What is the angle between the direction of $A$ and the positive direction of x?
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The x component of vector $A$ is 25.0 m and the y component is 40.0 m. (a) What is the magnitude of $A$? (b) What is the angle between the direction of $A$ and the positive direction of x?
I solved (a). When attempting (b) I tried using the formula $tantheta=frac{a_y}{a_x}=frac{40}{-25}=-1.6$, thus $arctan(-1.6)=-58º$ but the answer key is $122º$.
Any help is appreciated.
vectors
asked Sep 27 at 20:15
Mauricio Mendes
1018
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The x component of vector $A$ is 25.0 m and the y component is 40.0 m. (a) What is the magnitude of $A$? (b) What is the angle between the direction of $A$ and the positive direction of x?
I solved (a). When attempting (b) I tried using the formula $tantheta=frac{a_y}{a_x}=frac{40}{-25}=-1.6$, thus $arctan(-1.6)=-58º$ but the answer key is $122º$.
Any help is appreciated.
vectors
asked Sep 27 at 20:15
Mauricio Mendes
1018
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
The x component of vector $A$ is 25.0 m and the y component is 40.0 m. (a) What is the magnitude of $A$? (b) What is the angle between the direction of $A$ and the positive direction of x?
I solved (a). When attempting (b) I tried using the formula $tantheta=frac{a_y}{a_x}=frac{40}{-25}=-1.6$, thus $arctan(-1.6)=-58º$ but the answer key is $122º$.
Any help is appreciated.
vectors
asked Sep 27 at 20:15
Mauricio Mendes
1018
The x component of vector $A$ is 25.0 m and the y component is 40.0 m. (a) What is the magnitude of $A$? (b) What is the angle between the direction of $A$ and the positive direction of x?
I solved (a). When attempting (b) I tried using the formula $tantheta=frac{a_y}{a_x}=frac{40}{-25}=-1.6$, thus $arctan(-1.6)=-58º$ but the answer key is $122º$.
Any help is appreciated.
vectors
vectors
asked Sep 27 at 20:15
Mauricio Mendes
1018
asked Sep 27 at 20:15
Mauricio Mendes
1018
asked Sep 27 at 20:15
Mauricio Mendes
1018
asked Sep 27 at 20:15
Mauricio Mendes
1018
asked Sep 27 at 20:15
Mauricio Mendes
1018
1018
add a comment |
add a comment |
1 Answer
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It appears that you might mean for the point to be (-25,40) although you stated (25,40). The atan2(y,x) function using (-25,40) will yield ~122 deg.
answered Sep 27 at 21:40
Narlin
484310
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
It appears that you might mean for the point to be (-25,40) although you stated (25,40). The atan2(y,x) function using (-25,40) will yield ~122 deg.
answered Sep 27 at 21:40
Narlin
484310
add a comment |
up vote
0
down vote
It appears that you might mean for the point to be (-25,40) although you stated (25,40). The atan2(y,x) function using (-25,40) will yield ~122 deg.
answered Sep 27 at 21:40
Narlin
484310
add a comment |
up vote
0
down vote
up vote
0
down vote
It appears that you might mean for the point to be (-25,40) although you stated (25,40). The atan2(y,x) function using (-25,40) will yield ~122 deg.
answered Sep 27 at 21:40
Narlin
484310
It appears that you might mean for the point to be (-25,40) although you stated (25,40). The atan2(y,x) function using (-25,40) will yield ~122 deg.
answered Sep 27 at 21:40
Narlin
484310
answered Sep 27 at 21:40
Narlin
484310
answered Sep 27 at 21:40
Narlin
484310
answered Sep 27 at 21:40
Narlin
484310
484310
add a comment |
add a comment |
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