Why is Sesame Street's Count von Count's favorite number $34,!969$? [closed]












20












$begingroup$


In the 2 minute BBC News audio clip Sesame Street: What is Count von Count's favourite number? "The Count" is asked




Do you have a favorite number?




to which he replied




Thirty four thousand, nine hundred and sixty nine. It's a square root thing.




Does the number 34,969 have any particularly notable properties that would make it "The Count"'s favorite number?



enter image description here






Revelations from the world of counting from the late Jerry Nelson, the voice of Count von Count, who was interviewed by Tim Harford to mark Sesame Street's 40th anniversary in 2009.



Photo: Count von Count attends Macy's Thanksgiving Parade 2018 Credit: Getty Images



Release date: 01 February 2019
Duration: 2 minutes











share|cite|improve this question











$endgroup$



closed as primarily opinion-based by Peter, TheSimpliFire, Holo, Xander Henderson, José Carlos Santos Feb 3 at 18:27


Many good questions generate some degree of opinion based on expert experience, but answers to this question will tend to be almost entirely based on opinions, rather than facts, references, or specific expertise. If this question can be reworded to fit the rules in the help center, please edit the question.














  • 4




    $begingroup$
    Well, $34969 = 187^2$.
    $endgroup$
    – jvdhooft
    Feb 2 at 22:11






  • 7




    $begingroup$
    To go the other way $34969 = sqrt{1222830961}$. I think we just have to accept that this was just a dry joke. Given infinite numbers it's funny if one's favorite number is something arbitrary. And it's funnier if one gives a reason that, although not incorrect, reveals little.
    $endgroup$
    – fleablood
    Feb 2 at 22:27






  • 2




    $begingroup$
    "Does the number 34,969 have any particularly notable properties that would make it "The Count"'s favorite number?" Yes!
    $endgroup$
    – Count Iblis
    Feb 2 at 23:49








  • 5




    $begingroup$
    Why does this have so many upvotes??
    $endgroup$
    – YiFan
    Feb 3 at 5:03






  • 3




    $begingroup$
    @YiFan: This community seems to have a fondness for bat-related things.
    $endgroup$
    – Blue
    Feb 3 at 6:59


















20












$begingroup$


In the 2 minute BBC News audio clip Sesame Street: What is Count von Count's favourite number? "The Count" is asked




Do you have a favorite number?




to which he replied




Thirty four thousand, nine hundred and sixty nine. It's a square root thing.




Does the number 34,969 have any particularly notable properties that would make it "The Count"'s favorite number?



enter image description here






Revelations from the world of counting from the late Jerry Nelson, the voice of Count von Count, who was interviewed by Tim Harford to mark Sesame Street's 40th anniversary in 2009.



Photo: Count von Count attends Macy's Thanksgiving Parade 2018 Credit: Getty Images



Release date: 01 February 2019
Duration: 2 minutes











share|cite|improve this question











$endgroup$



closed as primarily opinion-based by Peter, TheSimpliFire, Holo, Xander Henderson, José Carlos Santos Feb 3 at 18:27


Many good questions generate some degree of opinion based on expert experience, but answers to this question will tend to be almost entirely based on opinions, rather than facts, references, or specific expertise. If this question can be reworded to fit the rules in the help center, please edit the question.














  • 4




    $begingroup$
    Well, $34969 = 187^2$.
    $endgroup$
    – jvdhooft
    Feb 2 at 22:11






  • 7




    $begingroup$
    To go the other way $34969 = sqrt{1222830961}$. I think we just have to accept that this was just a dry joke. Given infinite numbers it's funny if one's favorite number is something arbitrary. And it's funnier if one gives a reason that, although not incorrect, reveals little.
    $endgroup$
    – fleablood
    Feb 2 at 22:27






  • 2




    $begingroup$
    "Does the number 34,969 have any particularly notable properties that would make it "The Count"'s favorite number?" Yes!
    $endgroup$
    – Count Iblis
    Feb 2 at 23:49








  • 5




    $begingroup$
    Why does this have so many upvotes??
    $endgroup$
    – YiFan
    Feb 3 at 5:03






  • 3




    $begingroup$
    @YiFan: This community seems to have a fondness for bat-related things.
    $endgroup$
    – Blue
    Feb 3 at 6:59
















20












20








20


9



$begingroup$


In the 2 minute BBC News audio clip Sesame Street: What is Count von Count's favourite number? "The Count" is asked




Do you have a favorite number?




to which he replied




Thirty four thousand, nine hundred and sixty nine. It's a square root thing.




Does the number 34,969 have any particularly notable properties that would make it "The Count"'s favorite number?



enter image description here






Revelations from the world of counting from the late Jerry Nelson, the voice of Count von Count, who was interviewed by Tim Harford to mark Sesame Street's 40th anniversary in 2009.



Photo: Count von Count attends Macy's Thanksgiving Parade 2018 Credit: Getty Images



Release date: 01 February 2019
Duration: 2 minutes











share|cite|improve this question











$endgroup$




In the 2 minute BBC News audio clip Sesame Street: What is Count von Count's favourite number? "The Count" is asked




Do you have a favorite number?




to which he replied




Thirty four thousand, nine hundred and sixty nine. It's a square root thing.




Does the number 34,969 have any particularly notable properties that would make it "The Count"'s favorite number?



enter image description here






Revelations from the world of counting from the late Jerry Nelson, the voice of Count von Count, who was interviewed by Tim Harford to mark Sesame Street's 40th anniversary in 2009.



Photo: Count von Count attends Macy's Thanksgiving Parade 2018 Credit: Getty Images



Release date: 01 February 2019
Duration: 2 minutes








soft-question prime-numbers radicals






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Feb 3 at 18:14









Xander Henderson

14.7k103555




14.7k103555










asked Feb 2 at 22:06









uhohuhoh

5741618




5741618




closed as primarily opinion-based by Peter, TheSimpliFire, Holo, Xander Henderson, José Carlos Santos Feb 3 at 18:27


Many good questions generate some degree of opinion based on expert experience, but answers to this question will tend to be almost entirely based on opinions, rather than facts, references, or specific expertise. If this question can be reworded to fit the rules in the help center, please edit the question.









closed as primarily opinion-based by Peter, TheSimpliFire, Holo, Xander Henderson, José Carlos Santos Feb 3 at 18:27


Many good questions generate some degree of opinion based on expert experience, but answers to this question will tend to be almost entirely based on opinions, rather than facts, references, or specific expertise. If this question can be reworded to fit the rules in the help center, please edit the question.










  • 4




    $begingroup$
    Well, $34969 = 187^2$.
    $endgroup$
    – jvdhooft
    Feb 2 at 22:11






  • 7




    $begingroup$
    To go the other way $34969 = sqrt{1222830961}$. I think we just have to accept that this was just a dry joke. Given infinite numbers it's funny if one's favorite number is something arbitrary. And it's funnier if one gives a reason that, although not incorrect, reveals little.
    $endgroup$
    – fleablood
    Feb 2 at 22:27






  • 2




    $begingroup$
    "Does the number 34,969 have any particularly notable properties that would make it "The Count"'s favorite number?" Yes!
    $endgroup$
    – Count Iblis
    Feb 2 at 23:49








  • 5




    $begingroup$
    Why does this have so many upvotes??
    $endgroup$
    – YiFan
    Feb 3 at 5:03






  • 3




    $begingroup$
    @YiFan: This community seems to have a fondness for bat-related things.
    $endgroup$
    – Blue
    Feb 3 at 6:59
















  • 4




    $begingroup$
    Well, $34969 = 187^2$.
    $endgroup$
    – jvdhooft
    Feb 2 at 22:11






  • 7




    $begingroup$
    To go the other way $34969 = sqrt{1222830961}$. I think we just have to accept that this was just a dry joke. Given infinite numbers it's funny if one's favorite number is something arbitrary. And it's funnier if one gives a reason that, although not incorrect, reveals little.
    $endgroup$
    – fleablood
    Feb 2 at 22:27






  • 2




    $begingroup$
    "Does the number 34,969 have any particularly notable properties that would make it "The Count"'s favorite number?" Yes!
    $endgroup$
    – Count Iblis
    Feb 2 at 23:49








  • 5




    $begingroup$
    Why does this have so many upvotes??
    $endgroup$
    – YiFan
    Feb 3 at 5:03






  • 3




    $begingroup$
    @YiFan: This community seems to have a fondness for bat-related things.
    $endgroup$
    – Blue
    Feb 3 at 6:59










4




4




$begingroup$
Well, $34969 = 187^2$.
$endgroup$
– jvdhooft
Feb 2 at 22:11




$begingroup$
Well, $34969 = 187^2$.
$endgroup$
– jvdhooft
Feb 2 at 22:11




7




7




$begingroup$
To go the other way $34969 = sqrt{1222830961}$. I think we just have to accept that this was just a dry joke. Given infinite numbers it's funny if one's favorite number is something arbitrary. And it's funnier if one gives a reason that, although not incorrect, reveals little.
$endgroup$
– fleablood
Feb 2 at 22:27




$begingroup$
To go the other way $34969 = sqrt{1222830961}$. I think we just have to accept that this was just a dry joke. Given infinite numbers it's funny if one's favorite number is something arbitrary. And it's funnier if one gives a reason that, although not incorrect, reveals little.
$endgroup$
– fleablood
Feb 2 at 22:27




2




2




$begingroup$
"Does the number 34,969 have any particularly notable properties that would make it "The Count"'s favorite number?" Yes!
$endgroup$
– Count Iblis
Feb 2 at 23:49






$begingroup$
"Does the number 34,969 have any particularly notable properties that would make it "The Count"'s favorite number?" Yes!
$endgroup$
– Count Iblis
Feb 2 at 23:49






5




5




$begingroup$
Why does this have so many upvotes??
$endgroup$
– YiFan
Feb 3 at 5:03




$begingroup$
Why does this have so many upvotes??
$endgroup$
– YiFan
Feb 3 at 5:03




3




3




$begingroup$
@YiFan: This community seems to have a fondness for bat-related things.
$endgroup$
– Blue
Feb 3 at 6:59






$begingroup$
@YiFan: This community seems to have a fondness for bat-related things.
$endgroup$
– Blue
Feb 3 at 6:59












3 Answers
3






active

oldest

votes


















15












$begingroup$

There are some speculations in the following article:



https://www.bbc.com/news/magazine-19409960



The following is taken verbatim from the link:




34,969 is 187 squared. But why 187?



More or Less turned to its listeners for help.



Toby Lewis noted that 187 is the total number of points on the tiles
of a Scrabble game, speculating that the Count might have counted
them.



David Lees noticed that 187 is the product of two primes - 11 and 17 -
which makes 34,969 a very fine number indeed, being 11 squared times
17 squared. What, he asked, could be lovelier?



And Simon Philips calculated that 187 is 94 squared minus 93 squared -
and of course 187 is also 94 plus 93 (although that would be true of
any two consecutive numbers, as reader Lynn Wragg pointed out). An
embarrassment of riches!



But both he and Toby Lewis hinted at darkness behind the Count's
carefree laughter and charming flashes of lightning: 187 is also the
American police code for murder.



Murder squared: was the Count trying to tell us something?







share|cite|improve this answer









$endgroup$









  • 5




    $begingroup$
    0d187 = 0d11 * 0x11. Is that interesting?
    $endgroup$
    – eggyal
    Feb 3 at 1:11










  • $begingroup$
    The difference of squares observation is interesting given that the prime factorization indicates $187 = 11 cdot 17 = (14-3)(14+3) = 14^2 - 3^2$.
    $endgroup$
    – Benjamin Dickman
    Feb 3 at 17:11










  • $begingroup$
    It's very hard to choose an answer to accept, but in this particular case I'm going to go with the quoted source. Thanks everyone!
    $endgroup$
    – uhoh
    Feb 4 at 9:00



















7












$begingroup$

Curiously,
$$sqrt{1234567890}=35136.418ldots$$
which is kinda-sorta close to $34969$, although it doesn't seem close enough to make the joke work.



Perhaps it's that $34969=187^2$ is the largest perfect square whose own square doesn't exceed $1234567890$ (since $sqrt[4]{1234567890} = 187.447ldots$).





Considering how the Count counts, one might think his favorite number relates to
$$12345678910$$
It's perhaps worth noting that
$$begin{align}
sqrt{12345678910} &;=; 111,111.11ldots \
sqrt[4]{12345678910} &;=; phantom{111,}333.33333ldots
end{align}$$

where I have conveniently truncated the digits for best effect.





Unrelatedly: I've always been a little disappointed that the Count's full name is "Count von Count" instead of, say, "Count von Tuthrifore".






share|cite|improve this answer











$endgroup$









  • 3




    $begingroup$
    That definitely ought to be his name!
    $endgroup$
    – timtfj
    Feb 3 at 2:21






  • 2




    $begingroup$
    @timtfj: And then his daughter Zira could grow up to be a combinatorist and/or a programmer. :)
    $endgroup$
    – Blue
    Feb 3 at 3:02





















4












$begingroup$

Presumably if it's a square root thing, we're allowed to consider its square root, which, as other answers have noted, is $187$.



According to David Wells, The Penguin Dictionary of Curious and Interesting Numbers, (Penguin, 1986), $187$ is




The smallest of a group of $3$-digit numbers that require $23$ reversals to form a palindrome.




This is then followed by the entry for $196$, which includes an explanation of palindromes by reversal. The procedure is to reverse a number's digits and add the resulting number to the original.




Do all numbers become palindromes eventually? The answer to this problem is not known. $196$ is the only number less than $10,000$ that by this process has not yet produced a palindrome. P. C. Leyland has performed $50,000$ reversals, producing a number of more than $26,000$ digits with no palindrome appearing, and P. Anderton has taken this up to $70,928$ digits, also without success.




Most of the $3$-digit numbers require only a few reversals. The ones needing $23$ are



$${187, 286, 385, 583, 682, 781, 880},$$



all of which go via $968$ then $1837$, and end up at $8813200023188$.



So my guess is that the Count is able to take the square root of $34969$ in his head then do the $23$ reversals and get the palindrome, but hasn't yet managed to do the same with $38416=196^2$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    $968$ presumably only needs $22$ because it is the result of most of the others.
    $endgroup$
    – Ross Millikan
    Feb 3 at 1:57










  • $begingroup$
    @RossMillikan That must be right. I'll reword it a bit.
    $endgroup$
    – timtfj
    Feb 3 at 2:01










  • $begingroup$
    @RossMillikan And it must apply to $869$ as well.
    $endgroup$
    – timtfj
    Feb 3 at 2:04


















3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









15












$begingroup$

There are some speculations in the following article:



https://www.bbc.com/news/magazine-19409960



The following is taken verbatim from the link:




34,969 is 187 squared. But why 187?



More or Less turned to its listeners for help.



Toby Lewis noted that 187 is the total number of points on the tiles
of a Scrabble game, speculating that the Count might have counted
them.



David Lees noticed that 187 is the product of two primes - 11 and 17 -
which makes 34,969 a very fine number indeed, being 11 squared times
17 squared. What, he asked, could be lovelier?



And Simon Philips calculated that 187 is 94 squared minus 93 squared -
and of course 187 is also 94 plus 93 (although that would be true of
any two consecutive numbers, as reader Lynn Wragg pointed out). An
embarrassment of riches!



But both he and Toby Lewis hinted at darkness behind the Count's
carefree laughter and charming flashes of lightning: 187 is also the
American police code for murder.



Murder squared: was the Count trying to tell us something?







share|cite|improve this answer









$endgroup$









  • 5




    $begingroup$
    0d187 = 0d11 * 0x11. Is that interesting?
    $endgroup$
    – eggyal
    Feb 3 at 1:11










  • $begingroup$
    The difference of squares observation is interesting given that the prime factorization indicates $187 = 11 cdot 17 = (14-3)(14+3) = 14^2 - 3^2$.
    $endgroup$
    – Benjamin Dickman
    Feb 3 at 17:11










  • $begingroup$
    It's very hard to choose an answer to accept, but in this particular case I'm going to go with the quoted source. Thanks everyone!
    $endgroup$
    – uhoh
    Feb 4 at 9:00
















15












$begingroup$

There are some speculations in the following article:



https://www.bbc.com/news/magazine-19409960



The following is taken verbatim from the link:




34,969 is 187 squared. But why 187?



More or Less turned to its listeners for help.



Toby Lewis noted that 187 is the total number of points on the tiles
of a Scrabble game, speculating that the Count might have counted
them.



David Lees noticed that 187 is the product of two primes - 11 and 17 -
which makes 34,969 a very fine number indeed, being 11 squared times
17 squared. What, he asked, could be lovelier?



And Simon Philips calculated that 187 is 94 squared minus 93 squared -
and of course 187 is also 94 plus 93 (although that would be true of
any two consecutive numbers, as reader Lynn Wragg pointed out). An
embarrassment of riches!



But both he and Toby Lewis hinted at darkness behind the Count's
carefree laughter and charming flashes of lightning: 187 is also the
American police code for murder.



Murder squared: was the Count trying to tell us something?







share|cite|improve this answer









$endgroup$









  • 5




    $begingroup$
    0d187 = 0d11 * 0x11. Is that interesting?
    $endgroup$
    – eggyal
    Feb 3 at 1:11










  • $begingroup$
    The difference of squares observation is interesting given that the prime factorization indicates $187 = 11 cdot 17 = (14-3)(14+3) = 14^2 - 3^2$.
    $endgroup$
    – Benjamin Dickman
    Feb 3 at 17:11










  • $begingroup$
    It's very hard to choose an answer to accept, but in this particular case I'm going to go with the quoted source. Thanks everyone!
    $endgroup$
    – uhoh
    Feb 4 at 9:00














15












15








15





$begingroup$

There are some speculations in the following article:



https://www.bbc.com/news/magazine-19409960



The following is taken verbatim from the link:




34,969 is 187 squared. But why 187?



More or Less turned to its listeners for help.



Toby Lewis noted that 187 is the total number of points on the tiles
of a Scrabble game, speculating that the Count might have counted
them.



David Lees noticed that 187 is the product of two primes - 11 and 17 -
which makes 34,969 a very fine number indeed, being 11 squared times
17 squared. What, he asked, could be lovelier?



And Simon Philips calculated that 187 is 94 squared minus 93 squared -
and of course 187 is also 94 plus 93 (although that would be true of
any two consecutive numbers, as reader Lynn Wragg pointed out). An
embarrassment of riches!



But both he and Toby Lewis hinted at darkness behind the Count's
carefree laughter and charming flashes of lightning: 187 is also the
American police code for murder.



Murder squared: was the Count trying to tell us something?







share|cite|improve this answer









$endgroup$



There are some speculations in the following article:



https://www.bbc.com/news/magazine-19409960



The following is taken verbatim from the link:




34,969 is 187 squared. But why 187?



More or Less turned to its listeners for help.



Toby Lewis noted that 187 is the total number of points on the tiles
of a Scrabble game, speculating that the Count might have counted
them.



David Lees noticed that 187 is the product of two primes - 11 and 17 -
which makes 34,969 a very fine number indeed, being 11 squared times
17 squared. What, he asked, could be lovelier?



And Simon Philips calculated that 187 is 94 squared minus 93 squared -
and of course 187 is also 94 plus 93 (although that would be true of
any two consecutive numbers, as reader Lynn Wragg pointed out). An
embarrassment of riches!



But both he and Toby Lewis hinted at darkness behind the Count's
carefree laughter and charming flashes of lightning: 187 is also the
American police code for murder.



Murder squared: was the Count trying to tell us something?








share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Feb 2 at 22:25









PrismPrism

5,05731981




5,05731981








  • 5




    $begingroup$
    0d187 = 0d11 * 0x11. Is that interesting?
    $endgroup$
    – eggyal
    Feb 3 at 1:11










  • $begingroup$
    The difference of squares observation is interesting given that the prime factorization indicates $187 = 11 cdot 17 = (14-3)(14+3) = 14^2 - 3^2$.
    $endgroup$
    – Benjamin Dickman
    Feb 3 at 17:11










  • $begingroup$
    It's very hard to choose an answer to accept, but in this particular case I'm going to go with the quoted source. Thanks everyone!
    $endgroup$
    – uhoh
    Feb 4 at 9:00














  • 5




    $begingroup$
    0d187 = 0d11 * 0x11. Is that interesting?
    $endgroup$
    – eggyal
    Feb 3 at 1:11










  • $begingroup$
    The difference of squares observation is interesting given that the prime factorization indicates $187 = 11 cdot 17 = (14-3)(14+3) = 14^2 - 3^2$.
    $endgroup$
    – Benjamin Dickman
    Feb 3 at 17:11










  • $begingroup$
    It's very hard to choose an answer to accept, but in this particular case I'm going to go with the quoted source. Thanks everyone!
    $endgroup$
    – uhoh
    Feb 4 at 9:00








5




5




$begingroup$
0d187 = 0d11 * 0x11. Is that interesting?
$endgroup$
– eggyal
Feb 3 at 1:11




$begingroup$
0d187 = 0d11 * 0x11. Is that interesting?
$endgroup$
– eggyal
Feb 3 at 1:11












$begingroup$
The difference of squares observation is interesting given that the prime factorization indicates $187 = 11 cdot 17 = (14-3)(14+3) = 14^2 - 3^2$.
$endgroup$
– Benjamin Dickman
Feb 3 at 17:11




$begingroup$
The difference of squares observation is interesting given that the prime factorization indicates $187 = 11 cdot 17 = (14-3)(14+3) = 14^2 - 3^2$.
$endgroup$
– Benjamin Dickman
Feb 3 at 17:11












$begingroup$
It's very hard to choose an answer to accept, but in this particular case I'm going to go with the quoted source. Thanks everyone!
$endgroup$
– uhoh
Feb 4 at 9:00




$begingroup$
It's very hard to choose an answer to accept, but in this particular case I'm going to go with the quoted source. Thanks everyone!
$endgroup$
– uhoh
Feb 4 at 9:00











7












$begingroup$

Curiously,
$$sqrt{1234567890}=35136.418ldots$$
which is kinda-sorta close to $34969$, although it doesn't seem close enough to make the joke work.



Perhaps it's that $34969=187^2$ is the largest perfect square whose own square doesn't exceed $1234567890$ (since $sqrt[4]{1234567890} = 187.447ldots$).





Considering how the Count counts, one might think his favorite number relates to
$$12345678910$$
It's perhaps worth noting that
$$begin{align}
sqrt{12345678910} &;=; 111,111.11ldots \
sqrt[4]{12345678910} &;=; phantom{111,}333.33333ldots
end{align}$$

where I have conveniently truncated the digits for best effect.





Unrelatedly: I've always been a little disappointed that the Count's full name is "Count von Count" instead of, say, "Count von Tuthrifore".






share|cite|improve this answer











$endgroup$









  • 3




    $begingroup$
    That definitely ought to be his name!
    $endgroup$
    – timtfj
    Feb 3 at 2:21






  • 2




    $begingroup$
    @timtfj: And then his daughter Zira could grow up to be a combinatorist and/or a programmer. :)
    $endgroup$
    – Blue
    Feb 3 at 3:02


















7












$begingroup$

Curiously,
$$sqrt{1234567890}=35136.418ldots$$
which is kinda-sorta close to $34969$, although it doesn't seem close enough to make the joke work.



Perhaps it's that $34969=187^2$ is the largest perfect square whose own square doesn't exceed $1234567890$ (since $sqrt[4]{1234567890} = 187.447ldots$).





Considering how the Count counts, one might think his favorite number relates to
$$12345678910$$
It's perhaps worth noting that
$$begin{align}
sqrt{12345678910} &;=; 111,111.11ldots \
sqrt[4]{12345678910} &;=; phantom{111,}333.33333ldots
end{align}$$

where I have conveniently truncated the digits for best effect.





Unrelatedly: I've always been a little disappointed that the Count's full name is "Count von Count" instead of, say, "Count von Tuthrifore".






share|cite|improve this answer











$endgroup$









  • 3




    $begingroup$
    That definitely ought to be his name!
    $endgroup$
    – timtfj
    Feb 3 at 2:21






  • 2




    $begingroup$
    @timtfj: And then his daughter Zira could grow up to be a combinatorist and/or a programmer. :)
    $endgroup$
    – Blue
    Feb 3 at 3:02
















7












7








7





$begingroup$

Curiously,
$$sqrt{1234567890}=35136.418ldots$$
which is kinda-sorta close to $34969$, although it doesn't seem close enough to make the joke work.



Perhaps it's that $34969=187^2$ is the largest perfect square whose own square doesn't exceed $1234567890$ (since $sqrt[4]{1234567890} = 187.447ldots$).





Considering how the Count counts, one might think his favorite number relates to
$$12345678910$$
It's perhaps worth noting that
$$begin{align}
sqrt{12345678910} &;=; 111,111.11ldots \
sqrt[4]{12345678910} &;=; phantom{111,}333.33333ldots
end{align}$$

where I have conveniently truncated the digits for best effect.





Unrelatedly: I've always been a little disappointed that the Count's full name is "Count von Count" instead of, say, "Count von Tuthrifore".






share|cite|improve this answer











$endgroup$



Curiously,
$$sqrt{1234567890}=35136.418ldots$$
which is kinda-sorta close to $34969$, although it doesn't seem close enough to make the joke work.



Perhaps it's that $34969=187^2$ is the largest perfect square whose own square doesn't exceed $1234567890$ (since $sqrt[4]{1234567890} = 187.447ldots$).





Considering how the Count counts, one might think his favorite number relates to
$$12345678910$$
It's perhaps worth noting that
$$begin{align}
sqrt{12345678910} &;=; 111,111.11ldots \
sqrt[4]{12345678910} &;=; phantom{111,}333.33333ldots
end{align}$$

where I have conveniently truncated the digits for best effect.





Unrelatedly: I've always been a little disappointed that the Count's full name is "Count von Count" instead of, say, "Count von Tuthrifore".







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Feb 2 at 23:17

























answered Feb 2 at 23:06









BlueBlue

48.6k870156




48.6k870156








  • 3




    $begingroup$
    That definitely ought to be his name!
    $endgroup$
    – timtfj
    Feb 3 at 2:21






  • 2




    $begingroup$
    @timtfj: And then his daughter Zira could grow up to be a combinatorist and/or a programmer. :)
    $endgroup$
    – Blue
    Feb 3 at 3:02
















  • 3




    $begingroup$
    That definitely ought to be his name!
    $endgroup$
    – timtfj
    Feb 3 at 2:21






  • 2




    $begingroup$
    @timtfj: And then his daughter Zira could grow up to be a combinatorist and/or a programmer. :)
    $endgroup$
    – Blue
    Feb 3 at 3:02










3




3




$begingroup$
That definitely ought to be his name!
$endgroup$
– timtfj
Feb 3 at 2:21




$begingroup$
That definitely ought to be his name!
$endgroup$
– timtfj
Feb 3 at 2:21




2




2




$begingroup$
@timtfj: And then his daughter Zira could grow up to be a combinatorist and/or a programmer. :)
$endgroup$
– Blue
Feb 3 at 3:02






$begingroup$
@timtfj: And then his daughter Zira could grow up to be a combinatorist and/or a programmer. :)
$endgroup$
– Blue
Feb 3 at 3:02













4












$begingroup$

Presumably if it's a square root thing, we're allowed to consider its square root, which, as other answers have noted, is $187$.



According to David Wells, The Penguin Dictionary of Curious and Interesting Numbers, (Penguin, 1986), $187$ is




The smallest of a group of $3$-digit numbers that require $23$ reversals to form a palindrome.




This is then followed by the entry for $196$, which includes an explanation of palindromes by reversal. The procedure is to reverse a number's digits and add the resulting number to the original.




Do all numbers become palindromes eventually? The answer to this problem is not known. $196$ is the only number less than $10,000$ that by this process has not yet produced a palindrome. P. C. Leyland has performed $50,000$ reversals, producing a number of more than $26,000$ digits with no palindrome appearing, and P. Anderton has taken this up to $70,928$ digits, also without success.




Most of the $3$-digit numbers require only a few reversals. The ones needing $23$ are



$${187, 286, 385, 583, 682, 781, 880},$$



all of which go via $968$ then $1837$, and end up at $8813200023188$.



So my guess is that the Count is able to take the square root of $34969$ in his head then do the $23$ reversals and get the palindrome, but hasn't yet managed to do the same with $38416=196^2$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    $968$ presumably only needs $22$ because it is the result of most of the others.
    $endgroup$
    – Ross Millikan
    Feb 3 at 1:57










  • $begingroup$
    @RossMillikan That must be right. I'll reword it a bit.
    $endgroup$
    – timtfj
    Feb 3 at 2:01










  • $begingroup$
    @RossMillikan And it must apply to $869$ as well.
    $endgroup$
    – timtfj
    Feb 3 at 2:04
















4












$begingroup$

Presumably if it's a square root thing, we're allowed to consider its square root, which, as other answers have noted, is $187$.



According to David Wells, The Penguin Dictionary of Curious and Interesting Numbers, (Penguin, 1986), $187$ is




The smallest of a group of $3$-digit numbers that require $23$ reversals to form a palindrome.




This is then followed by the entry for $196$, which includes an explanation of palindromes by reversal. The procedure is to reverse a number's digits and add the resulting number to the original.




Do all numbers become palindromes eventually? The answer to this problem is not known. $196$ is the only number less than $10,000$ that by this process has not yet produced a palindrome. P. C. Leyland has performed $50,000$ reversals, producing a number of more than $26,000$ digits with no palindrome appearing, and P. Anderton has taken this up to $70,928$ digits, also without success.




Most of the $3$-digit numbers require only a few reversals. The ones needing $23$ are



$${187, 286, 385, 583, 682, 781, 880},$$



all of which go via $968$ then $1837$, and end up at $8813200023188$.



So my guess is that the Count is able to take the square root of $34969$ in his head then do the $23$ reversals and get the palindrome, but hasn't yet managed to do the same with $38416=196^2$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    $968$ presumably only needs $22$ because it is the result of most of the others.
    $endgroup$
    – Ross Millikan
    Feb 3 at 1:57










  • $begingroup$
    @RossMillikan That must be right. I'll reword it a bit.
    $endgroup$
    – timtfj
    Feb 3 at 2:01










  • $begingroup$
    @RossMillikan And it must apply to $869$ as well.
    $endgroup$
    – timtfj
    Feb 3 at 2:04














4












4








4





$begingroup$

Presumably if it's a square root thing, we're allowed to consider its square root, which, as other answers have noted, is $187$.



According to David Wells, The Penguin Dictionary of Curious and Interesting Numbers, (Penguin, 1986), $187$ is




The smallest of a group of $3$-digit numbers that require $23$ reversals to form a palindrome.




This is then followed by the entry for $196$, which includes an explanation of palindromes by reversal. The procedure is to reverse a number's digits and add the resulting number to the original.




Do all numbers become palindromes eventually? The answer to this problem is not known. $196$ is the only number less than $10,000$ that by this process has not yet produced a palindrome. P. C. Leyland has performed $50,000$ reversals, producing a number of more than $26,000$ digits with no palindrome appearing, and P. Anderton has taken this up to $70,928$ digits, also without success.




Most of the $3$-digit numbers require only a few reversals. The ones needing $23$ are



$${187, 286, 385, 583, 682, 781, 880},$$



all of which go via $968$ then $1837$, and end up at $8813200023188$.



So my guess is that the Count is able to take the square root of $34969$ in his head then do the $23$ reversals and get the palindrome, but hasn't yet managed to do the same with $38416=196^2$.






share|cite|improve this answer











$endgroup$



Presumably if it's a square root thing, we're allowed to consider its square root, which, as other answers have noted, is $187$.



According to David Wells, The Penguin Dictionary of Curious and Interesting Numbers, (Penguin, 1986), $187$ is




The smallest of a group of $3$-digit numbers that require $23$ reversals to form a palindrome.




This is then followed by the entry for $196$, which includes an explanation of palindromes by reversal. The procedure is to reverse a number's digits and add the resulting number to the original.




Do all numbers become palindromes eventually? The answer to this problem is not known. $196$ is the only number less than $10,000$ that by this process has not yet produced a palindrome. P. C. Leyland has performed $50,000$ reversals, producing a number of more than $26,000$ digits with no palindrome appearing, and P. Anderton has taken this up to $70,928$ digits, also without success.




Most of the $3$-digit numbers require only a few reversals. The ones needing $23$ are



$${187, 286, 385, 583, 682, 781, 880},$$



all of which go via $968$ then $1837$, and end up at $8813200023188$.



So my guess is that the Count is able to take the square root of $34969$ in his head then do the $23$ reversals and get the palindrome, but hasn't yet managed to do the same with $38416=196^2$.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Feb 3 at 2:16

























answered Feb 3 at 1:38









timtfjtimtfj

2,458420




2,458420












  • $begingroup$
    $968$ presumably only needs $22$ because it is the result of most of the others.
    $endgroup$
    – Ross Millikan
    Feb 3 at 1:57










  • $begingroup$
    @RossMillikan That must be right. I'll reword it a bit.
    $endgroup$
    – timtfj
    Feb 3 at 2:01










  • $begingroup$
    @RossMillikan And it must apply to $869$ as well.
    $endgroup$
    – timtfj
    Feb 3 at 2:04


















  • $begingroup$
    $968$ presumably only needs $22$ because it is the result of most of the others.
    $endgroup$
    – Ross Millikan
    Feb 3 at 1:57










  • $begingroup$
    @RossMillikan That must be right. I'll reword it a bit.
    $endgroup$
    – timtfj
    Feb 3 at 2:01










  • $begingroup$
    @RossMillikan And it must apply to $869$ as well.
    $endgroup$
    – timtfj
    Feb 3 at 2:04
















$begingroup$
$968$ presumably only needs $22$ because it is the result of most of the others.
$endgroup$
– Ross Millikan
Feb 3 at 1:57




$begingroup$
$968$ presumably only needs $22$ because it is the result of most of the others.
$endgroup$
– Ross Millikan
Feb 3 at 1:57












$begingroup$
@RossMillikan That must be right. I'll reword it a bit.
$endgroup$
– timtfj
Feb 3 at 2:01




$begingroup$
@RossMillikan That must be right. I'll reword it a bit.
$endgroup$
– timtfj
Feb 3 at 2:01












$begingroup$
@RossMillikan And it must apply to $869$ as well.
$endgroup$
– timtfj
Feb 3 at 2:04




$begingroup$
@RossMillikan And it must apply to $869$ as well.
$endgroup$
– timtfj
Feb 3 at 2:04



Popular posts from this blog

Probability when a professor distributes a quiz and homework assignment to a class of n students.

Aardman Animations

Are they similar matrix