What does “constant rate” mean in universal composable commitment scheme?












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I'm wondering what does the "constant rate" mean in universal composable commitment scheme? I have known the rate of a commitment scheme is message length divided by the communication complexity of the scheme. What's the "constant" mean here? Must the constant be a number less than 1?










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  • Can you please post a reference to a paper or something where you encountered this term?
    – SEJPM
    Dec 18 '18 at 17:21
















3














I'm wondering what does the "constant rate" mean in universal composable commitment scheme? I have known the rate of a commitment scheme is message length divided by the communication complexity of the scheme. What's the "constant" mean here? Must the constant be a number less than 1?










share|improve this question






















  • Can you please post a reference to a paper or something where you encountered this term?
    – SEJPM
    Dec 18 '18 at 17:21














3












3








3







I'm wondering what does the "constant rate" mean in universal composable commitment scheme? I have known the rate of a commitment scheme is message length divided by the communication complexity of the scheme. What's the "constant" mean here? Must the constant be a number less than 1?










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I'm wondering what does the "constant rate" mean in universal composable commitment scheme? I have known the rate of a commitment scheme is message length divided by the communication complexity of the scheme. What's the "constant" mean here? Must the constant be a number less than 1?







commitments






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asked Dec 18 '18 at 17:14









CryptoLover

402212




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  • Can you please post a reference to a paper or something where you encountered this term?
    – SEJPM
    Dec 18 '18 at 17:21


















  • Can you please post a reference to a paper or something where you encountered this term?
    – SEJPM
    Dec 18 '18 at 17:21
















Can you please post a reference to a paper or something where you encountered this term?
– SEJPM
Dec 18 '18 at 17:21




Can you please post a reference to a paper or something where you encountered this term?
– SEJPM
Dec 18 '18 at 17:21










1 Answer
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Constant rate in general means that the overhead from a non-secure method is constant. So, in a simple way, if I am committing to an $ell$-bit message, then the size of the commitment is $O(ell)$. In some cases, however, one also allows an additive factor that is independent of the message size. Thus, for example, it could be that to commit to a message of size $ell$ the amount is $O(ell)+{rm poly}(n)$, where $n$ is the security parameter.



Note that typically these are measured in an amortized manner. So, you have to send many commitments (or a long message) for it to be true. But, again, this depends on the exact scheme, so you'll have to read the details.






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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    Constant rate in general means that the overhead from a non-secure method is constant. So, in a simple way, if I am committing to an $ell$-bit message, then the size of the commitment is $O(ell)$. In some cases, however, one also allows an additive factor that is independent of the message size. Thus, for example, it could be that to commit to a message of size $ell$ the amount is $O(ell)+{rm poly}(n)$, where $n$ is the security parameter.



    Note that typically these are measured in an amortized manner. So, you have to send many commitments (or a long message) for it to be true. But, again, this depends on the exact scheme, so you'll have to read the details.






    share|improve this answer


























      4














      Constant rate in general means that the overhead from a non-secure method is constant. So, in a simple way, if I am committing to an $ell$-bit message, then the size of the commitment is $O(ell)$. In some cases, however, one also allows an additive factor that is independent of the message size. Thus, for example, it could be that to commit to a message of size $ell$ the amount is $O(ell)+{rm poly}(n)$, where $n$ is the security parameter.



      Note that typically these are measured in an amortized manner. So, you have to send many commitments (or a long message) for it to be true. But, again, this depends on the exact scheme, so you'll have to read the details.






      share|improve this answer
























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        4






        Constant rate in general means that the overhead from a non-secure method is constant. So, in a simple way, if I am committing to an $ell$-bit message, then the size of the commitment is $O(ell)$. In some cases, however, one also allows an additive factor that is independent of the message size. Thus, for example, it could be that to commit to a message of size $ell$ the amount is $O(ell)+{rm poly}(n)$, where $n$ is the security parameter.



        Note that typically these are measured in an amortized manner. So, you have to send many commitments (or a long message) for it to be true. But, again, this depends on the exact scheme, so you'll have to read the details.






        share|improve this answer












        Constant rate in general means that the overhead from a non-secure method is constant. So, in a simple way, if I am committing to an $ell$-bit message, then the size of the commitment is $O(ell)$. In some cases, however, one also allows an additive factor that is independent of the message size. Thus, for example, it could be that to commit to a message of size $ell$ the amount is $O(ell)+{rm poly}(n)$, where $n$ is the security parameter.



        Note that typically these are measured in an amortized manner. So, you have to send many commitments (or a long message) for it to be true. But, again, this depends on the exact scheme, so you'll have to read the details.







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        answered Dec 18 '18 at 17:34









        Yehuda Lindell

        18.6k3560




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