Product of evenly spaced factorials












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I am attempting to get a closed form expression for a product of factorials $$(a!)cdot(2a)!cdots (na)!$$ where $a$ is a positive integer. Mathematica seems able to compute this whichever $a$ I give it. For example for $a = 15$ the expression equals
a=15 expression
and for higher $a$ this expression gets uglier. However Mathematica strikes out for the general expression. I am asking for a general formula to compute this.










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  • you can't get a "closed form" because there is not a closed form for a simple factorial $n!$. You can write it also as $prod_{j=1}^{na}exp((n+1-lceil j/arceil)log j)$
    – Masacroso
    Nov 28 '18 at 14:11


















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I am attempting to get a closed form expression for a product of factorials $$(a!)cdot(2a)!cdots (na)!$$ where $a$ is a positive integer. Mathematica seems able to compute this whichever $a$ I give it. For example for $a = 15$ the expression equals
a=15 expression
and for higher $a$ this expression gets uglier. However Mathematica strikes out for the general expression. I am asking for a general formula to compute this.










share|cite|improve this question






















  • you can't get a "closed form" because there is not a closed form for a simple factorial $n!$. You can write it also as $prod_{j=1}^{na}exp((n+1-lceil j/arceil)log j)$
    – Masacroso
    Nov 28 '18 at 14:11
















0












0








0


1





I am attempting to get a closed form expression for a product of factorials $$(a!)cdot(2a)!cdots (na)!$$ where $a$ is a positive integer. Mathematica seems able to compute this whichever $a$ I give it. For example for $a = 15$ the expression equals
a=15 expression
and for higher $a$ this expression gets uglier. However Mathematica strikes out for the general expression. I am asking for a general formula to compute this.










share|cite|improve this question













I am attempting to get a closed form expression for a product of factorials $$(a!)cdot(2a)!cdots (na)!$$ where $a$ is a positive integer. Mathematica seems able to compute this whichever $a$ I give it. For example for $a = 15$ the expression equals
a=15 expression
and for higher $a$ this expression gets uglier. However Mathematica strikes out for the general expression. I am asking for a general formula to compute this.







factorial products






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asked Nov 28 '18 at 11:00









SweSnow

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  • you can't get a "closed form" because there is not a closed form for a simple factorial $n!$. You can write it also as $prod_{j=1}^{na}exp((n+1-lceil j/arceil)log j)$
    – Masacroso
    Nov 28 '18 at 14:11




















  • you can't get a "closed form" because there is not a closed form for a simple factorial $n!$. You can write it also as $prod_{j=1}^{na}exp((n+1-lceil j/arceil)log j)$
    – Masacroso
    Nov 28 '18 at 14:11


















you can't get a "closed form" because there is not a closed form for a simple factorial $n!$. You can write it also as $prod_{j=1}^{na}exp((n+1-lceil j/arceil)log j)$
– Masacroso
Nov 28 '18 at 14:11






you can't get a "closed form" because there is not a closed form for a simple factorial $n!$. You can write it also as $prod_{j=1}^{na}exp((n+1-lceil j/arceil)log j)$
– Masacroso
Nov 28 '18 at 14:11












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