hypothesis testing, P-value calculation, standard deviation unknown












0












$begingroup$


i have following problem,



"The null hypothesis says that a sprinter's reaction time follows a normal distribution with mean at most 0.150 seconds. Six measurements of a sprinter's reaction time show 0.152, 0.154, 0.166, 0.147, 0.161, and 0.159 seconds. What is the p value?"



i have calculated first sample mean as 0.157
and standard deviation under t-student distribution as 0.00686
then applying $t=frac{bar{x}-mu}{s/sqrt{n}}$ i got 2.45



CDF of t(2.45) is around 0.973 which i believe is the p-value requested.



what wrong did i do?










share|cite|improve this question









$endgroup$












  • $begingroup$
    It's $p=1-0.973$.
    $endgroup$
    – Michael Hoppe
    Dec 10 '18 at 19:20










  • $begingroup$
    Yes p = 1 - cdf(t_score). thank you Michael.
    $endgroup$
    – Nour
    Dec 12 '18 at 2:59
















0












$begingroup$


i have following problem,



"The null hypothesis says that a sprinter's reaction time follows a normal distribution with mean at most 0.150 seconds. Six measurements of a sprinter's reaction time show 0.152, 0.154, 0.166, 0.147, 0.161, and 0.159 seconds. What is the p value?"



i have calculated first sample mean as 0.157
and standard deviation under t-student distribution as 0.00686
then applying $t=frac{bar{x}-mu}{s/sqrt{n}}$ i got 2.45



CDF of t(2.45) is around 0.973 which i believe is the p-value requested.



what wrong did i do?










share|cite|improve this question









$endgroup$












  • $begingroup$
    It's $p=1-0.973$.
    $endgroup$
    – Michael Hoppe
    Dec 10 '18 at 19:20










  • $begingroup$
    Yes p = 1 - cdf(t_score). thank you Michael.
    $endgroup$
    – Nour
    Dec 12 '18 at 2:59














0












0








0





$begingroup$


i have following problem,



"The null hypothesis says that a sprinter's reaction time follows a normal distribution with mean at most 0.150 seconds. Six measurements of a sprinter's reaction time show 0.152, 0.154, 0.166, 0.147, 0.161, and 0.159 seconds. What is the p value?"



i have calculated first sample mean as 0.157
and standard deviation under t-student distribution as 0.00686
then applying $t=frac{bar{x}-mu}{s/sqrt{n}}$ i got 2.45



CDF of t(2.45) is around 0.973 which i believe is the p-value requested.



what wrong did i do?










share|cite|improve this question









$endgroup$




i have following problem,



"The null hypothesis says that a sprinter's reaction time follows a normal distribution with mean at most 0.150 seconds. Six measurements of a sprinter's reaction time show 0.152, 0.154, 0.166, 0.147, 0.161, and 0.159 seconds. What is the p value?"



i have calculated first sample mean as 0.157
and standard deviation under t-student distribution as 0.00686
then applying $t=frac{bar{x}-mu}{s/sqrt{n}}$ i got 2.45



CDF of t(2.45) is around 0.973 which i believe is the p-value requested.



what wrong did i do?







hypothesis-testing






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 10 '18 at 14:22









NourNour

254




254












  • $begingroup$
    It's $p=1-0.973$.
    $endgroup$
    – Michael Hoppe
    Dec 10 '18 at 19:20










  • $begingroup$
    Yes p = 1 - cdf(t_score). thank you Michael.
    $endgroup$
    – Nour
    Dec 12 '18 at 2:59


















  • $begingroup$
    It's $p=1-0.973$.
    $endgroup$
    – Michael Hoppe
    Dec 10 '18 at 19:20










  • $begingroup$
    Yes p = 1 - cdf(t_score). thank you Michael.
    $endgroup$
    – Nour
    Dec 12 '18 at 2:59
















$begingroup$
It's $p=1-0.973$.
$endgroup$
– Michael Hoppe
Dec 10 '18 at 19:20




$begingroup$
It's $p=1-0.973$.
$endgroup$
– Michael Hoppe
Dec 10 '18 at 19:20












$begingroup$
Yes p = 1 - cdf(t_score). thank you Michael.
$endgroup$
– Nour
Dec 12 '18 at 2:59




$begingroup$
Yes p = 1 - cdf(t_score). thank you Michael.
$endgroup$
– Nour
Dec 12 '18 at 2:59










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