Uniqueness of set where subset exactly sums to 1
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Let $A = {a_1, a_2, ldots, a_I}$ be a set of real numbers, where for all $i in {1,2,ldots,I}$, $0<a_ile1$ and $sum_{j ne i} a_j ge 1$.
I am interested in the set (or sets) $A$ satisfying the following condition:
For every subset $S subset {1,2,ldots,I}$ where $sum_{i in S} a_i ge 1$, there exists a subset $S' subseteq S$ where $sum_{i in S'} a_i = 1$, i.e. that exactly sums to 1.
Is it true that the only set $A$ satisfying this condition is the one where, for all $i in {1,2,ldots,I}$:
$$a_i = a quadlandquad frac{1}{a} text{ is an integer}$$
proof-verification integers
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Let $A = {a_1, a_2, ldots, a_I}$ be a set of real numbers, where for all $i in {1,2,ldots,I}$, $0<a_ile1$ and $sum_{j ne i} a_j ge 1$.
I am interested in the set (or sets) $A$ satisfying the following condition:
For every subset $S subset {1,2,ldots,I}$ where $sum_{i in S} a_i ge 1$, there exists a subset $S' subseteq S$ where $sum_{i in S'} a_i = 1$, i.e. that exactly sums to 1.
Is it true that the only set $A$ satisfying this condition is the one where, for all $i in {1,2,ldots,I}$:
$$a_i = a quadlandquad frac{1}{a} text{ is an integer}$$
proof-verification integers
Could you please give an example of what you're looking for?
– MJD
Nov 23 at 14:03
@MJD: $A=left{frac{1}{2}, frac{1}{2}, frac{1}{2}right}$ satisfies the condition, while $A=left{frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ doesn't since the sum of $S'=left{frac{1}{3}, frac{1}{2}right}$ does not exactly equal 1.
– bonna
Nov 23 at 14:14
But for that second example, $A$ doesn't satisfy the $forall iin {1,ldots,I}: sum_{jneq i} a_j geq 1$?
– Henrik
Nov 23 at 14:16
Sorry. Let the second example be $A=left{frac{1}{3}, frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ and $S'=left{frac{1}{3}, frac{1}{3}, frac{1}{2}right}$
– bonna
Nov 23 at 14:20
add a comment |
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Let $A = {a_1, a_2, ldots, a_I}$ be a set of real numbers, where for all $i in {1,2,ldots,I}$, $0<a_ile1$ and $sum_{j ne i} a_j ge 1$.
I am interested in the set (or sets) $A$ satisfying the following condition:
For every subset $S subset {1,2,ldots,I}$ where $sum_{i in S} a_i ge 1$, there exists a subset $S' subseteq S$ where $sum_{i in S'} a_i = 1$, i.e. that exactly sums to 1.
Is it true that the only set $A$ satisfying this condition is the one where, for all $i in {1,2,ldots,I}$:
$$a_i = a quadlandquad frac{1}{a} text{ is an integer}$$
proof-verification integers
Let $A = {a_1, a_2, ldots, a_I}$ be a set of real numbers, where for all $i in {1,2,ldots,I}$, $0<a_ile1$ and $sum_{j ne i} a_j ge 1$.
I am interested in the set (or sets) $A$ satisfying the following condition:
For every subset $S subset {1,2,ldots,I}$ where $sum_{i in S} a_i ge 1$, there exists a subset $S' subseteq S$ where $sum_{i in S'} a_i = 1$, i.e. that exactly sums to 1.
Is it true that the only set $A$ satisfying this condition is the one where, for all $i in {1,2,ldots,I}$:
$$a_i = a quadlandquad frac{1}{a} text{ is an integer}$$
proof-verification integers
proof-verification integers
asked Nov 23 at 13:58
bonna
858
858
Could you please give an example of what you're looking for?
– MJD
Nov 23 at 14:03
@MJD: $A=left{frac{1}{2}, frac{1}{2}, frac{1}{2}right}$ satisfies the condition, while $A=left{frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ doesn't since the sum of $S'=left{frac{1}{3}, frac{1}{2}right}$ does not exactly equal 1.
– bonna
Nov 23 at 14:14
But for that second example, $A$ doesn't satisfy the $forall iin {1,ldots,I}: sum_{jneq i} a_j geq 1$?
– Henrik
Nov 23 at 14:16
Sorry. Let the second example be $A=left{frac{1}{3}, frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ and $S'=left{frac{1}{3}, frac{1}{3}, frac{1}{2}right}$
– bonna
Nov 23 at 14:20
add a comment |
Could you please give an example of what you're looking for?
– MJD
Nov 23 at 14:03
@MJD: $A=left{frac{1}{2}, frac{1}{2}, frac{1}{2}right}$ satisfies the condition, while $A=left{frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ doesn't since the sum of $S'=left{frac{1}{3}, frac{1}{2}right}$ does not exactly equal 1.
– bonna
Nov 23 at 14:14
But for that second example, $A$ doesn't satisfy the $forall iin {1,ldots,I}: sum_{jneq i} a_j geq 1$?
– Henrik
Nov 23 at 14:16
Sorry. Let the second example be $A=left{frac{1}{3}, frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ and $S'=left{frac{1}{3}, frac{1}{3}, frac{1}{2}right}$
– bonna
Nov 23 at 14:20
Could you please give an example of what you're looking for?
– MJD
Nov 23 at 14:03
Could you please give an example of what you're looking for?
– MJD
Nov 23 at 14:03
@MJD: $A=left{frac{1}{2}, frac{1}{2}, frac{1}{2}right}$ satisfies the condition, while $A=left{frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ doesn't since the sum of $S'=left{frac{1}{3}, frac{1}{2}right}$ does not exactly equal 1.
– bonna
Nov 23 at 14:14
@MJD: $A=left{frac{1}{2}, frac{1}{2}, frac{1}{2}right}$ satisfies the condition, while $A=left{frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ doesn't since the sum of $S'=left{frac{1}{3}, frac{1}{2}right}$ does not exactly equal 1.
– bonna
Nov 23 at 14:14
But for that second example, $A$ doesn't satisfy the $forall iin {1,ldots,I}: sum_{jneq i} a_j geq 1$?
– Henrik
Nov 23 at 14:16
But for that second example, $A$ doesn't satisfy the $forall iin {1,ldots,I}: sum_{jneq i} a_j geq 1$?
– Henrik
Nov 23 at 14:16
Sorry. Let the second example be $A=left{frac{1}{3}, frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ and $S'=left{frac{1}{3}, frac{1}{3}, frac{1}{2}right}$
– bonna
Nov 23 at 14:20
Sorry. Let the second example be $A=left{frac{1}{3}, frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ and $S'=left{frac{1}{3}, frac{1}{3}, frac{1}{2}right}$
– bonna
Nov 23 at 14:20
add a comment |
1 Answer
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No, it is not true. Consider the following counter-example where $a_i ne a, forall i$:
$$A = {a_1, a_2, a_3, a_4}, text{ where } a_1 = a_2 = frac{1}{4} text{ and } a_3 = a_4 = frac{1}{2}$$
This satisfies the condition that all the subsets $$S = {a_1, a_2, a_3}, {a_1, a_2, a_4}, {a_3, a_4}, {a_1, a_3, a_4}, {a_2, a_3, a_4}$$ where $sum_{i in S} a_i ge 1$, have subsets $$S' = {a_1, a_2, a_3}, {a_1, a_2, a_4}, {a_3, a_4}$$ where $sum_{i in S'} a_i = 1$.
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1 Answer
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1 Answer
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active
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votes
active
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active
oldest
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up vote
0
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accepted
No, it is not true. Consider the following counter-example where $a_i ne a, forall i$:
$$A = {a_1, a_2, a_3, a_4}, text{ where } a_1 = a_2 = frac{1}{4} text{ and } a_3 = a_4 = frac{1}{2}$$
This satisfies the condition that all the subsets $$S = {a_1, a_2, a_3}, {a_1, a_2, a_4}, {a_3, a_4}, {a_1, a_3, a_4}, {a_2, a_3, a_4}$$ where $sum_{i in S} a_i ge 1$, have subsets $$S' = {a_1, a_2, a_3}, {a_1, a_2, a_4}, {a_3, a_4}$$ where $sum_{i in S'} a_i = 1$.
add a comment |
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0
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No, it is not true. Consider the following counter-example where $a_i ne a, forall i$:
$$A = {a_1, a_2, a_3, a_4}, text{ where } a_1 = a_2 = frac{1}{4} text{ and } a_3 = a_4 = frac{1}{2}$$
This satisfies the condition that all the subsets $$S = {a_1, a_2, a_3}, {a_1, a_2, a_4}, {a_3, a_4}, {a_1, a_3, a_4}, {a_2, a_3, a_4}$$ where $sum_{i in S} a_i ge 1$, have subsets $$S' = {a_1, a_2, a_3}, {a_1, a_2, a_4}, {a_3, a_4}$$ where $sum_{i in S'} a_i = 1$.
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
No, it is not true. Consider the following counter-example where $a_i ne a, forall i$:
$$A = {a_1, a_2, a_3, a_4}, text{ where } a_1 = a_2 = frac{1}{4} text{ and } a_3 = a_4 = frac{1}{2}$$
This satisfies the condition that all the subsets $$S = {a_1, a_2, a_3}, {a_1, a_2, a_4}, {a_3, a_4}, {a_1, a_3, a_4}, {a_2, a_3, a_4}$$ where $sum_{i in S} a_i ge 1$, have subsets $$S' = {a_1, a_2, a_3}, {a_1, a_2, a_4}, {a_3, a_4}$$ where $sum_{i in S'} a_i = 1$.
No, it is not true. Consider the following counter-example where $a_i ne a, forall i$:
$$A = {a_1, a_2, a_3, a_4}, text{ where } a_1 = a_2 = frac{1}{4} text{ and } a_3 = a_4 = frac{1}{2}$$
This satisfies the condition that all the subsets $$S = {a_1, a_2, a_3}, {a_1, a_2, a_4}, {a_3, a_4}, {a_1, a_3, a_4}, {a_2, a_3, a_4}$$ where $sum_{i in S} a_i ge 1$, have subsets $$S' = {a_1, a_2, a_3}, {a_1, a_2, a_4}, {a_3, a_4}$$ where $sum_{i in S'} a_i = 1$.
answered Nov 23 at 15:12
bonna
858
858
add a comment |
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Could you please give an example of what you're looking for?
– MJD
Nov 23 at 14:03
@MJD: $A=left{frac{1}{2}, frac{1}{2}, frac{1}{2}right}$ satisfies the condition, while $A=left{frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ doesn't since the sum of $S'=left{frac{1}{3}, frac{1}{2}right}$ does not exactly equal 1.
– bonna
Nov 23 at 14:14
But for that second example, $A$ doesn't satisfy the $forall iin {1,ldots,I}: sum_{jneq i} a_j geq 1$?
– Henrik
Nov 23 at 14:16
Sorry. Let the second example be $A=left{frac{1}{3}, frac{1}{3}, frac{1}{2}, frac{1}{2}right}$ and $S'=left{frac{1}{3}, frac{1}{3}, frac{1}{2}right}$
– bonna
Nov 23 at 14:20