solution.
– Johny547
Nov 25 at 14:54
Yes, it is correct.
– José Carlos Santos
Nov 25 at 14:56
Edited a mistype in my solution.
– Johny547
Nov 25 at 14:54
Edited a mistype in my solution.
– Johny547
Nov 25 at 14:54
Yes, it is correct.
– José Carlos Santos
Nov 25 at 14:56
Yes, it is correct.
– José Carlos Santos
Nov 25 at 14:56
add a comment |
1 Answer
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That is correct. $y' = frac{1}{2sqrt{x}(x+1)}$
answered Nov 25 at 15:04
TeamoBeamo
161
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
That is correct. $y' = frac{1}{2sqrt{x}(x+1)}$
answered Nov 25 at 15:04
TeamoBeamo
161
add a comment |
That is correct. $y' = frac{1}{2sqrt{x}(x+1)}$
answered Nov 25 at 15:04
TeamoBeamo
161
add a comment |
That is correct. $y' = frac{1}{2sqrt{x}(x+1)}$
answered Nov 25 at 15:04
TeamoBeamo
161
That is correct. $y' = frac{1}{2sqrt{x}(x+1)}$
answered Nov 25 at 15:04
TeamoBeamo
161
answered Nov 25 at 15:04
TeamoBeamo
161
answered Nov 25 at 15:04
TeamoBeamo
161
answered Nov 25 at 15:04
TeamoBeamo
161
161
add a comment |
add a comment |
Edited a mistype in my solution.
– Johny547
Nov 25 at 14:54
Yes, it is correct.
– José Carlos Santos
Nov 25 at 14:56