How to prove associativity of lattice?
(a^b)^c = a^(b^c) I can understand intuitively that it is right but i am not able to write the proof.
Also i didn't understood the answer in Associativity of a lattice
discrete-mathematics
asked Nov 26 at 18:32
Amit
1388
add a comment |
(a^b)^c = a^(b^c) I can understand intuitively that it is right but i am not able to write the proof.
Also i didn't understood the answer in Associativity of a lattice
discrete-mathematics
asked Nov 26 at 18:32
Amit
1388
add a comment |
(a^b)^c = a^(b^c) I can understand intuitively that it is right but i am not able to write the proof.
Also i didn't understood the answer in Associativity of a lattice
discrete-mathematics
asked Nov 26 at 18:32
Amit
1388
(a^b)^c = a^(b^c) I can understand intuitively that it is right but i am not able to write the proof.
Also i didn't understood the answer in Associativity of a lattice
discrete-mathematics
discrete-mathematics
asked Nov 26 at 18:32
Amit
1388
asked Nov 26 at 18:32
Amit
1388
asked Nov 26 at 18:32
Amit
1388
asked Nov 26 at 18:32
Amit
1388
asked Nov 26 at 18:32
Amit
1388
1388
add a comment |
add a comment |
1 Answer
1
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oldest
votes
If you're familiar with school course of informatics, just remember about AND (logic symbol) and act like ^ is AND.
Or you can draw a simple picture. You need: a circle, b circle, c circle. Draw a picture as a overlaps with b, and another picture as b overlaps with c. Then add to each picture a third circle which overlaps with those two in their intersection. Voila!
[edit] Note about informatics. Imagine that ^ is multiplication and a,b, and c can be either 1 or 0 (doesn't matter in this problem, though). Then (a*b)c=a(b*c).
Also, "a", "b", or "c" in my text is more like "rule about a/b/c", not a,b,c themselves. This allows us to use informatics principles: rule can be either suiting (1) or not (0).
answered Nov 26 at 19:21
Kelly Shepphard
2298
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you're familiar with school course of informatics, just remember about AND (logic symbol) and act like ^ is AND.
Or you can draw a simple picture. You need: a circle, b circle, c circle. Draw a picture as a overlaps with b, and another picture as b overlaps with c. Then add to each picture a third circle which overlaps with those two in their intersection. Voila!
[edit] Note about informatics. Imagine that ^ is multiplication and a,b, and c can be either 1 or 0 (doesn't matter in this problem, though). Then (a*b)c=a(b*c).
Also, "a", "b", or "c" in my text is more like "rule about a/b/c", not a,b,c themselves. This allows us to use informatics principles: rule can be either suiting (1) or not (0).
answered Nov 26 at 19:21
Kelly Shepphard
2298
add a comment |
If you're familiar with school course of informatics, just remember about AND (logic symbol) and act like ^ is AND.
Or you can draw a simple picture. You need: a circle, b circle, c circle. Draw a picture as a overlaps with b, and another picture as b overlaps with c. Then add to each picture a third circle which overlaps with those two in their intersection. Voila!
[edit] Note about informatics. Imagine that ^ is multiplication and a,b, and c can be either 1 or 0 (doesn't matter in this problem, though). Then (a*b)c=a(b*c).
Also, "a", "b", or "c" in my text is more like "rule about a/b/c", not a,b,c themselves. This allows us to use informatics principles: rule can be either suiting (1) or not (0).
answered Nov 26 at 19:21
Kelly Shepphard
2298
add a comment |
If you're familiar with school course of informatics, just remember about AND (logic symbol) and act like ^ is AND.
Or you can draw a simple picture. You need: a circle, b circle, c circle. Draw a picture as a overlaps with b, and another picture as b overlaps with c. Then add to each picture a third circle which overlaps with those two in their intersection. Voila!
[edit] Note about informatics. Imagine that ^ is multiplication and a,b, and c can be either 1 or 0 (doesn't matter in this problem, though). Then (a*b)c=a(b*c).
Also, "a", "b", or "c" in my text is more like "rule about a/b/c", not a,b,c themselves. This allows us to use informatics principles: rule can be either suiting (1) or not (0).
answered Nov 26 at 19:21
Kelly Shepphard
2298
If you're familiar with school course of informatics, just remember about AND (logic symbol) and act like ^ is AND.
Or you can draw a simple picture. You need: a circle, b circle, c circle. Draw a picture as a overlaps with b, and another picture as b overlaps with c. Then add to each picture a third circle which overlaps with those two in their intersection. Voila!
[edit] Note about informatics. Imagine that ^ is multiplication and a,b, and c can be either 1 or 0 (doesn't matter in this problem, though). Then (a*b)c=a(b*c).
Also, "a", "b", or "c" in my text is more like "rule about a/b/c", not a,b,c themselves. This allows us to use informatics principles: rule can be either suiting (1) or not (0).
answered Nov 26 at 19:21
Kelly Shepphard
2298
edited Nov 26 at 19:53
answered Nov 26 at 19:21
Kelly Shepphard
2298
answered Nov 26 at 19:21
Kelly Shepphard
2298
answered Nov 26 at 19:21
Kelly Shepphard
2298
2298
add a comment |
add a comment |
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