How to identify a face is circle using it's vertices [closed]












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Is there a way to identify whether a face is of circular shape and it's center?. All I have is the face and it's vertices.






surfaces







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closed as unclear what you're asking by Hans Lundmark, Lord Shark the Unknown, KReiser, Rebellos, Cesareo Dec 7 '18 at 11:50


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.


















  • $begingroup$
    Are you asking, given the numerical coordinates of some points in the plane, how do you tell if they lie on a circle? If so, are you concerned about numerical imprecision?
    $endgroup$
    – kimchi lover
    Dec 6 '18 at 15:45










  • $begingroup$
    Yes. I am not concerned.
    $endgroup$
    – Chandu
    Dec 6 '18 at 23:44
















0












$begingroup$


Is there a way to identify whether a face is of circular shape and it's center?. All I have is the face and it's vertices.






surfaces







share|cite|improve this question









$endgroup$



closed as unclear what you're asking by Hans Lundmark, Lord Shark the Unknown, KReiser, Rebellos, Cesareo Dec 7 '18 at 11:50


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.


















  • $begingroup$
    Are you asking, given the numerical coordinates of some points in the plane, how do you tell if they lie on a circle? If so, are you concerned about numerical imprecision?
    $endgroup$
    – kimchi lover
    Dec 6 '18 at 15:45










  • $begingroup$
    Yes. I am not concerned.
    $endgroup$
    – Chandu
    Dec 6 '18 at 23:44














0












0








0





$begingroup$


Is there a way to identify whether a face is of circular shape and it's center?. All I have is the face and it's vertices.






surfaces







share|cite|improve this question









$endgroup$




Is there a way to identify whether a face is of circular shape and it's center?. All I have is the face and it's vertices.






surfaces




surfaces






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 6 '18 at 15:16









ChanduChandu

1




1




closed as unclear what you're asking by Hans Lundmark, Lord Shark the Unknown, KReiser, Rebellos, Cesareo Dec 7 '18 at 11:50


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.









closed as unclear what you're asking by Hans Lundmark, Lord Shark the Unknown, KReiser, Rebellos, Cesareo Dec 7 '18 at 11:50


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • $begingroup$
    Are you asking, given the numerical coordinates of some points in the plane, how do you tell if they lie on a circle? If so, are you concerned about numerical imprecision?
    $endgroup$
    – kimchi lover
    Dec 6 '18 at 15:45










  • $begingroup$
    Yes. I am not concerned.
    $endgroup$
    – Chandu
    Dec 6 '18 at 23:44


















  • $begingroup$
    Are you asking, given the numerical coordinates of some points in the plane, how do you tell if they lie on a circle? If so, are you concerned about numerical imprecision?
    $endgroup$
    – kimchi lover
    Dec 6 '18 at 15:45










  • $begingroup$
    Yes. I am not concerned.
    $endgroup$
    – Chandu
    Dec 6 '18 at 23:44
















$begingroup$
Are you asking, given the numerical coordinates of some points in the plane, how do you tell if they lie on a circle? If so, are you concerned about numerical imprecision?
$endgroup$
– kimchi lover
Dec 6 '18 at 15:45




$begingroup$
Are you asking, given the numerical coordinates of some points in the plane, how do you tell if they lie on a circle? If so, are you concerned about numerical imprecision?
$endgroup$
– kimchi lover
Dec 6 '18 at 15:45












$begingroup$
Yes. I am not concerned.
$endgroup$
– Chandu
Dec 6 '18 at 23:44




$begingroup$
Yes. I am not concerned.
$endgroup$
– Chandu
Dec 6 '18 at 23:44










2 Answers
2






active

oldest

votes


















1












$begingroup$

Three non-aligned points are enough to unambiguously define a circle. You find the center as the intersection of two mediatrices. http://www.manufacturinget.org/2011/07/construct-circle-through-three-points/



When you have the center, you can check that all points are at the same distance from it.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    This condition will identify a square face too as circle?
    $endgroup$
    – Chandu
    Dec 7 '18 at 1:29










  • $begingroup$
    @Chandu: are you serious ?
    $endgroup$
    – Yves Daoust
    Dec 7 '18 at 8:47



















-1












$begingroup$

Given a list of $(x_i,y_i)$ pairs, representing points in the plain, see if you can predict $x_i^2+y_i^2$ with an affine function of $(x_i,y_i)$, by, say, least squares. If your points lie exactly on a circle, the residual sum of squares should equal 0.






share|cite|improve this answer











$endgroup$









  • 1




    $begingroup$
    The little that I can understand of this answer, is wrong.
    $endgroup$
    – Yves Daoust
    Dec 7 '18 at 0:35


















2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









1












$begingroup$

Three non-aligned points are enough to unambiguously define a circle. You find the center as the intersection of two mediatrices. http://www.manufacturinget.org/2011/07/construct-circle-through-three-points/



When you have the center, you can check that all points are at the same distance from it.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    This condition will identify a square face too as circle?
    $endgroup$
    – Chandu
    Dec 7 '18 at 1:29










  • $begingroup$
    @Chandu: are you serious ?
    $endgroup$
    – Yves Daoust
    Dec 7 '18 at 8:47
















1












$begingroup$

Three non-aligned points are enough to unambiguously define a circle. You find the center as the intersection of two mediatrices. http://www.manufacturinget.org/2011/07/construct-circle-through-three-points/



When you have the center, you can check that all points are at the same distance from it.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    This condition will identify a square face too as circle?
    $endgroup$
    – Chandu
    Dec 7 '18 at 1:29










  • $begingroup$
    @Chandu: are you serious ?
    $endgroup$
    – Yves Daoust
    Dec 7 '18 at 8:47














1












1








1





$begingroup$

Three non-aligned points are enough to unambiguously define a circle. You find the center as the intersection of two mediatrices. http://www.manufacturinget.org/2011/07/construct-circle-through-three-points/



When you have the center, you can check that all points are at the same distance from it.






share|cite|improve this answer









$endgroup$



Three non-aligned points are enough to unambiguously define a circle. You find the center as the intersection of two mediatrices. http://www.manufacturinget.org/2011/07/construct-circle-through-three-points/



When you have the center, you can check that all points are at the same distance from it.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Dec 7 '18 at 0:38









Yves DaoustYves Daoust

125k671223




125k671223












  • $begingroup$
    This condition will identify a square face too as circle?
    $endgroup$
    – Chandu
    Dec 7 '18 at 1:29










  • $begingroup$
    @Chandu: are you serious ?
    $endgroup$
    – Yves Daoust
    Dec 7 '18 at 8:47


















  • $begingroup$
    This condition will identify a square face too as circle?
    $endgroup$
    – Chandu
    Dec 7 '18 at 1:29










  • $begingroup$
    @Chandu: are you serious ?
    $endgroup$
    – Yves Daoust
    Dec 7 '18 at 8:47
















$begingroup$
This condition will identify a square face too as circle?
$endgroup$
– Chandu
Dec 7 '18 at 1:29




$begingroup$
This condition will identify a square face too as circle?
$endgroup$
– Chandu
Dec 7 '18 at 1:29












$begingroup$
@Chandu: are you serious ?
$endgroup$
– Yves Daoust
Dec 7 '18 at 8:47




$begingroup$
@Chandu: are you serious ?
$endgroup$
– Yves Daoust
Dec 7 '18 at 8:47











-1












$begingroup$

Given a list of $(x_i,y_i)$ pairs, representing points in the plain, see if you can predict $x_i^2+y_i^2$ with an affine function of $(x_i,y_i)$, by, say, least squares. If your points lie exactly on a circle, the residual sum of squares should equal 0.






share|cite|improve this answer











$endgroup$









  • 1




    $begingroup$
    The little that I can understand of this answer, is wrong.
    $endgroup$
    – Yves Daoust
    Dec 7 '18 at 0:35
















-1












$begingroup$

Given a list of $(x_i,y_i)$ pairs, representing points in the plain, see if you can predict $x_i^2+y_i^2$ with an affine function of $(x_i,y_i)$, by, say, least squares. If your points lie exactly on a circle, the residual sum of squares should equal 0.






share|cite|improve this answer











$endgroup$









  • 1




    $begingroup$
    The little that I can understand of this answer, is wrong.
    $endgroup$
    – Yves Daoust
    Dec 7 '18 at 0:35














-1












-1








-1





$begingroup$

Given a list of $(x_i,y_i)$ pairs, representing points in the plain, see if you can predict $x_i^2+y_i^2$ with an affine function of $(x_i,y_i)$, by, say, least squares. If your points lie exactly on a circle, the residual sum of squares should equal 0.






share|cite|improve this answer











$endgroup$



Given a list of $(x_i,y_i)$ pairs, representing points in the plain, see if you can predict $x_i^2+y_i^2$ with an affine function of $(x_i,y_i)$, by, say, least squares. If your points lie exactly on a circle, the residual sum of squares should equal 0.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Dec 7 '18 at 1:05

























answered Dec 7 '18 at 0:07









kimchi loverkimchi lover

9,84131128




9,84131128








  • 1




    $begingroup$
    The little that I can understand of this answer, is wrong.
    $endgroup$
    – Yves Daoust
    Dec 7 '18 at 0:35














  • 1




    $begingroup$
    The little that I can understand of this answer, is wrong.
    $endgroup$
    – Yves Daoust
    Dec 7 '18 at 0:35








1




1




$begingroup$
The little that I can understand of this answer, is wrong.
$endgroup$
– Yves Daoust
Dec 7 '18 at 0:35




$begingroup$
The little that I can understand of this answer, is wrong.
$endgroup$
– Yves Daoust
Dec 7 '18 at 0:35



-

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