Solve for x & y for this complex equation.
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$(2+3i)x² - (3-2i)y = 2x - 3y + 5i$
Where "i" is $sqrt-1$
complex-analysis complex-numbers
asked Nov 13 at 5:10
Kaustuv Sawarn
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up vote
0
down vote
favorite
$(2+3i)x² - (3-2i)y = 2x - 3y + 5i$
Where "i" is $sqrt-1$
complex-analysis complex-numbers
asked Nov 13 at 5:10
Kaustuv Sawarn
345
New contributor
Kaustuv Sawarn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
$(2+3i)x² - (3-2i)y = 2x - 3y + 5i$
Where "i" is $sqrt-1$
complex-analysis complex-numbers
asked Nov 13 at 5:10
Kaustuv Sawarn
345
New contributor
Kaustuv Sawarn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$(2+3i)x² - (3-2i)y = 2x - 3y + 5i$
Where "i" is $sqrt-1$
complex-analysis complex-numbers
complex-analysis complex-numbers
asked Nov 13 at 5:10
Kaustuv Sawarn
345
New contributor
Kaustuv Sawarn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 13 at 5:10
Kaustuv Sawarn
345
New contributor
Kaustuv Sawarn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 13 at 5:10
Kaustuv Sawarn
345
New contributor
Kaustuv Sawarn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 13 at 5:10
Kaustuv Sawarn
345
asked Nov 13 at 5:10
Kaustuv Sawarn
345
345
New contributor
Kaustuv Sawarn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Kaustuv Sawarn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Kaustuv Sawarn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
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votes
up vote
1
down vote
accepted
Two complex numbers are equal if and only if the real parts are equal and the imaginary parts are also equal.
In your problem we have $$ 2x^2 -3y = 2x-3y$$ and $$ 3x^2+2y =5$$.
solve for $x$ and $y$ to get $$ x=0, y=5/2$$ or $$x=1, y=1$$
answered Nov 13 at 5:24
Mohammad Riazi-Kermani
39.8k41957
You are assuming $x,y$ are real, which is probably correct but not given by OP
– Ross Millikan
Nov 13 at 5:32
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Two complex numbers are equal if and only if the real parts are equal and the imaginary parts are also equal.
In your problem we have $$ 2x^2 -3y = 2x-3y$$ and $$ 3x^2+2y =5$$.
solve for $x$ and $y$ to get $$ x=0, y=5/2$$ or $$x=1, y=1$$
answered Nov 13 at 5:24
Mohammad Riazi-Kermani
39.8k41957
You are assuming $x,y$ are real, which is probably correct but not given by OP
– Ross Millikan
Nov 13 at 5:32
add a comment |
up vote
1
down vote
accepted
Two complex numbers are equal if and only if the real parts are equal and the imaginary parts are also equal.
In your problem we have $$ 2x^2 -3y = 2x-3y$$ and $$ 3x^2+2y =5$$.
solve for $x$ and $y$ to get $$ x=0, y=5/2$$ or $$x=1, y=1$$
answered Nov 13 at 5:24
Mohammad Riazi-Kermani
39.8k41957
You are assuming $x,y$ are real, which is probably correct but not given by OP
– Ross Millikan
Nov 13 at 5:32
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Two complex numbers are equal if and only if the real parts are equal and the imaginary parts are also equal.
In your problem we have $$ 2x^2 -3y = 2x-3y$$ and $$ 3x^2+2y =5$$.
solve for $x$ and $y$ to get $$ x=0, y=5/2$$ or $$x=1, y=1$$
answered Nov 13 at 5:24
Mohammad Riazi-Kermani
39.8k41957
Two complex numbers are equal if and only if the real parts are equal and the imaginary parts are also equal.
In your problem we have $$ 2x^2 -3y = 2x-3y$$ and $$ 3x^2+2y =5$$.
solve for $x$ and $y$ to get $$ x=0, y=5/2$$ or $$x=1, y=1$$
answered Nov 13 at 5:24
Mohammad Riazi-Kermani
39.8k41957
answered Nov 13 at 5:24
Mohammad Riazi-Kermani
39.8k41957
answered Nov 13 at 5:24
Mohammad Riazi-Kermani
39.8k41957
answered Nov 13 at 5:24
Mohammad Riazi-Kermani
39.8k41957
39.8k41957
You are assuming $x,y$ are real, which is probably correct but not given by OP
– Ross Millikan
Nov 13 at 5:32
add a comment |
You are assuming $x,y$ are real, which is probably correct but not given by OP
– Ross Millikan
Nov 13 at 5:32
You are assuming $x,y$ are real, which is probably correct but not given by OP
– Ross Millikan
Nov 13 at 5:32
You are assuming $x,y$ are real, which is probably correct but not given by OP
– Ross Millikan
Nov 13 at 5:32
add a comment |
Kaustuv Sawarn is a new contributor. Be nice, and check out our Code of Conduct.
Kaustuv Sawarn is a new contributor. Be nice, and check out our Code of Conduct.
Kaustuv Sawarn is a new contributor. Be nice, and check out our Code of Conduct.
Kaustuv Sawarn is a new contributor. Be nice, and check out our Code of Conduct.
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