Finding Fourier transform using some properties












1












$begingroup$


I am trying to solve a question of Fourier transform in which I am given two signals:$$X(jω)=δ(ω)+δ(ω-π)+δ(ω-5)\h(t)=u(t)-u(t-2)=begin{cases}1&0<x<2\0&text{otherwise}end{cases}$$
I am asked to find the whether the convolution of $x(t)$ and $h(t)$ is periodic or not. Now using properties I have founded the signal $x(t)$ but I am stuck at the Fourier transform of $h(t)$.



Now I need to find its Fourier Transform using the properties and the one I got is:
$$\x(t)=begin{cases}1&|t|<T _1\0&text{otherwise}end{cases} rightarrow frac{2sinomega T_1}{omega} $$
Using this property we know that the time period of the wave is 2, hence:
$$H(jomega) = frac{2sinomega2}{omega},$$
but the one mentioned in book is
$$H(jomega) = e^{-jomega} frac{2sinomega}{omega}.$$
Can somebody explain that why my expression is wrong?










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$endgroup$












  • $begingroup$
    One could explain why the book's expression is right....
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 10:00










  • $begingroup$
    @LordSharktheUnknown can you please point out my mistake?
    $endgroup$
    – Ahmad Qayyum
    Jan 6 at 10:03






  • 3




    $begingroup$
    I cannot point out your mistake, and nor can anyone else apart from yourself, since you have not provided details of your calculation.
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 10:04












  • $begingroup$
    @LordSharktheUnknown can you point out my mistake now?
    $endgroup$
    – Ahmad Qayyum
    Jan 6 at 11:56






  • 1




    $begingroup$
    Your formula works for $x(T)$ which is $1$ on the interval $(-T_1,T_1)$ and zero outside. But your $h$ is not of this form.
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 14:07
















1












$begingroup$


I am trying to solve a question of Fourier transform in which I am given two signals:$$X(jω)=δ(ω)+δ(ω-π)+δ(ω-5)\h(t)=u(t)-u(t-2)=begin{cases}1&0<x<2\0&text{otherwise}end{cases}$$
I am asked to find the whether the convolution of $x(t)$ and $h(t)$ is periodic or not. Now using properties I have founded the signal $x(t)$ but I am stuck at the Fourier transform of $h(t)$.



Now I need to find its Fourier Transform using the properties and the one I got is:
$$\x(t)=begin{cases}1&|t|<T _1\0&text{otherwise}end{cases} rightarrow frac{2sinomega T_1}{omega} $$
Using this property we know that the time period of the wave is 2, hence:
$$H(jomega) = frac{2sinomega2}{omega},$$
but the one mentioned in book is
$$H(jomega) = e^{-jomega} frac{2sinomega}{omega}.$$
Can somebody explain that why my expression is wrong?










share|cite|improve this question











$endgroup$












  • $begingroup$
    One could explain why the book's expression is right....
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 10:00










  • $begingroup$
    @LordSharktheUnknown can you please point out my mistake?
    $endgroup$
    – Ahmad Qayyum
    Jan 6 at 10:03






  • 3




    $begingroup$
    I cannot point out your mistake, and nor can anyone else apart from yourself, since you have not provided details of your calculation.
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 10:04












  • $begingroup$
    @LordSharktheUnknown can you point out my mistake now?
    $endgroup$
    – Ahmad Qayyum
    Jan 6 at 11:56






  • 1




    $begingroup$
    Your formula works for $x(T)$ which is $1$ on the interval $(-T_1,T_1)$ and zero outside. But your $h$ is not of this form.
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 14:07














1












1








1





$begingroup$


I am trying to solve a question of Fourier transform in which I am given two signals:$$X(jω)=δ(ω)+δ(ω-π)+δ(ω-5)\h(t)=u(t)-u(t-2)=begin{cases}1&0<x<2\0&text{otherwise}end{cases}$$
I am asked to find the whether the convolution of $x(t)$ and $h(t)$ is periodic or not. Now using properties I have founded the signal $x(t)$ but I am stuck at the Fourier transform of $h(t)$.



Now I need to find its Fourier Transform using the properties and the one I got is:
$$\x(t)=begin{cases}1&|t|<T _1\0&text{otherwise}end{cases} rightarrow frac{2sinomega T_1}{omega} $$
Using this property we know that the time period of the wave is 2, hence:
$$H(jomega) = frac{2sinomega2}{omega},$$
but the one mentioned in book is
$$H(jomega) = e^{-jomega} frac{2sinomega}{omega}.$$
Can somebody explain that why my expression is wrong?










share|cite|improve this question











$endgroup$




I am trying to solve a question of Fourier transform in which I am given two signals:$$X(jω)=δ(ω)+δ(ω-π)+δ(ω-5)\h(t)=u(t)-u(t-2)=begin{cases}1&0<x<2\0&text{otherwise}end{cases}$$
I am asked to find the whether the convolution of $x(t)$ and $h(t)$ is periodic or not. Now using properties I have founded the signal $x(t)$ but I am stuck at the Fourier transform of $h(t)$.



Now I need to find its Fourier Transform using the properties and the one I got is:
$$\x(t)=begin{cases}1&|t|<T _1\0&text{otherwise}end{cases} rightarrow frac{2sinomega T_1}{omega} $$
Using this property we know that the time period of the wave is 2, hence:
$$H(jomega) = frac{2sinomega2}{omega},$$
but the one mentioned in book is
$$H(jomega) = e^{-jomega} frac{2sinomega}{omega}.$$
Can somebody explain that why my expression is wrong?







fourier-transform






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 6 at 11:55







Ahmad Qayyum

















asked Jan 6 at 9:59









Ahmad QayyumAhmad Qayyum

677




677












  • $begingroup$
    One could explain why the book's expression is right....
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 10:00










  • $begingroup$
    @LordSharktheUnknown can you please point out my mistake?
    $endgroup$
    – Ahmad Qayyum
    Jan 6 at 10:03






  • 3




    $begingroup$
    I cannot point out your mistake, and nor can anyone else apart from yourself, since you have not provided details of your calculation.
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 10:04












  • $begingroup$
    @LordSharktheUnknown can you point out my mistake now?
    $endgroup$
    – Ahmad Qayyum
    Jan 6 at 11:56






  • 1




    $begingroup$
    Your formula works for $x(T)$ which is $1$ on the interval $(-T_1,T_1)$ and zero outside. But your $h$ is not of this form.
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 14:07


















  • $begingroup$
    One could explain why the book's expression is right....
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 10:00










  • $begingroup$
    @LordSharktheUnknown can you please point out my mistake?
    $endgroup$
    – Ahmad Qayyum
    Jan 6 at 10:03






  • 3




    $begingroup$
    I cannot point out your mistake, and nor can anyone else apart from yourself, since you have not provided details of your calculation.
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 10:04












  • $begingroup$
    @LordSharktheUnknown can you point out my mistake now?
    $endgroup$
    – Ahmad Qayyum
    Jan 6 at 11:56






  • 1




    $begingroup$
    Your formula works for $x(T)$ which is $1$ on the interval $(-T_1,T_1)$ and zero outside. But your $h$ is not of this form.
    $endgroup$
    – Lord Shark the Unknown
    Jan 6 at 14:07
















$begingroup$
One could explain why the book's expression is right....
$endgroup$
– Lord Shark the Unknown
Jan 6 at 10:00




$begingroup$
One could explain why the book's expression is right....
$endgroup$
– Lord Shark the Unknown
Jan 6 at 10:00












$begingroup$
@LordSharktheUnknown can you please point out my mistake?
$endgroup$
– Ahmad Qayyum
Jan 6 at 10:03




$begingroup$
@LordSharktheUnknown can you please point out my mistake?
$endgroup$
– Ahmad Qayyum
Jan 6 at 10:03




3




3




$begingroup$
I cannot point out your mistake, and nor can anyone else apart from yourself, since you have not provided details of your calculation.
$endgroup$
– Lord Shark the Unknown
Jan 6 at 10:04






$begingroup$
I cannot point out your mistake, and nor can anyone else apart from yourself, since you have not provided details of your calculation.
$endgroup$
– Lord Shark the Unknown
Jan 6 at 10:04














$begingroup$
@LordSharktheUnknown can you point out my mistake now?
$endgroup$
– Ahmad Qayyum
Jan 6 at 11:56




$begingroup$
@LordSharktheUnknown can you point out my mistake now?
$endgroup$
– Ahmad Qayyum
Jan 6 at 11:56




1




1




$begingroup$
Your formula works for $x(T)$ which is $1$ on the interval $(-T_1,T_1)$ and zero outside. But your $h$ is not of this form.
$endgroup$
– Lord Shark the Unknown
Jan 6 at 14:07




$begingroup$
Your formula works for $x(T)$ which is $1$ on the interval $(-T_1,T_1)$ and zero outside. But your $h$ is not of this form.
$endgroup$
– Lord Shark the Unknown
Jan 6 at 14:07










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