Why do electromagnetic waves have the magnetic and electric field intensities in the same phase?












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My question is: in electromagnetic waves, if we consider the electric field as a sine function, the magnetic field will be also a sine function, but I am confused why that is this way.



If I look at Maxwell's equation, the changing magnetic field generates the electric field and the changing electric field generates the magnetic field, so according to my opinion if the accelerating electron generates a sine electric field change, then its magnetic field should be a cosine function because $frac{d(sin x)}{dx}=cos x$.










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$endgroup$








  • 1




    $begingroup$
    "changing magnetic field generates the electric field and the changing electric field generates the magnetic field" - I think this is misleading. Maxwell's equations aren't statements of cause and effect. Although we talk about one field changing inducing another, they happen at the same time. An increasing magnetic field doesn't really cause a curl to exist in the electric field, they are physically the same - an increasing magnetic field cannot exist without the curl in the electric field.
    $endgroup$
    – andars
    Feb 18 at 4:46






  • 1




    $begingroup$
    It's worth stating clearly that the in-phase nature of the waves is true in the far field (i.e. when the waves are examined much farther from the source than the size of the source), but that this is not the case in the near field (i.e. when you are close to the source).
    $endgroup$
    – dmckee
    Feb 18 at 5:58








  • 1




    $begingroup$
    Note that for standing waves E and B are out of phase.
    $endgroup$
    – my2cts
    Feb 18 at 7:28










  • $begingroup$
    @my2cts, i do not believe you meant what you wrote, just think of an open ended (or short circuited) transmission line.
    $endgroup$
    – hyportnex
    Feb 18 at 15:18
















11












$begingroup$


My question is: in electromagnetic waves, if we consider the electric field as a sine function, the magnetic field will be also a sine function, but I am confused why that is this way.



If I look at Maxwell's equation, the changing magnetic field generates the electric field and the changing electric field generates the magnetic field, so according to my opinion if the accelerating electron generates a sine electric field change, then its magnetic field should be a cosine function because $frac{d(sin x)}{dx}=cos x$.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    "changing magnetic field generates the electric field and the changing electric field generates the magnetic field" - I think this is misleading. Maxwell's equations aren't statements of cause and effect. Although we talk about one field changing inducing another, they happen at the same time. An increasing magnetic field doesn't really cause a curl to exist in the electric field, they are physically the same - an increasing magnetic field cannot exist without the curl in the electric field.
    $endgroup$
    – andars
    Feb 18 at 4:46






  • 1




    $begingroup$
    It's worth stating clearly that the in-phase nature of the waves is true in the far field (i.e. when the waves are examined much farther from the source than the size of the source), but that this is not the case in the near field (i.e. when you are close to the source).
    $endgroup$
    – dmckee
    Feb 18 at 5:58








  • 1




    $begingroup$
    Note that for standing waves E and B are out of phase.
    $endgroup$
    – my2cts
    Feb 18 at 7:28










  • $begingroup$
    @my2cts, i do not believe you meant what you wrote, just think of an open ended (or short circuited) transmission line.
    $endgroup$
    – hyportnex
    Feb 18 at 15:18














11












11








11


1



$begingroup$


My question is: in electromagnetic waves, if we consider the electric field as a sine function, the magnetic field will be also a sine function, but I am confused why that is this way.



If I look at Maxwell's equation, the changing magnetic field generates the electric field and the changing electric field generates the magnetic field, so according to my opinion if the accelerating electron generates a sine electric field change, then its magnetic field should be a cosine function because $frac{d(sin x)}{dx}=cos x$.










share|cite|improve this question











$endgroup$




My question is: in electromagnetic waves, if we consider the electric field as a sine function, the magnetic field will be also a sine function, but I am confused why that is this way.



If I look at Maxwell's equation, the changing magnetic field generates the electric field and the changing electric field generates the magnetic field, so according to my opinion if the accelerating electron generates a sine electric field change, then its magnetic field should be a cosine function because $frac{d(sin x)}{dx}=cos x$.







electromagnetic-radiation






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share|cite|improve this question













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edited Feb 18 at 4:07









David Z

63.8k23136252




63.8k23136252










asked Feb 17 at 22:12









Bálint TataiBálint Tatai

22827




22827








  • 1




    $begingroup$
    "changing magnetic field generates the electric field and the changing electric field generates the magnetic field" - I think this is misleading. Maxwell's equations aren't statements of cause and effect. Although we talk about one field changing inducing another, they happen at the same time. An increasing magnetic field doesn't really cause a curl to exist in the electric field, they are physically the same - an increasing magnetic field cannot exist without the curl in the electric field.
    $endgroup$
    – andars
    Feb 18 at 4:46






  • 1




    $begingroup$
    It's worth stating clearly that the in-phase nature of the waves is true in the far field (i.e. when the waves are examined much farther from the source than the size of the source), but that this is not the case in the near field (i.e. when you are close to the source).
    $endgroup$
    – dmckee
    Feb 18 at 5:58








  • 1




    $begingroup$
    Note that for standing waves E and B are out of phase.
    $endgroup$
    – my2cts
    Feb 18 at 7:28










  • $begingroup$
    @my2cts, i do not believe you meant what you wrote, just think of an open ended (or short circuited) transmission line.
    $endgroup$
    – hyportnex
    Feb 18 at 15:18














  • 1




    $begingroup$
    "changing magnetic field generates the electric field and the changing electric field generates the magnetic field" - I think this is misleading. Maxwell's equations aren't statements of cause and effect. Although we talk about one field changing inducing another, they happen at the same time. An increasing magnetic field doesn't really cause a curl to exist in the electric field, they are physically the same - an increasing magnetic field cannot exist without the curl in the electric field.
    $endgroup$
    – andars
    Feb 18 at 4:46






  • 1




    $begingroup$
    It's worth stating clearly that the in-phase nature of the waves is true in the far field (i.e. when the waves are examined much farther from the source than the size of the source), but that this is not the case in the near field (i.e. when you are close to the source).
    $endgroup$
    – dmckee
    Feb 18 at 5:58








  • 1




    $begingroup$
    Note that for standing waves E and B are out of phase.
    $endgroup$
    – my2cts
    Feb 18 at 7:28










  • $begingroup$
    @my2cts, i do not believe you meant what you wrote, just think of an open ended (or short circuited) transmission line.
    $endgroup$
    – hyportnex
    Feb 18 at 15:18








1




1




$begingroup$
"changing magnetic field generates the electric field and the changing electric field generates the magnetic field" - I think this is misleading. Maxwell's equations aren't statements of cause and effect. Although we talk about one field changing inducing another, they happen at the same time. An increasing magnetic field doesn't really cause a curl to exist in the electric field, they are physically the same - an increasing magnetic field cannot exist without the curl in the electric field.
$endgroup$
– andars
Feb 18 at 4:46




$begingroup$
"changing magnetic field generates the electric field and the changing electric field generates the magnetic field" - I think this is misleading. Maxwell's equations aren't statements of cause and effect. Although we talk about one field changing inducing another, they happen at the same time. An increasing magnetic field doesn't really cause a curl to exist in the electric field, they are physically the same - an increasing magnetic field cannot exist without the curl in the electric field.
$endgroup$
– andars
Feb 18 at 4:46




1




1




$begingroup$
It's worth stating clearly that the in-phase nature of the waves is true in the far field (i.e. when the waves are examined much farther from the source than the size of the source), but that this is not the case in the near field (i.e. when you are close to the source).
$endgroup$
– dmckee
Feb 18 at 5:58






$begingroup$
It's worth stating clearly that the in-phase nature of the waves is true in the far field (i.e. when the waves are examined much farther from the source than the size of the source), but that this is not the case in the near field (i.e. when you are close to the source).
$endgroup$
– dmckee
Feb 18 at 5:58






1




1




$begingroup$
Note that for standing waves E and B are out of phase.
$endgroup$
– my2cts
Feb 18 at 7:28




$begingroup$
Note that for standing waves E and B are out of phase.
$endgroup$
– my2cts
Feb 18 at 7:28












$begingroup$
@my2cts, i do not believe you meant what you wrote, just think of an open ended (or short circuited) transmission line.
$endgroup$
– hyportnex
Feb 18 at 15:18




$begingroup$
@my2cts, i do not believe you meant what you wrote, just think of an open ended (or short circuited) transmission line.
$endgroup$
– hyportnex
Feb 18 at 15:18










4 Answers
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active

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E and B are in phase for a running plane wave, but are out of phase for a standing wave. standing waveThis can be easily seen by considering the vector potential, $A(t, x) $. Using $E = partial_t A$ and $B=partial_x A$. For $A=sin(omega t - kx) $ you find that E and B are in phase. For $A=sin(omega t) sin(kx) $, a standing wave, E and B are out of phase.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thanks. Could you tell me when can standing waves occur ?
    $endgroup$
    – Bálint Tatai
    Feb 19 at 14:57



















13












$begingroup$

The Maxwell equations that relate electric and magnetic fields to each other read (in vacuum, in SI units) as
begin{align}
nabla times mathbf E & = -frac{partialmathbf B}{partial t} \
nabla times mathbf B & = frac{1}{c^2} frac{partialmathbf E}{partial t},
end{align}

where the notation $nabla times{cdot}$ is a spatial derivative (the curl). This means that both sides have derivatives, and if you're applying them to a function like $cos(kx-omega t)$, then they will both change the cosine into a sine. This is what locks the phase of both waves to equal values.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Just to comment with my comment on the questions, this explanation works nicely if spatial arrangement of the fields is uniform enough (as in a plane wave, which is to say in he far-field), but misses important details if the wave has a no-planar structure (as in the near-field).
    $endgroup$
    – dmckee
    Feb 18 at 6:00






  • 1




    $begingroup$
    @dmckee Oh, absolutely. And indeed if you don't have a plane wave (which can mean that you have anything from a near-field to something as sophisticated as the superposition of two plane waves) then the fields are not required to be (strictly) orthogonal to each other or to the propagation direction. Hence the "if..." in this answer.
    $endgroup$
    – Emilio Pisanty
    Feb 18 at 7:13



















0












$begingroup$

This is one of those 'why' questions that physics can or cannot answer, depending on what you want from answer to 'why'.



If equations are a satisfactory explanation, then the Maxwells Equation in Emilios answer are a complete answer.



Unfortunately, not far beneath the surface of that answer is 'why do Maxwells Equations' fit reality?' or 'why do fields behave the way they do so that we can derive Maxwells Equations?'. Wigner along with many other physicists was similarly troubled by such questions.



It doesn't get any more intuitive if you go down further to QED to try to explain the classical behaviour.



At the lowest level, the answer is 'that's the way Nature behaves'.






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$endgroup$













  • $begingroup$
    Lower level physical theories can describe why, but I don't think any where put forth outside if either theories because at the time of Maxwell the atom hadn't yet been proven or shown necessary. Gravitation and any field theories had this problem. I think in general everyone supposed the mechanisms describing these fields, happen on scales far to small, and for all they knew possibly fundamental to reality. Then quantum came along and were all taught to not try and describe these mechanisms. Simply by the words of Feynman that it is impossible to understand.
    $endgroup$
    – marshal craft
    Feb 18 at 7:43










  • $begingroup$
    And here we are today, no further really have we progressed it seems. Further it is maybe just as interesting to ask why nobody considers this? Perhaps for the pure sport of it alone, why nobody has framed wiled hypothesis as to the mechanisms underlying fields?
    $endgroup$
    – marshal craft
    Feb 18 at 7:45










  • $begingroup$
    But from an abstract math perspective, chaos, infinitely complicated systems i guess are more interesting. Maybe they all know and don't say, that we need to be able to handle insanely complex, large systems and discover abstract principles which emerge at large scales, to get ahead of the curve.
    $endgroup$
    – marshal craft
    Feb 18 at 7:48












  • $begingroup$
    This refusal of even an attempt of a deeper understanding is unsatisfying. A mathematical formula, such as given by Emilio, is nothing but an insight cast into a strict notational form. Only by understanding the formula and the insight it communicates do we obtain a true mental grasp of a matter which allows us to mentally proceed on our own.
    $endgroup$
    – Peter A. Schneider
    Feb 18 at 13:45



















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The E and H fields in a time-harmonic EM wave are in phase in the time domain when the medium's polarization (electric and magnetic) are in phase with the corresponding fields. You can see that polarization fields inherently act as 'source' terms in Maxwell's equations, and hence, instantaneous polarization implies in-phase relationship. However, whenever there is dissipation (such as existence of conduction current, or out of phase polarization), the E and H fields are no longer in phase. In other words, the one phasor cannot respond instantaneously to the changes of the second one in time. Note that regardless of propagating or standing wave, E and H fields are in phase with each other in the time domain in a lossless medium (for a standing wave, they are 'out of phase' spatially).






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    4 Answers
    4






    active

    oldest

    votes








    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

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    2












    $begingroup$

    E and B are in phase for a running plane wave, but are out of phase for a standing wave. standing waveThis can be easily seen by considering the vector potential, $A(t, x) $. Using $E = partial_t A$ and $B=partial_x A$. For $A=sin(omega t - kx) $ you find that E and B are in phase. For $A=sin(omega t) sin(kx) $, a standing wave, E and B are out of phase.






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      Thanks. Could you tell me when can standing waves occur ?
      $endgroup$
      – Bálint Tatai
      Feb 19 at 14:57
















    2












    $begingroup$

    E and B are in phase for a running plane wave, but are out of phase for a standing wave. standing waveThis can be easily seen by considering the vector potential, $A(t, x) $. Using $E = partial_t A$ and $B=partial_x A$. For $A=sin(omega t - kx) $ you find that E and B are in phase. For $A=sin(omega t) sin(kx) $, a standing wave, E and B are out of phase.






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      Thanks. Could you tell me when can standing waves occur ?
      $endgroup$
      – Bálint Tatai
      Feb 19 at 14:57














    2












    2








    2





    $begingroup$

    E and B are in phase for a running plane wave, but are out of phase for a standing wave. standing waveThis can be easily seen by considering the vector potential, $A(t, x) $. Using $E = partial_t A$ and $B=partial_x A$. For $A=sin(omega t - kx) $ you find that E and B are in phase. For $A=sin(omega t) sin(kx) $, a standing wave, E and B are out of phase.






    share|cite|improve this answer









    $endgroup$



    E and B are in phase for a running plane wave, but are out of phase for a standing wave. standing waveThis can be easily seen by considering the vector potential, $A(t, x) $. Using $E = partial_t A$ and $B=partial_x A$. For $A=sin(omega t - kx) $ you find that E and B are in phase. For $A=sin(omega t) sin(kx) $, a standing wave, E and B are out of phase.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered Feb 18 at 22:52









    my2ctsmy2cts

    5,5952718




    5,5952718












    • $begingroup$
      Thanks. Could you tell me when can standing waves occur ?
      $endgroup$
      – Bálint Tatai
      Feb 19 at 14:57


















    • $begingroup$
      Thanks. Could you tell me when can standing waves occur ?
      $endgroup$
      – Bálint Tatai
      Feb 19 at 14:57
















    $begingroup$
    Thanks. Could you tell me when can standing waves occur ?
    $endgroup$
    – Bálint Tatai
    Feb 19 at 14:57




    $begingroup$
    Thanks. Could you tell me when can standing waves occur ?
    $endgroup$
    – Bálint Tatai
    Feb 19 at 14:57











    13












    $begingroup$

    The Maxwell equations that relate electric and magnetic fields to each other read (in vacuum, in SI units) as
    begin{align}
    nabla times mathbf E & = -frac{partialmathbf B}{partial t} \
    nabla times mathbf B & = frac{1}{c^2} frac{partialmathbf E}{partial t},
    end{align}

    where the notation $nabla times{cdot}$ is a spatial derivative (the curl). This means that both sides have derivatives, and if you're applying them to a function like $cos(kx-omega t)$, then they will both change the cosine into a sine. This is what locks the phase of both waves to equal values.






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      Just to comment with my comment on the questions, this explanation works nicely if spatial arrangement of the fields is uniform enough (as in a plane wave, which is to say in he far-field), but misses important details if the wave has a no-planar structure (as in the near-field).
      $endgroup$
      – dmckee
      Feb 18 at 6:00






    • 1




      $begingroup$
      @dmckee Oh, absolutely. And indeed if you don't have a plane wave (which can mean that you have anything from a near-field to something as sophisticated as the superposition of two plane waves) then the fields are not required to be (strictly) orthogonal to each other or to the propagation direction. Hence the "if..." in this answer.
      $endgroup$
      – Emilio Pisanty
      Feb 18 at 7:13
















    13












    $begingroup$

    The Maxwell equations that relate electric and magnetic fields to each other read (in vacuum, in SI units) as
    begin{align}
    nabla times mathbf E & = -frac{partialmathbf B}{partial t} \
    nabla times mathbf B & = frac{1}{c^2} frac{partialmathbf E}{partial t},
    end{align}

    where the notation $nabla times{cdot}$ is a spatial derivative (the curl). This means that both sides have derivatives, and if you're applying them to a function like $cos(kx-omega t)$, then they will both change the cosine into a sine. This is what locks the phase of both waves to equal values.






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      Just to comment with my comment on the questions, this explanation works nicely if spatial arrangement of the fields is uniform enough (as in a plane wave, which is to say in he far-field), but misses important details if the wave has a no-planar structure (as in the near-field).
      $endgroup$
      – dmckee
      Feb 18 at 6:00






    • 1




      $begingroup$
      @dmckee Oh, absolutely. And indeed if you don't have a plane wave (which can mean that you have anything from a near-field to something as sophisticated as the superposition of two plane waves) then the fields are not required to be (strictly) orthogonal to each other or to the propagation direction. Hence the "if..." in this answer.
      $endgroup$
      – Emilio Pisanty
      Feb 18 at 7:13














    13












    13








    13





    $begingroup$

    The Maxwell equations that relate electric and magnetic fields to each other read (in vacuum, in SI units) as
    begin{align}
    nabla times mathbf E & = -frac{partialmathbf B}{partial t} \
    nabla times mathbf B & = frac{1}{c^2} frac{partialmathbf E}{partial t},
    end{align}

    where the notation $nabla times{cdot}$ is a spatial derivative (the curl). This means that both sides have derivatives, and if you're applying them to a function like $cos(kx-omega t)$, then they will both change the cosine into a sine. This is what locks the phase of both waves to equal values.






    share|cite|improve this answer









    $endgroup$



    The Maxwell equations that relate electric and magnetic fields to each other read (in vacuum, in SI units) as
    begin{align}
    nabla times mathbf E & = -frac{partialmathbf B}{partial t} \
    nabla times mathbf B & = frac{1}{c^2} frac{partialmathbf E}{partial t},
    end{align}

    where the notation $nabla times{cdot}$ is a spatial derivative (the curl). This means that both sides have derivatives, and if you're applying them to a function like $cos(kx-omega t)$, then they will both change the cosine into a sine. This is what locks the phase of both waves to equal values.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered Feb 17 at 22:28









    Emilio PisantyEmilio Pisanty

    85.7k23211430




    85.7k23211430












    • $begingroup$
      Just to comment with my comment on the questions, this explanation works nicely if spatial arrangement of the fields is uniform enough (as in a plane wave, which is to say in he far-field), but misses important details if the wave has a no-planar structure (as in the near-field).
      $endgroup$
      – dmckee
      Feb 18 at 6:00






    • 1




      $begingroup$
      @dmckee Oh, absolutely. And indeed if you don't have a plane wave (which can mean that you have anything from a near-field to something as sophisticated as the superposition of two plane waves) then the fields are not required to be (strictly) orthogonal to each other or to the propagation direction. Hence the "if..." in this answer.
      $endgroup$
      – Emilio Pisanty
      Feb 18 at 7:13


















    • $begingroup$
      Just to comment with my comment on the questions, this explanation works nicely if spatial arrangement of the fields is uniform enough (as in a plane wave, which is to say in he far-field), but misses important details if the wave has a no-planar structure (as in the near-field).
      $endgroup$
      – dmckee
      Feb 18 at 6:00






    • 1




      $begingroup$
      @dmckee Oh, absolutely. And indeed if you don't have a plane wave (which can mean that you have anything from a near-field to something as sophisticated as the superposition of two plane waves) then the fields are not required to be (strictly) orthogonal to each other or to the propagation direction. Hence the "if..." in this answer.
      $endgroup$
      – Emilio Pisanty
      Feb 18 at 7:13
















    $begingroup$
    Just to comment with my comment on the questions, this explanation works nicely if spatial arrangement of the fields is uniform enough (as in a plane wave, which is to say in he far-field), but misses important details if the wave has a no-planar structure (as in the near-field).
    $endgroup$
    – dmckee
    Feb 18 at 6:00




    $begingroup$
    Just to comment with my comment on the questions, this explanation works nicely if spatial arrangement of the fields is uniform enough (as in a plane wave, which is to say in he far-field), but misses important details if the wave has a no-planar structure (as in the near-field).
    $endgroup$
    – dmckee
    Feb 18 at 6:00




    1




    1




    $begingroup$
    @dmckee Oh, absolutely. And indeed if you don't have a plane wave (which can mean that you have anything from a near-field to something as sophisticated as the superposition of two plane waves) then the fields are not required to be (strictly) orthogonal to each other or to the propagation direction. Hence the "if..." in this answer.
    $endgroup$
    – Emilio Pisanty
    Feb 18 at 7:13




    $begingroup$
    @dmckee Oh, absolutely. And indeed if you don't have a plane wave (which can mean that you have anything from a near-field to something as sophisticated as the superposition of two plane waves) then the fields are not required to be (strictly) orthogonal to each other or to the propagation direction. Hence the "if..." in this answer.
    $endgroup$
    – Emilio Pisanty
    Feb 18 at 7:13











    0












    $begingroup$

    This is one of those 'why' questions that physics can or cannot answer, depending on what you want from answer to 'why'.



    If equations are a satisfactory explanation, then the Maxwells Equation in Emilios answer are a complete answer.



    Unfortunately, not far beneath the surface of that answer is 'why do Maxwells Equations' fit reality?' or 'why do fields behave the way they do so that we can derive Maxwells Equations?'. Wigner along with many other physicists was similarly troubled by such questions.



    It doesn't get any more intuitive if you go down further to QED to try to explain the classical behaviour.



    At the lowest level, the answer is 'that's the way Nature behaves'.






    share|cite|improve this answer











    $endgroup$













    • $begingroup$
      Lower level physical theories can describe why, but I don't think any where put forth outside if either theories because at the time of Maxwell the atom hadn't yet been proven or shown necessary. Gravitation and any field theories had this problem. I think in general everyone supposed the mechanisms describing these fields, happen on scales far to small, and for all they knew possibly fundamental to reality. Then quantum came along and were all taught to not try and describe these mechanisms. Simply by the words of Feynman that it is impossible to understand.
      $endgroup$
      – marshal craft
      Feb 18 at 7:43










    • $begingroup$
      And here we are today, no further really have we progressed it seems. Further it is maybe just as interesting to ask why nobody considers this? Perhaps for the pure sport of it alone, why nobody has framed wiled hypothesis as to the mechanisms underlying fields?
      $endgroup$
      – marshal craft
      Feb 18 at 7:45










    • $begingroup$
      But from an abstract math perspective, chaos, infinitely complicated systems i guess are more interesting. Maybe they all know and don't say, that we need to be able to handle insanely complex, large systems and discover abstract principles which emerge at large scales, to get ahead of the curve.
      $endgroup$
      – marshal craft
      Feb 18 at 7:48












    • $begingroup$
      This refusal of even an attempt of a deeper understanding is unsatisfying. A mathematical formula, such as given by Emilio, is nothing but an insight cast into a strict notational form. Only by understanding the formula and the insight it communicates do we obtain a true mental grasp of a matter which allows us to mentally proceed on our own.
      $endgroup$
      – Peter A. Schneider
      Feb 18 at 13:45
















    0












    $begingroup$

    This is one of those 'why' questions that physics can or cannot answer, depending on what you want from answer to 'why'.



    If equations are a satisfactory explanation, then the Maxwells Equation in Emilios answer are a complete answer.



    Unfortunately, not far beneath the surface of that answer is 'why do Maxwells Equations' fit reality?' or 'why do fields behave the way they do so that we can derive Maxwells Equations?'. Wigner along with many other physicists was similarly troubled by such questions.



    It doesn't get any more intuitive if you go down further to QED to try to explain the classical behaviour.



    At the lowest level, the answer is 'that's the way Nature behaves'.






    share|cite|improve this answer











    $endgroup$













    • $begingroup$
      Lower level physical theories can describe why, but I don't think any where put forth outside if either theories because at the time of Maxwell the atom hadn't yet been proven or shown necessary. Gravitation and any field theories had this problem. I think in general everyone supposed the mechanisms describing these fields, happen on scales far to small, and for all they knew possibly fundamental to reality. Then quantum came along and were all taught to not try and describe these mechanisms. Simply by the words of Feynman that it is impossible to understand.
      $endgroup$
      – marshal craft
      Feb 18 at 7:43










    • $begingroup$
      And here we are today, no further really have we progressed it seems. Further it is maybe just as interesting to ask why nobody considers this? Perhaps for the pure sport of it alone, why nobody has framed wiled hypothesis as to the mechanisms underlying fields?
      $endgroup$
      – marshal craft
      Feb 18 at 7:45










    • $begingroup$
      But from an abstract math perspective, chaos, infinitely complicated systems i guess are more interesting. Maybe they all know and don't say, that we need to be able to handle insanely complex, large systems and discover abstract principles which emerge at large scales, to get ahead of the curve.
      $endgroup$
      – marshal craft
      Feb 18 at 7:48












    • $begingroup$
      This refusal of even an attempt of a deeper understanding is unsatisfying. A mathematical formula, such as given by Emilio, is nothing but an insight cast into a strict notational form. Only by understanding the formula and the insight it communicates do we obtain a true mental grasp of a matter which allows us to mentally proceed on our own.
      $endgroup$
      – Peter A. Schneider
      Feb 18 at 13:45














    0












    0








    0





    $begingroup$

    This is one of those 'why' questions that physics can or cannot answer, depending on what you want from answer to 'why'.



    If equations are a satisfactory explanation, then the Maxwells Equation in Emilios answer are a complete answer.



    Unfortunately, not far beneath the surface of that answer is 'why do Maxwells Equations' fit reality?' or 'why do fields behave the way they do so that we can derive Maxwells Equations?'. Wigner along with many other physicists was similarly troubled by such questions.



    It doesn't get any more intuitive if you go down further to QED to try to explain the classical behaviour.



    At the lowest level, the answer is 'that's the way Nature behaves'.






    share|cite|improve this answer











    $endgroup$



    This is one of those 'why' questions that physics can or cannot answer, depending on what you want from answer to 'why'.



    If equations are a satisfactory explanation, then the Maxwells Equation in Emilios answer are a complete answer.



    Unfortunately, not far beneath the surface of that answer is 'why do Maxwells Equations' fit reality?' or 'why do fields behave the way they do so that we can derive Maxwells Equations?'. Wigner along with many other physicists was similarly troubled by such questions.



    It doesn't get any more intuitive if you go down further to QED to try to explain the classical behaviour.



    At the lowest level, the answer is 'that's the way Nature behaves'.







    share|cite|improve this answer














    share|cite|improve this answer



    share|cite|improve this answer








    edited Feb 18 at 8:36

























    answered Feb 18 at 7:11









    Neil_UKNeil_UK

    1605




    1605












    • $begingroup$
      Lower level physical theories can describe why, but I don't think any where put forth outside if either theories because at the time of Maxwell the atom hadn't yet been proven or shown necessary. Gravitation and any field theories had this problem. I think in general everyone supposed the mechanisms describing these fields, happen on scales far to small, and for all they knew possibly fundamental to reality. Then quantum came along and were all taught to not try and describe these mechanisms. Simply by the words of Feynman that it is impossible to understand.
      $endgroup$
      – marshal craft
      Feb 18 at 7:43










    • $begingroup$
      And here we are today, no further really have we progressed it seems. Further it is maybe just as interesting to ask why nobody considers this? Perhaps for the pure sport of it alone, why nobody has framed wiled hypothesis as to the mechanisms underlying fields?
      $endgroup$
      – marshal craft
      Feb 18 at 7:45










    • $begingroup$
      But from an abstract math perspective, chaos, infinitely complicated systems i guess are more interesting. Maybe they all know and don't say, that we need to be able to handle insanely complex, large systems and discover abstract principles which emerge at large scales, to get ahead of the curve.
      $endgroup$
      – marshal craft
      Feb 18 at 7:48












    • $begingroup$
      This refusal of even an attempt of a deeper understanding is unsatisfying. A mathematical formula, such as given by Emilio, is nothing but an insight cast into a strict notational form. Only by understanding the formula and the insight it communicates do we obtain a true mental grasp of a matter which allows us to mentally proceed on our own.
      $endgroup$
      – Peter A. Schneider
      Feb 18 at 13:45


















    • $begingroup$
      Lower level physical theories can describe why, but I don't think any where put forth outside if either theories because at the time of Maxwell the atom hadn't yet been proven or shown necessary. Gravitation and any field theories had this problem. I think in general everyone supposed the mechanisms describing these fields, happen on scales far to small, and for all they knew possibly fundamental to reality. Then quantum came along and were all taught to not try and describe these mechanisms. Simply by the words of Feynman that it is impossible to understand.
      $endgroup$
      – marshal craft
      Feb 18 at 7:43










    • $begingroup$
      And here we are today, no further really have we progressed it seems. Further it is maybe just as interesting to ask why nobody considers this? Perhaps for the pure sport of it alone, why nobody has framed wiled hypothesis as to the mechanisms underlying fields?
      $endgroup$
      – marshal craft
      Feb 18 at 7:45










    • $begingroup$
      But from an abstract math perspective, chaos, infinitely complicated systems i guess are more interesting. Maybe they all know and don't say, that we need to be able to handle insanely complex, large systems and discover abstract principles which emerge at large scales, to get ahead of the curve.
      $endgroup$
      – marshal craft
      Feb 18 at 7:48












    • $begingroup$
      This refusal of even an attempt of a deeper understanding is unsatisfying. A mathematical formula, such as given by Emilio, is nothing but an insight cast into a strict notational form. Only by understanding the formula and the insight it communicates do we obtain a true mental grasp of a matter which allows us to mentally proceed on our own.
      $endgroup$
      – Peter A. Schneider
      Feb 18 at 13:45
















    $begingroup$
    Lower level physical theories can describe why, but I don't think any where put forth outside if either theories because at the time of Maxwell the atom hadn't yet been proven or shown necessary. Gravitation and any field theories had this problem. I think in general everyone supposed the mechanisms describing these fields, happen on scales far to small, and for all they knew possibly fundamental to reality. Then quantum came along and were all taught to not try and describe these mechanisms. Simply by the words of Feynman that it is impossible to understand.
    $endgroup$
    – marshal craft
    Feb 18 at 7:43




    $begingroup$
    Lower level physical theories can describe why, but I don't think any where put forth outside if either theories because at the time of Maxwell the atom hadn't yet been proven or shown necessary. Gravitation and any field theories had this problem. I think in general everyone supposed the mechanisms describing these fields, happen on scales far to small, and for all they knew possibly fundamental to reality. Then quantum came along and were all taught to not try and describe these mechanisms. Simply by the words of Feynman that it is impossible to understand.
    $endgroup$
    – marshal craft
    Feb 18 at 7:43












    $begingroup$
    And here we are today, no further really have we progressed it seems. Further it is maybe just as interesting to ask why nobody considers this? Perhaps for the pure sport of it alone, why nobody has framed wiled hypothesis as to the mechanisms underlying fields?
    $endgroup$
    – marshal craft
    Feb 18 at 7:45




    $begingroup$
    And here we are today, no further really have we progressed it seems. Further it is maybe just as interesting to ask why nobody considers this? Perhaps for the pure sport of it alone, why nobody has framed wiled hypothesis as to the mechanisms underlying fields?
    $endgroup$
    – marshal craft
    Feb 18 at 7:45












    $begingroup$
    But from an abstract math perspective, chaos, infinitely complicated systems i guess are more interesting. Maybe they all know and don't say, that we need to be able to handle insanely complex, large systems and discover abstract principles which emerge at large scales, to get ahead of the curve.
    $endgroup$
    – marshal craft
    Feb 18 at 7:48






    $begingroup$
    But from an abstract math perspective, chaos, infinitely complicated systems i guess are more interesting. Maybe they all know and don't say, that we need to be able to handle insanely complex, large systems and discover abstract principles which emerge at large scales, to get ahead of the curve.
    $endgroup$
    – marshal craft
    Feb 18 at 7:48














    $begingroup$
    This refusal of even an attempt of a deeper understanding is unsatisfying. A mathematical formula, such as given by Emilio, is nothing but an insight cast into a strict notational form. Only by understanding the formula and the insight it communicates do we obtain a true mental grasp of a matter which allows us to mentally proceed on our own.
    $endgroup$
    – Peter A. Schneider
    Feb 18 at 13:45




    $begingroup$
    This refusal of even an attempt of a deeper understanding is unsatisfying. A mathematical formula, such as given by Emilio, is nothing but an insight cast into a strict notational form. Only by understanding the formula and the insight it communicates do we obtain a true mental grasp of a matter which allows us to mentally proceed on our own.
    $endgroup$
    – Peter A. Schneider
    Feb 18 at 13:45











    0












    $begingroup$

    The E and H fields in a time-harmonic EM wave are in phase in the time domain when the medium's polarization (electric and magnetic) are in phase with the corresponding fields. You can see that polarization fields inherently act as 'source' terms in Maxwell's equations, and hence, instantaneous polarization implies in-phase relationship. However, whenever there is dissipation (such as existence of conduction current, or out of phase polarization), the E and H fields are no longer in phase. In other words, the one phasor cannot respond instantaneously to the changes of the second one in time. Note that regardless of propagating or standing wave, E and H fields are in phase with each other in the time domain in a lossless medium (for a standing wave, they are 'out of phase' spatially).






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      The E and H fields in a time-harmonic EM wave are in phase in the time domain when the medium's polarization (electric and magnetic) are in phase with the corresponding fields. You can see that polarization fields inherently act as 'source' terms in Maxwell's equations, and hence, instantaneous polarization implies in-phase relationship. However, whenever there is dissipation (such as existence of conduction current, or out of phase polarization), the E and H fields are no longer in phase. In other words, the one phasor cannot respond instantaneously to the changes of the second one in time. Note that regardless of propagating or standing wave, E and H fields are in phase with each other in the time domain in a lossless medium (for a standing wave, they are 'out of phase' spatially).






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        The E and H fields in a time-harmonic EM wave are in phase in the time domain when the medium's polarization (electric and magnetic) are in phase with the corresponding fields. You can see that polarization fields inherently act as 'source' terms in Maxwell's equations, and hence, instantaneous polarization implies in-phase relationship. However, whenever there is dissipation (such as existence of conduction current, or out of phase polarization), the E and H fields are no longer in phase. In other words, the one phasor cannot respond instantaneously to the changes of the second one in time. Note that regardless of propagating or standing wave, E and H fields are in phase with each other in the time domain in a lossless medium (for a standing wave, they are 'out of phase' spatially).






        share|cite|improve this answer









        $endgroup$



        The E and H fields in a time-harmonic EM wave are in phase in the time domain when the medium's polarization (electric and magnetic) are in phase with the corresponding fields. You can see that polarization fields inherently act as 'source' terms in Maxwell's equations, and hence, instantaneous polarization implies in-phase relationship. However, whenever there is dissipation (such as existence of conduction current, or out of phase polarization), the E and H fields are no longer in phase. In other words, the one phasor cannot respond instantaneously to the changes of the second one in time. Note that regardless of propagating or standing wave, E and H fields are in phase with each other in the time domain in a lossless medium (for a standing wave, they are 'out of phase' spatially).







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Feb 21 at 3:24









        user207826user207826

        113




        113






























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