Find coordinates of intersection of vector and a square's edges
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Not big problem, but I can't find a formula for the following stuff.
I have this kind of things:
(I was not able to draw vector in my application so I represented the source by point and the end of the arrow by nothing, and the vector is the segment) ; also don't pay attention the red ones on this image)
So I'll have a lot of vectors composed of a source point (inside the square) and a destination point (inside or outside the square).
The square is delimited by the four black points in the corners.
I need a formula to get the coordinates of the intersection with the edge (if there is one).
For example I'd need the coordinates of the "points" on the following image:
Anybody has an idea on how to achieve that?
geometry
asked Nov 18 at 23:49
Axel Carré
112
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show 4 more comments
up vote
0
down vote
favorite
Not big problem, but I can't find a formula for the following stuff.
I have this kind of things:
(I was not able to draw vector in my application so I represented the source by point and the end of the arrow by nothing, and the vector is the segment) ; also don't pay attention the red ones on this image)
So I'll have a lot of vectors composed of a source point (inside the square) and a destination point (inside or outside the square).
The square is delimited by the four black points in the corners.
I need a formula to get the coordinates of the intersection with the edge (if there is one).
For example I'd need the coordinates of the "points" on the following image:
Anybody has an idea on how to achieve that?
geometry
asked Nov 18 at 23:49
Axel Carré
112
It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
Nov 19 at 1:05
Just edited my post.
– Axel Carré
Nov 19 at 7:46
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
Nov 19 at 8:34
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
Nov 19 at 9:47
And yes direction was irrelevant you were right.
– Axel Carré
Nov 19 at 9:48
|
show 4 more comments
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Not big problem, but I can't find a formula for the following stuff.
I have this kind of things:
(I was not able to draw vector in my application so I represented the source by point and the end of the arrow by nothing, and the vector is the segment) ; also don't pay attention the red ones on this image)
So I'll have a lot of vectors composed of a source point (inside the square) and a destination point (inside or outside the square).
The square is delimited by the four black points in the corners.
I need a formula to get the coordinates of the intersection with the edge (if there is one).
For example I'd need the coordinates of the "points" on the following image:
Anybody has an idea on how to achieve that?
geometry
asked Nov 18 at 23:49
Axel Carré
112
Not big problem, but I can't find a formula for the following stuff.
I have this kind of things:
(I was not able to draw vector in my application so I represented the source by point and the end of the arrow by nothing, and the vector is the segment) ; also don't pay attention the red ones on this image)
So I'll have a lot of vectors composed of a source point (inside the square) and a destination point (inside or outside the square).
The square is delimited by the four black points in the corners.
I need a formula to get the coordinates of the intersection with the edge (if there is one).
For example I'd need the coordinates of the "points" on the following image:
Anybody has an idea on how to achieve that?
geometry
geometry
asked Nov 18 at 23:49
Axel Carré
112
asked Nov 18 at 23:49
Axel Carré
112
edited Nov 19 at 7:41
asked Nov 18 at 23:49
Axel Carré
112
asked Nov 18 at 23:49
Axel Carré
112
asked Nov 18 at 23:49
Axel Carré
112
112
It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
Nov 19 at 1:05
Just edited my post.
– Axel Carré
Nov 19 at 7:46
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
Nov 19 at 8:34
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
Nov 19 at 9:47
And yes direction was irrelevant you were right.
– Axel Carré
Nov 19 at 9:48
|
show 4 more comments
It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
Nov 19 at 1:05
Just edited my post.
– Axel Carré
Nov 19 at 7:46
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
Nov 19 at 8:34
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
Nov 19 at 9:47
And yes direction was irrelevant you were right.
– Axel Carré
Nov 19 at 9:48
It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
Nov 19 at 1:05
It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
Nov 19 at 1:05
Just edited my post.
– Axel Carré
Nov 19 at 7:46
Just edited my post.
– Axel Carré
Nov 19 at 7:46
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
Nov 19 at 8:34
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
Nov 19 at 8:34
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
Nov 19 at 9:47
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
Nov 19 at 9:47
And yes direction was irrelevant you were right.
– Axel Carré
Nov 19 at 9:48
And yes direction was irrelevant you were right.
– Axel Carré
Nov 19 at 9:48
|
show 4 more comments
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It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
Nov 19 at 1:05
Just edited my post.
– Axel Carré
Nov 19 at 7:46
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
Nov 19 at 8:34
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
Nov 19 at 9:47
And yes direction was irrelevant you were right.
– Axel Carré
Nov 19 at 9:48