Algebralization of a puzzle












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I tried to put this algerba through algebra and couldn't:



Each of 20 students in a group have solved three problems from the homework assignment, and each problem was solved by two students. How many problems were in the assignment?










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$endgroup$

















    0












    $begingroup$


    I tried to put this algerba through algebra and couldn't:



    Each of 20 students in a group have solved three problems from the homework assignment, and each problem was solved by two students. How many problems were in the assignment?










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      I tried to put this algerba through algebra and couldn't:



      Each of 20 students in a group have solved three problems from the homework assignment, and each problem was solved by two students. How many problems were in the assignment?










      share|cite|improve this question











      $endgroup$




      I tried to put this algerba through algebra and couldn't:



      Each of 20 students in a group have solved three problems from the homework assignment, and each problem was solved by two students. How many problems were in the assignment?







      discrete-mathematics






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      share|cite|improve this question













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      edited Jan 19 at 17:01









      greedoid

      39.5k114797




      39.5k114797










      asked Dec 5 '18 at 20:49









      J.MohJ.Moh

      395




      395






















          1 Answer
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          $begingroup$

          First compute, how many tasks where performed by all students together. As each students solved three (different) problems, we have a total of
          $$20 * 3 = 60$$
          performed tasks. Now every problem was solved by exactly two students. So there were at all
          $$ frac{60}{2} = 30$$
          problems.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thanks, do you study at Mittweida?
            $endgroup$
            – J.Moh
            Dec 5 '18 at 20:56











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          1 Answer
          1






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          oldest

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          active

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          2












          $begingroup$

          First compute, how many tasks where performed by all students together. As each students solved three (different) problems, we have a total of
          $$20 * 3 = 60$$
          performed tasks. Now every problem was solved by exactly two students. So there were at all
          $$ frac{60}{2} = 30$$
          problems.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thanks, do you study at Mittweida?
            $endgroup$
            – J.Moh
            Dec 5 '18 at 20:56
















          2












          $begingroup$

          First compute, how many tasks where performed by all students together. As each students solved three (different) problems, we have a total of
          $$20 * 3 = 60$$
          performed tasks. Now every problem was solved by exactly two students. So there were at all
          $$ frac{60}{2} = 30$$
          problems.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thanks, do you study at Mittweida?
            $endgroup$
            – J.Moh
            Dec 5 '18 at 20:56














          2












          2








          2





          $begingroup$

          First compute, how many tasks where performed by all students together. As each students solved three (different) problems, we have a total of
          $$20 * 3 = 60$$
          performed tasks. Now every problem was solved by exactly two students. So there were at all
          $$ frac{60}{2} = 30$$
          problems.






          share|cite|improve this answer









          $endgroup$



          First compute, how many tasks where performed by all students together. As each students solved three (different) problems, we have a total of
          $$20 * 3 = 60$$
          performed tasks. Now every problem was solved by exactly two students. So there were at all
          $$ frac{60}{2} = 30$$
          problems.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 5 '18 at 20:52









          red_trumpetred_trumpet

          843219




          843219












          • $begingroup$
            Thanks, do you study at Mittweida?
            $endgroup$
            – J.Moh
            Dec 5 '18 at 20:56


















          • $begingroup$
            Thanks, do you study at Mittweida?
            $endgroup$
            – J.Moh
            Dec 5 '18 at 20:56
















          $begingroup$
          Thanks, do you study at Mittweida?
          $endgroup$
          – J.Moh
          Dec 5 '18 at 20:56




          $begingroup$
          Thanks, do you study at Mittweida?
          $endgroup$
          – J.Moh
          Dec 5 '18 at 20:56


















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