Set of linear operators problem












0














Let S be a set of linear operators $ in L(mathbb{C^3}) $ so that no two linear operators are similar and so that
$$ A^{10} +3*A^9 +2*A^8 = 0 , forall A in S $$
How many elements can S contain?
I tried by looking at similarity invariants but don't really know what elements of S look like










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  • Can you infer anything from $A^{10}+3A^9+2A^8=A^8(A+2I)(A+I)=0$?
    – Yadati Kiran
    Nov 28 '18 at 13:32










  • Then S would contain three linear operators whose matrixes are the solutions of the equation? The three matrixes are not similar because they have different determinants?
    – user15269
    Nov 28 '18 at 13:41










  • Not only three. $A^8=0$ does not only imply $A=0$. $A$ can be nilpotent.
    – Yadati Kiran
    Nov 28 '18 at 13:42












  • Also yes for your second question. Similar matrices have same determinants. But the converse is not true.
    – Yadati Kiran
    Nov 28 '18 at 13:45












  • Seems to me, that uin this case there are not that many nilpotent operators - en.wikipedia.org/wiki/Nilpotent_matrix
    – pepa.dvorak
    Nov 30 '18 at 10:46
















0














Let S be a set of linear operators $ in L(mathbb{C^3}) $ so that no two linear operators are similar and so that
$$ A^{10} +3*A^9 +2*A^8 = 0 , forall A in S $$
How many elements can S contain?
I tried by looking at similarity invariants but don't really know what elements of S look like










share|cite|improve this question






















  • Can you infer anything from $A^{10}+3A^9+2A^8=A^8(A+2I)(A+I)=0$?
    – Yadati Kiran
    Nov 28 '18 at 13:32










  • Then S would contain three linear operators whose matrixes are the solutions of the equation? The three matrixes are not similar because they have different determinants?
    – user15269
    Nov 28 '18 at 13:41










  • Not only three. $A^8=0$ does not only imply $A=0$. $A$ can be nilpotent.
    – Yadati Kiran
    Nov 28 '18 at 13:42












  • Also yes for your second question. Similar matrices have same determinants. But the converse is not true.
    – Yadati Kiran
    Nov 28 '18 at 13:45












  • Seems to me, that uin this case there are not that many nilpotent operators - en.wikipedia.org/wiki/Nilpotent_matrix
    – pepa.dvorak
    Nov 30 '18 at 10:46














0












0








0







Let S be a set of linear operators $ in L(mathbb{C^3}) $ so that no two linear operators are similar and so that
$$ A^{10} +3*A^9 +2*A^8 = 0 , forall A in S $$
How many elements can S contain?
I tried by looking at similarity invariants but don't really know what elements of S look like










share|cite|improve this question













Let S be a set of linear operators $ in L(mathbb{C^3}) $ so that no two linear operators are similar and so that
$$ A^{10} +3*A^9 +2*A^8 = 0 , forall A in S $$
How many elements can S contain?
I tried by looking at similarity invariants but don't really know what elements of S look like







linear-algebra






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Nov 28 '18 at 13:28









user15269

1608




1608












  • Can you infer anything from $A^{10}+3A^9+2A^8=A^8(A+2I)(A+I)=0$?
    – Yadati Kiran
    Nov 28 '18 at 13:32










  • Then S would contain three linear operators whose matrixes are the solutions of the equation? The three matrixes are not similar because they have different determinants?
    – user15269
    Nov 28 '18 at 13:41










  • Not only three. $A^8=0$ does not only imply $A=0$. $A$ can be nilpotent.
    – Yadati Kiran
    Nov 28 '18 at 13:42












  • Also yes for your second question. Similar matrices have same determinants. But the converse is not true.
    – Yadati Kiran
    Nov 28 '18 at 13:45












  • Seems to me, that uin this case there are not that many nilpotent operators - en.wikipedia.org/wiki/Nilpotent_matrix
    – pepa.dvorak
    Nov 30 '18 at 10:46


















  • Can you infer anything from $A^{10}+3A^9+2A^8=A^8(A+2I)(A+I)=0$?
    – Yadati Kiran
    Nov 28 '18 at 13:32










  • Then S would contain three linear operators whose matrixes are the solutions of the equation? The three matrixes are not similar because they have different determinants?
    – user15269
    Nov 28 '18 at 13:41










  • Not only three. $A^8=0$ does not only imply $A=0$. $A$ can be nilpotent.
    – Yadati Kiran
    Nov 28 '18 at 13:42












  • Also yes for your second question. Similar matrices have same determinants. But the converse is not true.
    – Yadati Kiran
    Nov 28 '18 at 13:45












  • Seems to me, that uin this case there are not that many nilpotent operators - en.wikipedia.org/wiki/Nilpotent_matrix
    – pepa.dvorak
    Nov 30 '18 at 10:46
















Can you infer anything from $A^{10}+3A^9+2A^8=A^8(A+2I)(A+I)=0$?
– Yadati Kiran
Nov 28 '18 at 13:32




Can you infer anything from $A^{10}+3A^9+2A^8=A^8(A+2I)(A+I)=0$?
– Yadati Kiran
Nov 28 '18 at 13:32












Then S would contain three linear operators whose matrixes are the solutions of the equation? The three matrixes are not similar because they have different determinants?
– user15269
Nov 28 '18 at 13:41




Then S would contain three linear operators whose matrixes are the solutions of the equation? The three matrixes are not similar because they have different determinants?
– user15269
Nov 28 '18 at 13:41












Not only three. $A^8=0$ does not only imply $A=0$. $A$ can be nilpotent.
– Yadati Kiran
Nov 28 '18 at 13:42






Not only three. $A^8=0$ does not only imply $A=0$. $A$ can be nilpotent.
– Yadati Kiran
Nov 28 '18 at 13:42














Also yes for your second question. Similar matrices have same determinants. But the converse is not true.
– Yadati Kiran
Nov 28 '18 at 13:45






Also yes for your second question. Similar matrices have same determinants. But the converse is not true.
– Yadati Kiran
Nov 28 '18 at 13:45














Seems to me, that uin this case there are not that many nilpotent operators - en.wikipedia.org/wiki/Nilpotent_matrix
– pepa.dvorak
Nov 30 '18 at 10:46




Seems to me, that uin this case there are not that many nilpotent operators - en.wikipedia.org/wiki/Nilpotent_matrix
– pepa.dvorak
Nov 30 '18 at 10:46










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