Prove that $phi(t)= frac{1}{2} + frac{e^{t^2}}{4e^{t^2} - 2}$ defines characteristic function












2












$begingroup$



Let $phi : mathbb{R} rightarrow mathbb{R}$ be given by
$$phi(t) = frac{1}{2} + frac{e^{t^2}}{4e^{t^2} - 2}$$
Prove that $phi$ is a characteristic function.




My attempt:



I know that there are certain criteria that say that a function is a characteristic function of distribution, eg the Bochner criterion, but I do not know how to prove that a function is positively defined. I also have the Polya criterion, but here the condition that $phi (infty) = 0$ is not satisfied. Could You give me some hints?










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$endgroup$








  • 4




    $begingroup$
    Low-tech approach: Expanding the geometric series, one gets $$varphi(t)=frac12+frac14frac1{1-frac12e^{-t^2}}=frac34+sum_{ngeqslant1}frac1{2^{n+2}}e^{-nt^2}$$ Now, use (and/or prove) the result that if every $varphi_n$ is a characteristic function and if $(p_n)$ are nonnegative with $sum p_n=1$ then $$varphi=sum_{ngeqslant0}p_nvarphi_n$$ is a characteristic function as well.
    $endgroup$
    – Did
    Dec 6 '18 at 15:24












  • $begingroup$
    @Did That approach needs slightly more care in this case because there are infinitely many of the $varphi_n$, but it works.
    $endgroup$
    – J.G.
    Dec 6 '18 at 15:25






  • 1




    $begingroup$
    @J.G. I do not know what you mean by "slightly more care" ("more" than what?) but indeed the result I mentioned holds, for infinitely many nonzero coefficients $p_n$ just like it holds for finitely many.
    $endgroup$
    – Did
    Dec 6 '18 at 15:28






  • 1




    $begingroup$
    @Did It's a trivial result when we take a linear combination of any finite number of cfs by induction, but the extension to infinitely many requires discussion of limits. In this case I'd take the pointwise limit of a sequence of pdfs from Fourier inversion, then Fourier-transform back to $varphi$.
    $endgroup$
    – J.G.
    Dec 6 '18 at 15:35






  • 1




    $begingroup$
    "Discussion of limits" Not necessarily, if one builds explicitely a random variable whose CF is $sumlimits_{n=0}^infty p_nvarphi_n$.
    $endgroup$
    – Did
    Dec 6 '18 at 16:06
















2












$begingroup$



Let $phi : mathbb{R} rightarrow mathbb{R}$ be given by
$$phi(t) = frac{1}{2} + frac{e^{t^2}}{4e^{t^2} - 2}$$
Prove that $phi$ is a characteristic function.




My attempt:



I know that there are certain criteria that say that a function is a characteristic function of distribution, eg the Bochner criterion, but I do not know how to prove that a function is positively defined. I also have the Polya criterion, but here the condition that $phi (infty) = 0$ is not satisfied. Could You give me some hints?










share|cite|improve this question











$endgroup$








  • 4




    $begingroup$
    Low-tech approach: Expanding the geometric series, one gets $$varphi(t)=frac12+frac14frac1{1-frac12e^{-t^2}}=frac34+sum_{ngeqslant1}frac1{2^{n+2}}e^{-nt^2}$$ Now, use (and/or prove) the result that if every $varphi_n$ is a characteristic function and if $(p_n)$ are nonnegative with $sum p_n=1$ then $$varphi=sum_{ngeqslant0}p_nvarphi_n$$ is a characteristic function as well.
    $endgroup$
    – Did
    Dec 6 '18 at 15:24












  • $begingroup$
    @Did That approach needs slightly more care in this case because there are infinitely many of the $varphi_n$, but it works.
    $endgroup$
    – J.G.
    Dec 6 '18 at 15:25






  • 1




    $begingroup$
    @J.G. I do not know what you mean by "slightly more care" ("more" than what?) but indeed the result I mentioned holds, for infinitely many nonzero coefficients $p_n$ just like it holds for finitely many.
    $endgroup$
    – Did
    Dec 6 '18 at 15:28






  • 1




    $begingroup$
    @Did It's a trivial result when we take a linear combination of any finite number of cfs by induction, but the extension to infinitely many requires discussion of limits. In this case I'd take the pointwise limit of a sequence of pdfs from Fourier inversion, then Fourier-transform back to $varphi$.
    $endgroup$
    – J.G.
    Dec 6 '18 at 15:35






  • 1




    $begingroup$
    "Discussion of limits" Not necessarily, if one builds explicitely a random variable whose CF is $sumlimits_{n=0}^infty p_nvarphi_n$.
    $endgroup$
    – Did
    Dec 6 '18 at 16:06














2












2








2


0



$begingroup$



Let $phi : mathbb{R} rightarrow mathbb{R}$ be given by
$$phi(t) = frac{1}{2} + frac{e^{t^2}}{4e^{t^2} - 2}$$
Prove that $phi$ is a characteristic function.




My attempt:



I know that there are certain criteria that say that a function is a characteristic function of distribution, eg the Bochner criterion, but I do not know how to prove that a function is positively defined. I also have the Polya criterion, but here the condition that $phi (infty) = 0$ is not satisfied. Could You give me some hints?










share|cite|improve this question











$endgroup$





Let $phi : mathbb{R} rightarrow mathbb{R}$ be given by
$$phi(t) = frac{1}{2} + frac{e^{t^2}}{4e^{t^2} - 2}$$
Prove that $phi$ is a characteristic function.




My attempt:



I know that there are certain criteria that say that a function is a characteristic function of distribution, eg the Bochner criterion, but I do not know how to prove that a function is positively defined. I also have the Polya criterion, but here the condition that $phi (infty) = 0$ is not satisfied. Could You give me some hints?







probability-theory characteristic-functions






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 6 '18 at 15:26









Did

247k23223459




247k23223459










asked Dec 6 '18 at 15:13









Marcinek665Marcinek665

265110




265110








  • 4




    $begingroup$
    Low-tech approach: Expanding the geometric series, one gets $$varphi(t)=frac12+frac14frac1{1-frac12e^{-t^2}}=frac34+sum_{ngeqslant1}frac1{2^{n+2}}e^{-nt^2}$$ Now, use (and/or prove) the result that if every $varphi_n$ is a characteristic function and if $(p_n)$ are nonnegative with $sum p_n=1$ then $$varphi=sum_{ngeqslant0}p_nvarphi_n$$ is a characteristic function as well.
    $endgroup$
    – Did
    Dec 6 '18 at 15:24












  • $begingroup$
    @Did That approach needs slightly more care in this case because there are infinitely many of the $varphi_n$, but it works.
    $endgroup$
    – J.G.
    Dec 6 '18 at 15:25






  • 1




    $begingroup$
    @J.G. I do not know what you mean by "slightly more care" ("more" than what?) but indeed the result I mentioned holds, for infinitely many nonzero coefficients $p_n$ just like it holds for finitely many.
    $endgroup$
    – Did
    Dec 6 '18 at 15:28






  • 1




    $begingroup$
    @Did It's a trivial result when we take a linear combination of any finite number of cfs by induction, but the extension to infinitely many requires discussion of limits. In this case I'd take the pointwise limit of a sequence of pdfs from Fourier inversion, then Fourier-transform back to $varphi$.
    $endgroup$
    – J.G.
    Dec 6 '18 at 15:35






  • 1




    $begingroup$
    "Discussion of limits" Not necessarily, if one builds explicitely a random variable whose CF is $sumlimits_{n=0}^infty p_nvarphi_n$.
    $endgroup$
    – Did
    Dec 6 '18 at 16:06














  • 4




    $begingroup$
    Low-tech approach: Expanding the geometric series, one gets $$varphi(t)=frac12+frac14frac1{1-frac12e^{-t^2}}=frac34+sum_{ngeqslant1}frac1{2^{n+2}}e^{-nt^2}$$ Now, use (and/or prove) the result that if every $varphi_n$ is a characteristic function and if $(p_n)$ are nonnegative with $sum p_n=1$ then $$varphi=sum_{ngeqslant0}p_nvarphi_n$$ is a characteristic function as well.
    $endgroup$
    – Did
    Dec 6 '18 at 15:24












  • $begingroup$
    @Did That approach needs slightly more care in this case because there are infinitely many of the $varphi_n$, but it works.
    $endgroup$
    – J.G.
    Dec 6 '18 at 15:25






  • 1




    $begingroup$
    @J.G. I do not know what you mean by "slightly more care" ("more" than what?) but indeed the result I mentioned holds, for infinitely many nonzero coefficients $p_n$ just like it holds for finitely many.
    $endgroup$
    – Did
    Dec 6 '18 at 15:28






  • 1




    $begingroup$
    @Did It's a trivial result when we take a linear combination of any finite number of cfs by induction, but the extension to infinitely many requires discussion of limits. In this case I'd take the pointwise limit of a sequence of pdfs from Fourier inversion, then Fourier-transform back to $varphi$.
    $endgroup$
    – J.G.
    Dec 6 '18 at 15:35






  • 1




    $begingroup$
    "Discussion of limits" Not necessarily, if one builds explicitely a random variable whose CF is $sumlimits_{n=0}^infty p_nvarphi_n$.
    $endgroup$
    – Did
    Dec 6 '18 at 16:06








4




4




$begingroup$
Low-tech approach: Expanding the geometric series, one gets $$varphi(t)=frac12+frac14frac1{1-frac12e^{-t^2}}=frac34+sum_{ngeqslant1}frac1{2^{n+2}}e^{-nt^2}$$ Now, use (and/or prove) the result that if every $varphi_n$ is a characteristic function and if $(p_n)$ are nonnegative with $sum p_n=1$ then $$varphi=sum_{ngeqslant0}p_nvarphi_n$$ is a characteristic function as well.
$endgroup$
– Did
Dec 6 '18 at 15:24






$begingroup$
Low-tech approach: Expanding the geometric series, one gets $$varphi(t)=frac12+frac14frac1{1-frac12e^{-t^2}}=frac34+sum_{ngeqslant1}frac1{2^{n+2}}e^{-nt^2}$$ Now, use (and/or prove) the result that if every $varphi_n$ is a characteristic function and if $(p_n)$ are nonnegative with $sum p_n=1$ then $$varphi=sum_{ngeqslant0}p_nvarphi_n$$ is a characteristic function as well.
$endgroup$
– Did
Dec 6 '18 at 15:24














$begingroup$
@Did That approach needs slightly more care in this case because there are infinitely many of the $varphi_n$, but it works.
$endgroup$
– J.G.
Dec 6 '18 at 15:25




$begingroup$
@Did That approach needs slightly more care in this case because there are infinitely many of the $varphi_n$, but it works.
$endgroup$
– J.G.
Dec 6 '18 at 15:25




1




1




$begingroup$
@J.G. I do not know what you mean by "slightly more care" ("more" than what?) but indeed the result I mentioned holds, for infinitely many nonzero coefficients $p_n$ just like it holds for finitely many.
$endgroup$
– Did
Dec 6 '18 at 15:28




$begingroup$
@J.G. I do not know what you mean by "slightly more care" ("more" than what?) but indeed the result I mentioned holds, for infinitely many nonzero coefficients $p_n$ just like it holds for finitely many.
$endgroup$
– Did
Dec 6 '18 at 15:28




1




1




$begingroup$
@Did It's a trivial result when we take a linear combination of any finite number of cfs by induction, but the extension to infinitely many requires discussion of limits. In this case I'd take the pointwise limit of a sequence of pdfs from Fourier inversion, then Fourier-transform back to $varphi$.
$endgroup$
– J.G.
Dec 6 '18 at 15:35




$begingroup$
@Did It's a trivial result when we take a linear combination of any finite number of cfs by induction, but the extension to infinitely many requires discussion of limits. In this case I'd take the pointwise limit of a sequence of pdfs from Fourier inversion, then Fourier-transform back to $varphi$.
$endgroup$
– J.G.
Dec 6 '18 at 15:35




1




1




$begingroup$
"Discussion of limits" Not necessarily, if one builds explicitely a random variable whose CF is $sumlimits_{n=0}^infty p_nvarphi_n$.
$endgroup$
– Did
Dec 6 '18 at 16:06




$begingroup$
"Discussion of limits" Not necessarily, if one builds explicitely a random variable whose CF is $sumlimits_{n=0}^infty p_nvarphi_n$.
$endgroup$
– Did
Dec 6 '18 at 16:06










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