How do I find the most right point on a circle? [closed]
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I have given the center point and the radius of a circle but i am interested in the most right point which is lying on that circle.
edited:
thanks for the comments. I have the central point c
and have the radius r
as well. And my question was what is the equation to get the most right point p
on the circle surrounding the center by the given radius.
r = sqrt((p1-c1)(p1-c1) + (p2-c2)(p2-c2))
then i am looking for the (p1,p2) point
At the end I found it out with the help and hint from you. As I mentioned I had the central point C
and the radius R
and I was looking for the most right point P
on the edge of the circle. My approach what finally helped was to calculate a square around the circle (bounding box) and take as x
coordinate for the P
point the x
coordinate of the top right corner of that bounding box, and the y
coordinate for the P
point the y
of the C
point.
Thanks for every help, as far as it showed me the right direction.
P(x,y)=(xC,yC)+v⃗ R <--- this helped also as the v⃗ R is a normal vector on the right edge of the mentioned bounding box.
circle
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closed as unclear what you're asking by José Carlos Santos, TheGeekGreek, Alexander Gruber♦ Dec 4 '18 at 4:26
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
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show 1 more comment
$begingroup$
I have given the center point and the radius of a circle but i am interested in the most right point which is lying on that circle.
edited:
thanks for the comments. I have the central point c
and have the radius r
as well. And my question was what is the equation to get the most right point p
on the circle surrounding the center by the given radius.
r = sqrt((p1-c1)(p1-c1) + (p2-c2)(p2-c2))
then i am looking for the (p1,p2) point
At the end I found it out with the help and hint from you. As I mentioned I had the central point C
and the radius R
and I was looking for the most right point P
on the edge of the circle. My approach what finally helped was to calculate a square around the circle (bounding box) and take as x
coordinate for the P
point the x
coordinate of the top right corner of that bounding box, and the y
coordinate for the P
point the y
of the C
point.
Thanks for every help, as far as it showed me the right direction.
P(x,y)=(xC,yC)+v⃗ R <--- this helped also as the v⃗ R is a normal vector on the right edge of the mentioned bounding box.
circle
$endgroup$
closed as unclear what you're asking by José Carlos Santos, TheGeekGreek, Alexander Gruber♦ Dec 4 '18 at 4:26
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
I assume you have the equation. Set $y$ equal to the height of the center and solve for $x$. If that's not what you want, edit the question to tell us what you do know.
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– Ethan Bolker
Dec 3 '18 at 11:19
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It's a very vague question but still i suggest you use parametric coordinates for this purpose
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– Aditya Garg
Dec 3 '18 at 11:19
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If i understand it right:Center $vec{c}$, radius $r$, $vec{p}$ the point you are looking for. $vec{p} = vec{c} + r vec{e_x}$, where $vec{e_x}$ is the unit-vector in x-direction.
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– denklo
Dec 3 '18 at 11:20
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thanks for the comments. I have the central point and have the radius as well. And my question was what is the equation to get the most right point on the circle surrounding the center by the given radius
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– Csabi
Dec 3 '18 at 11:26
1
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@Csabi It woulb be useful if you could show your work here editing your question.
$endgroup$
– gimusi
Dec 3 '18 at 21:16
|
show 1 more comment
$begingroup$
I have given the center point and the radius of a circle but i am interested in the most right point which is lying on that circle.
edited:
thanks for the comments. I have the central point c
and have the radius r
as well. And my question was what is the equation to get the most right point p
on the circle surrounding the center by the given radius.
r = sqrt((p1-c1)(p1-c1) + (p2-c2)(p2-c2))
then i am looking for the (p1,p2) point
At the end I found it out with the help and hint from you. As I mentioned I had the central point C
and the radius R
and I was looking for the most right point P
on the edge of the circle. My approach what finally helped was to calculate a square around the circle (bounding box) and take as x
coordinate for the P
point the x
coordinate of the top right corner of that bounding box, and the y
coordinate for the P
point the y
of the C
point.
Thanks for every help, as far as it showed me the right direction.
P(x,y)=(xC,yC)+v⃗ R <--- this helped also as the v⃗ R is a normal vector on the right edge of the mentioned bounding box.
circle
$endgroup$
I have given the center point and the radius of a circle but i am interested in the most right point which is lying on that circle.
edited:
thanks for the comments. I have the central point c
and have the radius r
as well. And my question was what is the equation to get the most right point p
on the circle surrounding the center by the given radius.
r = sqrt((p1-c1)(p1-c1) + (p2-c2)(p2-c2))
then i am looking for the (p1,p2) point
At the end I found it out with the help and hint from you. As I mentioned I had the central point C
and the radius R
and I was looking for the most right point P
on the edge of the circle. My approach what finally helped was to calculate a square around the circle (bounding box) and take as x
coordinate for the P
point the x
coordinate of the top right corner of that bounding box, and the y
coordinate for the P
point the y
of the C
point.
Thanks for every help, as far as it showed me the right direction.
P(x,y)=(xC,yC)+v⃗ R <--- this helped also as the v⃗ R is a normal vector on the right edge of the mentioned bounding box.
circle
circle
edited Dec 5 '18 at 6:49
Csabi
asked Dec 3 '18 at 11:16
CsabiCsabi
135116
135116
closed as unclear what you're asking by José Carlos Santos, TheGeekGreek, Alexander Gruber♦ Dec 4 '18 at 4:26
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as unclear what you're asking by José Carlos Santos, TheGeekGreek, Alexander Gruber♦ Dec 4 '18 at 4:26
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
I assume you have the equation. Set $y$ equal to the height of the center and solve for $x$. If that's not what you want, edit the question to tell us what you do know.
$endgroup$
– Ethan Bolker
Dec 3 '18 at 11:19
$begingroup$
It's a very vague question but still i suggest you use parametric coordinates for this purpose
$endgroup$
– Aditya Garg
Dec 3 '18 at 11:19
$begingroup$
If i understand it right:Center $vec{c}$, radius $r$, $vec{p}$ the point you are looking for. $vec{p} = vec{c} + r vec{e_x}$, where $vec{e_x}$ is the unit-vector in x-direction.
$endgroup$
– denklo
Dec 3 '18 at 11:20
$begingroup$
thanks for the comments. I have the central point and have the radius as well. And my question was what is the equation to get the most right point on the circle surrounding the center by the given radius
$endgroup$
– Csabi
Dec 3 '18 at 11:26
1
$begingroup$
@Csabi It woulb be useful if you could show your work here editing your question.
$endgroup$
– gimusi
Dec 3 '18 at 21:16
|
show 1 more comment
$begingroup$
I assume you have the equation. Set $y$ equal to the height of the center and solve for $x$. If that's not what you want, edit the question to tell us what you do know.
$endgroup$
– Ethan Bolker
Dec 3 '18 at 11:19
$begingroup$
It's a very vague question but still i suggest you use parametric coordinates for this purpose
$endgroup$
– Aditya Garg
Dec 3 '18 at 11:19
$begingroup$
If i understand it right:Center $vec{c}$, radius $r$, $vec{p}$ the point you are looking for. $vec{p} = vec{c} + r vec{e_x}$, where $vec{e_x}$ is the unit-vector in x-direction.
$endgroup$
– denklo
Dec 3 '18 at 11:20
$begingroup$
thanks for the comments. I have the central point and have the radius as well. And my question was what is the equation to get the most right point on the circle surrounding the center by the given radius
$endgroup$
– Csabi
Dec 3 '18 at 11:26
1
$begingroup$
@Csabi It woulb be useful if you could show your work here editing your question.
$endgroup$
– gimusi
Dec 3 '18 at 21:16
$begingroup$
I assume you have the equation. Set $y$ equal to the height of the center and solve for $x$. If that's not what you want, edit the question to tell us what you do know.
$endgroup$
– Ethan Bolker
Dec 3 '18 at 11:19
$begingroup$
I assume you have the equation. Set $y$ equal to the height of the center and solve for $x$. If that's not what you want, edit the question to tell us what you do know.
$endgroup$
– Ethan Bolker
Dec 3 '18 at 11:19
$begingroup$
It's a very vague question but still i suggest you use parametric coordinates for this purpose
$endgroup$
– Aditya Garg
Dec 3 '18 at 11:19
$begingroup$
It's a very vague question but still i suggest you use parametric coordinates for this purpose
$endgroup$
– Aditya Garg
Dec 3 '18 at 11:19
$begingroup$
If i understand it right:Center $vec{c}$, radius $r$, $vec{p}$ the point you are looking for. $vec{p} = vec{c} + r vec{e_x}$, where $vec{e_x}$ is the unit-vector in x-direction.
$endgroup$
– denklo
Dec 3 '18 at 11:20
$begingroup$
If i understand it right:Center $vec{c}$, radius $r$, $vec{p}$ the point you are looking for. $vec{p} = vec{c} + r vec{e_x}$, where $vec{e_x}$ is the unit-vector in x-direction.
$endgroup$
– denklo
Dec 3 '18 at 11:20
$begingroup$
thanks for the comments. I have the central point and have the radius as well. And my question was what is the equation to get the most right point on the circle surrounding the center by the given radius
$endgroup$
– Csabi
Dec 3 '18 at 11:26
$begingroup$
thanks for the comments. I have the central point and have the radius as well. And my question was what is the equation to get the most right point on the circle surrounding the center by the given radius
$endgroup$
– Csabi
Dec 3 '18 at 11:26
1
1
$begingroup$
@Csabi It woulb be useful if you could show your work here editing your question.
$endgroup$
– gimusi
Dec 3 '18 at 21:16
$begingroup$
@Csabi It woulb be useful if you could show your work here editing your question.
$endgroup$
– gimusi
Dec 3 '18 at 21:16
|
show 1 more comment
2 Answers
2
active
oldest
votes
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HINT
Assuming the center at $C(x_C,y_C)$ any other point on the circle with radius $R$ can by obtained by
$$P(x,y)=(x_C,y_C)+vec v_R$$
with $|vec v_R|=R$.
$endgroup$
$begingroup$
Hi thanks for the answer, but i would like to know if it is possible to have the most right point received by an equasion
$endgroup$
– Csabi
Dec 3 '18 at 11:29
1
$begingroup$
@Csabi You need to figure out what the vector $vec v_R$ needs to be. You have already received some big hint by the comments.
$endgroup$
– gimusi
Dec 3 '18 at 11:31
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thanks your answer showed me the right way. I have edited my answer and showcased my solution. @gimusi
$endgroup$
– Csabi
Dec 5 '18 at 6:55
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That's nice! Well done, Bye
$endgroup$
– gimusi
Dec 5 '18 at 7:48
add a comment |
$begingroup$
I would draw a picture. How is the $x$-coordinate of the rightmost point related to the $x$-coordinate of the center? How are their $y$-coordinates related?
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add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
HINT
Assuming the center at $C(x_C,y_C)$ any other point on the circle with radius $R$ can by obtained by
$$P(x,y)=(x_C,y_C)+vec v_R$$
with $|vec v_R|=R$.
$endgroup$
$begingroup$
Hi thanks for the answer, but i would like to know if it is possible to have the most right point received by an equasion
$endgroup$
– Csabi
Dec 3 '18 at 11:29
1
$begingroup$
@Csabi You need to figure out what the vector $vec v_R$ needs to be. You have already received some big hint by the comments.
$endgroup$
– gimusi
Dec 3 '18 at 11:31
$begingroup$
thanks your answer showed me the right way. I have edited my answer and showcased my solution. @gimusi
$endgroup$
– Csabi
Dec 5 '18 at 6:55
$begingroup$
That's nice! Well done, Bye
$endgroup$
– gimusi
Dec 5 '18 at 7:48
add a comment |
$begingroup$
HINT
Assuming the center at $C(x_C,y_C)$ any other point on the circle with radius $R$ can by obtained by
$$P(x,y)=(x_C,y_C)+vec v_R$$
with $|vec v_R|=R$.
$endgroup$
$begingroup$
Hi thanks for the answer, but i would like to know if it is possible to have the most right point received by an equasion
$endgroup$
– Csabi
Dec 3 '18 at 11:29
1
$begingroup$
@Csabi You need to figure out what the vector $vec v_R$ needs to be. You have already received some big hint by the comments.
$endgroup$
– gimusi
Dec 3 '18 at 11:31
$begingroup$
thanks your answer showed me the right way. I have edited my answer and showcased my solution. @gimusi
$endgroup$
– Csabi
Dec 5 '18 at 6:55
$begingroup$
That's nice! Well done, Bye
$endgroup$
– gimusi
Dec 5 '18 at 7:48
add a comment |
$begingroup$
HINT
Assuming the center at $C(x_C,y_C)$ any other point on the circle with radius $R$ can by obtained by
$$P(x,y)=(x_C,y_C)+vec v_R$$
with $|vec v_R|=R$.
$endgroup$
HINT
Assuming the center at $C(x_C,y_C)$ any other point on the circle with radius $R$ can by obtained by
$$P(x,y)=(x_C,y_C)+vec v_R$$
with $|vec v_R|=R$.
answered Dec 3 '18 at 11:28
gimusigimusi
1
1
$begingroup$
Hi thanks for the answer, but i would like to know if it is possible to have the most right point received by an equasion
$endgroup$
– Csabi
Dec 3 '18 at 11:29
1
$begingroup$
@Csabi You need to figure out what the vector $vec v_R$ needs to be. You have already received some big hint by the comments.
$endgroup$
– gimusi
Dec 3 '18 at 11:31
$begingroup$
thanks your answer showed me the right way. I have edited my answer and showcased my solution. @gimusi
$endgroup$
– Csabi
Dec 5 '18 at 6:55
$begingroup$
That's nice! Well done, Bye
$endgroup$
– gimusi
Dec 5 '18 at 7:48
add a comment |
$begingroup$
Hi thanks for the answer, but i would like to know if it is possible to have the most right point received by an equasion
$endgroup$
– Csabi
Dec 3 '18 at 11:29
1
$begingroup$
@Csabi You need to figure out what the vector $vec v_R$ needs to be. You have already received some big hint by the comments.
$endgroup$
– gimusi
Dec 3 '18 at 11:31
$begingroup$
thanks your answer showed me the right way. I have edited my answer and showcased my solution. @gimusi
$endgroup$
– Csabi
Dec 5 '18 at 6:55
$begingroup$
That's nice! Well done, Bye
$endgroup$
– gimusi
Dec 5 '18 at 7:48
$begingroup$
Hi thanks for the answer, but i would like to know if it is possible to have the most right point received by an equasion
$endgroup$
– Csabi
Dec 3 '18 at 11:29
$begingroup$
Hi thanks for the answer, but i would like to know if it is possible to have the most right point received by an equasion
$endgroup$
– Csabi
Dec 3 '18 at 11:29
1
1
$begingroup$
@Csabi You need to figure out what the vector $vec v_R$ needs to be. You have already received some big hint by the comments.
$endgroup$
– gimusi
Dec 3 '18 at 11:31
$begingroup$
@Csabi You need to figure out what the vector $vec v_R$ needs to be. You have already received some big hint by the comments.
$endgroup$
– gimusi
Dec 3 '18 at 11:31
$begingroup$
thanks your answer showed me the right way. I have edited my answer and showcased my solution. @gimusi
$endgroup$
– Csabi
Dec 5 '18 at 6:55
$begingroup$
thanks your answer showed me the right way. I have edited my answer and showcased my solution. @gimusi
$endgroup$
– Csabi
Dec 5 '18 at 6:55
$begingroup$
That's nice! Well done, Bye
$endgroup$
– gimusi
Dec 5 '18 at 7:48
$begingroup$
That's nice! Well done, Bye
$endgroup$
– gimusi
Dec 5 '18 at 7:48
add a comment |
$begingroup$
I would draw a picture. How is the $x$-coordinate of the rightmost point related to the $x$-coordinate of the center? How are their $y$-coordinates related?
$endgroup$
add a comment |
$begingroup$
I would draw a picture. How is the $x$-coordinate of the rightmost point related to the $x$-coordinate of the center? How are their $y$-coordinates related?
$endgroup$
add a comment |
$begingroup$
I would draw a picture. How is the $x$-coordinate of the rightmost point related to the $x$-coordinate of the center? How are their $y$-coordinates related?
$endgroup$
I would draw a picture. How is the $x$-coordinate of the rightmost point related to the $x$-coordinate of the center? How are their $y$-coordinates related?
answered Dec 3 '18 at 11:46
Cameron BuieCameron Buie
85.1k771155
85.1k771155
add a comment |
add a comment |
$begingroup$
I assume you have the equation. Set $y$ equal to the height of the center and solve for $x$. If that's not what you want, edit the question to tell us what you do know.
$endgroup$
– Ethan Bolker
Dec 3 '18 at 11:19
$begingroup$
It's a very vague question but still i suggest you use parametric coordinates for this purpose
$endgroup$
– Aditya Garg
Dec 3 '18 at 11:19
$begingroup$
If i understand it right:Center $vec{c}$, radius $r$, $vec{p}$ the point you are looking for. $vec{p} = vec{c} + r vec{e_x}$, where $vec{e_x}$ is the unit-vector in x-direction.
$endgroup$
– denklo
Dec 3 '18 at 11:20
$begingroup$
thanks for the comments. I have the central point and have the radius as well. And my question was what is the equation to get the most right point on the circle surrounding the center by the given radius
$endgroup$
– Csabi
Dec 3 '18 at 11:26
1
$begingroup$
@Csabi It woulb be useful if you could show your work here editing your question.
$endgroup$
– gimusi
Dec 3 '18 at 21:16