how to solve the complex logarithm problem with limit Re(z) converges to infinity?
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Prove that $$lim_{Re(z)rightarrow infty }(logGamma (z+1)-(z+frac{1}{2})log z+z)=frac{1}{2}log2pi.$$
analysis
edited Nov 15 at 8:48
Tianlalu
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asked Nov 15 at 8:34
Jidnoi Kajidlit
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Prove that $$lim_{Re(z)rightarrow infty }(logGamma (z+1)-(z+frac{1}{2})log z+z)=frac{1}{2}log2pi.$$
analysis
edited Nov 15 at 8:48
Tianlalu
2,629632
asked Nov 15 at 8:34
Jidnoi Kajidlit
4
3
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 15 at 8:35
1
Are you allowed the use of the Stirling formula ?
– Yves Daoust
Nov 15 at 8:55
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Prove that $$lim_{Re(z)rightarrow infty }(logGamma (z+1)-(z+frac{1}{2})log z+z)=frac{1}{2}log2pi.$$
analysis
edited Nov 15 at 8:48
Tianlalu
2,629632
asked Nov 15 at 8:34
Jidnoi Kajidlit
4
Prove that $$lim_{Re(z)rightarrow infty }(logGamma (z+1)-(z+frac{1}{2})log z+z)=frac{1}{2}log2pi.$$
analysis
analysis
edited Nov 15 at 8:48
Tianlalu
2,629632
asked Nov 15 at 8:34
Jidnoi Kajidlit
4
edited Nov 15 at 8:48
Tianlalu
2,629632
asked Nov 15 at 8:34
Jidnoi Kajidlit
4
edited Nov 15 at 8:48
Tianlalu
2,629632
edited Nov 15 at 8:48
Tianlalu
2,629632
edited Nov 15 at 8:48
Tianlalu
2,629632
2,629632
asked Nov 15 at 8:34
Jidnoi Kajidlit
4
asked Nov 15 at 8:34
Jidnoi Kajidlit
4
asked Nov 15 at 8:34
Jidnoi Kajidlit
4
4
3
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 15 at 8:35
1
Are you allowed the use of the Stirling formula ?
– Yves Daoust
Nov 15 at 8:55
add a comment |
3
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 15 at 8:35
1
Are you allowed the use of the Stirling formula ?
– Yves Daoust
Nov 15 at 8:55
3
3
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 15 at 8:35
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 15 at 8:35
1
1
Are you allowed the use of the Stirling formula ?
– Yves Daoust
Nov 15 at 8:55
Are you allowed the use of the Stirling formula ?
– Yves Daoust
Nov 15 at 8:55
add a comment |
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Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 15 at 8:35
1
Are you allowed the use of the Stirling formula ?
– Yves Daoust
Nov 15 at 8:55