Where does the Xmon simulator from Googles cirq framework its entropy from?
$begingroup$
Measurements create entropy as we all know. But computers themselves are deterministic machines. Most devices use processor heat as a source for random number generation as far as I know - which has lead to problems in the past. Any cryptographic key is only as good as the entropy source from which its content originate. When I try to collect binary entropy as results from a quantum measurement it is still a simulation - yet for huge numbers it converges well to the distribution I should obtain. So how does the simulator collect the entropy for the measurement outcomes?
measurement simulation cirq entropy nisq
edited Feb 2 at 21:18
Blue♦
6,26041355
asked Feb 2 at 20:58
sycramoresycramore
442
$endgroup$
add a comment |
$begingroup$
Measurements create entropy as we all know. But computers themselves are deterministic machines. Most devices use processor heat as a source for random number generation as far as I know - which has lead to problems in the past. Any cryptographic key is only as good as the entropy source from which its content originate. When I try to collect binary entropy as results from a quantum measurement it is still a simulation - yet for huge numbers it converges well to the distribution I should obtain. So how does the simulator collect the entropy for the measurement outcomes?
measurement simulation cirq entropy nisq
edited Feb 2 at 21:18
Blue♦
6,26041355
asked Feb 2 at 20:58
sycramoresycramore
442
$endgroup$
add a comment |
$begingroup$
Measurements create entropy as we all know. But computers themselves are deterministic machines. Most devices use processor heat as a source for random number generation as far as I know - which has lead to problems in the past. Any cryptographic key is only as good as the entropy source from which its content originate. When I try to collect binary entropy as results from a quantum measurement it is still a simulation - yet for huge numbers it converges well to the distribution I should obtain. So how does the simulator collect the entropy for the measurement outcomes?
measurement simulation cirq entropy nisq
edited Feb 2 at 21:18
Blue♦
6,26041355
asked Feb 2 at 20:58
sycramoresycramore
442
$endgroup$
Measurements create entropy as we all know. But computers themselves are deterministic machines. Most devices use processor heat as a source for random number generation as far as I know - which has lead to problems in the past. Any cryptographic key is only as good as the entropy source from which its content originate. When I try to collect binary entropy as results from a quantum measurement it is still a simulation - yet for huge numbers it converges well to the distribution I should obtain. So how does the simulator collect the entropy for the measurement outcomes?
measurement simulation cirq entropy nisq
measurement simulation cirq entropy nisq
edited Feb 2 at 21:18
Blue♦
6,26041355
asked Feb 2 at 20:58
sycramoresycramore
442
edited Feb 2 at 21:18
Blue♦
6,26041355
asked Feb 2 at 20:58
sycramoresycramore
442
edited Feb 2 at 21:18
Blue♦
6,26041355
edited Feb 2 at 21:18
Blue♦
6,26041355
edited Feb 2 at 21:18
Blue♦
6,26041355
6,26041355
asked Feb 2 at 20:58
sycramoresycramore
442
asked Feb 2 at 20:58
sycramoresycramore
442
asked Feb 2 at 20:58
sycramoresycramore
442
442
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Cirq uses numpy's pseudo random number generator to pick measurement results, e.g. here is code from XmonStepper.simulate_measurement:
def simulate_measurement(self, index: int) -> bool:
[...]
prob_one = np.sum(self._pool.map(_one_prob_per_shard, args))
result = bool(np.random.random() <= prob_one)
[...]
Cirq simulations are not intended to be a source of cryptographically secure entropy.
answered Feb 2 at 21:46
Craig GidneyCraig Gidney
4,471220
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "694"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fquantumcomputing.stackexchange.com%2fquestions%2f5356%2fwhere-does-the-xmon-simulator-from-googles-cirq-framework-its-entropy-from%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Cirq uses numpy's pseudo random number generator to pick measurement results, e.g. here is code from XmonStepper.simulate_measurement:
def simulate_measurement(self, index: int) -> bool:
[...]
prob_one = np.sum(self._pool.map(_one_prob_per_shard, args))
result = bool(np.random.random() <= prob_one)
[...]
Cirq simulations are not intended to be a source of cryptographically secure entropy.
answered Feb 2 at 21:46
Craig GidneyCraig Gidney
4,471220
$endgroup$
add a comment |
$begingroup$
Cirq uses numpy's pseudo random number generator to pick measurement results, e.g. here is code from XmonStepper.simulate_measurement:
def simulate_measurement(self, index: int) -> bool:
[...]
prob_one = np.sum(self._pool.map(_one_prob_per_shard, args))
result = bool(np.random.random() <= prob_one)
[...]
Cirq simulations are not intended to be a source of cryptographically secure entropy.
answered Feb 2 at 21:46
Craig GidneyCraig Gidney
4,471220
$endgroup$
add a comment |
$begingroup$
Cirq uses numpy's pseudo random number generator to pick measurement results, e.g. here is code from XmonStepper.simulate_measurement:
def simulate_measurement(self, index: int) -> bool:
[...]
prob_one = np.sum(self._pool.map(_one_prob_per_shard, args))
result = bool(np.random.random() <= prob_one)
[...]
Cirq simulations are not intended to be a source of cryptographically secure entropy.
answered Feb 2 at 21:46
Craig GidneyCraig Gidney
4,471220
$endgroup$
Cirq uses numpy's pseudo random number generator to pick measurement results, e.g. here is code from XmonStepper.simulate_measurement:
def simulate_measurement(self, index: int) -> bool:
[...]
prob_one = np.sum(self._pool.map(_one_prob_per_shard, args))
result = bool(np.random.random() <= prob_one)
[...]
Cirq simulations are not intended to be a source of cryptographically secure entropy.
answered Feb 2 at 21:46
Craig GidneyCraig Gidney
4,471220
answered Feb 2 at 21:46
Craig GidneyCraig Gidney
4,471220
answered Feb 2 at 21:46
Craig GidneyCraig Gidney
4,471220
answered Feb 2 at 21:46
Craig GidneyCraig Gidney
4,471220
4,471220
add a comment |
add a comment |
Thanks for contributing an answer to Quantum Computing Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fquantumcomputing.stackexchange.com%2fquestions%2f5356%2fwhere-does-the-xmon-simulator-from-googles-cirq-framework-its-entropy-from%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
