Converting input containing special character to float












4














This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.



I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.



def toNum(interest):

if '/' not in interest:
if float(interest) > 1:
return float(interest)/100

else:
return float(interest)


else:
l=
n = 0
count = 1

list_interest=
for e in interest:
list_interest.append(e)

for e in list_interest:

if count == 1 or count == 3:
l.append(e)
count = count +1
continue


if e == '/':
n = n + 1
count = count +1
else:
l[n] = l[n] + e

return int(l[0]) / int(l[1])









interest = input("Interest rate: ")
interest = toNum(interest)
print(interest)









share|improve this question



























    4














    This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.



    I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.



    def toNum(interest):

    if '/' not in interest:
    if float(interest) > 1:
    return float(interest)/100

    else:
    return float(interest)


    else:
    l=
    n = 0
    count = 1

    list_interest=
    for e in interest:
    list_interest.append(e)

    for e in list_interest:

    if count == 1 or count == 3:
    l.append(e)
    count = count +1
    continue


    if e == '/':
    n = n + 1
    count = count +1
    else:
    l[n] = l[n] + e

    return int(l[0]) / int(l[1])









    interest = input("Interest rate: ")
    interest = toNum(interest)
    print(interest)









    share|improve this question

























      4












      4








      4







      This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.



      I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.



      def toNum(interest):

      if '/' not in interest:
      if float(interest) > 1:
      return float(interest)/100

      else:
      return float(interest)


      else:
      l=
      n = 0
      count = 1

      list_interest=
      for e in interest:
      list_interest.append(e)

      for e in list_interest:

      if count == 1 or count == 3:
      l.append(e)
      count = count +1
      continue


      if e == '/':
      n = n + 1
      count = count +1
      else:
      l[n] = l[n] + e

      return int(l[0]) / int(l[1])









      interest = input("Interest rate: ")
      interest = toNum(interest)
      print(interest)









      share|improve this question













      This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.



      I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.



      def toNum(interest):

      if '/' not in interest:
      if float(interest) > 1:
      return float(interest)/100

      else:
      return float(interest)


      else:
      l=
      n = 0
      count = 1

      list_interest=
      for e in interest:
      list_interest.append(e)

      for e in list_interest:

      if count == 1 or count == 3:
      l.append(e)
      count = count +1
      continue


      if e == '/':
      n = n + 1
      count = count +1
      else:
      l[n] = l[n] + e

      return int(l[0]) / int(l[1])









      interest = input("Interest rate: ")
      interest = toNum(interest)
      print(interest)






      python python-3.x






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 26 at 13:51









      ikadorus

      234




      234






















          2 Answers
          2






          active

          oldest

          votes


















          4














          For reading a fraction such as "97/100", you can use the fractions library.



          For example:





          from fractions import Fraction

          f = Fraction("97/100")

          print(float(f)) # prints 0.97


          And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:



          from fractions import Fraction

          def toNum(interest):
          f = Fraction(interest)
          f = float(f)

          if f > 1:
          f /= 100

          return f

          print(toNum("97/100")) # prints 0.97
          print(toNum(0.97)) # prints 0.97
          print(toNum(9)) # prints 0.09





          share|improve this answer



















          • 1




            Why convert to float at all and not keep a fractions.Fraction object all along?
            – Mathias Ettinger
            Nov 26 at 15:59










          • @MathiasEttinger That's also a good option, just depends on preference.
            – esote
            Nov 26 at 16:14



















          1














          While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:



          if "/" in interest:
          numerator, denominator = map(int, interest.split("/"))
          return numerator / denominator


          Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.



          Note also that using sensible names makes it immediately obvious what this code does.






          share|improve this answer





















            Your Answer





            StackExchange.ifUsing("editor", function () {
            return StackExchange.using("mathjaxEditing", function () {
            StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
            StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
            });
            });
            }, "mathjax-editing");

            StackExchange.ifUsing("editor", function () {
            StackExchange.using("externalEditor", function () {
            StackExchange.using("snippets", function () {
            StackExchange.snippets.init();
            });
            });
            }, "code-snippets");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "196"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: false,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: null,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f208448%2fconverting-input-containing-special-character-to-float%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4














            For reading a fraction such as "97/100", you can use the fractions library.



            For example:





            from fractions import Fraction

            f = Fraction("97/100")

            print(float(f)) # prints 0.97


            And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:



            from fractions import Fraction

            def toNum(interest):
            f = Fraction(interest)
            f = float(f)

            if f > 1:
            f /= 100

            return f

            print(toNum("97/100")) # prints 0.97
            print(toNum(0.97)) # prints 0.97
            print(toNum(9)) # prints 0.09





            share|improve this answer



















            • 1




              Why convert to float at all and not keep a fractions.Fraction object all along?
              – Mathias Ettinger
              Nov 26 at 15:59










            • @MathiasEttinger That's also a good option, just depends on preference.
              – esote
              Nov 26 at 16:14
















            4














            For reading a fraction such as "97/100", you can use the fractions library.



            For example:





            from fractions import Fraction

            f = Fraction("97/100")

            print(float(f)) # prints 0.97


            And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:



            from fractions import Fraction

            def toNum(interest):
            f = Fraction(interest)
            f = float(f)

            if f > 1:
            f /= 100

            return f

            print(toNum("97/100")) # prints 0.97
            print(toNum(0.97)) # prints 0.97
            print(toNum(9)) # prints 0.09





            share|improve this answer



















            • 1




              Why convert to float at all and not keep a fractions.Fraction object all along?
              – Mathias Ettinger
              Nov 26 at 15:59










            • @MathiasEttinger That's also a good option, just depends on preference.
              – esote
              Nov 26 at 16:14














            4












            4








            4






            For reading a fraction such as "97/100", you can use the fractions library.



            For example:





            from fractions import Fraction

            f = Fraction("97/100")

            print(float(f)) # prints 0.97


            And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:



            from fractions import Fraction

            def toNum(interest):
            f = Fraction(interest)
            f = float(f)

            if f > 1:
            f /= 100

            return f

            print(toNum("97/100")) # prints 0.97
            print(toNum(0.97)) # prints 0.97
            print(toNum(9)) # prints 0.09





            share|improve this answer














            For reading a fraction such as "97/100", you can use the fractions library.



            For example:





            from fractions import Fraction

            f = Fraction("97/100")

            print(float(f)) # prints 0.97


            And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:



            from fractions import Fraction

            def toNum(interest):
            f = Fraction(interest)
            f = float(f)

            if f > 1:
            f /= 100

            return f

            print(toNum("97/100")) # prints 0.97
            print(toNum(0.97)) # prints 0.97
            print(toNum(9)) # prints 0.09






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 26 at 15:03

























            answered Nov 26 at 14:11









            esote

            1,7951933




            1,7951933








            • 1




              Why convert to float at all and not keep a fractions.Fraction object all along?
              – Mathias Ettinger
              Nov 26 at 15:59










            • @MathiasEttinger That's also a good option, just depends on preference.
              – esote
              Nov 26 at 16:14














            • 1




              Why convert to float at all and not keep a fractions.Fraction object all along?
              – Mathias Ettinger
              Nov 26 at 15:59










            • @MathiasEttinger That's also a good option, just depends on preference.
              – esote
              Nov 26 at 16:14








            1




            1




            Why convert to float at all and not keep a fractions.Fraction object all along?
            – Mathias Ettinger
            Nov 26 at 15:59




            Why convert to float at all and not keep a fractions.Fraction object all along?
            – Mathias Ettinger
            Nov 26 at 15:59












            @MathiasEttinger That's also a good option, just depends on preference.
            – esote
            Nov 26 at 16:14




            @MathiasEttinger That's also a good option, just depends on preference.
            – esote
            Nov 26 at 16:14













            1














            While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:



            if "/" in interest:
            numerator, denominator = map(int, interest.split("/"))
            return numerator / denominator


            Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.



            Note also that using sensible names makes it immediately obvious what this code does.






            share|improve this answer


























              1














              While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:



              if "/" in interest:
              numerator, denominator = map(int, interest.split("/"))
              return numerator / denominator


              Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.



              Note also that using sensible names makes it immediately obvious what this code does.






              share|improve this answer
























                1












                1








                1






                While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:



                if "/" in interest:
                numerator, denominator = map(int, interest.split("/"))
                return numerator / denominator


                Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.



                Note also that using sensible names makes it immediately obvious what this code does.






                share|improve this answer












                While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:



                if "/" in interest:
                numerator, denominator = map(int, interest.split("/"))
                return numerator / denominator


                Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.



                Note also that using sensible names makes it immediately obvious what this code does.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 27 at 11:27









                Graipher

                23.5k53585




                23.5k53585






























                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to Code Review Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    Use MathJax to format equations. MathJax reference.


                    To learn more, see our tips on writing great answers.





                    Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


                    Please pay close attention to the following guidance:


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f208448%2fconverting-input-containing-special-character-to-float%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    Probability when a professor distributes a quiz and homework assignment to a class of n students.

                    Aardman Animations

                    Are they similar matrix